R,S,Z , K nonce and public key Signature samples

COBRAS

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Quote from: lavina888 on February 04, 2025, 09:37:31 AM

Quote from: JohnnyTX on June 25, 2024, 09:15:25 AM

Hi there!
It looks like you all are crazy for nonces and signatures, so I have some special values for you Wink

Code:

r=0x678afdb0fe5548271967f1a67130b7105cd6a828e03909a67962e0ea1f61deb6
s=0x24c8a42e8fe11d670633fa66ebedb1672c71a517a30cbbaa9e14f2d5a15a3783
z=SHA256('This is test 1.')
PubKey=0x3e42b3151f310f5f417f11b4c32d8360b22109dcc6432339243332b56cd596de, 0x7903116327cab6891b810588e4c909273c7eb013aea2162fa63afa1f11562b3a

r=0x678afdb0fe5548271967f1a67130b7105cd6a828e03909a67962e0ea1f61deb6
s=0x768a0e3b0cfb3c8d9b7899f59f480555176ef25eefa1e96d3ac575ba4ffe85fd
z=SHA256('This is test 2.')
PubKey=0xc79fa242694e3148c8d50e667010e0c221f6004d108692c5040ff139595ed081, 0x525bd76c21c8e2d45725a378c973a646d5971acd8f240322e5f1fdf0ed4f8589

r=0x678afdb0fe5548271967f1a67130b7105cd6a828e03909a67962e0ea1f61deb6
s=0xd17c5ed9fb37692cd152f381c4a3f16a896f96d26100310fe818d6963c402b25
z=SHA256('This is test 3.')
PubKey=0xc03657988e2baf31a1a1061a87fa3da20f166dc8a22c02658f6d325dec722d84, 0x97ffbac6bec2de2b8d9f9bcaeced8e56abdd0b3996b48153cf0a1a92dc2d5529

Btw. I think that those who do serious research of this topic do not need your script, but all contributions are welcome, of course.

nonce found, but in theory knowing this value - it is possible to restore the private key from each address: x = (s*k-m)/r, but this is not true at all. for all three signatures it is impossible to restore the correct keys to the addresses.

publick keys different, because it not posible find privkey for adress.

lavina888

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Activity: 78

Merit: 10

Elcoin.io Team, CTO

Quote from: JohnnyTX on June 25, 2024, 09:15:25 AM

Hi there!
It looks like you all are crazy for nonces and signatures, so I have some special values for you Wink

Code:

r=0x678afdb0fe5548271967f1a67130b7105cd6a828e03909a67962e0ea1f61deb6
s=0x24c8a42e8fe11d670633fa66ebedb1672c71a517a30cbbaa9e14f2d5a15a3783
z=SHA256('This is test 1.')
PubKey=0x3e42b3151f310f5f417f11b4c32d8360b22109dcc6432339243332b56cd596de, 0x7903116327cab6891b810588e4c909273c7eb013aea2162fa63afa1f11562b3a

r=0x678afdb0fe5548271967f1a67130b7105cd6a828e03909a67962e0ea1f61deb6
s=0x768a0e3b0cfb3c8d9b7899f59f480555176ef25eefa1e96d3ac575ba4ffe85fd
z=SHA256('This is test 2.')
PubKey=0xc79fa242694e3148c8d50e667010e0c221f6004d108692c5040ff139595ed081, 0x525bd76c21c8e2d45725a378c973a646d5971acd8f240322e5f1fdf0ed4f8589

r=0x678afdb0fe5548271967f1a67130b7105cd6a828e03909a67962e0ea1f61deb6
s=0xd17c5ed9fb37692cd152f381c4a3f16a896f96d26100310fe818d6963c402b25
z=SHA256('This is test 3.')
PubKey=0xc03657988e2baf31a1a1061a87fa3da20f166dc8a22c02658f6d325dec722d84, 0x97ffbac6bec2de2b8d9f9bcaeced8e56abdd0b3996b48153cf0a1a92dc2d5529

Btw. I think that those who do serious research of this topic do not need your script, but all contributions are welcome, of course.

nonce found, but in theory knowing this value - it is possible to restore the private key from each address: x = (s*k-m)/r, but this is not true at all. for all three signatures it is impossible to restore the correct keys to the addresses.

Lolo54

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Activity: 131

Merit: 32

Intriguing all the same, this RetiredCoder his way of writing, of composing his posts and some facts intrigue me (1 example post de JohnnyTX 29/07/24) I'm probably wrong but satoshi_rider= RetiredCoder=satoshi why not 🤔?! I don't understand the meaning of some of his messages including the one in the signature of #130 involving a famous quote from Jules Verne?? nor why this one….nor even how it was a clue if not a message or rather an implied clue free to everyone to appreciate its significance. Why is it he who gives the explanation then the privkey on how to achieve it and not the solver…. strange brief

?

Activity: -

Merit: -

Quote from: COBRAS on December 15, 2024, 04:21:13 PM

Quote from: JohnnyTX on December 15, 2024, 03:32:00 PM

Quote from: JohnnyTX on July 29, 2024, 07:22:10 AM

Code:

r2 = 0xdfb77cd83e2251dc96caad4c45cf98fcf76b8c24aa349c2dbba548029571331f
s2 = 0x352b52b52b52b52b52b52b52b52b52b4e7c1db2bf914fdd54560dc7fb517156e
z2 = Private key for Puzzle #130

Update:

Code:

z2 = 0x33e7665705359f04f28b88cf897c603c9

Code:

r = 0xdb30127de06f6c9d04e4ebc9cdefb93433a37be972db697b21c22724f6cf69d2
s = 0xe759203cae759203cae759203cae7590ddcd6e80d38035c802aef0f1080384ed
z = Private key for Puzzle #135

Hi, can you multiply or add r to number and edit s,z after , so what signatures will be valid ?

the question is how RetiredCoder makes this valuable and connected
"r1_1 = 02de97092bfb7c02148a827b4f8b62db1e189a739c77815799df5e6fb35ae88a1f
r2_1 = 02838db77b981db321faf527a830461cfda01aed50d85c345a7b0a8f4e5e4fd3fc
delta = 031e283a9ebc4c50b0a93f27d411e69d0a97aad2a6d4ae26f5725f8b55fb5176f5
delta _k = 0xfffffffffffffffffffffffffffffffebaaedce6af487e246f4eac90b714b3bd
N- delta _k = 0x22175083b1fc19218d84

r1_2= 03de97092bfb7c02148a827b4f8b62db1e189a739c77815799df5e6fb35ae88a1f
r2_2= 03838db77b981db321faf527a830461cfda01aed50d85c345a7b0a8f4e5e4fd3fc
delta = 021e283a9ebc4c50b0a93f27d411e69d0a97aad2a6d4ae26f5725f8b55fb5176f5
delta _k = 0x22175083b1fc19218d84

PK = 33e7665705359f04f28b88cf897c603c9" I wasted maybe 48 hours coding Cheesy

,
Then, one out of the community claimed the puzzle and didn`t show up. Grin

where are you? Roll Eyes

COBRAS

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Quote from: JohnnyTX on December 15, 2024, 03:32:00 PM

Quote from: JohnnyTX on July 29, 2024, 07:22:10 AM

Code:

r2 = 0xdfb77cd83e2251dc96caad4c45cf98fcf76b8c24aa349c2dbba548029571331f
s2 = 0x352b52b52b52b52b52b52b52b52b52b4e7c1db2bf914fdd54560dc7fb517156e
z2 = Private key for Puzzle #130

Update:

Code:

z2 = 0x33e7665705359f04f28b88cf897c603c9

Code:

r = 0xdb30127de06f6c9d04e4ebc9cdefb93433a37be972db697b21c22724f6cf69d2
s = 0xe759203cae759203cae759203cae7590ddcd6e80d38035c802aef0f1080384ed
z = Private key for Puzzle #135

Hi, can you multiply or add r to number and edit s,z after , so what signatures will be valid ?

JohnnyTX

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Activity: 7

Merit: 0

Quote from: JohnnyTX on July 29, 2024, 07:22:10 AM

Code:

r2 = 0xdfb77cd83e2251dc96caad4c45cf98fcf76b8c24aa349c2dbba548029571331f
s2 = 0x352b52b52b52b52b52b52b52b52b52b4e7c1db2bf914fdd54560dc7fb517156e
z2 = Private key for Puzzle #130

Update:

Code:

z2 = 0x33e7665705359f04f28b88cf897c603c9

Code:

r = 0xdb30127de06f6c9d04e4ebc9cdefb93433a37be972db697b21c22724f6cf69d2
s = 0xe759203cae759203cae759203cae7590ddcd6e80d38035c802aef0f1080384ed
z = Private key for Puzzle #135

Sergey Magalyas

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Activity: 32

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Quote from: krashfire on June 25, 2024, 01:11:27 AM

Quote from: jacky19790729 on June 24, 2024, 05:21:41 AM

I have been learning about ECDSA ( r s z, public key ,private key ) for about 2 months

# 130 Although only one rsz is know , but 1000 rsz can be produced using the public key, the nonce K value will be 240~256 bits

would you mind sharing your code on how you leak the RSZ and how you create more sample for the given public key. thank you

Friend, give me a code that allows you to create 1000 rsz using a public key.

garlonicon

copper member

Activity: 944

Merit: 2257

Quote

can you share more numbers

Just use inversion, and get some ECC calculator:

Code:

1/2=0x7fffffffffffffffffffffffffffffff5d576e7357a4501ddfe92f46681b20a1
1/3=0xaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa9d1c9e899ca306ad27fe1945de0242b81
1/4=0xbfffffffffffffffffffffffffffffff0c0325ad0376782ccfddc6e99c28b0f1
1/5=0x66666666666666666666666666666665e445f1f5dfb6a67e4cba8c385348e6e7
1/6=0xd5555555555555555555555555555554463c62c03cbc85871fd9f975582d3661
1/7=0x49249249249249249249249249249248c79facd43214c011123c1b03a93412a5
1/8=0xdffffffffffffffffffffffffffffffee3590149d95f8c3447d812bb362f7919
1/9=0x8e38e38e38e38e38e38e38e38e38e38d842841d57dd303af6a9150f8e5737996
1/10=0xb33333333333333333333333333333324f7a676e477fa35d0646756291bf9414
1/11=0xa2e8ba2e8ba2e8ba2e8ba2e8ba2e8ba219b51835b55cc30ebfe2f6599bc56f58
1/12=0xeaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa980759fd3760292e16fd62c011431bbd1
1/13=0x13b13b13b13b13b13b13b13b13b13b139834d5ea5c40a9dd3623dfe3727a53ca
1/14=0xa4924924924924924924924924924923c12744dd70aeb02669073cc83cb529f3
1/15=0x22222222222222222222222222222221f6c1fb51f53ce22a19938412c66da24d
1/16=0xeffffffffffffffffffffffffffffffecf03ef184454163803d538a40332dd2d
...
1/128=0x7dffffffffffffffffffffffffffffff5fe210b98a45bedd68698a894e7ab41e
1/129=0xa4b692da4b692da4b692da4b692da4b5c18a4ea054ff19b357b30348bd881e14
1/130=0x352b52b52b52b52b52b52b52b52b52b4e7c1db2bf914fdd54560dc7fb517156e
1/131=0x7b1d501f44659e4a427157f05dcd30da4254182896bd4f03546ef0e3f6b28500
1/132=0xb83e0f83e0f83e0f83e0f83e0f83e0f753ee5548eea2d0690fdf28e557c9f4c8
1/133=0xe8e6fa39be8e6fa39be8e6fa39be8e6e7ba4dc37e2d648a225da5604eb9f12f2
1/134=0x05bb39503d226357e16ece540f4898d5f11332cbd9e4f81fe7a346e495db0176
1/135=0xe759203cae759203cae759203cae7590ddcd6e80d38035c802aef0f1080384ed
...
1/0xfffffffffffffffffffffffffffffffebaaedce6af48a03bbfd25e8cd036413d=0x3fffffffffffffffffffffffffffffffaeabb739abd2280eeff497a3340d9050
1/0xfffffffffffffffffffffffffffffffebaaedce6af48a03bbfd25e8cd036413e=0x55555555555555555555555555555554e8e4f44ce51835693ff0ca2ef01215c0
1/0xfffffffffffffffffffffffffffffffebaaedce6af48a03bbfd25e8cd036413f=0x7fffffffffffffffffffffffffffffff5d576e7357a4501ddfe92f46681b20a0
1/0xfffffffffffffffffffffffffffffffebaaedce6af48a03bbfd25e8cd0364140=0xfffffffffffffffffffffffffffffffebaaedce6af48a03bbfd25e8cd0364140

For example: https://www.boxentriq.com/code-breaking/big-number-calculator

Kpot87

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Activity: 43

Merit: 1

Quote from: garlonicon on July 30, 2024, 07:48:24 AM

Quote

Code:

s2 = 0x352b52b52b52b52b52b52b52b52b52b4e7c1db2bf914fdd54560dc7fb517156e
            ^repeated pattern^        |<----       130 bits       --->|

It is just an inversion of 0x82, nothing special. If you multiply 0x352b52b52b52b52b52b52b52b52b52b4e7c1db2bf914fdd54560dc7fb517156e by 0x82, you will get 0x1affffffffffffffffffffffffffffffddb0714c547ca8e64d3b2ff8d9f5b8e1dc as a result, which is equal to one, if you apply modulo n=0xfffffffffffffffffffffffffffffffebaaedce6af48a03bbfd25e8cd0364141 on that.

can you share more numbers like 0x1affffffffffffffffffffffffffffffddb0714c547ca8e64d3b2ff8d9f5b8e1dc
thank you!

JDScreesh

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Activity: 51

Merit: 13

Hi there.

Puzzle 130 was solved, but I don't know which script or technique was used Huh

Anyway, gratz to the solver

COBRAS

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Lattice for rs and pub

https://bitcointalksearch.org/topic/--5504929

JohnnyTX

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Activity: 7

Merit: 0

Quote from: garlonicon on July 30, 2024, 07:48:24 AM

It is just an inversion of 0x82, nothing special.

Well, thanks, I was too hasty this time.

garlonicon

copper member

Activity: 944

Merit: 2257

Quote

Code:

s2 = 0x352b52b52b52b52b52b52b52b52b52b4e7c1db2bf914fdd54560dc7fb517156e
^repeated pattern^ |<---- 130 bits --->|

It is just an inversion of 0x82, nothing special. If you multiply 0x352b52b52b52b52b52b52b52b52b52b4e7c1db2bf914fdd54560dc7fb517156e by 0x82, you will get 0x1affffffffffffffffffffffffffffffddb0714c547ca8e64d3b2ff8d9f5b8e1dc as a result, which is equal to one, if you apply modulo n=0xfffffffffffffffffffffffffffffffebaaedce6af48a03bbfd25e8cd0364141 on that.

JohnnyTX

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Activity: 7

Merit: 0

Quote from: jacky19790729 on July 29, 2024, 01:04:13 PM

I can't understand special values

Which values? All values are special ;-)
First 3 signatures use Satoshi private key #1 as a nonce, but signed real messages (not random). Nobody noticed?
The fourth signature signs again real message, and with the same key also a private key of Puzzle #130 as input, there is no "why", that's an intention.

~~And finally the value of s2 shows the weakness of the private key here~~:

Code:

s2 = 0x352b52b52b52b52b52b52b52b52b52b4e7c1db2bf914fdd54560dc7fb517156e
^repeated pattern^ |<---- 130 bits --->|

jacky19790729

jr. member

Activity: 82

Merit: 8

Quote from: JohnnyTX on July 29, 2024, 07:22:10 AM

Public Key 0x40f08294791bb07e908196847f79ad162ba0dff28eb312b1669ee2c8a72f7bfb, 0x28c29cc6ec6f2ddf9f54f32da1ea727de71c2ef168528475f5233ba28c06c4a8

Code:

r1 = 0x7029db68c1420fe2d41c1fd7b86ea0739bc8e6d0a7c58f754b93e5ff6c8040
s1 = 0xdbe4b484c838fce2aa65d85901f94f6fad6ad5f604d805c30ce05c58371c6991
z1 = SHA256('This is test 4.')

r2 = 0xdfb77cd83e2251dc96caad4c45cf98fcf76b8c24aa349c2dbba548029571331f
s2 = 0x352b52b52b52b52b52b52b52b52b52b4e7c1db2bf914fdd54560dc7fb517156e
z2 = Private key for Puzzle #130

Interesting, right?

Recovered Bitcoin public key: 0240f08294791bb07e908196847f79ad162ba0dff28eb312b1669ee2c8a72f7bfb
Bitcoin Address： 1AaEnbgVCKmG7RM8KYxjiQ2xaqn4NmyA7a

r1 = 0x7029db68c1420fe2d41c1fd7b86ea0739bc8e6d0a7c58f754b93e5ff6c8040
s1 = 0xdbe4b484c838fce2aa65d85901f94f6fad6ad5f604d805c30ce05c58371c6991
z1 = 0x9cabe7317b243f04a211a282035b96caa14d646dc32ba0e326f52d43cef07d8c

why z2 will be Private key for Puzzle #130 ??

jacky19790729

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Activity: 82

Merit: 8

Quote from: JohnnyTX on June 25, 2024, 09:15:25 AM

Hi there!
It looks like you all are crazy for nonces and signatures, so I have some special values for you Wink

Code:

r=0x678afdb0fe5548271967f1a67130b7105cd6a828e03909a67962e0ea1f61deb6
s=0x24c8a42e8fe11d670633fa66ebedb1672c71a517a30cbbaa9e14f2d5a15a3783
z=SHA256('This is test 1.')
PubKey=0x3e42b3151f310f5f417f11b4c32d8360b22109dcc6432339243332b56cd596de, 0x7903116327cab6891b810588e4c909273c7eb013aea2162fa63afa1f11562b3a

r=0x678afdb0fe5548271967f1a67130b7105cd6a828e03909a67962e0ea1f61deb6
s=0x768a0e3b0cfb3c8d9b7899f59f480555176ef25eefa1e96d3ac575ba4ffe85fd
z=SHA256('This is test 2.')
PubKey=0xc79fa242694e3148c8d50e667010e0c221f6004d108692c5040ff139595ed081, 0x525bd76c21c8e2d45725a378c973a646d5971acd8f240322e5f1fdf0ed4f8589

r=0x678afdb0fe5548271967f1a67130b7105cd6a828e03909a67962e0ea1f61deb6
s=0xd17c5ed9fb37692cd152f381c4a3f16a896f96d26100310fe818d6963c402b25
z=SHA256('This is test 3.')
PubKey=0xc03657988e2baf31a1a1061a87fa3da20f166dc8a22c02658f6d325dec722d84, 0x97ffbac6bec2de2b8d9f9bcaeced8e56abdd0b3996b48153cf0a1a92dc2d5529

Btw. I think that those who do serious research of this topic do not need your script, but all contributions are welcome, of course.

Recovered Bitcoin public key: 023e42b3151f310f5f417f11b4c32d8360b22109dcc6432339243332b56cd596de
Bitcoin Address： 1ak61eAXk4bxNbovZuqh4f1PxBaf1VUBV
r=0x678afdb0fe5548271967f1a67130b7105cd6a828e03909a67962e0ea1f61deb6
s=0x24c8a42e8fe11d670633fa66ebedb1672c71a517a30cbbaa9e14f2d5a15a3783
z=0xe0f6c07e19eb2dfa2e0c3586a2a9f4b225dba10c353fc354baa2dabcc9d42051

---
Recovered Bitcoin public key: 03c79fa242694e3148c8d50e667010e0c221f6004d108692c5040ff139595ed081
Bitcoin Address： 1GLKrFmj8eUsHS7s91PTMh2L6rPtF1RzNj
r=0x678afdb0fe5548271967f1a67130b7105cd6a828e03909a67962e0ea1f61deb6
s=0x768a0e3b0cfb3c8d9b7899f59f480555176ef25eefa1e96d3ac575ba4ffe85fd
z=0x48ef5d298a862b6f74338ebb5281f5212d8221a2fd8cce827be72779bffd25dd

---
Recovered Bitcoin public key: 03c03657988e2baf31a1a1061a87fa3da20f166dc8a22c02658f6d325dec722d84
Bitcoin Address： 17aj9BWZyDTqr6UnK7LScoCHdsbFRT6LZG
r=0x678afdb0fe5548271967f1a67130b7105cd6a828e03909a67962e0ea1f61deb6
s=0xd17c5ed9fb37692cd152f381c4a3f16a896f96d26100310fe818d6963c402b25
z=0x1e6a32d38fb096d19ad46186c6299f82b7bfd5a92d0d3b17142e8ff18b75e358

I can't understand special values

JohnnyTX

newbie

Activity: 7

Merit: 0

Public Key 0x40f08294791bb07e908196847f79ad162ba0dff28eb312b1669ee2c8a72f7bfb, 0x28c29cc6ec6f2ddf9f54f32da1ea727de71c2ef168528475f5233ba28c06c4a8

Code:

r1 = 0x7029db68c1420fe2d41c1fd7b86ea0739bc8e6d0a7c58f754b93e5ff6c8040
s1 = 0xdbe4b484c838fce2aa65d85901f94f6fad6ad5f604d805c30ce05c58371c6991
z1 = SHA256('This is test 4.')

r2 = 0xdfb77cd83e2251dc96caad4c45cf98fcf76b8c24aa349c2dbba548029571331f
s2 = 0x352b52b52b52b52b52b52b52b52b52b4e7c1db2bf914fdd54560dc7fb517156e
z2 = Private key for Puzzle #130

Interesting, right?

jacky19790729

jr. member

Activity: 82

Merit: 8

Quote from: JohnnyTX on June 25, 2024, 12:55:44 PM

Code:

# rsz 1
r=0xd7232c0eed9a80a6e53d74b57d80cd892816b46c69157f8e543ee76dc21f8410
s=0xe6665792427b98ebd93cd43f694e03383c84af34b00e5f471c5cec5a24541808
z=0xc3479c8d5591597a4b12018ccacd0215528e584aa18125d63fac5c0c0c92588b
# rsz 2
r=0xafc4670c63a5677641ba51b0eb413f7d8be3cfeb100f2c2097eb57dd673d58c2
s=0xe14e5906641085412561a083c002b76d6ac5a54372a9c811edc9e3b86b2dde11
z=0x1b636df9eef267995d6918047ba3bafca25f693a47ff73c7c0d500cd4aa9783a

Code:

N = 0xFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFEBAAEDCE6AF48A03BBFD25E8CD0364141

def inv(a):
return pow(a, N - 2, N)

r1 = 0xd7232c0eed9a80a6e53d74b57d80cd892816b46c69157f8e543ee76dc21f8410
s1 = 0xe6665792427b98ebd93cd43f694e03383c84af34b00e5f471c5cec5a24541808
z1 = 0xc3479c8d5591597a4b12018ccacd0215528e584aa18125d63fac5c0c0c92588b

HA = 0xd7232c0eed9a80a6e53d74b57d80cd892816b46c69157f8e543ee76dc21f8410 * inv(0xafc4670c63a5677641ba51b0eb413f7d8be3cfeb100f2c2097eb57dd673d58c2)
HA = HA % N
print("HA: %064x" % HA )

r2 = 0xafc4670c63a5677641ba51b0eb413f7d8be3cfeb100f2c2097eb57dd673d58c2 * HA
s2 = 0xe14e5906641085412561a083c002b76d6ac5a54372a9c811edc9e3b86b2dde11 * HA
z2 = 0x1b636df9eef267995d6918047ba3bafca25f693a47ff73c7c0d500cd4aa9783a * HA

z2 = z2 - s2
r2 = r2 % N
s2 = s2 % N
z2 = z2 % N

print("r1= 0x%064x " % r1 )
print("s1= 0x%064x " % s1 )
print("z1= 0x%064x " % z1 )
print("r2= 0x%064x " % r2 )
print("s2= 0x%064x " % s2 )
print("z2= 0x%064x " % z2 )

output:
HA: e809a06f968e72e232e96f55e26f809d22d922681acca6904f12c4ba1b53018d
r1 = 0xd7232c0eed9a80a6e53d74b57d80cd892816b46c69157f8e543ee76dc21f8410
s1 = 0xe6665792427b98ebd93cd43f694e03383c84af34b00e5f471c5cec5a24541808
z1 = 0xc3479c8d5591597a4b12018ccacd0215528e584aa18125d63fac5c0c0c92588b
r2= 0xd7232c0eed9a80a6e53d74b57d80cd892816b46c69157f8e543ee76dc21f8410
s2= 0xe6665792427b98ebd93cd43f694e03383c84af34b00e5f471c5cec5a24541808
z2= 0xc3479c8d5591597a4b12018ccacd0215528e584aa18125d63fac5c0c0c92588b

r1 = r2 , s1 = s2 , z1 = z2 .......Your 2 rsz are from the same rsz Cry

jacky19790729

jr. member

Activity: 82

Merit: 8

Quote from: COBRAS on June 25, 2024, 03:39:34 PM

Code:

# rsz 1
r=0xd7232c0eed9a80a6e53d74b57d80cd892816b46c69157f8e543ee76dc21f8410
s=0xe6665792427b98ebd93cd43f694e03383c84af34b00e5f471c5cec5a24541808
z=0xc3479c8d5591597a4b12018ccacd0215528e584aa18125d63fac5c0c0c92588b
# rsz 2
r=0xafc4670c63a5677641ba51b0eb413f7d8be3cfeb100f2c2097eb57dd673d58c2
s=0xe14e5906641085412561a083c002b76d6ac5a54372a9c811edc9e3b86b2dde11
z=0x1b636df9eef267995d6918047ba3bafca25f693a47ff73c7c0d500cd4aa9783a

You try bruteforce 02d7232c0eed9a80a6e53d74b57d80cd892816b46c69157f8e543ee76dc21f8410 ?

no....bruteforce nonce k , that is impossible

It's seem use 1 rsz convert to 2 rsz
even know that
k2 = k1 + 1
I still can't recovery private key

COBRAS

member

Activity: 873

Merit: 22

$$P2P BTC BRUTE.JOIN NOW ! https://uclck.me/SQPJk

Quote from: jacky19790729 on June 25, 2024, 02:00:33 PM

Quote from: JohnnyTX on June 25, 2024, 12:55:44 PM

Code:

# rsz 1
r=0xd7232c0eed9a80a6e53d74b57d80cd892816b46c69157f8e543ee76dc21f8410
s=0xe6665792427b98ebd93cd43f694e03383c84af34b00e5f471c5cec5a24541808
z=0xc3479c8d5591597a4b12018ccacd0215528e584aa18125d63fac5c0c0c92588b

# rsz 2
r=0xafc4670c63a5677641ba51b0eb413f7d8be3cfeb100f2c2097eb57dd673d58c2
s=0xe14e5906641085412561a083c002b76d6ac5a54372a9c811edc9e3b86b2dde11
z=0x1b636df9eef267995d6918047ba3bafca25f693a47ff73c7c0d500cd4aa9783a

With k2 = k1 + 1.

sorry......I can't recovery private key for this 2 rsz

my result:
k1 = 0
k2 = 1

Recovered Bitcoin public key: 028629507d9eef1748ec67ca2c4ab641fa0951d7f0bb0cf226f1c0f465a4e29404
Bitcoin Address： 1Ln1NYjtCamBG2UZDTKcHqcaNLP8TUrKFe

Recovered Bitcoin public key: 0395c632a7af384a67104afd5b6a4a5d882e782d232519c59084f0744d08093876
Bitcoin Address： 1P5TaCC8ZQohntb3NwRXQE5zFzB2De2Dvz

show your private key .. ??

You try bruteforce 02d7232c0eed9a80a6e53d74b57d80cd892816b46c69157f8e543ee76dc21f8410 ?

Topic: R,S,Z , K nonce and public key Signature samples (Read 1045 times)