simply you can't according algebra.
you have in math something like:
r1,s1,z1 of addres1 and r1,s2,z2 of addres2
and you have equation:
a*addres1 = b*addres2
so:
addres1 = b*addres2/a
addres2 = a*addres1/b
addres1-addres2 = b*addres2/a - a*addres1/b
after computional of this equation
in this example you have b*s1/a=a*s2/b -> is the same - when you make perdorm calc -> you have zero.
but there can be chance if and only if linear distance beetween addres 1 and adress 2 is less than 127 bit.
Topic: same-r-value-is-used-for-two-different-addresses - page 2. (Read 479 times)
hi all
i have 2 addresses that have same R value
address 1 same R
address 2 same R
i know R
i know S1 and S2
i know M signed message or Z M1 and M2
When a signing secret was used to sign two different messages, you can recover the signing secret with this calculation:
k = (m1-m2)/(s1-s2)
the problem is that i can recover only privatekey of 1 address
i have need of recover privatekey address 2
what is correct formula for recover the privatekey of address 1 and address 2 that have same R used in 2 different address?
thanks for your help
i have 2 addresses that have same R value
address 1 same R
address 2 same R
i know R
i know S1 and S2
i know M signed message or Z M1 and M2
When a signing secret was used to sign two different messages, you can recover the signing secret with this calculation:
k = (m1-m2)/(s1-s2)
the problem is that i can recover only privatekey of 1 address
i have need of recover privatekey address 2
what is correct formula for recover the privatekey of address 1 and address 2 that have same R used in 2 different address?
thanks for your help
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