chance = 90
basebet = balance*.0001
startbalance = balance
nextbet = 0
tartget = .01
bethigh = true
low = 0
high = 0
losecount = 0
stopnow = false
totallose = 0
wincount = 0
nextwinbet = basebet*1.5
boombet = balance*.1
bet1lose = previousbet*2
bet2lose = previousbet*5
bet3lose = previousbet*20
profitamount = 0
sessionprofit = 0
profittarget = 0.001
profitlimit = .005
won = 0
lost = 0
function dobet()
if (lastBet.roll < chance) then
low += 1
end
if (lastBet.roll > (100 - chance)) then
high += 100
end
profitamount=profitamount+currentprofit
if (win) then
if (high > low) then
bethigh = true
else
bethigh = false
end
won = won+1
lost = 0
if (profitamount >= profittarget) then
profitamount = 0
nextbet = basebet
end
if (sessionprofit >= profitlimit) then
print("Profit Limit reached. Stopping now...")z
print("Session Profit: " .. sessionprofit)
sessionprofit = 0
nextbet = basebet
end
if (won >= 1) then
nextbet = previousbet*2
won += 1
lost += 0
end
if (won == 2) then
nextbet = boombet
won += 1
lost += 0
end
if (won == 3) then
nextbet = boombet*1.5
won += 1
lost += 0
end
if (won <= 5) then
nextbet = boombet/3
won += 1
lost += 0
end
else
lost = lost+1
won = 0
if (lost == 1) then
nextbet = bet1lose
end
if (lost == 2) then
nextbet = bet2lose
end
if (lost == 3) then
nextbet = bet3lose
end
if (lost >= 4) then
chance = 49.5
nextbet = previousbet*2
end
if (lost >= 6) then
nextbet = basebet
end
end
end
at first i was just wanting to just mess around and see what works;
But now I want to turn it into 95 or 90 chance;
on first win do a massive bet almost full balance; then slowly decrease to a limit you set;
then i would like it to save some of that money aside for the next win for an even bigger second bet etc
on loss, i want it to do big multipler to almost regain all of whats lost, but the second bet should cover the last lost as the second win should be a big bet anyways, but if thats a loss I want a smaller multiplier till a win and on a win do a bigger than before to regain previous loss,
all based on basebet balance;
is something like that possible ?
chance=77.7
multiplier=1.5
multiplier2=1.09
base=0.0000250
nextbet = base
bethigh = false
target = .0005
investtarget = .01
tmpprofit = 0
investprofit = 0
wincount = 10
stopnow = false
function dobet()
tmpprofit += currentprofit
investprofit += currentprofit
if win then
print("We Won")
if (tmpprofit > target) then
tmpprofit = 0
nextbet = base
if(stopnow) then stop() end
if(investprofit > investtarget ) then
investprofit = 0
invest(investtarget)
end
else
print("Since we Won we are now times our last bet by multiplier 2")
nextbet=previousbet*multiplier2
if(nextbet < base) then
nextbet = base end
end
else
print("we lost so we are timzing by multiplier 1")
nextbet=previousbet*multiplier
if(nextbet < base) then
print("if next bet is less than base bet next bet = base bet")nextbet = base end
end
end
Something like this but 90 percent, but with a chance to win quicker this seems to take 2 - 3 wins to gain id like 1 - 2 if possible and since its based on balance, it shouldnt really need to worry about to many losses also being 90% in a row anyways
This would be the ultimate tho i think;
win 1
win 1.5
win 2.25
win 1.8
win 1.44
win 1.152
win 1 etc
for all wins
on a lose tho something like this
win 1
win 1.5
loss 2.25 < remebers this
wins 1
wins 1.5 + work out how to make loss even on second bet so it would be on 90% the pay out is 1.1 so we lost 2.25 we would need 22.5+ 1 to make it all back second bet i think
or is that way to risky even in the lower numbers like 0.0005 etc ?
and if it was to lose like this
win 1
lose 1.5
win 1.5 + 15
win 1
lose 1.5 <-- remeber 1
lose 16.5 < -- remember 2
then go back to normal
lose 1
lose 1
win 1
win 16.5
win 1
win 1.5
lose 2.25
win 2.25 + 165 from remember 2
then if it was to go like this
win 1
lose 1.5
win 16.5
lose 1
win 16.5
lose 1
win 16.5
win 1
win 1.5
doesnt have to be those calculations but I have a feeling it could work ?what do you guys think ?