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Topic: The Legend of Satoshi Nakamato, FINAL STEP PUBLISHED.... 4.87 BTC GRAND PRIZE! - page 30. (Read 108519 times)

jr. member
Activity: 62
Merit: 5

Update on this one, there appears to be another channel of info we've been ignoring (or not talking about publicly on this forum). Props to smracer for noticing it. If you view the "skinny/fat" inner flame as another channel of data, then there is an *almost* 16 digit match between the outer bottom height and it's skinnyness. Flame # 9 counting r 2 l along the outer bottom doesn't match with this otherwise perfect match. The interpretation of the skinnyness is a bit more subjective than the others but once you've spent some time deciding between them it becomes easier to call. This track contains the weird solid red flame most have been ignoring. See for yourself and let me know what you think. Perhaps we could compare our skinny/fat calls and start using this new channel of data for playing around with... Not quite as solid a lead as alphabetcannary's discovery but I think it's significant.

There might be one more channel of data not picked up on yet. I'll let you know once I've poked around with it a bit.

As you are saying it is subjective, but in my interpretation of skinnyness, there are two flames, namely #6 and #9, that don't match. Both flames are thin (skinny as you call it) and long, while the match for thin in outer bottom is short. Again, it is subjective. I think I found a mismatch or two of my interpretation of skinnyness with what zbyszek2 posted (he called it blob in his post), too
member
Activity: 105
Merit: 10
@kn0w0n3, @Cammy: great thanks for explaining in length!
jr. member
Activity: 51
Merit: 1

In the interest of keeping my post about more then just engaging this nonsense.., I wanted to visually be able to see what flames were responsible for that "iskeyfile" pattern.., so I worked through it by hand and color coded the bits.

Note: when I say Top/Top I am referring to the outside track of the top of the image, after it has been rotated 90 degrees cw (Portrait).

https://imgur.com/a/DGGOg

Could you please tell more on what to look for in the visualisation? I mean, the color codes, there are quite a lot of colors used in the file, could you please explain how to read the file?

Sure,

Starting at the top, the first row contains percentages for each track. This is the percentage of erroneous bits (Flames that did not contribute to making a word) Below that are the 6 tracks of flames that we are going to work with. Below that are the tracks of flames combined, below that are the same flames, but split into groups of 6. After that come the ribbon bits for xoring and below at the resultant bitstring. Finally, the last row (Right above the letters) is the decoded string. (After we've taken every 5th bit multiple times)

Then you have the letters decoded from the bacon cypher and below that some tables.


As far as what the colors mean. There are two kinds, and they mean different things.

Text Colors:

Each time I went through and counted every 5th bit (after xoring) I assigned it a color.

First run was green
Second run was light blue
Third run was purple
and finally the last run was Dark blue

If a bit (flame) did not contribute to making one of the words "the" or "iskeyfile" it was assigned a red color.

Now you can easily see what words were created from what flames, on which track. For instance, the word "the" was created from the first three and 1 flame from the fourth track. (Meaning maybe we just got the last two tracks out of order). "keyf" is made up of a bit from every single track. So either this is a very big coincidence (50 bits had to line up correctly for iskeyfile), or this is the actual translation. I find it very unlikely that this could be a collision (unless we are using completely the wrong cyphers and just got lucky) because otherwise we would have to find a different modulus that puts 27 bits into the same order as this in order to reproduce "keyf" and part of "s". If this is how you decypher this flames, idk how I feel about that, perhaps the six letters from crax0rs version are another cypher key and perhaps the reason for the odd word choice, is because they somehow knew that those words would still be able to arranged in the 1x1x0x1x1x0x pattern.

More likely though. This is probably not the actual message, but I do like the way they went about it.., because I have a feeling more then one cypher was used.

Background colors:

The background colors in the table are easy.

The table on the left is the inner flames, the table on the right is the outer flames. I have indexed the flames 0-151 (going cw for inner flames cw for outer flames).

Blue background color is even flames that are 1
Red background color is even flames that are 0
Dark red background (flame 119) is the flame after the weird tiny red flame
Gold background color (flame 13) is the flame I'm pretty sure she originally painted as a 1 and then changed to a 0.

I find it interesting that the flame it looks like she adjusted is an odd numbered flame and not part of alphabet canary's pattern.

Anyway, hopefully that's enough for you to make sense of it. I need to stop here though as I am late for work.



newbie
Activity: 2
Merit: 0

In the interest of keeping my post about more then just engaging this nonsense.., I wanted to visually be able to see what flames were responsible for that "iskeyfile" pattern.., so I worked through it by hand and color coded the bits.

Note: when I say Top/Top I am referring to the outside track of the top of the image, after it has been rotated 90 degrees cw (Portrait).

https://imgur.com/a/DGGOg

Could you please tell more on what to look for in the visualisation? I mean, the color codes, there are quite a lot of colors used in the file, could you please explain how to read the file?

I'm not the same guy, but I've been trying to figure this out too.

The long black binary string in the top center is the flame heights in the order described by RealOnTheMF.

He then gets rid of the first 0 on the string, and breaks it down into chunks of 6 binary digits (top row in each column above each letter). Each one of these chunks is XOR'd with 011010 (the heights on the ribbons), to get the value in the third row.

The next step is a little strange. He's getting every fifth digit along this row, looping back to the start each time it wraps the end. This is where the colours come in. It starts with green (100110011100100), then proceeds to red, etc. This goes along the whole row.

Ignoring the colours now, we break this new string into sets of 5, giving 10011, 001111, 00100, etc. These are the ones directly above each letter.

Finally, each of this is decoded using the Bacon v2 cipher, giving T, H, E, etc.
member
Activity: 105
Merit: 10

In the interest of keeping my post about more then just engaging this nonsense.., I wanted to visually be able to see what flames were responsible for that "iskeyfile" pattern.., so I worked through it by hand and color coded the bits.

Note: when I say Top/Top I am referring to the outside track of the top of the image, after it has been rotated 90 degrees cw (Portrait).

https://imgur.com/a/DGGOg

Could you please tell more on what to look for in the visualisation? I mean, the color codes, there are quite a lot of colors used in the file, could you please explain how to read the file?
jr. member
Activity: 33
Merit: 2
"The biggest Troll of Satoshi Nakamoto. The fucking Step"
Seems that those creators and coin-troll mom killed the rabbit!
The only one that I am following and missing in this forum is the rabbit.
No rabbit No solution.

You are just waiting around hoping that someone gives you the answer.

Exploring DNA/RNA codons is better then just whining for someone to give you the answer.

In the interest of keeping my post about more then just engaging this nonsense.., I wanted to visually be able to see what flames were responsible for that "iskeyfile" pattern.., so I worked through it by hand and color coded the bits.

Note: when I say Top/Top I am referring to the outside track of the top of the image, after it has been rotated 90 degrees cw (Portrait).

https://imgur.com/a/DGGOg

Don't feedo troll.
jr. member
Activity: 51
Merit: 1
"The biggest Troll of Satoshi Nakamoto. The fucking Step"
Seems that those creators and coin-troll mom killed the rabbit!
The only one that I am following and missing in this forum is the rabbit.
No rabbit No solution.

You are just waiting around hoping that someone gives you the answer.

Exploring DNA/RNA codons is better then just whining for someone to give you the answer.

In the interest of keeping my post about more then just engaging this nonsense.., I wanted to visually be able to see what flames were responsible for that "iskeyfile" pattern.., so I worked through it by hand and color coded the bits.

Note: when I say Top/Top I am referring to the outside track of the top of the image, after it has been rotated 90 degrees cw (Portrait).

https://imgur.com/a/DGGOg
hero member
Activity: 694
Merit: 500
"The biggest Troll of Satoshi Nakamoto. The fucking Step"
Seems that those creators and coin-troll mom killed the rabbit!
The only one that I am following and missing in this forum is the rabbit.
No rabbit No solution.
hero member
Activity: 694
Merit: 500
When read according to the drips clockwise, the very start of the decode you get the following word relevant to the painting:
*MPSRI*
Prism.

Can you please elaborate on this? I've been trying to explore decoding via this method over the past day or so, but I haven't had much luck. I also do not understand how DNA/RNA codons are supposed to be paired (I mean obviously in groups of three, but how are you proposing those groups of three be created?). I wrote some more, fairly badly executed, code that can decode the flames based on the amino acids (posted below) and I've tried reading the flames in all sorts of ways, But haven't found anything interesting..., So I'm curious by what you mean according to the drips?

You are asking a blind, he doesn't know.
I've asked more than 30 experts in cryptography, encrypted language, machine language...etc and still I don't have a clear answer how to interpret that fucking language.
member
Activity: 93
Merit: 10
This is too much for me, I tried to decipher it on my own and ended up being blown up.
hero member
Activity: 694
Merit: 500
Well. For now I'm throwing the towel in. I think the puzzle is interesting but there are obvious things that make it stand out as more frustrating than challenging. If it was straightforward, I am sure it would have been solved by now. There are many people showing promising ideas, but there is a lack of any notable progress.

The creator likely will not provide any assistance as it gives her more use unsolved than solved (advertising and it will be a hallmark if it remains unsolved as the MYSTERIOUS painting that baffled tons of people. When in reality, if a solution is published, it's probably riddled with inelegance and logical jumps that you'd have to be lucky in order to explore). Good luck everyone!



Hahaha finally you understand! .. seems you have read my previous posts as I've mentioned the same idea many times.. this puzzle is not difficult but it's made in such a way that it's impossible to solve.. one has to think in extremely unlogical crazy way and has crazy luck to get only one fraction of the solution.

Forgot about the idea that dna nucleotides are encrypted into the flames.
What's the relation between the DNA,RNA, CODONS and that fucking story of the turtle dove and phoenix!
newbie
Activity: 121
Merit: 0
newbie
Activity: 13
Merit: 0

Quote
ah I see, yes, makes more sense! So I guess we are looking for ATG as the starting point?

I'm going to play with this now though, thank you!

Depends. Did the author start the encoding the way real proteins would start? Any flame could be a reasonable start point depending how things were encoded.
jr. member
Activity: 51
Merit: 1
newbie
Activity: 41
Merit: 0
Well. For now I'm throwing the towel in. I think the puzzle is interesting but there are obvious things that make it stand out as more frustrating than challenging. If it was straightforward, I am sure it would have been solved by now. There are many people showing promising ideas, but there is a lack of any notable progress.

The creator likely will not provide any assistance as it gives her more use unsolved than solved (advertising and it will be a hallmark if it remains unsolved as the MYSTERIOUS painting that baffled tons of people. When in reality, if a solution is published, it's probably riddled with inelegance and logical jumps that you'd have to be lucky in order to explore). Good luck everyone!

jr. member
Activity: 51
Merit: 1
When read according to the drips clockwise, the very start of the decode you get the following word relevant to the painting:
*MPSRI*
Prism.

Can you please elaborate on this? I've been trying to explore decoding via this method over the past day or so, but I haven't had much luck. I also do not understand how DNA/RNA codons are supposed to be paired (I mean obviously in groups of three, but how are you proposing those groups of three be created?). I wrote some more, fairly badly executed, code that can decode the flames based on the amino acids (posted below) and I've tried reading the flames in all sorts of ways, But haven't found anything interesting..., So I'm curious by what you mean according to the drips?


For anyone who wants it.., although I'm sure you could do better, here is my shitty code. To use it for DNA/RNA decypher: ./debacon -f filename -D | less

The File must be a text file containing no more then 16 lines. Also, It doesn't recognize dna/rna codons via the letters atcg or aucg, but instead c is either b or p (depending if you wanna call the color purple or blue), a is o (for orange, maybe it's red, but I think the flames look orange), t or u is y (for yellow), and g is still g (for green)

Sample input for a track of flames: ypygygogyp

Code:
#include
#include
#include
#include

void shift(char* string);
int getlines(FILE* stream, char** line, ssize_t* nread, int* ntot, size_t len);
char* normalize(char* string, int nflag);
void clean(char* string);
void divideString(char* string, int n);
void debacon(char* string, int btype);
void flip(char* string);
void deHex(char* string);
void deRNA(char* string);
int verbose = 0;


int main(int argc, char* argv[]){
FILE* scram;
int opt;
int fcheck = 0;
int nflag = 0;
int btype = 0;
int bitflip = 0;
char** line = malloc(sizeof(char *) * 16);
int i = 0;
int j = 0;
int k = 0;
size_t len = 0;
ssize_t nread[16];
int ntot = 0;
char buffer[1024];
char temp[1024];
int runBacon = 0;
int runHex = 0;
int runDNA = 0;

while((opt = getopt(argc, argv, "hvf:a:n:i:HBD")) != -1){
switch(opt){
case 'h':
printf("\nUSAGE: ./decode -f path_to_input_file type_of_decode options\n");
printf("OPTIONS: -f [FILENAME] to specify input file\n");
printf("OPTIONS: -v for verbose mode\n");
printf("OPTIONS: -a [a or b] to specify which type of bacon alphebet (Bacon Cypher Only)\n");
printf("OPTIONS: -n [0 or 1 or 2 or 3] to specify how the bitstring should be read\n");
printf("OPTIONS: -i [t or f] to specify how 0's and 1's are read from the bitstring\n");
printf("OPTIONS: -B for Bacon Cypher\n");
printf("OPTIONS: -H for HEX conversion\n");
printf("OPTIONS: -D for DNA RNA Stop Codon Cypher\n");
printf("OPTIONS: -h displays this menu\n");
printf("\nEXAMPLE: ./decode -f file -B -a b -n 2 -i f -v\n");
exit(EXIT_SUCCESS);
case 'f':
scram = fopen(optarg, "r");
fcheck = 1;
break;
case 'v':
printf("\nTurning on Verbose Mode...\n");
verbose = 1;
break;
case 'a':
if(optarg[0] == 'a' || optarg[0] == 'A'){
btype = 0;
} else if(optarg[0] == 'b' || optarg[0] == 'B'){
btype = 1;
} else{
printf("\nERROR: Invalid argument for for -a option, must be a or b\n");
exit(EXIT_FAILURE);
}
break;
case 'n':
if(atoi(optarg) < 4){
nflag = atoi(optarg);
} else{
printf("\nERROR: Invalid argument for -n option, must be 0, 1, 2, or 3\n");
}
break;
case 'i':
if(optarg[0] == 't' || optarg[0] == 'T'){
bitflip = 1;
}
break;
case 'B':
if(runHex == 1){
printf("\nERROR: Cannot run Bacon Cypher and Hex conversion together\n");
exit(EXIT_FAILURE);
} else if(runDNA == 1){
printf("\nERROR: Cannot run Bacon Cypher and DNA RNA conversion together\n");
exit(EXIT_FAILURE);
} else{
runBacon = 1;
}
break;
case 'H':
if(runBacon == 1){
printf("\nERROR: Cannot run Bacon Cypher and Hex conversion together\n");
exit(EXIT_FAILURE);
} else if(runDNA== 1){
printf("\nERROR: Cannot run DNA RNA Cypher and Hex conversion together\n");
exit(EXIT_FAILURE);
} else{
runHex = 1;
}
break;
case 'D':
if(runHex == 1){
printf("\nERROR: Cannot run Hex conversion and DNA RNA Cypher together\n");
exit(EXIT_FAILURE);
} else if(runBacon == 1){
printf("\nERROR: Cannot run Bacon Cypher and DNA RNA Cypher together\n");
exit(EXIT_FAILURE);
} else{
runDNA = 1;
}
break;
default:
printf("ERROR: Unrecognized option, try -h\n");
exit(EXIT_FAILURE);
}
}

if(fcheck == 0){
printf("ERROR: Must specify input file, try -h\n");
exit(EXIT_FAILURE);
} else if(argc <=3){
printf("ERROR: Must specify -H, -B, or -D.., try -h for help\n");
}

i = getlines(scram, line, nread, &ntot, len);

if(verbose == 1){
for(j = 0; j < i; j++){
printf("Retrieved line of length %zu:\n", nread[j]);
printf("line %i is: %s\n", j, line[j]);
}
printf("Total Characters Read: %i\n\n", ntot);
j = 0;
}

if(runDNA == 1){
for(j = 0; j < i; j++){
line[j] = normalize(line[j], 8);
}
j = 1;
strcpy(buffer, line[0]);
for(j = 1; j < i; j++){
strcat(buffer, line[j]);
}

if(verbose == 1){
printf("\nCombined String: %s\n", buffer);
}

for(k = 0; k <= strlen(buffer); k++){
divideString(buffer, 3);
if(verbose == 1){
printf("\nString split into 3's for decoding:\n");
printf("%s\n", buffer);
printf("\nDNA RNA Cypher Decode\n");
}
deRNA(buffer);
shift(buffer);
}
for(j = 0; j <= i; j++){
free(line[j]);
}
fclose(scram);
return 0;
}

for(j = 0; j < i; j++){
        if(verbose == 1){
                printf("Normalizeing line %i\n", j);
                }
                if(bitflip == 1){
                flip(line[j]);
                }
                line[j] = normalize(line[j], nflag);
                if(verbose == 1){
                printf("Line %i is now: %s\n", j, line[j]);
                }
}
       
        j = 1;
        strcpy(buffer, line[0]);
        for(j = 1; j < i; j++){
        strcat(buffer, line[j]);
        }
       
        if(verbose == 1){
        printf("\nCombined String: %s\n", buffer);
        }


if(runBacon == 1){
for(k = 0; k <= strlen(buffer); k++){
divideString(buffer, 5);
if(verbose == 1){
printf("\nString split into 5's for decoding:\n");
printf("%s\n", buffer);

printf("\nDebaconing:\n");
}
debacon(buffer, btype);

shift(buffer);
}
}

if(runHex == 1){
for(k = 0; k <= strlen(buffer); k++){
if(strlen(buffer)%4 != 0){
switch(strlen(buffer)%4){
case 1:
temp[0] = '0';
temp[1] = '0';
temp[2] = '0';
temp[3] = '\0';
strcat(temp, buffer);
break;
case 2:
temp[0] = '0';
temp[1] = '0';
temp[2] = '\0';
strcat(temp, buffer);
break;
case 3:
temp[0] = '0';
temp[1] = '\0';
strcat(temp, buffer);
break;
default:
printf("Something bad happened...\n");
break;
}
} else{
strcpy(temp, buffer);
}
divideString(temp, 4);
if(verbose == 1){
printf("\nString split into 4's\n");
printf("%s\n", temp);
printf("\nConverting to Hex:\n");
}
deHex(temp);
clean(temp);
shift(buffer);

}
}
j = 0;
for(j = 0; j <= i; j++){
free(line[j]);
}
free(line);
fclose(scram);
return 0;
}

void flip(char *string){
char *i;
for(i=string; *i; i++){
if(*i == '1'){
*i = '0';
} else if(*i == '0'){
*i = '1';
}
}
}

void deRNA(char *string){
char buffer[4];
int i = 0;

while(string[i] != '\0'){
buffer[0] = string[i];
i++;
buffer[1] = string[i];
i++;
buffer[2] = string[i];
buffer[3] = '\0';
i+=2;

if(strcmp(buffer, "yyy") == 0 || strcmp(buffer, "YYY") == 0 || strcmp(buffer, "ttt") == 0 || strcmp(buffer, "TTT") == 0 || strcmp(buffer, "uuu") == 0 || strcmp(buffer, "UUU") == 0){
printf("F");
} if(strcmp(buffer, "yyp") == 0 || strcmp(buffer, "YYP") == 0 || strcmp(buffer, "yyb") == 0 || strcmp(buffer, "YYB") == 0){
printf("F");
} if(strcmp(buffer, "yyo") == 0 || strcmp(buffer, "YYO") == 0){
printf("L");
} if(strcmp(buffer, "yyg") == 0 || strcmp(buffer, "YYG") == 0){
printf("L");
} if(strcmp(buffer, "pyy") == 0 || strcmp(buffer, "PYY") == 0 || strcmp(buffer, "byy") == 0 || strcmp(buffer, "BYY") == 0){
printf("L");
} if(strcmp(buffer, "pyp") == 0 || strcmp(buffer, "PYP") == 0 || strcmp(buffer, "byb") == 0 || strcmp(buffer, "BYB") == 0){
printf("L");
} if(strcmp(buffer, "pyo") == 0 || strcmp(buffer, "PYO") == 0 || strcmp(buffer, "byr") == 0 || strcmp(buffer, "BYR") == 0){
printf("L");
} if(strcmp(buffer, "pyg") == 0 || strcmp(buffer, "PYG") == 0 || strcmp(buffer, "pyg") == 0 || strcmp(buffer, "PYG") == 0){
printf("L");
} if(strcmp(buffer, "oyy") == 0 || strcmp(buffer, "OYY") == 0){
printf("I");
} if(strcmp(buffer, "oyp") == 0 || strcmp(buffer, "OYP") == 0 || strcmp(buffer, "ryb") == 0 || strcmp(buffer, "RYB") == 0){
printf("I");
} if(strcmp(buffer, "oyo") == 0 || strcmp(buffer, "OYO") == 0){
printf("I");
} if(strcmp(buffer, "oyg") == 0 || strcmp(buffer, "OYG") == 0){
printf(" - M - ");
} if(strcmp(buffer, "gyy") == 0 || strcmp(buffer, "GYY") == 0){
printf("V");
} if(strcmp(buffer, "gyp") == 0 || strcmp(buffer, "GYP") == 0 || strcmp(buffer, "gyb") == 0 || strcmp(buffer, "GYB") == 0){
printf("V");
} if(strcmp(buffer, "gyo") == 0 || strcmp(buffer, "GYO") == 0){
printf("V");
} if(strcmp(buffer, "gyg") == 0 || strcmp(buffer, "GYG") == 0){
printf("V");
} if(strcmp(buffer, "ypy") == 0 || strcmp(buffer, "YPY") == 0 || strcmp(buffer, "yby") == 0 || strcmp(buffer, "YBY") == 0){
printf("S");
} if(strcmp(buffer, "ypp") == 0 || strcmp(buffer, "YPP") == 0 || strcmp(buffer, "ybb") == 0 || strcmp(buffer, "YBB") == 0){
printf("S");
} if(strcmp(buffer, "ypo") == 0 || strcmp(buffer, "YPO") == 0 || strcmp(buffer, "ybr") == 0 || strcmp(buffer, "YBR") == 0){
printf("S");
} if(strcmp(buffer, "ypg") == 0 || strcmp(buffer, "YPG") == 0 || strcmp(buffer, "ybg") == 0 || strcmp(buffer, "YBG") == 0){
printf("S");
} if(strcmp(buffer, "ppy") == 0 || strcmp(buffer, "PPY") == 0 || strcmp(buffer, "bby") == 0 || strcmp(buffer, "BBY") == 0){
printf("P");
} if(strcmp(buffer, "ppp") == 0 || strcmp(buffer, "PPP") == 0 || strcmp(buffer, "bbb") == 0 || strcmp(buffer, "BBB") == 0){
printf("P");
} if(strcmp(buffer, "ppo") == 0 || strcmp(buffer, "PPO") == 0 || strcmp(buffer, "bbr") == 0 || strcmp(buffer, "BBR") == 0){
printf("P");
} if(strcmp(buffer, "ppg") == 0 || strcmp(buffer, "PPG") == 0 || strcmp(buffer, "bbg") == 0 || strcmp(buffer, "BBG") == 0){
printf("P");
} if(strcmp(buffer, "opy") == 0 || strcmp(buffer, "OPY") == 0 || strcmp(buffer, "rby") == 0 || strcmp(buffer, "RBY") == 0){
printf("T");
} if(strcmp(buffer, "opp") == 0 || strcmp(buffer, "OPP") == 0 || strcmp(buffer, "rbb") == 0 || strcmp(buffer, "RBB") == 0){
printf("T");
} if(strcmp(buffer, "opo") == 0 || strcmp(buffer, "OOO") == 0 || strcmp(buffer, "rbr") == 0 || strcmp(buffer, "RBR") == 0){
printf("T");
} if(strcmp(buffer, "opg") == 0 || strcmp(buffer, "OPG") == 0 || strcmp(buffer, "rbg") == 0 || strcmp(buffer, "RBG") == 0){
printf("T");
} if(strcmp(buffer, "gpy") == 0 || strcmp(buffer, "GPY") == 0 || strcmp(buffer, "gby") == 0 || strcmp(buffer, "GBY") == 0){
printf("A");
} if(strcmp(buffer, "gpp") == 0 || strcmp(buffer, "GPP") == 0 || strcmp(buffer, "gbb") == 0 || strcmp(buffer, "GBB") == 0){
printf("A");
} if(strcmp(buffer, "gpo") == 0 || strcmp(buffer, "GPO") == 0 || strcmp(buffer, "gbr") == 0 || strcmp(buffer, "GBR") == 0){
printf("A");
} if(strcmp(buffer, "gpg") == 0 || strcmp(buffer, "GPG") == 0 || strcmp(buffer, "gbg") == 0 || strcmp(buffer, "GBG") == 0){
printf("A");
} if(strcmp(buffer, "yoy") == 0 || strcmp(buffer, "YOY") == 0){
printf("Y");
} if(strcmp(buffer, "yop") == 0 || strcmp(buffer, "YOP") == 0 || strcmp(buffer, "yrb") == 0 || strcmp(buffer, "YRB") == 0){
printf("Y");
} if(strcmp(buffer, "yoo") == 0 || strcmp(buffer, "YOO") == 0){
printf(" STOP ");
} if(strcmp(buffer, "yog") == 0 || strcmp(buffer, "YOG") == 0){
printf(" STOP ");
} if(strcmp(buffer, "poy") == 0 || strcmp(buffer, "POY") == 0 || strcmp(buffer, "bry") == 0 || strcmp(buffer, "BRY") == 0){
printf("H");
} if(strcmp(buffer, "pop") == 0 || strcmp(buffer, "POP") == 0 || strcmp(buffer, "brb") == 0 || strcmp(buffer, "BRB") == 0){
printf("H");
} if(strcmp(buffer, "poo") == 0 || strcmp(buffer, "POO") == 0 || strcmp(buffer, "brr") == 0 || strcmp(buffer, "BRR") == 0){
printf("Q");
} if(strcmp(buffer, "pog") == 0 || strcmp(buffer, "POG") == 0 || strcmp(buffer, "brg") == 0 || strcmp(buffer, "BRG") == 0){
printf("Q");
} if(strcmp(buffer, "ooy") == 0 || strcmp(buffer, "OOY") == 0){
printf("N");
} if(strcmp(buffer, "oop") == 0 || strcmp(buffer, "OOP") == 0 || strcmp(buffer, "rrb") == 0 || strcmp(buffer, "RRB") == 0){
printf("N");
} if(strcmp(buffer, "ooo") == 0 || strcmp(buffer, "OOO") == 0){
printf("K");
} if(strcmp(buffer, "oog") == 0 || strcmp(buffer, "OOG") == 0){
printf("K");
} if(strcmp(buffer, "goy") == 0 || strcmp(buffer, "GOY") == 0){
printf("D");
} if(strcmp(buffer, "gop") == 0 || strcmp(buffer, "GOP") == 0 || strcmp(buffer, "grb") == 0 || strcmp(buffer, "GRB") == 0){
printf("D");
} if(strcmp(buffer, "goo") == 0 || strcmp(buffer, "GOO") == 0){
printf("E");
} if(strcmp(buffer, "gog") == 0 || strcmp(buffer, "GOG") == 0){
printf("E");
} if(strcmp(buffer, "ygy") == 0 || strcmp(buffer, "YGY") == 0){
printf("C");
} if(strcmp(buffer, "ygp") == 0 || strcmp(buffer, "YGP") == 0 || strcmp(buffer, "ygb") == 0 || strcmp(buffer, "YGB") == 0){
printf("C");
} if(strcmp(buffer, "ygo") == 0 || strcmp(buffer, "YGO") == 0){
printf(" STOP ");
} if(strcmp(buffer, "ygg") == 0 || strcmp(buffer, "YGG") == 0){
printf("W");
} if(strcmp(buffer, "pgy") == 0 || strcmp(buffer, "PGY") == 0 || strcmp(buffer, "bgy") == 0 || strcmp(buffer, "BGY") == 0){
printf("R");
} if(strcmp(buffer, "pgp") == 0 || strcmp(buffer, "PGP") == 0 || strcmp(buffer, "bgb") == 0 || strcmp(buffer, "BGB") == 0){
printf("R");
} if(strcmp(buffer, "pgo") == 0 || strcmp(buffer, "PGO") == 0 || strcmp(buffer, "bgr") == 0 || strcmp(buffer, "BGR") == 0){
printf("R");
} if(strcmp(buffer, "pgg") == 0 || strcmp(buffer, "PGG") == 0 || strcmp(buffer, "bgg") == 0 || strcmp(buffer, "BGG") == 0){
printf("R");
} if(strcmp(buffer, "ogy") == 0 || strcmp(buffer, "OGY") == 0){
printf("S");
} if(strcmp(buffer, "ogp") == 0 || strcmp(buffer, "OGP") == 0 || strcmp(buffer, "rgb") == 0 || strcmp(buffer, "RGB") == 0){
printf("S");
} if(strcmp(buffer, "ogo") == 0 || strcmp(buffer, "OGO") == 0){
printf("R");
} if(strcmp(buffer, "ogg") == 0 || strcmp(buffer, "OGG") == 0){
printf("R");
} if(strcmp(buffer, "ggy") == 0 || strcmp(buffer, "GGY") == 0){
printf("G");
} if(strcmp(buffer, "ggp") == 0 || strcmp(buffer, "GGP") == 0 || strcmp(buffer, "ggb") == 0 || strcmp(buffer, "GGB") == 0){
printf("G");
} if(strcmp(buffer, "ggo") == 0 || strcmp(buffer, "GGO") == 0){
printf("G");
} if(strcmp(buffer, "ggg") == 0 || strcmp(buffer, "GGG") == 0){
printf("G");
} else{
printf(" ");
}
}
printf("\n");
}

void deHex(char *string){
char buffer[5];
int i = 0;

while(string[i] != '\0'){
buffer[0] = string[i];
i++;
buffer[1] = string[i];
i++;
buffer[2] = string[i];
i++;
buffer[3] = string[i];
buffer[4] = '\0';
i+=2;

if(strcmp(buffer, "0000") == 0){
printf("0");
} else if(strcmp(buffer, "0001") == 0){
printf("1");
} else if(strcmp(buffer, "0010") == 0){
printf("2");
} else if(strcmp(buffer, "0011") == 0){
printf("3");
} else if(strcmp(buffer, "0100") == 0){
printf("4");
} else if(strcmp(buffer, "0101") == 0){
printf("5");
} else if(strcmp(buffer, "0110") == 0){
printf("6");
} else if(strcmp(buffer, "0111") == 0){
printf("7");
} else if(strcmp(buffer, "1000") == 0){
printf("8");
} else if(strcmp(buffer, "1001") == 0){
printf("9");
} else if(strcmp(buffer, "1010") == 0){
printf("A");
} else if(strcmp(buffer, "1011") == 0){
printf("B");
} else if(strcmp(buffer, "1100") == 0){
printf("C");
} else if(strcmp(buffer, "1101") == 0){
;printf("D");
} else if(strcmp(buffer, "1110") == 0){
printf("E");
} else if(strcmp(buffer, "1111") == 0){
printf("F");
} else{
printf(" ");
}
}
printf("\n");
}

void debacon(char *string, int btype){
char buffer[6];
int i = 0;

while(string[i] != '\0'){

buffer[0] = string[i];
i++;
buffer[1] = string[i];
i++;
buffer[2] = string[i];
i++;
buffer[3] = string[i];
i++;
buffer[4] = string[i];
buffer[5] = '\0';
i+=2;

if(btype == 0){
if(strcmp(buffer, "00000") == 0){
printf("A");
} else if(strcmp(buffer, "00001") == 0){
printf("B");
} else if(strcmp(buffer, "00010") == 0){
printf("C");
} else if(strcmp(buffer, "00011") == 0){
printf("D");
} else if(strcmp(buffer, "00100") == 0){
printf("E");
} else if(strcmp(buffer, "00101") == 0){
printf("F");
} else if(strcmp(buffer, "00110") == 0){
printf("G");
} else if(strcmp(buffer, "00111") == 0){
printf("H");
} else if(strcmp(buffer, "01000") == 0){
printf("J");
} else if(strcmp(buffer, "01001") == 0){
printf("K");
} else if(strcmp(buffer, "01010") == 0){
printf("L");
} else if(strcmp(buffer, "01011") == 0){
printf("M");
} else if(strcmp(buffer, "01100") == 0){
printf("N");
} else if(strcmp(buffer, "01101") == 0){
printf("O");
} else if(strcmp(buffer, "01110") == 0){
printf("P");
} else if(strcmp(buffer, "01111") == 0){
printf("Q");
} else if(strcmp(buffer, "10000") == 0){
printf("R");
; } else if(strcmp(buffer, "10001") == 0){
printf("S");
} else if(strcmp(buffer, "10010") == 0){
printf("T");
} else if(strcmp(buffer, "10011") == 0){
printf("V");
} else if(strcmp(buffer, "10100") == 0){
printf("W");
} else if(strcmp(buffer, "10101") == 0){
printf("X");
} else if(strcmp(buffer, "10110") == 0){
printf("Y");
} else if(strcmp(buffer, "10111") == 0){
printf("Z");
} else{
printf(" ");
}
}
if(btype == 1){
if(strcmp(buffer, "00000") == 0){
printf("A");
} else if(strcmp(buffer, "00001") == 0){
printf("B");
} else if(strcmp(buffer, "00010") == 0){
printf("C");
} else if(strcmp(buffer, "00011") == 0){
printf("D");
} else if(strcmp(buffer, "00100") == 0){
printf("E");
} else if(strcmp(buffer, "00101") == 0){
printf("F");
} else if(strcmp(buffer, "00110") == 0){
printf("G");
} else if(strcmp(buffer, "00111") == 0){
printf("H");
} else if(strcmp(buffer, "01000") == 0){
printf("I");
} else if(strcmp(buffer, "01001") == 0){
printf("J");
} else if(strcmp(buffer, "01010") == 0){
printf("K");
} else if(strcmp(buffer, "01011") == 0){
printf("L");
} else if(strcmp(buffer, "01100") == 0){
printf("M");
} else if(strcmp(buffer, "01101") == 0){
printf("N");
} else if(strcmp(buffer, "01110") == 0){
printf("O");
} else if(strcmp(buffer, "01111") == 0){
printf("P");
} else if(strcmp(buffer, "10000") == 0){
printf("Q");
} else if(strcmp(buffer, "10001") == 0){
printf("R");
} else if(strcmp(buffer, "10010") == 0){
printf("S");
} else if(strcmp(buffer, "10011") == 0){
printf("T");
} else if(strcmp(buffer, "10100") == 0){
printf("U");
} else if(strcmp(buffer, "10101") == 0){
printf("V");
} else if(strcmp(buffer, "10110") == 0){
printf("W");
} else if(strcmp(buffer, "10111") == 0){
printf("X");
} else if(strcmp(buffer, "11000") == 0){
printf("Y");
} else if(strcmp(buffer, "11001") == 0){
printf("Z");
} else{
printf(" ");
}
}
}
printf("\n");
}

void divideString(char *string, int n){
int size = strlen(string);
int i = 1;
int j = 1;
char buffer[1024];

strcpy(buffer,string);
string[0] = buffer[0];

for(i = 1; j < size; i++){
if(j%n == 0){
string[i] = ' ';
i++;
}
string[i] = buffer[j];
j++;
}
string[i] = '\0';
}

char* normalize(char* string, int nflag){
char *i;
switch(nflag){
case 0:
for(i=string; *i; i++){
if(*i == 'y' || *i == 'Y'){
*i = '1';
} else if(*i == 'o' || *i == 'O'){
*i = '0';
} else if(*i == 'g' || *i == 'G'){
*i = '1';
} else if(*i == 'p' || *i == 'P' || *i == 'b' || *i == 'B'){
*i = '0';
} else if(*i == '\n'){
*i = '\0';
}
}
return string;
case 1:
for(i=string; *i; i++){
if(*i == 'y' || *i == 'Y'){
*i = '0';
} else if(*i == 'o' || *i == 'O'){
*i == '1';
} else if(*i == 'g' || *i == 'G'){
*i = '1';
} else if(*i == 'p' || *i == 'P' || *i == 'b' || *i == 'B'){
*i = '0';
} else if(*i == '\n'){
*i == '\0';
}
}
return string;
case 2:
for(i=string; *i; i++){
if(*i == 'y' || *i == 'Y'){
*i = '1';
} else if(*i == 'o' || *i == 'O'){
*i = '0';
} else if(*i == 'g' || *i == 'G'){
*i == '0';
} else if(*i == 'p' || *i == 'P' || *i == 'b' || *i == 'B'){
*i == '1';
} else if(*i == '\n'){
*i = '\0';
}
}
return string;
case 3:
for(i=string; *i; i++){
if(*i == 'y' || *i == 'Y'){
*i = '0';
} else if(*i == 'o' || *i == 'O'){
*i = '1';
} else if(*i == 'g' || *i == 'G'){
*i = '0';
} else if(*i == 'p' || *i == 'P' || *i == 'b' || *i == 'B'){
*i = '1';
} else if(*i == '\n'){
*i = '\0';
}
}
return string;
; case 8:
for(i=string; *i; i++){
if(*i == '\n'){
*i = '\0';
}
}
return string;
default:
printf("\nERROR: Could not normalize stirng\n");
return string;
}
}

int getlines(FILE* stream, char** line, ssize_t* nread, int* ntot, size_t len){
int i = 0;
for(i = 0; i < 16; i++){
nread[i] = getline(&line[i], &len, stream);
if(nread[i] == -1){
break;
}
*ntot += nread[i];
}

return i;
}

void clean(char* string){
char *nospace = string;
char *temp = string;

        if(verbose == 1){
        printf("\nRemoving Spaces\n");
}
while(*temp != 0){
*nospace = *temp++;
if(*nospace != ' '){
nospace++;
}
}
*nospace = 0;
}

void shift(char* string){
char *nospace = string;
char *temp = string;
char buffer[1024];

char t;
int i = 0;
int size;

if(verbose == 1){
printf("\nRemoving Spaces\n");
}
while(*temp != 0){
*nospace = *temp++;
if(*nospace != ' '){
nospace++;
}
}
*nospace = 0;
if(verbose == 1){
printf("\n%s\n", string);
printf("\nShifting String\n");
}
strcpy(buffer, string);
if(verbose == 1){
printf("Buffer: \n%s\n\n", buffer);
}
t = string[0];
size = strlen(string);
for(i = 0; i < (size-1); i++){
string[i] = buffer[i+1];
}
string[i] = t;
string[i+1] = '\0';
if(verbose == 1){
printf("%s\n", string);
}
}
member
Activity: 350
Merit: 10
Serious question for those new to crypto wallets (me)... How to I check a guess to the solution? How can I know if my private key resolves to the 1FLAMEN6 address? If it did, how would one use that key?

You can import the private key into something like blockchain.info then send the 5.001337 btc to a wallet you control.

So in blockchain.info for example, you can click login to wallet, you put in 1FLAMEN6rq2BqMnkUmsJBqCGWdwgVKcegd as the wallet? and the private key is the password?
There's a separate board to get this level of help: Beginners & Help
When I first started entering the crypto market and this forum I also often go to the section that you mentioned to learn some issues that I did not know. This forum is really a great place for crypto enthusiasts to have a playground to exchange and learn from each other and grow together. I secretly thank Mr. Satoshi for making this bitcoin and great forum.
member
Activity: 226
Merit: 10
Serious question for those new to crypto wallets (me)... How to I check a guess to the solution? How can I know if my private key resolves to the 1FLAMEN6 address? If it did, how would one use that key?

You can import the private key into something like blockchain.info then send the 5.001337 btc to a wallet you control.

So in blockchain.info for example, you can click login to wallet, you put in 1FLAMEN6rq2BqMnkUmsJBqCGWdwgVKcegd as the wallet? and the private key is the password?
There's a separate board to get this level of help: Beginners & Help
jr. member
Activity: 33
Merit: 2
for one thing it seems unlikely they would have mined minikeys for a vanity address...is there even vanity software that comes stock with that functionality?

Well, just because there is no off-the-shelf software to do something, doesn't mean its not doable:

Code:
SUPER1FLAMEN6QPEGRLTFZXDEAFFAL -> 1FLANSqJppAGxWdCrUW2VsrncH1NfWtNXo
SUPER1FLAMEN6JQWSXAAHLJQJDEZXR -> 1FLArjwv7oPTZGUuGxLhEtPh7pkfoSbRTX
SUPER1FLAMEN6RHJSDXWSCEFMSBMWX -> 1FLA4LzZtRuaV914mEJHaWmBGdaMt2AmRG

These are all valid mini-private keys that I vanitized in 2 minutes, on GPU it would be much faster...

They are:
  • 30 chars long
  • follow base58 charset
  • follow code128b charset


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