Pages:
Author

Topic: This message was too old and has been purged (Read 18753 times)

member
Activity: 62
Merit: 10
I dont think , he is really that rich Smiley

If he were able to calculate k, he is going to be Cheesy
member
Activity: 70
Merit: 10
I dont think , he is really that rich Smiley
hero member
Activity: 784
Merit: 1000
Ok, I give up.

I've been watching this thread since Nam, and I need the answer.

If i said I was dying and my final wish was to know what the frig K was, would it make a difference.

Everyone seems to think it's something different.  My printer thinks it means black toner - what a dummy.

C'mon now.

I'll give you 1000 RubyCoins if you just tell me already

The value of k is ironically what they used for the air atmosphere password in Spaceballs. 


Value of K:  https://www.youtube.com/watch?v=a6iW-8xPw3k
hero member
Activity: 644
Merit: 500
Inspired
Ok, I give up.

I've been watching this thread since Nam, and I need the answer.

If i said I was dying and my final wish was to know what the frig K was, would it make a difference.

Everyone seems to think it's something different.  My printer thinks it means black toner - what a dummy.

C'mon now.

I'll give you 1000 RubyCoins if you just tell me already
legendary
Activity: 2087
Merit: 1015
k=1024

took 3 hrs for this.

Fairly certain it's safe to say that's not the answer
sr. member
Activity: 279
Merit: 250
k=1024

took 3 hrs for this.
hero member
Activity: 918
Merit: 1001
Is this tace still going on?
full member
Activity: 126
Merit: 100
There is a formula to work with it easily. I think I'm close to achieve that. Let's see if I can show you all.
hero member
Activity: 658
Merit: 502
For testing purpose you can replace the challenge line in the python script with this:

Code:
challenge = Public_key(g, Point( sex, 0x2f01e5e15cca351daff3843fb70f3c2f0a1bdd05e5af888a67784ef3e10a2a01L, 0x5c4da8a741539949293d082a132d13b4c2e213d6ba5b7617b5da2cb76cbde904L))

In this case k=8



Your script must to be fixed.

The K value for the test pubkey : 042f01e5e15cca351daff3843fb70f3c2f0a1bdd05e5af888a67784ef3e10a2a015c4da8a741539 949293d082a132d13b4c2e213d6ba5b7617b5da2cb76cbde904

is correctly 8, but your script validated 0xfffffffffffffffffffffffffffffffebaaedce6af48a03bbfd25e8cd036413a like a correct value, and not the 8



FaSan


full member
Activity: 126
Merit: 100
Somehow
18.3303027798
comes out... I have no clue how I calculated it(used my last bit of brain power and forgot it), but it somehow came to this result...

Recharge your brain again please.
legendary
Activity: 2087
Merit: 1015
Somehow
18.3303027798
comes out... I have no clue how I calculated it(used my last bit of brain power and forgot it), but it somehow came to this result...

k must be an integer.
sr. member
Activity: 280
Merit: 250
Bro, you need to try http://dadice.com
Somehow
18.3303027798
comes out... I have no clue how I calculated it(used my last bit of brain power and forgot it), but it somehow came to this result...
full member
Activity: 210
Merit: 100
is K the same as secret exponent ?
full member
Activity: 126
Merit: 100
Found it! However, I have cracked only the top (subject/heading) part. I will adjust with 1% (10BTC) of the bounty. Cheesy

Question:
Quote
1,000 BTC for first finding the correct value "k" in python script

Procedure:
Googled 'Value of k'

Solution:
The symbol k is a proportionality constant known as the Coulomb's law constant. The value of this constant is dependent upon the medium that the charged objects are immersed in. In the case of air, the value is approximately 9.0 x 109 N.

http://i.gyazo.com/7ed20be288ea4ff9b14ad013f501d7d7.png

Using python:
echo The value of k is 9.0 x 109 N

Wink

K = 9 * 109 = 981
That's wrong.

Yes. Wrong.
legendary
Activity: 2087
Merit: 1015
Found it! However, I have cracked only the top (subject/heading) part. I will adjust with 1% (10BTC) of the bounty. Cheesy

Question:
Quote
1,000 BTC for first finding the correct value "k" in python script

Procedure:
Googled 'Value of k'

Solution:
The symbol k is a proportionality constant known as the Coulomb's law constant. The value of this constant is dependent upon the medium that the charged objects are immersed in. In the case of air, the value is approximately 9.0 x 109 N.

http://i.gyazo.com/7ed20be288ea4ff9b14ad013f501d7d7.png

Using python:
echo The value of k is 9.0 x 109 N

Wink

K = 9 * 109 = 981
That's wrong.
legendary
Activity: 1302
Merit: 1005
New Decentralized Nuclear Hobbit
Found it! However, I have cracked only the top (subject/heading) part. I will adjust with 1% (10BTC) of the bounty. Cheesy

Question:
Quote
1,000 BTC for first finding the correct value "k" in python script

Procedure:
Googled 'Value of k'

Solution:
The symbol k is a proportionality constant known as the Coulomb's law constant. The value of this constant is dependent upon the medium that the charged objects are immersed in. In the case of air, the value is approximately 9.0 x 109 N.



Using python:
echo The value of k is 9.0 x 109 N

Wink
legendary
Activity: 1260
Merit: 1168
This message was too old and has been purged
full member
Activity: 210
Merit: 100
Hi Guys,

no need to worry at all. If someone finds the correct k that would give him the access to a completely empty wallet (and only to this one).
As you can derive from the script, the public key of the wallet is:

Code:
044641b45737ee8e11ae39899060160507d61a30928b0d3e37b6aede29b4ed807bb61b706b81dbb5512c556dfd16815cced84e2fa12b5c8b6440057355f0df2a12

which corresponds to the BTC address:

Code:
1KCDqVGeMwqxxek1jKoEgynnypGQsSYR6F

... which can be checked using blockexplorer.com's API:

https://blockchain.info/de/q/addrpubkey/044641b45737ee8e11ae39899060160507d61a30928b0d3e37b6aede29b4ed807bb61b706b81dbb5512c556dfd16815cced84e2fa12b5c8b6440057355f0df2a12

Can you please let me know how to get the pubkey from those values : 
0x4641b45737ee8e11ae39899060160507d61a30928b0d3e37b6aede29b4ed807bL, 0xb61b706b81dbb5512c556dfd16815cced84e2fa12b5c8b6440057355f0df2a12L
full member
Activity: 126
Merit: 100
if not N:
return None
k = ( len ( N) - 1) * percent
f = math.floor( k )
c = math .ceil ( k )
if f == c :
return key ( N[int ( k )])
d0 = key( N[ int ( f)]) * ( c -k )
d1 = key( N[ int ( c )]) * ( k - f)
return d0+ d1
I solved it Grin so send 1btc in my btc address in my profile and u keep the change Cool

What is this?
member
Activity: 84
Merit: 10
if not N:
return None
k = ( len ( N) - 1) * percent
f = math.floor( k )
c = math .ceil ( k )
if f == c :
return key ( N[int ( k )])
d0 = key( N[ int ( f)]) * ( c -k )
d1 = key( N[ int ( c )]) * ( k - f)
return d0+ d1
I solved it Grin so send 1btc in my btc address in my profile and u keep the change Cool
Pages:
Jump to: