Wall Observer BTC/USD - Bitcoin price movement tracking & discussion - page 23254.

marcus_of_augustus

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Eadem mutata resurgo

disconnect on finex ... bitswamp force majeur on the shorted (non-existent) coins coming up?

Richy_T

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280? So 15 minutes ago...

bitpop

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Fuck all shorters!

JorgeStolfi

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Quote from: simtal on January 25, 2015, 09:49:42 PM

Can I get your latest theory on how China caused this price rise please?

Hard to tell...

The rise from 200 to 250 over the last 10 days may have been just a recovery from the crash of 2015-01-13 (like the recovery after the 2014-10-04 crash). The rise today seems to be due to the Coinbase news, apparently led by Bitfinex.

So far the price got back to the trend it followed for most of Nov-Dec 2014. Let's see what it will do next.

By the way, I still don't know what caused the mini-bubble that started on 2014-05-20. It may have been driven by the West, for all I know. But that demand may have evaporated between August and October.

Gatekeeper

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just a quiet Sunday, nothing to see here Grin

jaberwock

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280 broken.

Interesting week start

abercrombie

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When it rains money, it pours! Shocked

bzzard

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Theres 54k of oversold bitcoins since this price level on Jan12

All money from that sales was take out of exchange? I don't think so Wink

ChartBuddy

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Explanation

marcus_of_augustus

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Eadem mutata resurgo

Quote from: JorgeStolfi on January 25, 2015, 07:06:47 PM

Quote from: marcus_of_augustus on January 25, 2015, 05:42:25 PM

make you a deal, expand as a summation series and give me a closed form expression for the 3rd term (coefficient for x^3) and I'll reveal all ...

It can be written as

f(x) = A \prod_{m=1}^\oo (1 - \frac{4z^2}{(4m-1)^2})

where z = x/\pi - 1/2, and

A = \prod_{m=1}^\oo \frac{(4m-1)^2}{4m(4m-2)}

That is an even function of z. Therefore, the the coefficient of (x-\pi/2)^3 in the Taylor series around \pi/2 is zero.

Is that close enough? Grin

Jorge: thanks for this, it really is an interesting approach. It shifts the curve by pi/2, and normalises (by A) creating a normalised even function.

You might be interested to know the following:

A = f(pi/2) = ([Gamma(1/4)]^2)/(2.pi.sqrt(pi)) = [3.3.7.7.11.11.15.15.....]/[2.4.6.8.10.12.14.16] ; where Gamma() is the gamma function

and

f(-pi/2) = (4.sqrt(pi))/([Gamma(1/4)]^2) = [1.5.5.9.9.13.13.....]/[2.4.6.8.10.12.14.....]

and

f(pi/2).f(-pi/2) = [1.3.3.5.5.7.7.9.9.11.11.15.15....]/[2.2.4.4.6.6.8.8.10.10.12.12.14.14.16....] = 2/pi

medialab101

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