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Topic: Wall Observer BTC/USD - Bitcoin price movement tracking & discussion - page 28027. (Read 26712678 times)

legendary
Activity: 3766
Merit: 5146
Note the unconventional cAPITALIZATION!



Green lines even when price is declining, I like that!



Escher charting.  And I think the initial spike is supposed to have a little bit of time warping gangsta lean.
sr. member
Activity: 266
Merit: 250
Next up is a small rise on low volume until we hit 7am european time and we get another massive dump...
full member
Activity: 167
Merit: 100
I do not know what the price will be but the log brownian model does NOT say that (I am just repeating myself here) ...

Look at a call closed formula price, N(d2) represents the probability of the call being in the money, if you put S=K (our example here) you are left with N(something negative) which means that the probability that the price ends up above current value is ... less than 50% !
And below current value is ... more than 50%.

I don't understand your notation, here is mine

Basically, in the log-Brownian model the difference between successive values of Z(i) = log(P(i)) are independent random variables with probability distributions that are symmetric about zero.  Therefore after any number n of steps the probability distribution of Z(i+n) will be symmstric about the starting value Z(i).  That means Z(i+n) wil be less than Z(i) with 50% probability.  Since log is monotonic, it preserves cumulative probabilities, therefore P(i+n) will be less than P(i) with 50% probability.  What is wrong with this argument?  

(Strictly speaking, "Brownian" requires a normal distribution of increments with zero mean and fixed variance.  In practice the variance varies slowly and the distributions have fatter tails than the norma; but by the law of large numbers they become near-normal for large n.)




My notation is the standard financial notation as found under wikipedia black-scholes article (S=spot price, K=strike ...). So now you have my notation please take a look at my argument again.

To come back to yours, I think the error is in the first sentence : "the difference between successive values of Z(i) = log(P(i)) are independent random variables with probability distributions that are symmetric about zero"
Small proof: under log brownian (with no drift)  the important basic concept is that the best expectation of price in the future is the current value of the price. Your hypothesis does not respect that.
For instance let's say Pi=exp(1) so Z(i)=1, now we simulate a 1 step tree with 50% chance of going up 0.1 and 50% chance of going down 0.1 to simplify (doesnt change the result), and we compute Expectation[P(i+1)] which should be equal to exp(1). Well, Expectation[P(i+1)]=0.5*exp(1.1)+0.5*exp(0.9) which is not exp(1).

Also you can ask any bank quant, under simple log brownian mode, an at the money binary option (pays 1 if stock is above, 0 below) its theoretical price is strictly less than 0.5, which is exactly the probability of ending above current value, which is also exactly the value of the N(d2) I mentioned in my post before.
hero member
Activity: 798
Merit: 1000



Green lines even when price is declining, I like that!

legendary
Activity: 1470
Merit: 1007


Quality TA. AAA+++. Would post again in risto's thread.
sr. member
Activity: 266
Merit: 250
I am getting more and more the feeling that we are getting played by the Chinese.
hero member
Activity: 728
Merit: 500


I scrolled up but couldn't see where your second candle ends. Try to log your graph? Or do you need to log-star it?

I put it in log scale and it still bounded at the same point on the upside.
legendary
Activity: 947
Merit: 1008
central banking = outdated protocol
sr. member
Activity: 263
Merit: 250


I scrolled up but couldn't see where your second candle ends. Try to log your graph? Or do you need to log-star it?
hero member
Activity: 728
Merit: 500
legendary
Activity: 3766
Merit: 5146
Note the unconventional cAPITALIZATION!
We will stabalize @ 447-502 for a shot time (hours) before dropping quickly to ~ 408 where serious resistance will be met.

Is this a fact?

Not yet.  It is an opinion based on analysis.  

So far it's close to on target.  After an attempt at consolidation here we see a second sharp downturn.  This is a good spot to log some puts..

I tend to agree although I dont expect a full retracement, tops 485. short target 420 short term.


I think you may be more accurate here.  Perhaps in part this is true because the market is starting to desensitize to the china trick a bit.
sr. member
Activity: 308
Merit: 250
hero member
Activity: 644
Merit: 500
One Token to Move Anything Anywhere
hero member
Activity: 644
Merit: 500
One Token to Move Anything Anywhere
hero member
Activity: 728
Merit: 540
Our pictures are diverse and multi-faceted, thank you very much!  Grin




Awesome !
hero member
Activity: 728
Merit: 500
legendary
Activity: 1470
Merit: 1007
Look at that guys...  3 green hourly candles in a row...  Time to unironically start posting those rockets huh Cheesy

don't look at the volume though that'll only ruin the fun
hero member
Activity: 968
Merit: 624
Still a manic miner
8 green bars on stamp/15m..
another bulltrap?

btw, was it a fart that propelled the bull in that picture??? Roll Eyes
hero member
Activity: 798
Merit: 1000
apparently not only the sunlot is trying to propose a plan to resurrect Gox, but Okcoin too.

Got a source to the OKcoin story?



Im sure there will be something more official but just IRC atm, apparently Okcoin were creditors as well so have a vested interest, appartenly the Sunlot people were trying to make a deal with Mark to buy the company before it all broke but it sounds like a very shady deal from the Mark and Sunlot perspective.

OKCoin certainly makes sense with the China ban situation.
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