What is the maximum number of loosing streak possible in dice with 20%/5x win? - page 2.

hosseinimr93

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Quote from: onuarnob on January 07, 2023, 03:55:20 PM

Do you think 60 loss or more is possible with 5x profit set? I am not planing to get rich. I am planning to get 5$ a day maybe.

Yes, It is. As I already said in my previous post, everything is possible.

With 5x multiplier, the chance of winning a single bet would be around 20%. (Due to the house edge, the chance of winning a single bet would be a bit smaller than 20%).
The chance of losing 60 times in a row would be around 0.00015%.
With this low probability, you may think that it's almost impossible to have 60 consecutive losses. If so, you should note that with playing more games, the chance of having 60 consecutive losses would increase exponentially. Assuming you need to win 1 million bets to reach your goal, the chance of not having 60 consecutive losses would be only 21%.

I know what you are trying to do. Be sure that you will finally lose all your balance.

DoublerHunter

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Quote from: hosseinimr93 on January 07, 2023, 03:38:40 PM

There is no maximum number and any number of consecutive losses is possible. Take note that every time you wager, you play a new game which is independent from previous games and everything is possible.
If you are looking for a method to get rich, that's not possible. House will defeat you in the long run.

^You pointed it out.
If gambling works like this calculation, I think everyone knows how to calculate your odds in gambling which make you rich in that way.
I think gambling is there are no specific numbers that you must follow especially when it comes to dice 95% is based on luck and the rest would be your calculation. You cannot defeat the house edge and that is the fact in gambling that is based on luck and fighting against the house edge. It should be for fun and not for making money.

Lanatsa

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Quote from: onuarnob on January 07, 2023, 03:55:20 PM

Quote from: hosseinimr93 on January 07, 2023, 03:38:40 PM

There is no maximum number and any number of consecutive losses is possible. Take note that every time you wager, you play a new game which is independent from previous games and everything is possible.
If you are looking for a method to get rich, that's not possible. House will defeat you in the long run.

Do you think 60 loss or more is possible with 5x profit set? I am not planing to get rich. I am planning to get 5$ a day maybe.

Really hard to tell considering in all the experience i do have in dice then it is something would give you those lose streaks that you havent encountered before. Lets just put up some example about using martingale

considering that it is really just 2x with <50% chance due to HE but it did still give out that highest so for of 20-26 consecutive loss and that would be depending on your bankroll size.
If you do make out some just plain bet without using some strategies then it could be calculated mathematically but just like on the rest been saying that
no one can point out on how long it would be.

pixie85

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Quote from: hosseinimr93 on January 07, 2023, 03:38:40 PM

There is no maximum number and any number of losses in a row is possible. Take note that every time you wager, you play a new game which is independent from previous games and everything is possible.
If you are looking for a method to get rich, that's not possible. House will defeat you in the long run.

Unfortunately, that's it.

At 50% if it was just math your probability of rolling a win in dice should go up with every loss and after a few thousand rolls you should be at around 50% of wins. That's not the case with online dice though because you're not physically throwing it like in a real casino but you're running the same algorithm along 100 users or more at the same time.

The algo is going to be at 50% win but one of you can be getting more wins than the other. It's possible someone who plays at the same time is getting 5 wins and you're getting 5 losses in a row and the total stats of the game remain at 50%.

Probably every single person who plays dice had a streak of 10 or more losses in a row at 49% even though in a real game of dice you'd have to try very hard to achieve that.

onuarnob

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Quote from: hosseinimr93 on January 07, 2023, 03:38:40 PM

There is no maximum number and any number of consecutive losses is possible. Take note that every time you wager, you play a new game which is independent from previous games and everything is possible.
If you are looking for a method to get rich, that's not possible. House will defeat you in the long run.

Do you think 60 loss or more is possible with 5x profit set? I am not planing to get rich. I am planning to get 5$ a day maybe.

hosseinimr93

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Activity: 2380

Merit: 5213

There is no maximum number and any number of consecutive losses is possible. Take note that every time you wager, you play a new game which is independent from previous games and everything is possible.
If you are looking for a method to get rich, that's not possible. House will defeat you in the long run.

Hispo

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Leading Crypto Sports Betting & Casino Platform

If I recall correctly, it would be 2 wins for every 8 loses or 1 win every 4 losses.
But statistically, it can vary according to your luck, OP.

I would recommend you to read a bit about basic statistics or law of probabilities. It is useful to understand how much you are risking and helps you to adjust your risk threshold to a level you feel comfortable with.

onuarnob

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I need to know maximum possible streak number without hitting 5x once?

Topic: What is the maximum number of loosing streak possible in dice with 20%/5x win? - page 2. (Read 241 times)