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Topic: [ANN] [VASH] VpnCoin | AES Chat | BitChain | Domain&Website | Zero Knowledge - page 56. (Read 501968 times)

member
Activity: 80
Merit: 10
Thank you this looks very clear. It is good to have explanation of both cases in one place.

The closest one bet wins or must be direct hit?
legendary
Activity: 1619
Merit: 1004
Bitcoiner, Crypto-anarchist and Cypherpunk.
I hope you will not kill me.

You are telling that "HASH's last N byte" 369 = 392

I don't know how to convert 369 to 392. How do I do that step by step?
Or could you tell me which converter use? http://codebeautify.org/hex-decimal-converter

Maybe you are all here programmers and are able to count in all numeral systems in head but I need to have it in decimal to compare and see how close I was with my bet.

You don't need to be a programmer to understand this really.

I'm going to use this lottery as an example :

Code:
Creator: Vq9EBcb43uEfFDJYbcRDL4fk8V9mB6mkT8
Lottery address: Vw5x5cALxo3ngf2hRWjjLFN7Kr9LGSvNqf
Creator Bet: 300000VPN
Minimum Bet: 50VPN
Type: Guess a future block's hash(last N byte)
Difficulty: 3 characters
Creator bet number: "1bf"
Start block: 329060, Target block: 332063
Bet block range: 329061~332060 (3000)
Transaction id: 8b78c25ff400c2c10678a255c72317535a7298913b1afa8842f476d9c10aa046
Create time: 2015-05-29 09:43:08
Total Bonus: 300457.00000000VPN

Winner is: Vq9EBcb43uEfFDJYbcRDL4fk8V9mB6mkT8(Creator)
Bet amount: 300000.00000000VPN
Winning number: "a77"
Private key: WXys7315tNDYrYJ6jpFYDKSnzJ4ruvpQXQySoV1Y7d3rDfXFrNaX

You have two type of lottery ( the example type was "Guess a block's HASH, Last N Byte" :

1. Guess a block's HASH, last N byte :

In this example, the difficulty was 3. So people have to guess the 3 last byte of the target block that was the 332063 blocks.

If you look at the 332063 block's hash, you can see that the last 3 byte of the block's hash are a77 :
Code:
getblockhash 332063

a14a68332e3565f97b89702b90930fc413a90f4ad4d6d49514a2ece99872ca77

So if your bet number wasn't a77, you loose and get your money back ( i'm not sure for the money back, but i think it's happen only if nobody win ).


2. Guess a block's HASH, last N byte's digit value :

In the previous example, i'm going to use the same block and the same difficulty. So in this type of lottery you have to guess the last N byte's digit value of a block, so with a difficulty of 3, you need to find the digit value of the last 3 bytes to win.

If you look at the 332063 block's hash, you can see that the last 3 byte of the block's hash are a77. So the digit value of the last 3 bytes are :
10 + 7 + 7 = 24


Understood ?
member
Activity: 80
Merit: 10
I hope you will not kill me.

You are telling that "HASH's last N byte" 369 = 392

I don't know how to convert 369 to 392. How do I do that step by step?
Or could you tell me which converter use? http://codebeautify.org/hex-decimal-converter

Maybe you are all here programmers and are able to count in all numeral systems in head but I need to have it in decimal to compare and see how close I was with my bet.
hero member
Activity: 518
Merit: 500
Is there any statistics on actual vpn usage? Like the last month?

Android dial app is testing...



Nice, always good to see new developments.
hero member
Activity: 980
Merit: 1010
Blockchain engineer
More like 392. Just watch and see.

+1

It is Hex string, just wait...
hero member
Activity: 840
Merit: 1000
Ok. The last lottery and your bet is calculated this way?

369 = 873 decimal   
Is this right?

Thank you for your work!

No Sad

The last lottery is guess block's HASH's last N byte, it is hex string, not digit value.
Hex includes "0 ~ F".

Good we are almost there.

Now when I know it is not digit value type. How do I calculate result of "369" in this case?

369 is my guess,
You need bet your text,
The answer in the future, is unknown.

More like 392. Just watch and see.
hero member
Activity: 980
Merit: 1010
Blockchain engineer
Ok. The last lottery and your bet is calculated this way?

369 = 873 decimal   
Is this right?

Thank you for your work!

No Sad

The last lottery is guess block's HASH's last N byte, it is hex string, not digit value.
Hex includes "0 ~ F".

Good we are almost there.

Now when I know it is not digit value type. How do I calculate result of "369" in this case?

369 is my guess,
You need bet your text,
The answer in the future, is unknown.
member
Activity: 80
Merit: 10
Ok. The last lottery and your bet is calculated this way?

369 = 873 decimal   
Is this right?

Thank you for your work!

No Sad

The last lottery is guess block's HASH's last N byte, it is hex string, not digit value.
Hex includes "0 ~ F".

Good we are almost there.

Now when I know it is not digit value type. How do I calculate result of "369" in this case?
legendary
Activity: 1619
Merit: 1004
Bitcoiner, Crypto-anarchist and Cypherpunk.
hero member
Activity: 980
Merit: 1010
Blockchain engineer
Is there any statistics on actual vpn usage? Like the last month?

Android dial app is testing...

hero member
Activity: 980
Merit: 1010
Blockchain engineer
hero member
Activity: 840
Merit: 1000
Is there any statistics on actual vpn usage? Like the last month?
hero member
Activity: 980
Merit: 1010
Blockchain engineer
Ok. The last lottery and your bet is calculated this way?

369 = 873 decimal  
Is this right?

Thank you for your work!

369=18 I think the way he's doing decimal representation of hex values. It is confusing and the only reason I can think of to do this is to make it a 2 digit guess. FFF=45 000=00

Bet 50 on every value possible. I would but I'm far to lazy. Smiley

"369" is Hex string, the last lottery is guess block HASH's last N bytes HEX string, not digit value.
hero member
Activity: 980
Merit: 1010
Blockchain engineer
Ok. The last lottery and your bet is calculated this way?

369 = 873 decimal   
Is this right?

Thank you for your work!

No Sad

The last lottery is guess block's HASH's last N byte, it is hex string, not digit value.
Hex includes "0 ~ F".
legendary
Activity: 3836
Merit: 4969
Doomed to see the future and unable to prevent it
Ok. The last lottery and your bet is calculated this way?

369 = 873 decimal  
Is this right?

Thank you for your work!

369=18 I think the way he's doing decimal representation of hex values. It is confusing and the only reason I can think of to do this is to make it a 2 digit guess. FFF=45 000=00

Bet 50 on every value possible. I would but I'm far to lazy. Smiley
member
Activity: 80
Merit: 10
Ok. The last lottery and your bet is calculated this way?

369 = 873 decimal   
Is this right?

Thank you for your work!
hero member
Activity: 980
Merit: 1010
Blockchain engineer
My bet was 80d and I still not get exactly how should I convert these numbers to see right result. Could you please make clear example?

1) me - 80d (how far was I from win?)
2) you - 1bf
3) win - a77 (where can I see this number?)
4) difference in calculation between "(last N byte)" and "(last N byte)'s digit value"

You are doing great work however everything you do is cloaked in mystery. And many simple questions are around --> this will make usage impossible for some people.

Use getblockhash cmd to get target block's HASH:
Code:
getblockhash 328399

741f52332ad5362556c165cd270fff4c860eb5e04f032b6f10ff5a18766cc461

If you set last N byte's "N" = 3, the right number is "461",
If you bet digit value, the right number is 11, why?
Bcz that: 4 + 6 + 1 = 11


Thank you. In my last example - the reason why I didn't win was that my bet amount was too low?

a77 = 2679 decimal (winning)
80d = 2061 decimal (me)
1bf = 447 decimal (you)


I use a single character's digit value, and them add.

This is what you mean?

(last N byte):
 a77 = 10+7+7 = 24

(last N byte)'s digit value:
 a77 = 2679

Are these both examples correct?

Our Lottery have 2 guess type.
1, Guess a block's HASH, last N byte.
getblockhash 328399

741f52332ad5362556c165cd270fff4c860eb5e04f032b6f10ff5a18766cc461

If we set difficulty = 3, then the right answer is 461.

2, Guess a block's HASH, last N byte's digit value.
getblockhash 328399

741f52332ad5362556c165cd270fff4c860eb5e04f032b6f10ff5a18766cc461

If we set difficulty = 4, then the right answer is "12 + 4 + 6 + 1 = 23", hex "c"'s digit value = 12


I still don't understand - you explained the last bet here: https://bitcointalksearch.org/topic/m.11498167
and you told me that I should calculate it as 4 + 6 + 1 = 11 ---> but the bet was not N byte's digit value (guess type 2)

Based on your last example I should see it as a HEX number 461.

Maybe I'm still missing something important.

My English is not good, sorry Sad
member
Activity: 80
Merit: 10
My bet was 80d and I still not get exactly how should I convert these numbers to see right result. Could you please make clear example?

1) me - 80d (how far was I from win?)
2) you - 1bf
3) win - a77 (where can I see this number?)
4) difference in calculation between "(last N byte)" and "(last N byte)'s digit value"

You are doing great work however everything you do is cloaked in mystery. And many simple questions are around --> this will make usage impossible for some people.

Use getblockhash cmd to get target block's HASH:
Code:
getblockhash 328399

741f52332ad5362556c165cd270fff4c860eb5e04f032b6f10ff5a18766cc461

If you set last N byte's "N" = 3, the right number is "461",
If you bet digit value, the right number is 11, why?
Bcz that: 4 + 6 + 1 = 11


Thank you. In my last example - the reason why I didn't win was that my bet amount was too low?

a77 = 2679 decimal (winning)
80d = 2061 decimal (me)
1bf = 447 decimal (you)


I use a single character's digit value, and them add.

This is what you mean?

(last N byte):
 a77 = 10+7+7 = 24

(last N byte)'s digit value:
 a77 = 2679

Are these both examples correct?

Our Lottery have 2 guess type.
1, Guess a block's HASH, last N byte.
getblockhash 328399

741f52332ad5362556c165cd270fff4c860eb5e04f032b6f10ff5a18766cc461

If we set difficulty = 3, then the right answer is 461.

2, Guess a block's HASH, last N byte's digit value.
getblockhash 328399

741f52332ad5362556c165cd270fff4c860eb5e04f032b6f10ff5a18766cc461

If we set difficulty = 4, then the right answer is "12 + 4 + 6 + 1 = 23", hex "c"'s digit value = 12


I still don't understand - you explained the last bet here: https://bitcointalksearch.org/topic/m.11498167
and you told me that I should calculate it as 4 + 6 + 1 = 11 ---> but the bet was not N byte's digit value (guess type 2)

Based on your last example I should see it as a HEX number 461.

Maybe I'm still missing something important.
hero member
Activity: 980
Merit: 1010
Blockchain engineer
My bet was 80d and I still not get exactly how should I convert these numbers to see right result. Could you please make clear example?

1) me - 80d (how far was I from win?)
2) you - 1bf
3) win - a77 (where can I see this number?)
4) difference in calculation between "(last N byte)" and "(last N byte)'s digit value"

You are doing great work however everything you do is cloaked in mystery. And many simple questions are around --> this will make usage impossible for some people.

Use getblockhash cmd to get target block's HASH:
Code:
getblockhash 328399

741f52332ad5362556c165cd270fff4c860eb5e04f032b6f10ff5a18766cc461

If you set last N byte's "N" = 3, the right number is "461",
If you bet digit value, the right number is 11, why?
Bcz that: 4 + 6 + 1 = 11


Thank you. In my last example - the reason why I didn't win was that my bet amount was too low?

a77 = 2679 decimal (winning)
80d = 2061 decimal (me)
1bf = 447 decimal (you)


I use a single character's digit value, and them add.

This is what you mean?

(last N byte):
 a77 = 10+7+7 = 24

(last N byte)'s digit value:
 a77 = 2679

Are these both examples correct?

Our Lottery have 2 guess type.
1, Guess a block's HASH, last N byte.
getblockhash 328399

741f52332ad5362556c165cd270fff4c860eb5e04f032b6f10ff5a18766cc461

If we set difficulty = 3, then the right answer is 461.

2, Guess a block's HASH, last N byte's digit value.
getblockhash 328399

741f52332ad5362556c165cd270fff4c860eb5e04f032b6f10ff5a18766cc461

If we set difficulty = 4, then the right answer is "12 + 4 + 6 + 1 = 23", hex "c"'s digit value = 12
hero member
Activity: 980
Merit: 1010
Blockchain engineer
VPNcoin can now be use on the NXT network ! The asset is own by the user yiiy on the nxtforum, proof here.

Name: vpn2nxt (vpncoin)
Asset ID:  1989622569661755686
Issuing Account: NXT-WSHC-U9Z4-BKN6-543CS
Total Assets: 40,000,000
兑换流程:
VPN-->NXT:发送vpncoin到以下地址: VaaRtgxAcdRAsDpCPdSCDiYnGaVBrjvfk4,并附加留言注明接收vpn2nxt资产的NXT钱包地址(不能使用交易平台地址,必须是自己钱包地址)。收到vpncoin后,会将同等数量的vpn2nxt资产发送到相应的nxt地址。(充值限额:1-500万)
NXT-->VPN:购买vpn2nxt资产后,将资产发送到资产的发行账号NXT-WSHC-U9Z4-BKN6-543CS,并留言注明接收vpncoin的钱包地址。收到资产后,会将同等数量的vpncoin发送到相应的vpncoin地址。

Cash flow:
VPN-->NXT.
Send vpncoin to the following address: VaaRtgxAcdRAsDpCPdSCDiYnGaVBrjvfk4, and additional message marked NXT wallet address to receiving vpn2nxt assets(Only wallet address.Trading platform address can't be use.). After receiving vpncoin, I will send an equal number of vpn2nxt assets to the corresponding NXT address. (recharge limit: 1-5,000,000)
NXT-->VPN.
Buy vpn2nxt assets, then send assets to Issuing Account:NXT-WSHC-U9Z4-BKN6-543CS, and additional message marked receiving Vpncoin wallet address. After receiving assets, I will send the same amount of vpncoin to the corresponding vpncoin address.

Vpncoinwww.bitnet.wang
vpn2cny, https://yuanbaohui.com/trade/vpn2cny
--------vpn2nxt QQqun 319439561------

Nice work,
Thank you very much.
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