Hii devs and leaders,
i wanted to know what you 3 or 4 are going to pay for this trip to new york ?
Please make an exact list to see how much money everyone of you pay for this trip.
Jil and Spark chip in 0.35 BTC and 10.000 KDC
I invest 2500 KDC and 4 days off work (which cost me ~100 euro's a day = € 400,-)
The 3 of us invest
BTC 1 in total (without the 400 euro for my days off work).
Don't stare blindly to what we put in in money. We have and are investing huge amounts of time to make this work for you guys.
I am unable to put in more at this time. Not sure how Spark and Jilixi look at this.
I have ask the developers to support us with BTC too, since it's "their coin".
Please do not see this as a holiday trip, it isnt.
thanks for your reply
I'll try not to be offensive
i dont see this as a holiday trip. But really if i would fly to new york than i would pay at least 500-1000 Euro of my own money to go there.
I will calculate now generously:
"I invest 2500 KDC and 4 days off work (which cost me ~100 euro's a day = € 400,-)"
you invested 2500 kdc, 2500 x 0.00005200 BTC = 0.13019500 BTC !
0.13019500 BTC x 600 Dollars = 78.12 USD..
you say you earn 100 Euro per day and you only invest 78.12 USD ?
"Jil and Spark chip in 0.35 BTC and 10.000 KDC"
10000 kdc x 0.00005200 BTC = 0.52078000 BTC
0.35 BTC + 0.52078000 BTC = 0,87078 BTC = 522.47 USD
so that is a total of ~ 1 BTC
1 BTC for 3 persons that is nothing !!
that is 200 Dollar per person. Im sorry but i think you as you are flying there have to pay at least 3 times more.
I ask not to fund everything by yourself, i know this is not a holiday but its an experience to go to new york.
I would also like to fly to new yorks convention, meet important people in the cryptoworld and pay only 80 dollar and my time for it.
you say you need at least 5 btc more to go there but without promotion. Why should you go there when you can´t promote KDC there. If its not enough money then only 2 of you should go, or only 1.
i dont want to hurt someone that's just my opinion
Sry for my bad english.