And also, this is my 100th post on the forum!
Topic: Bitcoin Cipher/puzzle - 0.56 Prize ! Bitcoins [SOLVED] - page 5. (Read 19387 times)
I tried that too. Still no luck.
And also, this is my 100th post on the forum!
And also, this is my 100th post on the forum!
Well then now I have:
5Juu2CkB3EAhBpEcyH9dypNhPetergh6RQwwbo5ueBa6------E
I bruteforced all keys associated with this pattern. This is not correct. I suspect the Peter needs to be changed to something else.
5Juu2CkB3EAhBpEcyH9dypNhPetergh6RQwwbo5ueBa6------E
I bruteforced all keys associated with this pattern. This is not correct. I suspect the Peter needs to be changed to something else.
Change it to "DZ8fX"
Changed it to DZ8fX and no luck.
Well. only this is confirmed:
5Juu2CkB3-----EcyH9dypNhDZ8fXgh6RQwwbo5------------
I've tried almost all permutaions of 5Juu2CkB3 [EAhBp / NAhBp] EcyH9dypNhDZ8fXgh6RQwwbo5 [ueBa6 / pdBa6 / sdBa6]. No luck.
Well then now I have:
5Juu2CkB3EAhBpEcyH9dypNhPetergh6RQwwbo5ueBa6------E
I bruteforced all keys associated with this pattern. This is not correct. I suspect the Peter needs to be changed to something else.
5Juu2CkB3EAhBpEcyH9dypNhPetergh6RQwwbo5ueBa6------E
I bruteforced all keys associated with this pattern. This is not correct. I suspect the Peter needs to be changed to something else.
Change it to "DZ8fX"
Changed it to DZ8fX and no luck.
Well. only this is confirmed:
5Juu2CkB3-----EcyH9dypNhDZ8fXgh6RQwwbo5------------
Well then now I have:
5Juu2CkB3EAhBpEcyH9dypNhPetergh6RQwwbo5ueBa6------E
I bruteforced all keys associated with this pattern. This is not correct. I suspect the Peter needs to be changed to something else.
5Juu2CkB3EAhBpEcyH9dypNhPetergh6RQwwbo5ueBa6------E
I bruteforced all keys associated with this pattern. This is not correct. I suspect the Peter needs to be changed to something else.
Change it to "DZ8fX"
Changed it to DZ8fX and no luck.
i'll keep this short, i've made a cipher, anyone who can crack it will receive 0.56 Bitcoins. Depending on how long it will take you i might increase the reward over time (timer 30 Days, after that i'll decide what to do)
here it is !
Proof of funds; https://blockchain.info/address/1CQQ9menL2fZGdEseDsdC278rQ12Ai9XfG
(timer 30 Days, after that i'll decide what to do)here it is !
Proof of funds; https://blockchain.info/address/1CQQ9menL2fZGdEseDsdC278rQ12Ai9XfG
Someone has already won?
No, the prize is still in that address.
i'll keep this short, i've made a cipher, anyone who can crack it will receive 0.56 Bitcoins. Depending on how long it will take you i might increase the reward over time (timer 30 Days, after that i'll decide what to do)
here it is !
Proof of funds; https://blockchain.info/address/1CQQ9menL2fZGdEseDsdC278rQ12Ai9XfG
(timer 30 Days, after that i'll decide what to do)here it is !
Proof of funds; https://blockchain.info/address/1CQQ9menL2fZGdEseDsdC278rQ12Ai9XfG
Someone has already won?
Well then now I have:
5Juu2CkB3EAhBpEcyH9dypNhPetergh6RQwwbo5ueBa6------E
I bruteforced all keys associated with this pattern. This is not correct. I suspect the Peter needs to be changed to something else.
5Juu2CkB3EAhBpEcyH9dypNhPetergh6RQwwbo5ueBa6------E
I bruteforced all keys associated with this pattern. This is not correct. I suspect the Peter needs to be changed to something else.
Change it to "DZ8fX"
Well then now I have:
5Juu2CkB3EAhBpEcyH9dypNhPetergh6RQwwbo5ueBa6------E
I bruteforced all keys associated with this pattern. This is not correct. I suspect the Peter needs to be changed to something else.
5Juu2CkB3EAhBpEcyH9dypNhPetergh6RQwwbo5ueBa6------E
I bruteforced all keys associated with this pattern. This is not correct. I suspect the Peter needs to be changed to something else.
Honestly, coding that is a bit beyond my ability which was why I did it the way I did. I'm pretty sure my brain would explode before I had a working version of what you suggested.
It's really not as difficult as you might think. There are tools and libraries that already do most of the work.
Even if it was above your current abilities, there's still no good reason to include 4 characters in your iterations that aren't valid characters. You've made your result set at least 4000 X bigger than it needs to be.
I ran this overnight. I woke up to a 350+ gb unmanageable text doc and the script was still running. If someone gets one more letter, I can run it and it will be easier. Here is the code I used"
from itertools import product
import itertools
import sys
sys.stdout = open('c:/combo.txt', 'w')
for ele in itertools.product("0123456789abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ",repeat=6):
print("".join(ele))
from itertools import product
import itertools
import sys
sys.stdout = open('c:/combo.txt', 'w')
for ele in itertools.product("0123456789abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ",repeat=6):
print("".join(ele))
Note, you are including the letters I, O, l, and the number 0 which are all invalid base58check characters.
It also doesn't make much sense to store all the iterations in a file. Instead it would be better to generate each potential key and then verify the checksum. You only need to store those keys that have a valid checksum (which should be approximately 1 out every 4,294,967,296 keys generated).
You don't even really need to store the keys with a valid checksum. You could just compute the address for each key that has a valid checksum as you find it and see if the address matches the winning address. If it does, then you are done.
Honestly, coding that is a bit beyond my ability which was why I did it the way I did. I'm pretty sure my brain would explode before I had a working version of what you suggested.
I ran this overnight. I woke up to a 350+ gb unmanageable text doc and the script was still running. If someone gets one more letter, I can run it and it will be easier. Here is the code I used"
from itertools import product
import itertools
import sys
sys.stdout = open('c:/combo.txt', 'w')
for ele in itertools.product("0123456789abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ",repeat=6):
print("".join(ele))
from itertools import product
import itertools
import sys
sys.stdout = open('c:/combo.txt', 'w')
for ele in itertools.product("0123456789abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ",repeat=6):
print("".join(ele))
Note, you are including the letters I, O, l, and the number 0 which are all invalid base58check characters.
It also doesn't make much sense to store all the iterations in a file. Instead it would be better to generate each potential key and then verify the checksum. You only need to store those keys that have a valid checksum (which should be approximately 1 out every 4,294,967,296 keys generated).
You don't even really need to store the keys with a valid checksum. You could just compute the address for each key that has a valid checksum as you find it and see if the address matches the winning address. If it does, then you are done.
Cant crack.its more than logic than i thought.
I have gone back and looked at #3 again, I think the correct answer should be EAhBp
192 (7)-1 should be h. See the pdf file again, page 192 should be the page 208 in the pdf.
The OP purposely have a capital A in "announce" and an additional h, meaning the h is behind A => EAhBp
"this is a small hint" & "but hints can be small" => a small "h"
OP is really smart!!
Anyone willing to put their computing power into brute forcing the answer?
192 (7)-1 should be h. See the pdf file again, page 192 should be the page 208 in the pdf.
Hello! i will hold on for a day or two to Announche any right answers again
The OP purposely have a capital A in "announce" and an additional h, meaning the h is behind A => EAhBp
this is a small hint. but hints can be small. but this Hint is: Softcover
Level 3
Level 3
"this is a small hint" & "but hints can be small" => a small "h"
OP is really smart!!
Anyone willing to put their computing power into brute forcing the answer?
Well then now I have:
5Juu2CkB3EAhBpEcyH9dypNhPetergh6RQwwbo5ueBa6------E?
If you where to try and bruteforce the last part, assuming the rest is correct, it would only need 50 billion tries (if I calculated this correctly..)
The quickest way to tackle that would be using itertools in python. 6 places should go quick. I'll try it tomorrow if no one has yet.
I ran this overnight. I woke up to a 350+ gb unmanageable text doc and the script was still running. If someone gets one more letter, I can run it and it will be easier. Here is the code I used"
from itertools import product
import itertools
import sys
sys.stdout = open('c:/combo.txt', 'w')
for ele in itertools.product("0123456789abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ",repeat=6):
print("".join(ele))
if anyone had it done and get the prize 
This does look interesting. I wish I had more time to study it.
It looks like some of you are getting pretty close to solving it well in advance of the 30 day limit!
It looks like some of you are getting pretty close to solving it well in advance of the 30 day limit!
I have gone back and looked at #3 again, I think the correct answer should be EAhBp
192 (7)-1 should be h. See the pdf file again, page 192 should be the page 208 in the pdf.
The OP purposely have a capital A in "announce" and an additional h, meaning the h is behind A => EAhBp
"this is a small hint" & "but hints can be small" => a small "h"
OP is really smart!!
Anyone willing to put their computing power into brute forcing the answer?
192 (7)-1 should be h. See the pdf file again, page 192 should be the page 208 in the pdf.
Hello! i will hold on for a day or two to Announche any right answers again
The OP purposely have a capital A in "announce" and an additional h, meaning the h is behind A => EAhBp
this is a small hint. but hints can be small. but this Hint is: Softcover
Level 3
Level 3
"this is a small hint" & "but hints can be small" => a small "h"
OP is really smart!!
Anyone willing to put their computing power into brute forcing the answer?
Well then now I have:
5Juu2CkB3EAhBpEcyH9dypNhPetergh6RQwwbo5ueBa6------E?
If you where to try and bruteforce the last part, assuming the rest is correct, it would only need 50 billion tries (if I calculated this correctly..)
The quickest way to tackle that would be using itertools in python. 6 places should go quick. I'll try it tomorrow if no one has yet.
I guess we need OP to confirm the answers to #3 and #9 first, since hints have been given.
Then we move on to #6 and then 10.
Then we move on to #6 and then 10.
I have gone back and looked at #3 again, I think the correct answer should be EAhBp
192 (7)-1 should be h. See the pdf file again, page 192 should be the page 208 in the pdf.
The OP purposely have a capital A in "announce" and an additional h, meaning the h is behind A => EAhBp
"this is a small hint" & "but hints can be small" => a small "h"
OP is really smart!!
Anyone willing to put their computing power into brute forcing the answer?
192 (7)-1 should be h. See the pdf file again, page 192 should be the page 208 in the pdf.
Hello! i will hold on for a day or two to Announche any right answers again
The OP purposely have a capital A in "announce" and an additional h, meaning the h is behind A => EAhBp
this is a small hint. but hints can be small. but this Hint is: Softcover
Level 3
Level 3
"this is a small hint" & "but hints can be small" => a small "h"
OP is really smart!!
Anyone willing to put their computing power into brute forcing the answer?
Well then now I have:
5Juu2CkB3EAhBpEcyH9dypNhPetergh6RQwwbo5ueBa6------E?
If you where to try and bruteforce the last part, assuming the rest is correct, it would only need 50 billion tries (if I calculated this correctly..)
Well then now I have:
5Juu2CkB3EAhBpEcyH9dypNhPetergh6RQwwbo5ueBa6------E?
5Juu2CkB3EAhBpEcyH9dypNhPetergh6RQwwbo5ueBa6------E?
Why Peter?
I have gone back and looked at #3 again, I think the correct answer should be EAhBp
192 (7)-1 should be h. See the pdf file again, page 192 should be the page 208 in the pdf.
The OP purposely have a capital A in "announce" and an additional h, meaning the h is behind A => EAhBp
"this is a small hint" & "but hints can be small" => a small "h"
OP is really smart!!
Anyone willing to put their computing power into brute forcing the answer?
192 (7)-1 should be h. See the pdf file again, page 192 should be the page 208 in the pdf.
Hello! i will hold on for a day or two to Announche any right answers again
The OP purposely have a capital A in "announce" and an additional h, meaning the h is behind A => EAhBp
this is a small hint. but hints can be small. but this Hint is: Softcover
Level 3
Level 3
"this is a small hint" & "but hints can be small" => a small "h"
OP is really smart!!
Anyone willing to put their computing power into brute forcing the answer?
Well then now I have:
5Juu2CkB3EAhBpEcyH9dypNhPetergh6RQwwbo5ueBa6------E?
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