Bitcoin puzzle (3,350.00 BTC's ) - page 3.

anunta90

newbie

Activity: 1

Merit: 0

Quote from: bytcoin on March 03, 2021, 05:14:02 PM

@BurtW Once again I apologize!
The correct is:
(Nonce k2 of the second signature: k1 / 2 = k2)
That would be too easy! The order between s and h of the second signature is alternated ... You just need an efficient equation ... and the private key is all yours. Anyone who can calculate will own the 3,500.00 BTCs
You don't need to post formulas or equations here, just calculate and get the private key for yourself.
All the information needed to find the private key has already been exposed

Good morning thanks for the puzzle I have a question ...are there s2 and h2 correct values? sorry for asking but After recalculating all the values the only one I am getting wrong is h2

COBRAS

member

Activity: 846

Merit: 22

$$P2P BTC BRUTE.JOIN NOW ! https://uclck.me/SQPJk

Quote from: 100bitcoin on March 04, 2021, 08:33:48 AM

Quote from: bytcoin on March 03, 2021, 02:09:49 PM

Address: https://bitinfocharts.com/bitcoin/address/1FvUkW8thcqG6HP7gAvAjcR52fR7CYodBx

Public key : 040b8a0382802e12fc345e9bace8b99f6aed6b90fbfd796e8027ca9bb5f472778db863952bdb6e9 e399e34f941cab2fa6c244e65af2d15244fee2d795b3f6e222d

Is not difficult! An equation solves this. I will respond to comments only after the address has been drained.
Good luck!

First and foremost, provide a signature of the following quoted message, which is verifiable at https://tools.bitcoin.com/verify-message/ or https://reinproject.org/bitcoin-signature-tool/#verify or https://tools.qz.sg/

Quote from: AB de Royse777 on March 03, 2021, 02:17:18 PM

Today is 03/03/2021 and I (bytcoin) own this address

Hi. And what is a message in btx transaction Huh

100bitcoin

sr. member

Activity: 860

Merit: 423

Quote from: bytcoin on March 03, 2021, 02:09:49 PM

Address: https://bitinfocharts.com/bitcoin/address/1FvUkW8thcqG6HP7gAvAjcR52fR7CYodBx

Public key : 040b8a0382802e12fc345e9bace8b99f6aed6b90fbfd796e8027ca9bb5f472778db863952bdb6e9 e399e34f941cab2fa6c244e65af2d15244fee2d795b3f6e222d

Is not difficult! An equation solves this. I will respond to comments only after the address has been drained.
Good luck!

First and foremost, provide a signature of the following quoted message, which is verifiable at https://tools.bitcoin.com/verify-message/ or https://reinproject.org/bitcoin-signature-tool/#verify or https://tools.qz.sg/

Quote from: AB de Royse777 on March 03, 2021, 02:17:18 PM

Today is 03/03/2021 and I (bytcoin) own this address

j2002ba2

full member

Activity: 204

Merit: 437

Quote from: bytcoin on March 03, 2021, 03:18:53 PM

Before someone appears saying that the signatures do not exist and are not real ...
https://www.blockchain.com/btc/tx/d95d58461f2d3fd476db49a741944ced4383a548937bb107d8897ea6053aeda8

And it also checks the validity of the second signature Wink

It doesn't. The second R & S differs.

Yours are:
r2: b0c147a4046a541d051fa5f17906bc01aeb46fbe273ef9226610d2e0579dad88
s2: 7c9f48333e7ad71c9fc66c28efaa4032954bba147feb8f08664e3fce4619a75c

The signature from 523c3a9aa8f69af7a5b0491eeb4e49be3fb20ca5e5b0a9114e0bbdf273c1a690:
3044022070aee9c959607de56c500a2aefeaed489aab151daf42299df564106367c296e10220755799de9564d2968ceac7f8a3678d1d7b47e41fadb24ba6c694fc11eae6bcc901 040b8a0382802e12fc345e9bace8b99f6aed6b90fbfd796e8027ca9bb5f472778db863952bdb6e9 e399e34f941cab2fa6c244e65af2d15244fee2d795b3f6e222d
Didn't bother to check the hashes provided.

pooya87

legendary

Activity: 3444

Merit: 10558

Quote from: bytcoin on March 03, 2021, 05:14:02 PM

(Nonce k2 of the second signature: k1 / 2 = k2)
Anyone who can calculate will own the 3,500.00 BTCs

You are very confused.
There is no such relationship between the two ks used in the 2 signatures in the 2 transactions that were sent out of 1FvUkW8thcqG6HP7gAvAjcR52fR7CYodBx, I checked. If there were the coins would have been stolen a very long time ago.

COBRAS

member

Activity: 846

Merit: 22

$$P2P BTC BRUTE.JOIN NOW ! https://uclck.me/SQPJk

I get two variats, they are not valid.

0x81cdc964a3ed34ef41ff52b1e0962a794c0b5e8143dce2b927cb6cb2af6c8439

0xe773cf35fce567d0622203c28f67478a3361bae7e6eb4366b50e1d27eb1ed82e

I go to sleep now. Tomorrow continue work if adress was not empty.

But, Buddy, this adress has many input and output transaction, so, get R,S,Z for this adress is not so HARD, and you ca get it with 2xcoin.com

BR

bytcoin

member

Activity: 211

Merit: 20

$$$$$$$$$$$$$$$$$$$$$$$$$

@BurtW Once again I apologize!
The correct is:
(Nonce k2 of the second signature: k1 / 2 = k2)
That would be too easy! The order between s and h of the second signature is alternated ... You just need an efficient equation ... and the private key is all yours. Anyone who can calculate will own the 3,500.00 BTCs
You don't need to post formulas or equations here, just calculate and get the private key for yourself.
All the information needed to find the private key has already been exposed

BurtW

legendary

Activity: 2646

Merit: 1131

All paid signature campaigns should be banned.

If you have two valid signatures using the same private key where k' = 2k then:

From each message we can derive the z value (hash of the message) so:

First message and signature (m, r, s, z)
Second message and signature (m', r', s', z')

Therefore: ks = z + rd_A and k's' = z' + r'd_A

Therefore: (sk - z)/r = (s'k' - z')/r'

But in this case k' = 2k so:

(sk - z)/r = (2s'k - z')/r'

So all you have to do is solve for k. All the other values: s, z, r, s', z', and r' are all known.

rr'(sk - z)/r = rr'(2s'k - z')/r'

r'(sk - z) = r(2s'k - z')

r'sk - r'z = 2rs'k - rz'

r'sk - r'z +rz' = 2rs'k

k = (r'sk - r'z +rz')/2rs'

Once you know k you can simply calculate the private key, d_A = (sk - z)/r

I still do not see what your two signatures have to do with the BTC at 1FvUkW8thcqG6HP7gAvAjcR52fR7CYodBx

These two things: how to solve for the private key when you know k' = 2k and the BTC stored at 1FvUkW8thcqG6HP7gAvAjcR52fR7CYodBx seem to be unrelated, right?

COBRAS

member

Activity: 846

Merit: 22

$$P2P BTC BRUTE.JOIN NOW ! https://uclck.me/SQPJk

Quote from: bytcoin on March 03, 2021, 03:18:53 PM

I did almost everything 'manually' and from what I checked it was all right
Please read carefully! It has two signatures with the same private key, with the nonce k of the second signature being double the k1 (nonce signature 1: k1) (nonce signature 2: k1 * 2 = k2)
A linear equation solves this
If someone finds something wrong please post in the comments

why your second P is differert from first P ?

bytcoin

member

Activity: 211

Merit: 20

$$$$$$$$$$$$$$$$$$$$$$$$$

Before someone appears saying that the signatures do not exist and are not real ...
https://www.blockchain.com/btc/tx/d95d58461f2d3fd476db49a741944ced4383a548937bb107d8897ea6053aeda8

And it also checks the validity of the second signature Wink

BurtW

legendary

Activity: 2646

Merit: 1131

All paid signature campaigns should be banned.

Yes, as we have all told you before:

If there is a known mathematical relationship between the two nonce used (k₁ = k₀ + n OR k₁ = m * k₀) then you can derive the private key from the two signatures.

This is why the k value is picked at random (hopefully from a secure random number generator).

The key phrase here is "known mathematical relationship between the two nonce"

We have shown you the math for this - several times. You should be able to do the math yourself at this point.

What does the address 1FvUkW8thcqG6HP7gAvAjcR52fR7CYodBx have to do with anything?

Are you really claiming to know that there are two signatures in the block chain using the private key for 1FvUkW8thcqG6HP7gAvAjcR52fR7CYodBx that were constructed with k₁ = 2 * k₀?

How would you know this?

dothebeats

legendary

Activity: 3542

Merit: 1352

Cashback 15%

Quote from: AB de Royse777 on March 03, 2021, 02:17:18 PM

Quote from: bytcoin on March 03, 2021, 02:09:49 PM

1FvUkW8thcqG6HP7gAvAjcR52fR7CYodBx

It would be great if you are able to sign a message using this address. Use current date in the message like "Today is 03/03/2021 and I (bytcoin) own this address".

If you can't then most possibly you are wasting everyone's time here.

Yup, just so people wouldn't go on and solve this straight away thinking that they would get the btc only to find out that there isn't any coins to be had in the first place.

Not that we're trying to say that you're a fraud or anything but just to make sure that you really have the funds. Most puzzles here in bitcointalk went smoothly just because the one who gave the puzzle signed a message on the address they're trying to give away.

AB de Royse777

legendary

Activity: 2464

Merit: 3878

Visit: r7promotions.com

Quote from: bytcoin on March 03, 2021, 02:09:49 PM

1FvUkW8thcqG6HP7gAvAjcR52fR7CYodBx

It would be great if you are able to sign a message using this address. Use current date in the message like "Today is 03/03/2021 and I (bytcoin) own this address".

If you can't then most possibly you are wasting everyone's time here.

bytcoin

member

Activity: 211

Merit: 20

$$$$$$$$$$$$$$$$$$$$$$$$$

Edited!
I apologize to everyone!
I did almost everything "manually" is susceptible to errors
Two valid signatures with the same private key, but the nonce k of the second signature is half of the first. (Nonce k of the second signature: k1 / 2 = k2)

The second nonce k2 is half of the nonce k1 of the first signature

In decimal

Signature 1:

Nonce k1
r = 385570073629551546729230374184391439442417095537024350206131291065055332733
s = 76130260662571134678372154009160868461537800596554110575850229341703072615102
h = 42268864623620244998249895290537358742158169262361846431272029622156081203721

Signature 2:

Nonce k2 (k1 / 2 = k2)
r = 79948557280043978274449002532600374620672215928697101734828211284733327158664
s = 56368220214898939855776145385640746541620815395185097101215290078962069907292
h = 87726031595873281985439431891132599611815665254308710544703498112157039462043

Address: https://bitinfocharts.com/bitcoin/address/1FvUkW8thcqG6HP7gAvAjcR52fR7CYodBx

Public key : 040b8a0382802e12fc345e9bace8b99f6aed6b90fbfd796e8027ca9bb5f472778db863952bdb6e9 e399e34f941cab2fa6c244e65af2d15244fee2d795b3f6e222d

Is not difficult! An equation solves this. I will respond to comments only after the address has been drained.
Good luck!
Great song while trying to solve this puzzle Wink

https://i.imgur.com/THooBoC.png[/img]]https://www.youtube.com/watch?v=HWjCStB6k4o

Topic: Bitcoin puzzle (3,350.00 BTC's ) - page 3. (Read 2535 times)