Another angle to work on #130, there are many ways to manipulate the ranges, I'm just providing the easiest ones.
400000000000000000000000000000000
282a8bfbda44ad168dfff85563a4be809
17d5740425bb52e9720007aa9c5b417f7
The second and the third keys above could be considered as #130, look what happens when we subtract each of them from the end range, they are the reverse of each other in hex like 8 turns to 7, a=5, b=4, c=3, d=2, e=1, f=0 etc.
What that means, is that if you could find a definitive mathematical/modular relation between such keys, then you could theoretically solve any keys by doing the same subtractions as above.
They are like when added, they generate a composite number divisible by powers of 2. Only thing you have to figure, is to find a way either by +, -, /, and *, to land on a constant key, for example it doesn't matter what your key is, if you add 10 to 50 and divide by 2, you can get 30 which has a distance of 10 from half of 30(15) to 25 aka half of target.
I mean some relation like that, find that then you can solve any keys.
Let me show you, if you divide both keys and subtract their results, you can have:
2- 82a8bfbda44ad168dfff85563a4be809
3- aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa28e5131837b7a1186a8bed42070170dc
4- 7fffffffffffffffffffffffffffffff9eabce5229c9b8d24fe8f1f1854114a5
5- 34437fe574eaba29f33302227db7f66a
6- 555555555555555555555555555555551472898c1bdbd08c3545f6a10380b86e
7- 2554c9119ca7a98badb6b861c78366de
8- bfffffffffffffffffffffffffffffff2cad559c6c892c8707dda83f2abbaaf3
Now if you add the results, you will have these :
2- 200000000000000000000000000000000
3- aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaab271f3def1f85c027d536e9b3357980d6
4- 100000000000000000000000000000000
5- 99999999999999999999999999999999a335b7bd9c5ec68a3fe49f2149ba2727
6- 55555555555555555555555555555555938f9ef78fc2e013ea9b74d99abcc06b
7- 9249249249249249249249249249249221887e3aad4e126b490a7f2be4b149dc
8- 80000000000000000000000000000000
Now remember you can always know the second offsets, when you divide and add, if you are interested, try to find a relation between the first 8 offsets and the second 8 offsets, and note that they are only divided by 2 through 8, you can go beyond 2^100 and study the results carefully.
🦟🦟, who let these flies in?