Bitcoin puzzle transaction ~32 BTC prize to who solves it - page 64.

nomachine

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Quote from: Kelvin555 on September 14, 2024, 10:55:09 PM

There were so many bots listening to that address at every moment, and not even one tried to replace the transaction ? I doubt it, if so then the person who sent those sats is mocking us..... I interpreted "you're so dumb, what were you thinking and you deserve nothing" as what were you thinking trying to send out the coins through the mempool(exposing the public key), you're so dumb, the coins have been stolen from you, you deserve nothing OR mocking us, what were you thinking playing a losing game, you're so dumb, you deserve nothing.

I even turned off the bot, thinking that the winner would go through Mara's slipstream.

We’ll see next time if that person is mocking anyone. Next time, all my bots will be ON.

COBRAS

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vanity adresses like this , I read, what some of them more vulneranble then other.

1FuckUmT5yBAvozf6gT8GRQVbJ7iBDUnrH

because they generated not all time in 256 bit range, mach smaler

COBRAS

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Quote from: masken on September 14, 2024, 09:29:00 PM

https://github.com/nzengi/Dual-Vanity/blob/main/dual_vanity.py

Dual-Vanity new version v0.1

start_range = 0x40000000000000000
end_range = 0x7ffffffffffffffff

prefix = "1B"
suffix = "W9"

sample output :: C Address :: 1BxxxxxxxxxxxxxxxxxW9

thank you for the scrypt

Kelvin555

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Activity: 8

Merit: 0

Quote from: AndrewWeb on September 14, 2024, 05:53:11 PM

I don't think anything wrong happened here.

There were so many bots listening to that address at every moment, and not even one tried to replace the transaction ? I doubt it, if so then the person who sent those sats is mocking us..... I interpreted "you're so dumb, what were you thinking and you deserve nothing" as what were you thinking trying to send out the coins through the mempool(exposing the public key), you're so dumb, the coins have been stolen from you, you deserve nothing OR mocking us, what were you thinking playing a losing game, you're so dumb, you deserve nothing.

Quote from: COBRAS on September 14, 2024, 03:41:48 PM

Can sender of microsat know of balace move faster then others because this microsathoshi ?

I don't know.

masken

newbie

Activity: 3

Merit: 0

https://github.com/nzengi/Dual-Vanity/blob/main/dual_vanity.py

Dual-Vanity new version v0.1

start_range = 0x40000000000000000
end_range = 0x7ffffffffffffffff

prefix = "1B"
suffix = "W9"

sample output :: C Address :: 1BxxxxxxxxxxxxxxxxxW9

AndrewWeb

jr. member

Activity: 56

Merit: 2

I don't think anything wrong happened here.

5.94 BTC went to

bc1ql5lrt3y97djyu5k8ewmz87nnemxheycp6wdree
bc1qdplvug87leypur2a27xh64u8cu78e0td8edwv7
bc1qpa20zkg6kr55yl7gxnwh37aj8q00rt70k6q8ru

whereas 0.66 BTC (exactly 10% of the prize 6.60 BTC) went straight to Binance (for cash out ?)

Someone helped the finder with the transaction and got 10% of the prize ?

COBRAS

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Quote from: Kelvin555 on September 14, 2024, 03:21:44 PM

Quote from: kTimesG on September 13, 2024, 02:27:28 PM

Seems there are 12 satoshi left to grab on the #66 address. Hurry up guys.

TX input:

Code:

1FuckUmT5yBAvozf6gT8GRQVbJ7iBDUnrH

TX outputs:

Code:

1Jvv4yWkE9MhbuwGU66666666669sugEF 0.00000001
1YouAreSoDumbLoL666666666667K5aR4 0.00000002
1WhatWereUThinking6666666662wkqq1 0.00000003
1YouDeserveNothing6666666665sbbBC 0.00000004
1YouEpicFaiLure66666666666688GSDA 0.00000005
1BitchAssLoser66666666666669dBUVg 0.00000006
1AndEveryoneELse666666666669Vnc8C 0.00000007
1ThisisALosingGame6666666667HAZdf 0.00000008
1JustGetAReaLJob666666666665vGKVD 0.00000009
1YoureWastingTimeAndMoney664CVExC 0.00000010
1AndCausingCLimateChange6666HK8Qc 0.00000011
13zb1hQbWVsc2S7ZTZnP2G4undNNpdh5so 0.00000012
1Jvv4yWkE9MhbuwGUoqFYzDjRVQHaLWuJd 0.00000013
1FK5PjPNARQmg94n2cNHTo9417kWfXUDBQ 0.00002125

I think whoever sent these sats stole the price from the real solver of puzzle 66.

Can sender of microsat know of balace move faster then others because this microsathoshi ?

Probably we will seen transaction replace again.

Kelvin555

newbie

Activity: 8

Merit: 0

Quote from: kTimesG on September 13, 2024, 02:27:28 PM

Seems there are 12 satoshi left to grab on the #66 address. Hurry up guys.

TX input:

Code:

1FuckUmT5yBAvozf6gT8GRQVbJ7iBDUnrH

TX outputs:

Code:

1Jvv4yWkE9MhbuwGU66666666669sugEF 0.00000001
1YouAreSoDumbLoL666666666667K5aR4 0.00000002
1WhatWereUThinking6666666662wkqq1 0.00000003
1YouDeserveNothing6666666665sbbBC 0.00000004
1YouEpicFaiLure66666666666688GSDA 0.00000005
1BitchAssLoser66666666666669dBUVg 0.00000006
1AndEveryoneELse666666666669Vnc8C 0.00000007
1ThisisALosingGame6666666667HAZdf 0.00000008
1JustGetAReaLJob666666666665vGKVD 0.00000009
1YoureWastingTimeAndMoney664CVExC 0.00000010
1AndCausingCLimateChange6666HK8Qc 0.00000011
13zb1hQbWVsc2S7ZTZnP2G4undNNpdh5so 0.00000012
1Jvv4yWkE9MhbuwGUoqFYzDjRVQHaLWuJd 0.00000013
1FK5PjPNARQmg94n2cNHTo9417kWfXUDBQ 0.00002125

I think whoever sent these sats stole the price from the real solver of puzzle 66.

pbies

full member

Activity: 297

Merit: 133

Quote from: nomachine on September 14, 2024, 09:05:27 AM

The more private keys we have, the smaller the error would be....5% deviation on puzzle 130 is too big.

It depends how you want to search for them.

With keyhunt and option for addresses is useless as it will take ages,
but with keyhunt and option for bsgs (random or not) may be successful.

mcdouglasx

member

Activity: 239

Merit: 53

New ideas will be criticized and then admired.

Quote from: kTimesG on September 14, 2024, 06:08:42 AM

Quote from: madogss on September 14, 2024, 02:11:05 AM

Quote from: COBRAS on September 14, 2024, 12:07:43 AM

I think you need take official registered a USA or EU patent to you DB. This will be protect your Idea from stealing and maybe give some money. Then you have a patent, can try sell your method to google, microsft etc.

Agreed this DB will be especially useful for space and medicine with how far AI has come we could use mcdouglasx's db to store a detailed brain scan or a 3d map of a galaxy and train AI on the db so it could piece together the data and we could ask it questions about the data like does this scan have a blood clot or a misfiring neuron or map the most efficient trajectory to this planet and it could answer but instead of taking up petabytes or even exabytes of storage it would take a fraction of that. Of course right now your db is specifically for public keys but its the idea that matters if you could apply it to different areas that would be game changing.

I don't believe a brain blood cloth is willing to wait some exponential time for a "binary" DB to be "scanned". The current state of practical technology uses bytes, words, 64-bit addressing and registers, because these are the actual smallest units of data that are being read or operated within a single clock cycle, by a CPU, controller, or whatever. Especially memory, the higher the bus width, the more data can be transferred per cycle.

Using 0 and 1s is already the basis of everything we use every day, and lots of things in CS make heavy use of them for memory-trips efficiency already, flags, algorithms, etc. but they DO NOT do this because it uses less data, they do it because IT IS FASTER. As a few already said before, "scanning" speed of said DB is sub-optimal to say the least, but hey, I'm no one to judge people's ideas. However, I must say it does not sound like something that any non-graduate CS student hasn't already "seen this, done that" as there are dozens of algorithms that do a much better job. This is why I asked about complexities or insert/update/query operations on said DB, otherwise it's not a DB but mangled packed bits, e.g. some compression output.

Advances in society, especially in technology, are often evolutionary. An initial idea may be innovative, but over time, others improve it and adapt it to new needs and contexts. This collaborative and continuous process is what drives progress.
Don't give vague opinions. Maybe something is difficult today, but tomorrow we don't know.

nomachine

member

Activity: 503

Merit: 38

The more private keys we have, the smaller the error would be....5% deviation on puzzle 130 is too big.

pbies

full member

Activity: 297

Merit: 133

Quote from: nomachine on September 14, 2024, 08:08:08 AM

I need all possible PVK in decimal...from 161 to 256

There are no puzzles over 160. We can guess now most of 67-159.

Look here:

https://privatekeys.pw/puzzles/bitcoin-puzzle-tx

and convert with Python adding "0x" in front of hex number - just print the value:

puzzle 67

>>> 0x40000000000000000
73786976294838206464
>>> 0x7ffffffffffffffff
147573952589676412927

or you may use "bc" in WSL console (Linux).

COBRAS

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Quote from: nomachine on September 14, 2024, 08:08:08 AM

Quote from: COBRAS on September 14, 2024, 07:43:10 AM

try predict all upper known privkeys,what errors will be ?

python3 predict.py 70
Puzzle 70 Real Value: 970436974005023690481
Puzzle 70 Predicted Value: 730587102306582265856.00
Percentage error in the corrected prediction for Puzzle 70: 24.72%

python3 predict.py 105
Puzzle 105 Real Value: 29083230144918045706788529192435
Puzzle 105 Predicted Value: 27596983500174317470201354911744.00
Percentage error in the corrected prediction for Puzzle 105: 5.11%

python3 predict.py 115
Puzzle 115 Real Value: 31464123230573852164273674364426950
Puzzle 115 Predicted Value: 27143119219824810742015504299327488.00
Percentage error in the corrected prediction for Puzzle 115: 13.73%

I need all possible PVK in decimal...from 161 to 256

maybe on allprivatekeys and similar www has privkeys data

nomachine

member

Activity: 503

Merit: 38

Quote from: COBRAS on September 14, 2024, 07:43:10 AM

try predict all upper known privkeys,what errors will be ?

python3 predict.py 70
Puzzle 70 Real Value: 970436974005023690481
Puzzle 70 Predicted Value: 730587102306582265856.00
Percentage error in the corrected prediction for Puzzle 70: 24.72%

python3 predict.py 105
Puzzle 105 Real Value: 29083230144918045706788529192435
Puzzle 105 Predicted Value: 27596983500174317470201354911744.00
Percentage error in the corrected prediction for Puzzle 105: 5.11%

python3 predict.py 115
Puzzle 115 Real Value: 31464123230573852164273674364426950
Puzzle 115 Predicted Value: 27143119219824810742015504299327488.00
Percentage error in the corrected prediction for Puzzle 115: 13.73%

I need all possible PVK in decimal...from 161 to 256

COBRAS

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Merit: 22

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Quote from: mcdouglasx on September 14, 2024, 07:56:25 AM

Quote from: madogss on September 14, 2024, 02:11:05 AM

Quote from: COBRAS on September 14, 2024, 12:07:43 AM

I think you need take official registered a USA or EU patent to you DB. This will be protect your Idea from stealing and maybe give some money. Then you have a patent, can try sell your method to google, microsft etc.

Agreed this DB will be especially useful for space and medicine with how far AI has come we could use mcdouglasx's db to store a detailed brain scan or a 3d map of a galaxy and train AI on the db so it could piece together the data and we could ask it questions about the data like does this scan have a blood clot or a misfiring neuron or map the most efficient trajectory to this planet and it could answer but instead of taking up petabytes or even exabytes of storage it would take a fraction of that. Of course right now your db is specifically for public keys but its the idea that matters if you could apply it to different areas that would be game changing.

This is what it is, trying to achieve a significant improvement in the search for puzzles, nothing more, it has no general context.

Bro, Hi.

it is possible to put to DB not pubkey data , sach data for ex:

00000000000000000000
10000000000000000000
01000000000000000000
11000000000000000000
00100000000000000000
10100000000000000000
01100000000000000000
11100000000000000000
00010000000000000000
10010000000000000000
01010000000000000000
11010000000000000000
00110000000000000000
10110000000000000000
01110000000000000000
11110000000000000000
00001000000000000000
10001000000000000000
01001000000000000000
11001000000000000000
00101000000000000000
10101000000000000000

and this:

000000000000000000000010111000000000000011011100101010000000
000000000000000000000010111000000000000011010010001111000000
000000000000000000000010111000000000000011011010110001100000
000000000000000000000010111000000000000011010110010100010000
000000000000000000001010111000000000000001010111101001000000
000000000000000000001010111000000000000001011111001100100000
?

mcdouglasx

member

Activity: 239

Merit: 53

New ideas will be criticized and then admired.

Quote from: madogss on September 14, 2024, 02:11:05 AM

Quote from: COBRAS on September 14, 2024, 12:07:43 AM

I think you need take official registered a USA or EU patent to you DB. This will be protect your Idea from stealing and maybe give some money. Then you have a patent, can try sell your method to google, microsft etc.

Agreed this DB will be especially useful for space and medicine with how far AI has come we could use mcdouglasx's db to store a detailed brain scan or a 3d map of a galaxy and train AI on the db so it could piece together the data and we could ask it questions about the data like does this scan have a blood clot or a misfiring neuron or map the most efficient trajectory to this planet and it could answer but instead of taking up petabytes or even exabytes of storage it would take a fraction of that. Of course right now your db is specifically for public keys but its the idea that matters if you could apply it to different areas that would be game changing.

This is what it is, trying to achieve a significant improvement in the search for puzzles, nothing more, it has no general context.

COBRAS

member

Activity: 873

Merit: 22

$$P2P BTC BRUTE.JOIN NOW ! https://uclck.me/SQPJk

nomachine

member

Activity: 503

Merit: 38

Quote from: Andzhig on September 14, 2024, 06:19:57 AM

from the standpoint of probability, this doesn’t seem to mean anything

Here is my prediction script. I have +- 0-40% deviations
With correction factor for puzzle 66
alpha = 2.7931615407112251695923857484645003617613050861

more decimals in correction factor more precise result

Code:

import numpy as np
from mpmath import mp
import argparse

# Set higher decimal precision for mpmath
mp.dps = 60  # Adjust precision as needed

# Target numbers (ordinal, value) 
target_numbers = [
    (1, 1), (2, 3), (3, 7), (4, 8), (5, 21), (6, 49), (7, 76), (8, 224), (9, 467), (10, 514),
    (11, 1155), (12, 2683), (13, 5216), (14, 10544), (15, 26867), (16, 51510),
    (17, 95823), (18, 198669), (19, 357535), (20, 863317), (21, 1811764),
    (22, 3007503), (23, 5598802), (24, 14428676), (25, 33185509),
    (26, 54538862), (27, 111949941), (28, 227634408), (29, 400708894),
    (30, 1033162084), (31, 2102388551), (32, 3093472814), (33, 7137437912),
    (34, 14133072157), (35, 20112871792), (36, 42387769980), (37, 100251560595),
    (38, 146971536592), (39, 323724968937), (40, 1003651412950),
    (41, 1458252205147), (42, 2895374552463), (43, 7409811047825),
    (44, 15404761757071), (45, 19996463086597), (46, 51408670348612),
    (47, 119666659114170), (48, 191206974700443), (49, 409118905032525),
    (50, 611140496167764), (51, 2058769515153876), (52, 4216495639600700),
    (53, 6763683971478124), (54, 9974455244496707), (55, 30045390491869460),
    (56, 44218742292676575), (57, 138245758910846492), (58, 199976667976342049),
    (59, 525070384258266191), (60, 1135041350219496382), (61, 1425787542618654982),
    (62, 3908372542507822062), (63, 8993229949524469768),
    (64, 17799667357578236628), (65, 30568377312064202855), 
    (66, 46346217550346335726)
]

def main(puzzle_number):
    # Extracting the ordinal (x) and values (y) up to the puzzle before the target puzzle
    if puzzle_number in [x[0] for x in target_numbers]:
        ordinals = np.array([x[0] for x in target_numbers if x[0] < puzzle_number], dtype=float)
        values = np.array([x[1] for x in target_numbers if x[0] < puzzle_number], dtype=float)
    else:
        # Use all available data for prediction if puzzle_number is not in the list
        ordinals = np.array([x[0] for x in target_numbers], dtype=float)
        values = np.array([x[1] for x in target_numbers], dtype=float)

    # Compute log of the values using mpmath for high precision
    log_values = np.array([float(mp.log(val)) for val in values], dtype=float)

    # Introduce weights to give more importance to recent values
    weights = np.linspace(0.5, 1, len(ordinals))  # Linear weighting

    # Perform linear regression on log(values) to fit the exponential model, using weights
    coefficients = np.polyfit(ordinals, log_values, 1, w=weights)

    # Extracting the coefficients
    log_a = coefficients[1]
    log_b = coefficients[0]

    # Convert coefficients back to the exponential form
    a = mp.exp(log_a)
    b = mp.exp(log_b)

    # Correction factor
    alpha = 2.7931615407112251695923857484645003617613050861

    # Predict the value for the given puzzle using the exponential model
    predicted_value = (a * mp.power(b, puzzle_number)) - ((((2 ** puzzle_number) - 1) - (2 ** (puzzle_number - 1))) / alpha)

    # Check if the real value is available
    real_value = None
    if puzzle_number in [x[0] for x in target_numbers]:
        real_value = [x[1] for x in target_numbers if x[0] == puzzle_number][0]

    # Function to format mpmath values to avoid scientific notation
    def format_mp(value, decimals=None):
        if decimals is not None:
            # Use string formatting to keep decimal places without thousands separators
            return f"{float(value):,.{decimals}f}".replace(',', '')
        return mp.nstr(value, mp.dps)

    # Compare the corrected value with the real value for the given puzzle
    if real_value is not None:
        print(f"Puzzle {puzzle_number} Real Value: {format_mp(real_value)}")
    print(f"Puzzle {puzzle_number} Predicted Value: {format_mp(predicted_value, 2)}")

    # Calculate the percentage error in the corrected prediction if real value is available
    if real_value is not None:
        error_percentage = abs((predicted_value - real_value) / real_value) * 100
        print(f"Percentage error in the corrected prediction for Puzzle {puzzle_number}: {format_mp(error_percentage, 2)}%")

if __name__ == "__main__":
    parser = argparse.ArgumentParser(description="Predict puzzle values based on an exponential model.")
    parser.add_argument("puzzle_number", type=int, help="Puzzle number to predict")
    args = parser.parse_args()
    main(args.puzzle_number)

python3 predict.py 20
Puzzle 20 Real Value: 863317
Puzzle 20 Predicted Value: 580555.48
Percentage error in the corrected prediction for Puzzle 20: 32.75%

python3 predict.py 27
Puzzle 27 Real Value: 111949941
Puzzle 27 Predicted Value: 88704196.49
Percentage error in the corrected prediction for Puzzle 27: 20.76%

python3 predict.py 45
Puzzle 45 Real Value: 19996463086597
Puzzle 45 Predicted Value: 20580213444471.79
Percentage error in the corrected prediction for Puzzle 45: 2.92%

python3 predict.py 50
Puzzle 50 Real Value: 611140496167764
Puzzle 50 Predicted Value: 635143323281525.25
Percentage error in the corrected prediction for Puzzle 50: 3.93%

python3 predict.py 63
Puzzle 63 Real Value: 8993229949524469768
Puzzle 63 Predicted Value: 5468647699742324736.00
Percentage error in the corrected prediction for Puzzle 63: 39.19%

python3 predict.py 66
Puzzle 66 Real Value: 46346217550346335726
Puzzle 66 Predicted Value: 46346217550346338304.00
Percentage error in the corrected prediction for Puzzle 66: 0.00%

python3 predict.py 67
Puzzle 67 Predicted Value: 90626458014188470272.00

This is like looking into a crystal ball. It doesn't mean anything. Grin

Alienkenny

newbie

Activity: 1

Merit: 0

Does anyone know the key for the puzzles from 161 to 256?
Someone on the forum claimed that there are known.

Andzhig

jr. member

Activity: 184

Merit: 3

Well, it fell into an empty slot.

Imagine that we have a game cube with 64 sides and 160 throws, more throws means repetitions will occur. Next, for each of 64 we divide by 128, that is, we take a cube with 8192 sides so that there are no repetitions.

10000000000000000000000000000000 00000000000000000000000000000000 1 pz 2
00000000000000000000000000000000 00000000000010000000000000000000 45 pz 3
00000000000000000000000000000000 00000000000000000000001000000000 55 pz 4
10000000000000000000000000000000 00000000000000000000000000000000 1 pz 5
00000000000000000000000000000000 00100000000000000000000000000000 35 pz 6
00000000000000000000000000000000 00000000000001000000000000000000 46 pz 7
00000000000000000000000000100000 00000000000000000000000000000000 27 pz 8
00000000000000000000000000000000 00000000000000000000001000000000 55 pz 9
00000000000000000000000000000000 00000000000000000000000001000000 58 pz 10
00100000000000000000000000000000 00000000000000000000000000000000 3 pz 11
00000000000000000000010000000000 00000000000000000000000000000000 22 pz 12
00000000000000000000000000000000 00100000000000000000000000000000 35 pz 13
00000000000000000000000000000000 10000000000000000000000000000000 33 pz 14
00000000000000000000000000000000 01000000000000000000000000000000 34 pz 15
00000000000000000000000000000000 00000000000000000010000000000000 51 pz 16
00000000000000000000000000000000 00000000000000010000000000000000 48 pz 17
00000000000000000000000000000000 00000000001000000000000000000000 43 pz 18
00000000000000000000000000000000 00000000000010000000000000000000 45 pz 19
00000000000000000000000000000000 00000100000000000000000000000000 38 pz 20
00000000000000000000000000000000 00000000000000000010000000000000 51 pz 21
00000000000000000000000000000000 00000000000000000000010000000000 54 pz 22
00000000000000000000000000000000 00000000010000000000000000000000 42 pz 23
00000000000000000000000000000000 00000000000000000000010000000000 54 pz 24
00000000000000000000000000000000 00000000000000000000000000000010 63 pz 25
00000000000000000000000000000000 00000000000000000100000000000000 50 pz 26
00000000000000000000000000000000 00000000000000000001000000000000 52 pz 27
00000000000000000000000000000000 00000000000000000000100000000000 53 pz 28
00000000000000000000000000000000 00000000000100000000000000000000 44 pz 29
00000000000000000000000000000000 00000000000000000000000000001000 61 pz 30
00000000000000000000000000000000 00000000000000000000000000000100 62 pz 31
00000000000000000000000000000000 00000000010000000000000000000000 42 pz 32
00000000000000000000000000000000 00000000000000000001000000000000 52 pz 33
00000000000000000000000000000000 00000000000000000010000000000000 51 pz 34
00000000000000000000000001000000 00000000000000000000000000000000 26 pz 35
00000000000000000000000000000100 00000000000000000000000000000000 30 pz 36
00000000000000000000000000000000 00000000001000000000000000000000 43 pz 37
00000000000000010000000000000000 00000000000000000000000000000000 16 pz 38
00000000000000000000000001000000 00000000000000000000000000000000 26 pz 39
00000000000000000000000000000000 00000000000000000000000001000000 58 pz 40
00000000000000000000000000000000 00010000000000000000000000000000 36 pz 41
00000000000000000000000000000000 00010000000000000000000000000000 36 pz 42
00000000000000000000000000000000 00000000000000000001000000000000 52 pz 43
00000000000000000000000000000000 00000000000000000000001000000000 55 pz 44
00000000000000000000001000000000 00000000000000000000000000000000 23 pz 45
00000000000000000000000000000000 00000000001000000000000000000000 43 pz 46
00000000000000000000000000000000 00000000000000000000100000000000 53 pz 47
00000000000000000000000000000000 00000100000000000000000000000000 38 pz 48
00000000000000000000000000000000 00000000001000000000000000000000 43 pz 49
00000000000000000100000000000000 00000000000000000000000000000000 18 pz 50
00000000000000000000000000000000 00000000000000000000000001000000 58 pz 51
00000000000000000000000000000000 00000000000000000000000000100000 59 pz 52
00000000000000000000000000000000 00000000000010000000000000000000 45 pz 53
00000000000000000001000000000000 00000000000000000000000000000000 20 pz 54
00000000000000000000000000000000 00000000000000000001000000000000 52 pz 55
00000000000000000000000000000100 00000000000000000000000000000000 30 pz 56
00000000000000000000000000000000 00000000000000000000000000001000 61 pz 57
00000000000000000000000000000000 00000010000000000000000000000000 39 pz 58
00000000000000000000000000000000 00000000000000000000000001000000 58 pz 59
00000000000000000000000000000000 00000000000000000000000000000100 62 pz 60
00000000000000000000000000000010 00000000000000000000000000000000 31 pz 61
00000000000000000000000000000000 00000000000000000000100000000000 53 pz 62
00000000000000000000000000000000 00000000000000000000000000000100 62 pz 63
00000000000000000000000000000000 00000000000000000000000000001000 61 pz 64
00000000000000000000000000000000 00000000000000000010000000000000 51 pz 65
00000000000000000000000000000001 00000000000000000000000000000000 32 pz 66

...............x.x.x.xx..x...xxx xxxx.xx..xxxx..xxxxxxxx.xxx.xxx. pz 67

00000000000000000000000000000000 00000100000000000000000000000000 38 pz 70
00000000000000000000000000000000 00000000000000000000000010000000 57 pz 75
00000000000000000000000001000000 00000000000000000000000000000000 26 pz 80
00000000000000000000000000000000 00000000000000000000000000001000 61 pz 85
00000000000000000000000000000000 00000000000000001000000000000000 49 pz 90
00000000000000000000000000000000 00000000000000000000100000000000 53 pz 95
00000000000000000000000000000000 00000000000000000100000000000000 50 pz 100
00000000000000000000000000000000 00000000000000010000000000000000 48 pz 105
00000000000000000000000000000000 00010000000000000000000000000000 36 pz 110
00000000000000000000000000000000 00000000000100000000000000000000 44 pz 115
   pz 120
                         pz 125

not yet dropped free sides from 1 to 15, 17 19 21 24 25 27 28 29 37 40 41 46 47 56 60 64

for example, 43, 51, 52, 53, 58, 61 have already fallen out 4 times.

sides not yet rolled in a 64-sided die (128 each for 8192)

***

pz 64
8192, 64/2 32 8192/2 4096, 8192/64 128,
7899
(√(2^63)/8192×7899)^2+2^63; 7899/128 hex(F7051F27B09112D4
[17798765725016391680 61,7109375 dec(17799667357578236628]

pz 65
8192, 64/2 32 8192/2 4096, 8192/64 128,
6640
(√(2^64)/8192×6640)^2+2^64; 6640/128; hex(1A838B13505B26867
[30566001039707734016 51,875 dec(30568377312064202855]

pz 66
4146
(√(2^65)/8192×4146)^2+2^65 46343414555177123840
   46346217550346335726
(√(2^65)/8192×4147)^2+2^65 46347973680141697024

(√(2^65)/8192×4146)^2+2^65; 4146/128
46343414555177123840 32,390625 46346217550346335726

***

free missing sides and possible space for pz 67

1-15
(√(2^66)/8192×129)^2+2^66; 8192/128 73805273267836026880
(√(2^66)/8192×1921)^2+2^66; 8192/128 77844439183633940480

17
(√(2^66)/8192×2177)^2+2^66; 8192/128 78997923638194208768
(√(2^66)/8192×2305)^2+2^66; 8192/128 79628709061002788864

19
(√(2^66)/8192×2433)^2+2^66; 8192/128 80295523280830332928
(√(2^66)/8192×2561)^2+2^66; 8192/128 80998366297676840960

21
(√(2^66)/8192×2689)^2+2^66; 8192/128 81737238111542312960
(√(2^66)/8192×2817)^2+2^66; 8192/128 82512138722426748928

24
(√(2^66)/8192×3073)^2+2^66; 8192/128 84170026335252512768
(√(2^66)/8192×3201)^2+2^66; 8192/128 85053013337193840640

25
(√(2^66)/8192×3201)^2+2^66; 8192/128 85053013337193840640
(√(2^66)/8192×3329)^2+2^66; 8192/128 85972029136154132480

27
(√(2^66)/8192×3457)^2+2^66; 8192/128 86927073732133388288
(√(2^66)/8192×3585)^2+2^66; 8192/128 87918147125131608064

28
(√(2^66)/8192×3585)^2+2^66; 8192/128 87918147125131608064
(√(2^66)/8192×3713)^2+2^66; 8192/128 88945249315148791808

29
(√(2^66)/8192×3713)^2+2^66; 8192/128 88945249315148791808
(√(2^66)/8192×3841)^2+2^66; 8192/128 90008380302184939520

37
(√(2^66)/8192×4736)^2+2^66; 8192/128 98448687854319042560
(√(2^66)/8192×4864)^2+2^66; 8192/128 99799767742530191360

40
(√(2^66)/8192×5120)^2+2^66; 8192/128 102610013910009380864
(√(2^66)/8192×5248)^2+2^66; 8192/128 104069180189277421568

41
(√(2^66)/8192×5248)^2+2^66; 8192/128 104069180189277421568
(√(2^66)/8192×5376)^2+2^66; 8192/128 105564375265564426240

46
(√(2^66)/8192×5888)^2+2^66; 8192/128 111905443540902084608
(√(2^66)/8192×6016)^2+2^66; 8192/128 113580782602283909120

47
(√(2^66)/8192×6016)^2+2^66; 8192/128 113580782602283909120
(√(2^66)/8192×6144)^2+2^66; 8192/128 115292150460684697600

56
(√(2^66)/8192×7168)^2+2^66; 8192/128 130280130020573708288
(√(2^66)/8192×7296)^2+2^66; 8192/128 132315757052145172480

60
(√(2^66)/8192×7680)^2+2^66; 8192/128 138638810928973348864
(√(2^66)/8192×7808)^2+2^66; 8192/128 140818553148620668928

from the standpoint of probability, this doesn’t seem to mean anything, but you can try to look where else, according to this view Cool

Topic: Bitcoin puzzle transaction ~32 BTC prize to who solves it - page 64. (Read 245002 times)