Topic: Bitcoin puzzle transaction ~32 BTC prize to who solves it - page 95. (Read 215705 times)

Bitcoin address and hash160, has no meaning when searching for a private key.
You can select absolutely any search range and get the same results.

what is the best setting for an RTX 3090 with BitCrack? Is this the right setting? -b 128 -t 256 -p 1024

Have you read the instructions on what args you can use? The message says the problem is "-bits", try to get rid of -start. Either use bits or start:end.

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Really interesting, I was kind of looking for something similar having colored 3D view of points,  something in the vein of mandelbrot rendering.

Surprisingly using some of the points as G, makes some unique shapes,  for example,  having n/2 public key as G and viewed in "polar" makes interesting lines,  I could also see Fibonacci's patterns.  Here try these points as G and set start to end at 1, 99. Though you should try different ranges both in polar and 3D view.
Maybe we could find correlated connections based on each point differently, like e,g.  Having all the points generating spirals under one category, points generating triangles under one category, etc. Let me know what you think.

I would also like to! But if there is no pattern I find it difficult.
Too bad there is no Ramanujan in our time, I fear new mathematics is needed to solve it 

I am trying to solve the bitcoin puzzle mathematically.BTC

Theoretically speaking let's say I had a quantum computer with the computational power of a 100 qubit what algorithm would I use on qisqit python to run the program that would find the private key

How can i Use VanitySearch for Windows with .exe file for the Puzzle nr66? BitCrack dont work for me nothing happens after i enter the commands. Kangaroo and Keyhunt is to high for me to understand.

If i enter this command with Vanitysearch
./VanitySearch.exe -stop -t 0 -bits 66 -start 0000000000000000000000000000000000000000000000020000000000000000 -gpu 13zb1hQbWVsc2S7ZTZnP2G4undNNpdh5so

i get this message:

Unexpected -bits argument

can open your mind to new ideas such as keymath and keydivision..

Nice graphic. It won't help us much with the methods we're using here.

In summary, my search is 70%, I do not intend to take up your time waiting for a precise date, I do not take external factors into the equation when calculating the time, I live in an underdeveloped country where electrical failures are frequent, I have an i5 4GB ddr3, although I want to, I can't go faster, it is what it is, I got excited with the calculations and completely omitted the external factors, I have earned the criticism and I understand it, but it does not offend me, because my path continues.


no, I have not broken ecc, I never said it, otherwise, it would not take more than a month to find a key, breaking ecc is creating a formula that allows you to obtain the private key in an instant, this is not it, it is just a system of search faster than the already known ones, and it is easy to verify if a search code works or not, so I am not wrong.

edit:
It has not yet been proven that the ECDLP is computationally intractable, therefore in mathematics we cannot consider something impossible that you cannot prove to be impossible.

An algorithm has not been found that can solve the ECDLP in polynomial time, but it cannot be said that it does not have such a solution.

You can solve a problem in two ways:
1= solution.
2= no solution.
If you are going to come and tell me that ECDLP is unbreakable in polynomial time, publish the formula that shows that this is the case, otherwise don't see something as impossible just because it is difficult, if all humans had that way of thinking, society would It was still in the prehistoric era.

Yes, there are giant institutions studying this, this does not mean that you have to feel less than them, but that you can learn from them and overcome them.

And I conclude that if you try and fail, you will have learned something, if you consider yourself incapable you only gain ignorance.

similitudes with prime numbers...

https://www.youtube.com/watch?v=pnYkK6PqUro&ab_channel=voltagedrop

EC is a spiral curve like spring

try this 3d graph generator:



import matplotlib.pyplot as plt
from mpl_toolkits.mplot3d import Axes3D
import numpy as np

# parameters
p = 0xFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFEFFFFFC2F
a = 0
b = 7
Gx = 55066263022277343669578718895168534326250603453777594175500187360389116729240
Gy = 32670510020758816978083085130507043184471273380659243275938904335757337482424

# start + end decimal key
start = int(input("input start key: "))
end = int(input("input end key: "))

# generation
x = []
y = []
z = []
for i in range(start, end + 1):
    # point calculation index i
    Px = i * Gx
    Py = i * Gy
    x.append(Px % p)
    y.append(Py % p)
    z.append(i)

# 3D chart
fig = plt.figure()
ax = fig.add_subplot(111, projection='3d')
ax.plot(x, y, z, c='r', linewidth=2)

# add points on chart
for i, (xi, yi, zi) in enumerate(zip(x, y, z)):
    ax.text(xi, yi, zi, str(i), color='blue')

ax.set_xlabel('X')
ax.set_ylabel('Y')
ax.set_zlabel('Index')
ax.set_title('point on elliptic curve secp256k1 (3D graph)')

plt.show()

I agree with you, i hope to know what is he doing.

Based on mcdouglas' post-claim comments, I can feel his frustration when he encountered EC's punch in face! He's been tricked and overpowered by the Illusion-of-Mastery, which made him post such a big claim. I am not demotivating him, no no!! I am happy about him that he is learning good maths here. Trying to divide like 58.5 and figuring what half would be, good good, great!!!! Majority of guys here possibly have been through lots of similar curve punches here. Someone rightly figured out here that EC cannot be broken from inside, whatsoever!!!! The only thing attached to it from outside is its point at infinity, WHICH CAN'T BE TOUCHED DUE TO BEING AT INFINITY SOMEHOW I GUESS, OR MAY BE IDK!!
Whatever secret mcdouglasx has, I am sure many of guys here have already tried & tested and accordingly slapped in ass by EC! SORRY FOR THAT!!
The possibilities of EC being broken by any BTC puzzle enthusiast are very slim! Because there are giant research & security institutes (I know few of them personally visited as well) which are rigorously and systematically approaching towards the solutions to ECDLP.
I bet Satoshi must have a good laugh today, Cheers, it is 1st of Feb 24!!!

Oh thats right in any case puzzle 130 is still there:

1Fo65aKq8s8iquMt6weF1rku1moWVEd5Ua

@mcdouglasx was not targeting 66, but 130 with his new mysterious invention

Well, we're waiting  

puzzle 66 is still there @mcdouglasx

Sometimes calculations are off, could be +/- hours or days. And that's barring no down time via power outages, equipment failure, etc.

Hopefully he is close.

Today is the day for mcdouglasx to reveal his secret?

If your script giving you result, then ok, other word, it's simple solutions, for play with every floating points, I am not at laptop at this time, later explain if your script not working...