You can use Specific Heat Capacity
Q = m * C * ∆T
Q = heat transferred (in joules)
m = the mass of the substance (in kilograms)
C = the specific heat capacity of the substance (in joules per kilogram per degree Celsius)
ΔT/delta T= the change in temperature (in degrees Celsius
m=density×volume , air density at 20C = 1.2041 volume = 9000m3 so m = 10,836
c= of air is 1005
Delta T will depend on your room temperature and how much you want to raise the temps, let's say the normal room temp is 20c and you to raise it to 25, it would be 25-20 = 5
plug these in and you get
10,836*1005*5 = 54,450,900 joules
Now we need to figure out the time it takes for this to happen in order to find the power in watts needed
W = Q / T
Where W = watts, Q = Specific Heat Capacity , T = time in seconds
You say 5 S21s, it's 18,250W so in order to calculate time we would just inverse the equation and it becomes
T = Q/W
T = 49 minutes
If the outside temp is 5 and you need to hate the place to 25 then
200 mins for that to happen assuming no energy loss at all which is impossible, in fact, given the heat loss, you may never raise the room temp even by 2 degrees with that little heat, which is why real-life experience is crucial here, a professional who knows your country weather, the insulation you use, how often doors/windows are opened and all details that matter will be more accurate than any formula.
If we talk about real-life scenarios, it's 15c outside now, I run an 4KW AC in the living room, it keeps the living room and two rooms next to it pretty warm at 22c, the total area in cubic meters is roughly 300m3, the AC runs like 15 mins an hour, so you can say I use 1KW AC 24 hours to raise the temp in 300m3 area by 7 degrees if your place had the same condition as mine it would require 30KW running constantly 24/7.
I don't know about 35W per cubic meter seems like a lot, unless it's freezing outside and you want the room to be boiling hot, here is a random space heater calculated (based in the UK)
https://www.puravent.co.uk/calculator/space-heater
I plugged in your numbers which are 10*10*90 = 9000m3, with a delta T of 5c, it says 36KW is needed if your room is well insulated, 126KW if it's poorly insulated, which makes a lot of sense.
But with all seriousness, get a professional who would estimate the exact heat you need to operate your business, and then do the math based on that.