Sorry if I have overseen something here.
Topic: [Free Raffle] 12 MixTum collectible cards - page 4. (Read 2028 times)
The OP said: 12 MixTum collectible cards and we have only 10 winners
Sorry if I have overseen something here.
Sorry if I have overseen something here.
anyway - it's your (@GazetaBitcoin) first organized free raffle here in the collectibles section and considering the time pressure that it 'has' to be completed today, you have in my eyes done everything possible to make this free raffle as fair as possible for everyone.
of course there is room for improvement here and there, but everyone has started out like this to some extent and i strongly assume that your next free raffle will definitely cover all possible 'special aspects' (as far as the rules are concerned)
and congratulations to all the winners. as soon as i get the shipping addresses from whoever, i will send the [banned mixer] x Icarus cards to you
of course there is room for improvement here and there, but everyone has started out like this to some extent and i strongly assume that your next free raffle will definitely cover all possible 'special aspects' (as far as the rules are concerned)
and congratulations to all the winners. as soon as i get the shipping addresses from whoever, i will send the [banned mixer] x Icarus cards to you
legendary
Activity: 1680
Merit: 6524
Fully-fledged Merit Cycler|Spambuster'23|Pie Baker
that's why raffles should be 100 slots (00-99) or 16 slots (0-9,a-f). everything else is confusing. Don't understand the rationale/logic behind the 50 slots raffles anyway.
I can't speak for others, but in the case of this contest the reasons were the following: (1) a 16 slots raffle would not make sense for offering 12 prizes; (2) a 100 spots raffle would take too much to have the slots filled and the contest needs to finish before the end of the year. The prizes are subjected to mixers ban and the topic of the contest would be moved to Archival after the end of the year.
Yesterday were chosen 10 winners, the last one being NeuroticFish, the winner of block 823630.
Let's roll again with block 823695 for finding the next winner!
Last 2 digits of 823695 are 63. Since we don't have this number we'll take closest one => 42. tweetious is our eleventh winner!
Next block: 823698
Last 2 digits of 823698 are 07. krogoth is our eleventh winner!
that's why raffles should be 100 slots (00-99) or 16 slots (0-9,a-f). everything else is confusing. Don't understand the rationale/logic behind the 50 slots raffles anyway.
Would take 2x longer to fill?
The rational behind a 50 slot raffle is maximum participation in a shorter, more efficient time frame. If you're talking about running a raffle, filling all 100 slots and have a couple/few weeks or months available, then 100 slots may work. However, if you're looking at a day or a few days to a week, then 50 slots fit the bill better than 100 slots.
see krogoths solution in their raffles: reroll until there's a winner 
Yes I understand that, I just meant perhaps it is the mindset, not necessarily based on the maths/details.
that's why raffles should be 100 slots (00-99) or 16 slots (0-9,a-f). everything else is confusing. Don't understand the rationale/logic behind the 50 slots raffles anyway.
Would take 2x longer to fill?
Based on the op we should not oppose now as it is a time to roll even after starting the rolling. No one stopped us from taking the rolls 50, 49, and so on. We took based on our demand and free slot. Now changing any terms will not be fair though I took slot 00. Yet I think this should be completed based on the stated way. Many people didn't take from last on or near as the person could to understand this way or slot wasn't available. But now asking to reinitiate the terms is useless.
Yes, but as we are accustomed habitually for this draws any number bigger that [50 for this case] is just ignored and we wait for a next block!
I dont think anyone is opposing this its just that according to the rules any number drawn
per each of the 12 blocks greater than 50 JanEmil will automatically win that draw because
his guess [50] will be nearer every number from 51 to 99.
I read it differently in the op, I read it or assumed it as a standard rolling raffle.
it is what it is, its a FREE raffle, we should be thankful for that.
legendary
Activity: 1680
Merit: 6524
Fully-fledged Merit Cycler|Spambuster'23|Pie Baker
Yes, but as we are accustomed habitually for this draws any number bigger that [50 for this case] is just ignored and we wait for a next block!
You could be correct if it was mentioned at the time of posting the ann or anyone who is now opposing including you could say about this at the time of starting the ann. Even it could be considered if it had arisen before starting the roll. Yet it might require to repost and reschedule the slot. Now all is bad except completing the total phase as on the mentioned OP. Rules are rules whether it favors me or not.This is correct. Everybody saw the rules since the topic was launched. Everybody which joined this raffle did it voluntarily, with no coercion. By joining the raffle participants agreed to follow the stated rules. Good or bad, they were set. I already made mea culpa for not anticipating some possible issues. But from here to blaming someone which offers free goodies is a long distance.
Based on the op we should not oppose now as it is a time to roll even after starting the rolling. No one stopped us from taking the rolls 50, 49, and so on. We took based on our demand and free slot. Now changing any terms will not be fair though I took slot 00. Yet I think this should be completed based on the stated way. Many people didn't take from last on or near as the person could to understand this way or slot wasn't available. But now asking to reinitiate the terms is useless.
Yes, but as we are accustomed habitually for this draws any number bigger that [50 for this case] is just ignored and we wait for a next block!
IMHO 2stout's method (hereafter reffered to as "2SM") is just the easiest way to deal with this. 50 applicants (or any other number in fact), rolling, last two numbers, zero included. Rolling.
Did anyone win? Great.
No? Next block.
Still no? Next block.
Until there's a winner. Good, clean fight. (Or fun, whatever.)
Did anyone win? Great.
No? Next block.
Still no? Next block.
Until there's a winner. Good, clean fight. (Or fun, whatever.)
legendary
Activity: 1680
Merit: 6524
Fully-fledged Merit Cycler|Spambuster'23|Pie Baker
Instead of that may I propose, (and if Mr JanEmil is volunteer ti switch his spot to spot n° 26!), to make to calculus for numbers bigger to 49 like
I am not changing the rules while the contest is on-going.
But you didn't state the rules about the draw at all !
Actually, I did. Have you read OP?
After all places are filled I will choose 12 blocks. Once a block is chosen, the last digits of the hash will determine the winner.
If nobody guessed correctly the last digits of the block then winner will be the one with closest prediction.
If nobody guessed correctly the last digits of the block then winner will be the one with closest prediction.
Based on the op we should not oppose now as it is a time to roll even after starting the rolling. No one stopped us from taking the rolls 50, 49, and so on. We took based on our demand and free slot. Now changing any terms will not be fair though I took slot 00. Yet I think this should be completed based on the stated way. Many people didn't take from last on or near as the person could to understand this way or slot wasn't available. But now asking to reinitiate the terms is useless.
Yes, but as we are accustomed habitually for this draws any number bigger that [50 for this case] is just ignored and we wait for a next block!
That solution gives disadvantage to number 00.
No because 50 -(minus) 50 = 00 !
00 -to> 99 is 100 spots?, which is two times 50 !
Based on the op we should not oppose now as it is a time to roll even after starting the rolling. No one stopped us from taking the rolls 50, 49, and so on. We took based on our demand and free slot. Now changing any terms will not be fair though I took slot 00. Yet I think this should be completed based on the stated way. Many people didn't take from last on or near as the person could to understand this way or slot wasn't available. But now asking to reinitiate the terms is useless.
That solution can work too.
OK
Last 2 digits of 823593 are 88. Since we don't have this number we'll take closest one => 50. JanEmil is our first winner!
Next block: 823596!
Last 2 digits of 823596 are 48. Bullion-n-BTC is our second winner!
Next block: 823598!
Last 2 digits of 823596 are 69. Since we don't have this number we'll take closest one => 49. Willi9974 is our third winner!
Next block: 823599!
Last 2 digits of 823599 are 86. Since we don't have this number we'll take closest one => 47. hopenotlate is our fourth winner!
Next block: 823602!
Last 2 digits of 823602 are 38. BABY SHOES is our fifth winner!
Next block: 823604!
Instead of that may I propose, (and if Mr JanEmil is volunteer ti switch his spot to spot n° 26!), to make to calculus for numbers bigger to 49 like :
* 88 -(minus)50 = 38
* 69 - 50 = 19 etc.
So we subtract 50 for any number bigger between [50 and 99] !
Shouldn't we ignore what's higher than 50? Otherwise, the person who chooses 50 gets like way more advantage.
I guess since I did not state that in rules since the beginning it would be too late and not correct to do it now...
But you didn't state the rules about the draw at all !
The best way to do it would be like krogoth do his weekly raffles : 100 spots and a determined date to close the applications, and chose the block number no matter if all spots are full or not. 1% for everyone applying
That requires 100 spots, which is pretty limiting. The best way to do it is to simply ignore every invalid number. For example, in our case, if a block hash ends with "05f1159", the winner is 11. If it ended with "199999", the winner is 19. If the next one ended with "000119", the winner is 01 (19 is ignored, because they already won). The main purpose was to offer the prizes. I did not calculate thoroughly all mathematical possible issues.
I believe you can still fix this if you redo the process (e.g., plan another block to begin the raffle). I don't think anyone would disagree. It's just the fair thing to do.
No stress. Just because all would like to win a fine card. That is good sign.
I apologize for this, as I apologize as well for not anticipating the possible issue raised by cygan. Please bear in mind that this is my first free raffle though and have some understanding with me. I am sorry if I did not meet the standards of Collectibles board and all strategies. The main purpose was to offer the prizes. I did not calculate thoroughly all mathematical possible issues.
You are doing great!
I mean, we just need to re-roll each block which is > 50 and use the next one if we want to be fair, everything else is perfectly fine with this raffle imo
legendary
Activity: 1680
Merit: 6524
Fully-fledged Merit Cycler|Spambuster'23|Pie Baker
I personally don't mind much, but it's just unfair competition. The closer you are to 50, the more odds you have to win, statistically. The last participant (in terms of selected number) gets more than 50% chance to win, always.
I apologize for this, as I apologize as well for not anticipating the possible issue raised by cygan. Please bear in mind that this is my first free raffle though and have some understanding with me. I am sorry if I did not meet the standards of Collectibles board and all strategies. The main purpose was to offer the prizes. I did not calculate thoroughly all mathematical possible issues.
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