Topic: [Free Raffle] 12 MixTum collectible cards - page 5. (Read 1899 times)

No hard feelings to correct it for me.

I guess since I did not state that in rules since the beginning it would be too late and not correct to do it now...

Shouldn't we ignore what's higher than 50? Otherwise, the person who chooses 50 gets like way more advantage.

Last 2 digits of 823593 are 88. Since we don't have this number we'll take closest one => 50. JanEmil is our first winner!

Next block: 823596!

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Last 2 digits of 823596 are 48. Bullion-n-BTC is our second winner!

Next block: 823598!

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Last 2 digits of 823596 are 69. Since we don't have this number we'll take closest one => 49. Willi9974 is our third winner!

Next block: 823599!

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Last 2 digits of 823599 are 86. Since we don't have this number we'll take closest one => 47. hopenotlate is our fourth winner!

Next block: 823602!

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Last 2 digits of 823602 are 38. BABY SHOES is our fifth winner!

Next block: 823604!

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Last 2 digits of 823604 are 65. Since we don't have this number we'll take closest one => 46. wwzsocki is our sixth winner!

Next block: 823610!

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Last 2 digits of 823610 are 53. Since we don't have this number we'll take closest one => 45. bitbollo is our seventh winner!

Next block: 823616!

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Last 2 digits of 823616 are 38, which was a previous winner block. Both 37 and 39 are at equal distance to 28, this block is invalid.

Next block: 823622!

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Last 2 digits of 823622 are 49, which was a previous winner block. Since we don't have this number anymore we'll take closest one => 44. mv1986 is our eighth winner!

Next block: 823624!

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Last 2 digits of 823624 are 71. Since we don't have this number anymore we'll take closest one => 43. Caribbean_Treasures is our ninth winner!

Next block: 823630!

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Last 2 digits of 823630 are 28. NeuroticFish is our tenth winner!

Yeeeah 
Good luck guys!

Okay, let's roll with block 823593!

Raffle updated once more! There is one remaining available number: 26. If it won't be filled in 1-2h or so we'll roll anyway. Good luck everybody!
There are 12 prizes and 50 spots, so the parity is 0.24. In other words, this means that each participant has almost 25% chances to win a prize

25 - DYING_S0UL

34 - moparminingllc thank you!

35 - Buchi-88

Thank you

Thank you for this
I take the Number 3

14 - anonymousminer

Thank you

36 - mendace

06- rifmax

Good luck

11 - fillippone

gotcha!
such a rule can only be found in the free raffles that have more than one prize to give away - because several winners are determined there

Raffle updated once more! There are 9 remaining available numbers available:
03
06
11
14
25
26
34
35
36

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Apparently you also did not read carefully the rules. You are not eligible for the contest.

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I inspired my rules from other similar raffles and I didn't see anywhere such a rule... I guess the odds for this to happen are minuscule Anyway, we should not have a winner with more than one prize. So there will be 12 winners for the 12 cards. so if the situation you described above actually happens (although I hope it won't ) then the winner of the next block which has same digits as a previous block will be the one with the closest prediction to those digits.

35 - bestcoin_59
Thanks for the raffle

Sorry for that.

47 - hopenotlate

Thanks again

@GazetaBitcoin what happens to the blocks that show the same last two digits again - does the user win a second or even third card or is the block then 'invalid' and a new attempt is started?
unfortunately this is not clear from the rules