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Topic: Gambler's fallacy, what do you think? - page 3. (Read 5873 times)

sr. member
Activity: 434
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:)
March 26, 2015, 10:50:57 PM
#62
Each game is diferent, some games like casinos online (Who don't have a provably fair system) chose if you win or lost by the house winning, simple maths, if casino say the house odds are 95%, you will stop losing when the casino cover that 5% for the house. In that case your last bet will affect your next bet.

But other sites like Satoshi bones, or lucky bit (Who have a provably fair system) chose the bet result from the "Tx ID" and other factors. This way, your last bet don't will affect your next bet and with the right luck you can get the jackpock every bet.

Some times i think some sites have an anti-martingale system... if $bet = $bet*2; then; lose.
Speaking of gamblers fallacy, lol. Fortunately provably fair fixes this
legendary
Activity: 3192
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Top Crypto Casino
March 26, 2015, 01:19:18 PM
#61
Each game is diferent, some games like casinos online (Who don't have a provably fair system) chose if you win or lost by the house winning, simple maths, if casino say the house odds are 95%, you will stop losing when the casino cover that 5% for the house. In that case your last bet will affect your next bet.

But other sites like Satoshi bones, or lucky bit (Who have a provably fair system) chose the bet result from the "Tx ID" and other factors. This way, your last bet don't will affect your next bet and with the right luck you can get the jackpock every bet.

Some times i think some sites have an anti-martingale system... if $bet = $bet*2; then; lose.
legendary
Activity: 1302
Merit: 1005
New Decentralized Nuclear Hobbit
March 26, 2015, 01:06:35 PM
#60
If something has a 50% chance of happening, it has a 50% chance of happening, what has happened beforehand makes no difference.

Wrong! (I love to debate)

There is 50% chance that A will get a tail. A died. The chance is 0%.  Grin
Or the site you were betting went down..

Now, who is talking for?
legendary
Activity: 1526
Merit: 1000
March 26, 2015, 12:47:40 PM
#59
The concept is pretty confusing actually. If you consider the odds of 11th Head after 10 heads, then its 50% , however if you consider the odds of 10 simultaneous heads, then thats very less , and the odds of 11 heads is lower, and so on.
So overall the gamblers fallacy isn't true but a tails to happen soon does increase by a bit according to me.

You don't care about the odds of throwing 11 heads in a row, after you already did 10. There is only 1 left to throw so it is 50/50.

The odds of throwing 11 heads in a row is (1/2)^11. That's the same as ((1/2)^10) * (1/2). The bold is throwing the first 10, AFTER you've thrown 10 heads in a row the odds of throwing 11 in a row are 50/50.

Yes thats true, but what I mean was say the odds of throwing the first 10 in a row is very low,  then the odds of throwing 11 heads is even lower and hence chance of tails coming up to satisfy the natural existing probability  of 50-50 should increase.

It doesn't. The odds of throwing the 11th are 50/50. To satisfy getting to 50/50 overall you just need to keep flipping the coin and getting 50% heads, look for my post earlier in this thread where I break it down.
hero member
Activity: 910
Merit: 1000
March 26, 2015, 12:30:44 PM
#58
The concept is pretty confusing actually. If you consider the odds of 11th Head after 10 heads, then its 50% , however if you consider the odds of 10 simultaneous heads, then thats very less , and the odds of 11 heads is lower, and so on.
So overall the gamblers fallacy isn't true but a tails to happen soon does increase by a bit according to me.

You don't care about the odds of throwing 11 heads in a row, after you already did 10. There is only 1 left to throw so it is 50/50.

The odds of throwing 11 heads in a row is (1/2)^11. That's the same as ((1/2)^10) * (1/2). The bold is throwing the first 10, AFTER you've thrown 10 heads in a row the odds of throwing 11 in a row are 50/50.

Yes thats true, but what I mean was say the odds of throwing the first 10 in a row is very low,  then the odds of throwing 11 heads is even lower and hence chance of tails coming up to satisfy the natural existing probability  of 50-50 should increase.
legendary
Activity: 1526
Merit: 1000
March 26, 2015, 11:35:12 AM
#57
The concept is pretty confusing actually. If you consider the odds of 11th Head after 10 heads, then its 50% , however if you consider the odds of 10 simultaneous heads, then thats very less , and the odds of 11 heads is lower, and so on.
So overall the gamblers fallacy isn't true but a tails to happen soon does increase by a bit according to me.

You don't care about the odds of throwing 11 heads in a row, after you already did 10. There is only 1 left to throw so it is 50/50.

The odds of throwing 11 heads in a row is (1/2)^11. That's the same as ((1/2)^10) * (1/2). The bold is throwing the first 10, AFTER you've thrown 10 heads in a row the odds of throwing 11 in a row are 50/50.
sr. member
Activity: 378
Merit: 250
Pre-sale - March 18
March 26, 2015, 09:16:56 AM
#56
I beleive in ebating the casion yo will need its bankroll plus another 35 percent more funds, to truly beat the house.




You would only beat the casino if it had no max bet but pretty much all the casinos do have a max bet

Yes that too.
legendary
Activity: 1862
Merit: 1004
March 26, 2015, 08:16:07 AM
#55
If something has a 50% chance of happening, it has a 50% chance of happening, what has happened beforehand makes no difference.
From the mathematical point of view it is completely true. Yet people are not "mathematical" creatures they tend to have flawed logic of things. From my experience my and my friends noticed that we are all biased by gambler's fallacy. The best example here is slots, I lost too much money thinking that 'this time would be different' during the game.
hero member
Activity: 490
Merit: 500
March 26, 2015, 07:11:39 AM
#54
The concept is pretty confusing actually. If you consider the odds of 11th Head after 10 heads, then its 50% , however if you consider the odds of 10 simultaneous heads, then thats very less , and the odds of 11 heads is lower, and so on.
So overall the gamblers fallacy isn't true but a tails to happen soon does increase by a bit according to me.


Wrong. in 3 bets you have this possibilities:

HEADS HEADS HEADS
HEADS HEADS TAILS
HEADS TAILS HEADS
HEADS TAILS TAILS
TAILS TAILS TAILS
TAILS TAILS HEADS
TAILS HEADS TAILS
TAILS HEADS HEADS

12.5% chance of each of them

If you get 2 heads in a row then this is what is left

(HEADS HEADS) HEADS

(HEADS HEADS) TAILS

50% EACH
legendary
Activity: 2282
Merit: 1035
March 26, 2015, 07:02:24 AM
#53
Theory is theory.. In practice there always is % House Edge so website owner (casino owner) is taking his part and in this way there never is 50%
hero member
Activity: 910
Merit: 1000
March 26, 2015, 06:58:09 AM
#52
The concept is pretty confusing actually. If you consider the odds of 11th Head after 10 heads, then its 50% , however if you consider the odds of 10 simultaneous heads, then thats very less , and the odds of 11 heads is lower, and so on.
So overall the gamblers fallacy isn't true but a tails to happen soon does increase by a bit according to me.
hero member
Activity: 490
Merit: 500
March 26, 2015, 06:47:36 AM
#51
Googled it.



yeah because you cant use those scientific calculators to calculate a number with so many zeros what i did and i dont know if it was correct was, 0.5 ^ 10 is 3 zeros, 0.5^ 100 is 30 zeros so i asumed that 0.5 ^ 10.000 was 3000 zeros

You are almost correct there. Smiley
There should be 3010 zeros after the decimal point as 0.5^10000 = 5.01237274920645200929755593374297774932156778133842583 × 10^-3011
http://www.wolframalpha.com/input/?i=0.5^10000

Oh nice i didnt know about that site, yeah i knew there must have been some more zeros i just didnt know how many thanks for the info tho.
legendary
Activity: 910
Merit: 1000
March 26, 2015, 06:39:30 AM
#50
Googled it.



yeah because you cant use those scientific calculators to calculate a number with so many zeros what i did and i dont know if it was correct was, 0.5 ^ 10 is 3 zeros, 0.5^ 100 is 30 zeros so i asumed that 0.5 ^ 10.000 was 3000 zeros

You are almost correct there. Smiley
There should be 3010 zeros after the decimal point as 0.5^10000 = 5.01237274920645200929755593374297774932156778133842583 × 10^-3011
http://www.wolframalpha.com/input/?i=0.5^10000
hero member
Activity: 490
Merit: 500
March 26, 2015, 06:06:17 AM
#49
Googled it.



yeah because you cant use those scientific calculators to calculate a number with so many zeros what i did and i dont know if it was correct was, 0.5 ^ 10 is 3 zeros, 0.5^ 100 is 30 zeros so i asumed that 0.5 ^ 10.000 was 3000 zeros
legendary
Activity: 1302
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New Decentralized Nuclear Hobbit
March 26, 2015, 05:40:32 AM
#48
Googled it.

hero member
Activity: 490
Merit: 500
March 26, 2015, 05:34:27 AM
#47
hero member
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March 26, 2015, 05:27:05 AM
#46
hero member
Activity: 490
Merit: 500
March 26, 2015, 05:25:43 AM
#45
lol, had already answered all those yesterday. Wink


Well Gambler's Fallacy is derived from the law of large numbers. Of course if you flip a coin 10,000 times with all heads, the next flip is still a 50/50 but the odds of that happening are really low.

--snip--


That would be the chances of getting 10.000 heads in a row if im not mistaken

That is definitely not right. The odds of getting 10 heads in a row is 0.09% . And not the figure you have posted.

Any questions? Tongue

(If you are confusing '.' and ',' read : http://en.wikipedia.org/wiki/Decimal_mark#Countries_using_Arabic_numerals_with_decimal_point
Easy way to identify is if there are 3 zeroes, it is thousands and not a decimal point usually.)

Yep thats what i said and it was obvious i was talking about 10 thousand since the probability for it is almost impossible and anyways no one would be able to survive more than 50 heads in a row unless he was betting static bets but i dont see why would anyone do that
legendary
Activity: 1302
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New Decentralized Nuclear Hobbit
March 26, 2015, 05:18:00 AM
#44
lol, had already answered all those yesterday. Wink


Well Gambler's Fallacy is derived from the law of large numbers. Of course if you flip a coin 10,000 times with all heads, the next flip is still a 50/50 but the odds of that happening are really low.

--snip--


That would be the chances of getting 10.000 heads in a row if im not mistaken

That is definitely not right. The odds of getting 10 heads in a row is 0.09% . And not the figure you have posted.

Any questions? Tongue

(If you are confusing '.' and ',' read : http://en.wikipedia.org/wiki/Decimal_mark#Countries_using_Arabic_numerals_with_decimal_point
Easy way to identify is if there are 3 zeroes, it is thousands and not a decimal point usually.)
hero member
Activity: 490
Merit: 500
March 26, 2015, 05:10:30 AM
#43
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