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Topic: I find way to win on dice - page 11. (Read 2138 times)

hero member
Activity: 3038
Merit: 634
October 05, 2022, 03:25:30 AM
#9
Do only 50% bet 20$ every time if it fails do 60$ it fails do 150$ if it fails do 350$ if it fails do 900$ if it fails do 2300$

There is no way you will fail 7 times and if you do just increase the bet and you will get it back eventually even if you wait 12 times.

what you think on my method?
It's a known method, martingale.

Good luck with that method and for the first try maybe you're able to win at your 7th bet or earlier than that. But to tell you,it's a risky strategy and it's hard to win with that strategy in the long run.

You may win with some of your bets at the beginning or you'll able to recover it back when you bet double with your latest lose. But, how long you'll think that luck is with you because this isn't ideal for those that have a limited budget.
legendary
Activity: 3584
Merit: 5248
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October 05, 2022, 03:24:19 AM
#8
--snip--

If you have  50k budget to bet there is no way you get 20 red in a rows. i think can make bank with this mehtod if you have good budget.

Sure there is... Let's assume there is no house edge (aka, the most profitable scenario from your point of view). I'm also assuming "original" martingale where you double on losing and reset on winning (your martingale approach will make you lose more money faster during a losing streak, so it'll be even worse)
The odds of rolling 1 time and losing: 1/2, you just lost $20
The odds of rolling 2 times and losing: 1/2 * 1/2 = 1/4, you just lost $20 + $40 = $60
The odds of rolling 3 times and losing: 1/8, you just lost $60 + $80 = $140
The odds of rolling 4 times and losing: 1/16, you just lost $140 + $160 = $300
5 => 1/32, you just lost $300 + $320 = $620
6 => 1/64, you just lost $620 + $640 = $1260
7 => 1/128, you just lost $1260 + $1280 = $2540
8 => 1/256, you just lost $2540 + $2560 = $5100
9 => 1/512, you just lost $5100 + $5120 = $10220
10 => 1/1024, you just lost $10220 + $10240 = $20460
11 => 1/2048, you just lost $20460 + $20480= $40940

And you're done... your $50k bankroll can no longer suffice for continuing...
if you try to win $20 (cause that's all you'll win) for 2048 times, on average you'll lose $40k of your $50k bankroll...
hero member
Activity: 2800
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October 05, 2022, 03:23:54 AM
#7
You should start with the very minimum amount to minimize risk. Maybe start with 1$ if you have that huge amount of money willing to bet on dice with such strategy.

Losing  10x I think is actually common to dice players. Call it rigged. But stop when you make money out of it.  Probably try a budget of jusy 100$ and start with $0.10 if they allow.
legendary
Activity: 3668
Merit: 6382
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October 05, 2022, 03:20:59 AM
#6
If you have  50k budget to bet there is no way you get 20 red in a rows. i think can make bank with this mehtod if you have good budget.
at least for short term you must be extremly  unlucky to to fail with it. Or  have casino games rigged.

You're wrong. I've looked up for you a little and you can see here some math about 15 reds in a row. It's an example and it shows that the chance does exist.
Indeed, for 15-20 reds in a row you have to be very unlucky, but it's basic math, the longer you play the bigger the chance even the events with small odds can happen.


When I play dice I do something somewhat similar with your logic, but with a very big difference: if I get to a 4-5 losing streak already I stop and go back to the initial amount. And you know why? Because it's not worth to wager 1000s of dollars to basically try to recover 20$ (give or take).
member
Activity: 1103
Merit: 76
October 05, 2022, 03:18:47 AM
#5
Do only 50% bet 20$ every time if it fails do 60$ it fails do 150$ if it fails do 350$ if it fails do 900$ if it fails do 2300$

There is no way you will fail 7 times and if you do just increase the bet and you will get it back eventually even if you wait 12 times.

what you think on my method?

Your method is just another variation of Martingale.
You forget that the value the dice shows is not related to the value it has shown at the previous throw.
You forget that you don't have infinite money and the casino doesn't allow you wager over a certain amount.
And you're wrong, there can be that you fail 7 or more times in a row.

So no, sorry, imho your method is not as good as you would think. Do some research on how tricky and bad Martingale is.


Edit: I see hosseinimr93 was faster; I will leave this because I feel I covered a bit more, but if somebody more objective considers this as being duplicate please PM me and I'll remove.


If you have  50k budget to bet there is no way you get 20 red in a rows. i think can make bank with this mehtod if you have good budget.
at least for short term you must be extremly  unlucky to to fail with it. Or  have casino games rigged.
here is a thread where people shared their losing streaks before, mine was 14 losing streaks
https://bitcointalk.org/index.php?topic=5245375.20

Also if there is a winning method that is when there is a loophole in the system, like if the dice system was coded very bad
example of it was PRC when a player found out that he can win if he plays a certain strat and by playing long-term because the variance was against the casino.
newbie
Activity: 56
Merit: 0
October 05, 2022, 03:12:21 AM
#4
Do only 50% bet 20$ every time if it fails do 60$ it fails do 150$ if it fails do 350$ if it fails do 900$ if it fails do 2300$

There is no way you will fail 7 times and if you do just increase the bet and you will get it back eventually even if you wait 12 times.

what you think on my method?

Your method is just another variation of Martingale.
You forget that the value the dice shows is not related to the value it has shown at the previous throw.
You forget that you don't have infinite money and the casino doesn't allow you wager over a certain amount.
And you're wrong, there can be that you fail 7 or more times in a row.

So no, sorry, imho your method is not as good as you would think. Do some research on how tricky and bad Martingale is.


Edit: I see hosseinimr93 was faster; I will leave this because I feel I covered a bit more, but if somebody more objective considers this as being duplicate please PM me and I'll remove.


If you have  50k budget to bet there is no way you get 20 red in a rows. i think can make bank with this mehtod if you have good budget.
at least for short term you must be extremly  unlucky to to fail with it. Or  have casino games rigged.
legendary
Activity: 3668
Merit: 6382
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October 05, 2022, 03:00:29 AM
#3
Do only 50% bet 20$ every time if it fails do 60$ it fails do 150$ if it fails do 350$ if it fails do 900$ if it fails do 2300$

There is no way you will fail 7 times and if you do just increase the bet and you will get it back eventually even if you wait 12 times.

what you think on my method?

Your method is just another variation of Martingale.
You forget that the value the dice shows is not related to the value it has shown at the previous throw.
You forget that you don't have infinite money and the casino doesn't allow you wager over a certain amount.
And you're wrong, there can be that you fail 7 or more times in a row.

So no, sorry, imho your method is not as good as you would think. Do some research on how tricky and bad Martingale is.


Edit: I see hosseinimr93 was faster; I will leave this because I feel I covered a bit more, but if somebody more objective considers this as being duplicate please PM me and I'll remove.
legendary
Activity: 2380
Merit: 5213
October 05, 2022, 03:00:12 AM
#2
This method is called martingale strategy.
You increase the bet amount every time you lose and return to the base amount if you win the bet.
If this method could work, all casinos would have gone bankrupt by now.
The house edge is always against you and users always lose in the long run.


There is no way you will fail 7 times and if you do just increase the bet and you will get it back eventually even if you wait 12 times.
It's possible to lose many more bets consecutively.
To be successful, you need an unlimited balance which is impossible.  
newbie
Activity: 56
Merit: 0
October 05, 2022, 02:54:35 AM
#1
Do only 50% bet 20$ every time if it fails do 60$ it fails do 150$ if it fails do 350$ if it fails do 900$ if it fails do 2300$

There is no way you will fail 7 times and if you do just increase the bet and you will get it back eventually even if you wait 12 times.

what you think on my method?
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