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Topic: Martingale Question - Risk Big or Stay Safe? - page 2. (Read 688 times)

legendary
Activity: 1470
Merit: 1002
Either way, i will see it as the same as the percentage of winning is always less than half and the difference is not a lot. It is more of what is your objective of playing. Are you looking for a huge win or a lot of small successes. Understand your gambling needs and address them accordingly. Otherwise you are just playing for the sake of playing.
hero member
Activity: 1302
Merit: 540
thanks for sharing this mate, it gather my attention when i see your strategy if luck accompany us with this a good profits will follow,
the only thing with dice games or any other luck base games even you got a good method the possibility to burned your bankroll is
really big, will try to study this and use the faucets rewards.
hero member
Activity: 1470
Merit: 655
maybe it is just me but i don't like these numbers much, i mean making calculations like this. because in dice it will always come down to luck. you can start betting with 0.01% chance of win and then win on the first roll! or do the same and never win not even after 463 times or 926 or 1389 times.

and that is why i don't like the second strategy (risking big). and also not the first safe one either. i prefer a more "in the middle" kind of strategy. and that means not 0.01% and not 90% chance. something along the lines of 40% to 60% chance of winning is good for me.
hero member
Activity: 1568
Merit: 511
What's your strategy here?

I have came across with this question and doubt and for me

Risking safe
Win rate 55% and Above with martingale require a very huge bankroll and the rate of return is okish, still one streak lose and you are done.

Risking big
Win rate <50%, i even tried with a win rate of 0.01 - 0.05%. Basically a 0.01 is the same chance as hitting a jackpot of number 77.77. It is very risky and somehow its almost impossible but the reward is just god damn huge.

With the setting
Bankroll : $10
base bet : 100 Satoshi
0.05% win chance
increment on loss of 1.01%



Result of simulate with Seuntjie dice Bot [ Each try with $10]
- Lose
- Lose
- Lose
- Lose
- Win on bet #201 , Profit 0.013 Btc
- Lose
- Lose
- Win on bet #286, Profit 0.032 Btc
- Win on bet #245, Profit 0.021 Btc
- Win on bet #166, Profit 0.009 Btc
- Lose
- Lose
- Lose
- Lose
- Lose
- Lose
- Win on bet #234, Profit 0.019 Btc
- Lose
- Win on bet #344, Profit 0.057 Btc
- Lose
- Win on bet #356, Profit 0.066 Btc
- Lose
- Lose
- Win on bet #65, Profit 0.003 Btc
- Lose
- Lose
- Lose
- Lose
- Lose
- Win on bet #402, Profit 0.1 Btc


Result of 30 Bet
Win - 9 Time - 0.32 Btc
Losses - 21 Time - 0.21 Btc

9/30 * 100% = 30%
Will do more times as require a huge tries to calculate the true value




With $10, it can afford to lose 463 Time
To achieve a losing streak of 463 Time, the chance of occur with 0.05% chance is 79.329677%.
Of course, this does not mean that we will have 21% chance of wining when we are on the 463 time, we are still having the same winning chance.
Anyhow, if we really got lucky to win
If we wini at streak number #401 ~ #463
The Winning Profit = 0.1 btc ~ 0.18 btc ~ $100 - $200

From this calculation, could the statement below be made
Risking $10 for $100 with a chance of 21%?
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