63a169e28af90b75159c93ac88638314 -0000006f7d4a376f241adf3febd1ce73
779155e640a6f97c0d87b47ee5eec0f6 00000bc152a6b02a0bc5730dd5be8ae0
Since these are all 128-bit numbers I'm guessing the left numbers are tame kangaroo positions and the right numbers are distances (with their bit 126 set to 0=TAME constant) right?
This might sound like a dumb question but I also assume the px and py pointers above are the public keys right? No way those can be private keys or kangaroo positions because there are two of these.
Yes, if you looked at a tame file, the left is pubkey x coord and that pubkey's priv key is on the right side. For the wild, the distance is based off of Y coord position, not distance traveled...I do believe that's how it works. Basically, if you took a wild dp and ran the priv key, it wouldn't correlate to the pubkey but the tames do.
Here are examples of mine:
Tames
3AA3BB15292F3A2688A85F1DC635E159BF18120631AE07AA4844EF9D00000000 000000000000000000000000000000000000000000136B4461F2984CBB55F8CA
1B91BF8C8C3993578623E10E9D979FE8C3FAE2C390A48997930416A700000000 0000000000000000000000000000000000000000001E70CC8AAB08D481DD25AD
Wilds
087A24CA49535730AAEFBAB161100740BECF3187F27E9F94FA34709B00000000 0000000000000000000000000000000000000000000A021D0CD9D38B5BA7639D
79E73EC2D79A6E794B692B03910D31137936859E9505B92316AA807000000000 00000000000000000000000000000000000000000001D3C65E1F9264DECB72ED