balance 6234 mb (1/2 = 3117mB)
wagered = 98456mB = lvl 6 = 0.9% house edge
first roll: 3117mB on 49%; loss total wagered: 101573mb = lvl 7 =0.88% house edge = -3117mB profit
second roll : 3117 mB on 49% , @ 0.88 house edge win
= +3188.2 mB profit
total session profit = -3117mB + 3188.24571mB
=+71.24571mB
sorry if process is a bit blurry, had to do it fast, haha! hope its correct though..
USERNAME: CASIO
Yes, you got it correct.
Trivia Winner : CASIO10 m
BTC sent.
Runner-ups: (1 m
BTC each)
forfuna,
kshyzer and
fumblingperch. Your answers are correct. Good job and Keep it up.
kshyzer has however taken a different interpretation of the problem which is not wrong though I hadn't thought of taking it that way. The decimal and the thousands separator is taken to be of the same as Rollin uses.
Question : X, who has wagered 98,456 mBTC has a balance of 6,234 mBTC at Rollin at the time. He bets half of the balance at 49% win chance and loses and then goes all-in at 49% win chance and wins. What is his profit or loss? Show working.
Level House Edge Wagered amount
6 0.90 % 50000 m฿
7 0.88 % 100000 m฿
Let us check the first bet,
Bet : 3117 m
BTCWin chance : 49%
House Edge : 0.9%
Result : Lose
Payout : 0.
New Level 7. (Since the total wagered now passes 100,000 m
BTC)
And the second bet,
Bet : 3117 m
BTCWin chance : 49%
House Edge : 0.88%
Result Win
Payout : 6305.24571 m
BTCTotal bet : 6,234 m
BTCTotal payout : 6305.24571 m
BTCProfit: 71.24571 m
BTC