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Topic: ¦¯¦¦¯¦ROLLIN.IO¦¯¦¦¯¦Rollin 2017 New Year ¦¯¦ $500 Lottery Prizes ¦¯¦ CLOSED ¦¯¦ - page 4. (Read 6113 times)

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Draw methodology
1. I take a Block hash from a certain Bitcoin block. I will of course announce which block to use before the Draw*. I realize this is not perfectly random, but it is totally unpredictable, which is random enough for me.
I want a system that can easily be verified by anybody.

2. I create a md5sum of the hash. I do this command line, if you save the hash to a file you can do it online. For multiple prizes I'll use a nonce (add a growing number (1,2,3,4,...) to the block hash), and start with the highest prize. This way, if one person wins more than one prize on the same day, he'll only get the first price (as explained in the Rules), and I'll use the next nonce to pick the next winning number.

3. From the resulting md5sum, I use only the numbers. I take the first 8, divide it by the number of tickets, and the remainder of this equation will be the winning number. If the remainder is zero ("0"), the last ticket (AKA "the number of tickets") wins.
Wolfram Alpha can be used to easily calculate the remainder.

These Block hashes will be used for the Draws
December 17: 443900
December 18: 444000

Example for a Draw with 2 prizes:
First prize
1. Use Block #440000, mined November 22
Block hash: 0000000000000000038cc0f7bcdbb451ad34a458e2d535764f835fdeb896f29b

2. md5sum: d4defe3908df871b4c256de36d7b6ddb
numbers only: 4390887142563676
First 8 digits: 43908871

3. Currently, the spreadsheet shows 185 tickets.
43908871/185 = 237345 x 185 + 46.
Ticket 46 wins the highest prize (if there is a difference).

Second prize
1. Add a 1 at the end of the block hash:
Block hash: 0000000000000000038cc0f7bcdbb451ad34a458e2d535764f835fdeb896f29b1

2. md5sum: 8817039f09fdc97224166869c054e7e7
numbers only: 8817039099722416686905477
First 8 digits: 88170390

3. 88170390/185 =  476596 x 185 + 130.
Ticket 130 wins the next prize.

*On average Bitcoin miners mine one block every 10 minutes. But this is an average, so it's not possible to predict exactly when a certain block will be found.
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