SatoshiDice hit 1,000,000 bets today.
Rock on, Bitcoin.
Rock on, Bitcoin.
at what kind of volume?
Topic: SatoshiDICE.com - The World's Most Popular Bitcoin Game - page 240. (Read 495794 times)
at what kind of volume?
hi,
how do I send a bet to 50% odd multiple times?
i tried doing it but it says cannot send to a duplicate address
im doing it in my pc wallet not online
how do I send a bet to 50% odd multiple times?
i tried doing it but it says cannot send to a duplicate address
im doing it in my pc wallet not online
me likey likey..
but is there an easier way to get the winnings from a new address?
but is there an easier way to get the winnings from a new address?
It's being worked on...
me likey likey..
but is there an easier way to get the winnings from a new address?
but is there an easier way to get the winnings from a new address?
Right on man,,, Pretty cool...
SatoshiDice hit 1,000,000 bets today.
Rock on, Bitcoin.
Rock on, Bitcoin.
WOW, just WOW! Yes, with capitals!
Congrats!
SatoshiDice hit 1,000,000 bets today.
Rock on, Bitcoin.
Rock on, Bitcoin.
It seems like it gets stuck sometimes..... I had 3 or 4 confirmations on 5 bets before it returned anything.. But it will 
I've been gambling all morning but it seems it has frozen? This transaction has yet to get a win/loss response:
https://blockchain.info/tx-index/15903774/018e2439cd61ea26264f0ea35f682b1a28074afb926e5b087840ab874f2aafd6
https://blockchain.info/tx-index/15903774/018e2439cd61ea26264f0ea35f682b1a28074afb926e5b087840ab874f2aafd6
...
2 games
all wins : 0.732422 * 0.732422 = 53.64%
1 win 1 lose : 0.732422 * 0.267578 = 19.59%
all loses : 0.267578 * 0.267578 = 7.15%
...
Why the sum of all percentage in 2 games are not 100% ?
1 win 1 lose : 0.732422 * 0.267578 = 19.59% times 22 games
all wins : 0.732422 * 0.732422 = 53.64%
1 win 1 lose : 0.732422 * 0.267578 = 19.59%
all loses : 0.267578 * 0.267578 = 7.15%
...
Why the sum of all percentage in 2 games are not 100% ?
(1 win 1 loss = 1 loss 1 win)
Thanks, so this is the correct one :
1 game
win : 73%
lose : 27%
2 games = 2^2 = 4 combination
all wins : 0.732422 * 0.732422 = 53.64%
1 win 1 lose : 0.732422 * 0.267578 = 19.59%
1 lose 1 win : 0.732422 * 0.267578 = 19.59%
all loses : 0.267578 * 0.267578 = 7.15%
3 games = 2^3 = 8 combination
win win win
win win lose
win lose win
win lose lose
lose win lose
lose win win
lose lose win
lose lose lose
compacted to
1 [win win win] : 0.732422 * 0.732422 * 0.732422 = 39.29%
3 [win win lose] : 0.732422 * 0.732422 * 0.267578 = 14.35% * 3 = 43.05%
3 [lose lose win] : 0.267578 * 0.267578 * 0.732422 = 5.24% * 3 = 15.73%
1 [lose lose lose] : 0.267578 * 0.267578 * 0.267578 = 1.91
The winning chance streak get reduced after each game
As long as I don't play more than
...
2 games
all wins : 0.732422 * 0.732422 = 53.64%
1 win 1 lose : 0.732422 * 0.267578 = 19.59%
all loses : 0.267578 * 0.267578 = 7.15%
...
Why the sum of all percentage in 2 games are not 100% ?
1 win 1 lose : 0.732422 * 0.267578 = 19.59% times 22 games
all wins : 0.732422 * 0.732422 = 53.64%
1 win 1 lose : 0.732422 * 0.267578 = 19.59%
all loses : 0.267578 * 0.267578 = 7.15%
...
Why the sum of all percentage in 2 games are not 100% ?
(1 win 1 loss = 1 loss 1 win)
For any three games in a row:
chance of win = p = 0.732422
chance of loss = 1 - p = 1 - 0.732422 = 0.267578
chance of 2 wins and one loss = p*p*(1-p) = 0.1435401
chance of win = p = 0.732422
chance of loss = 1 - p = 1 - 0.732422 = 0.267578
chance of 2 wins and one loss = p*p*(1-p) = 0.1435401
Following your math, is this correct ?
1 game
win : 73%
lose : 27%
2 games
all wins : 0.732422 * 0.732422 = 53.64%
1 win 1 lose : 0.732422 * 0.267578 = 19.59%
all loses : 0.267578 * 0.267578 = 7.15%
3 games
all wins : 0.732422 * 0.732422 * 0.732422 = 39.29%
2 wins 1 lose : 0.732422 * 0.732422 * 0.267578 = 14.35%
1 wins 2 loses : 0.732422 * 0.267578 * 0.267578 = 5.24%
all loses : 0.267578 * 0.267578 * 0.267578 = 1.91%
Why the sum of all percentage in 2 games are not 100% ?
For any three games in a row:
chance of win = p = 0.732422
chance of loss = 1 - p = 1 - 0.732422 = 0.267578
chance of 2 wins and one loss = p*p*(1-p) = 0.1435401
chance of win = p = 0.732422
chance of loss = 1 - p = 1 - 0.732422 = 0.267578
chance of 2 wins and one loss = p*p*(1-p) = 0.1435401
percent chance to lose once or to lose 3 times in a row
Percent chance to lose once. I want to know the formula so I can calculate when I'll approach my loss and stop gambling while I'm still winning.
Formula to calculate percent chance to lose 2-3 time in a row is fine too.
Still winning so far, thanks SatoshiDice !
One quick question, what's the % chance to lose if I do 73% roll three times ?
One quick question, what's the % chance to lose if I do 73% roll three times ?
percent chance to lose once or to lose 3 times in a row
Still winning so far, thanks SatoshiDice !
One quick question, what's the % chance to lose if I do 73% roll three times ?
One quick question, what's the % chance to lose if I do 73% roll three times ?
http://satoshidice.com/lookup.php?tx=6fbcfb5bfe0101d9959d934b7d7cda998727ad4d70032d71b29b07e2b46c4b85
I think there is a problem with this bet, as it has not been returned to me yet.
I think there is a problem with this bet, as it has not been returned to me yet.
This has now been fixed - arij can confirm
TX ID's:
f50d27ad60f37cf87113b35fa4c694234c8fd21aa89b7f2d9938a53fd72bf08d
b83441d912f88c19c6165ad7c904a6f702b80023fdcf1d3c508d8d4c00c9c646
244986081d499e75e35210049182e8753e61b28352ddc5aff456695d301708fc
963f684757f7b409f977756add7518e3a324f8d1c8455217ed819a86aec1a91b
94b95dcf7cfbd4572a7396bce23d40e83f64e02884a734f097cab99fc81b92b4
None of these have returned anything and are on confirmation 2 of 6..
Came through.. Took a very long time...
http://satoshidice.com/lookup.php?tx=6fbcfb5bfe0101d9959d934b7d7cda998727ad4d70032d71b29b07e2b46c4b85
I think there is a problem with this bet, as it has not been returned to me yet.
I think there is a problem with this bet, as it has not been returned to me yet.
Please take a look at the newbie section. There is quite a few threads needing your attention. (directed to op)
Thanks for mentioning, I always forget to check there! Reviewing now.
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