Нет. Тут чистая статистика как при майнинге биткоинов на процессоре.
Да, надо будет посмотреть исходники и понять, от чего зависят шансы
Code:
scheduledThreadPool.scheduleWithFixedDelay(new Runnable() {
@Override
public void run() {
try {
HashMap unlockedAccounts = new HashMap<>();
for (User user : users.values()) {
if (user.secretPhrase != null) {
Account account = accounts.get(Account.getId(Crypto.getPublicKey(user.secretPhrase)));
if (account != null && account.getEffectiveBalance() > 0) {
unlockedAccounts.put(account, user);
}
}
}
for (Map.Entry unlockedAccountEntry : unlockedAccounts.entrySet()) {
Account account = unlockedAccountEntry.getKey();
User user = unlockedAccountEntry.getValue();
Block lastBlock = Block.getLastBlock();
if (lastBlocks.get(account) != lastBlock) {
byte[] generationSignature = Crypto.sign(lastBlock.generationSignature, user.secretPhrase);
byte[] generationSignatureHash = MessageDigest.getInstance("SHA-256").digest(generationSignature);
BigInteger hit = new BigInteger(1, new byte[] {generationSignatureHash[7], generationSignatureHash[6], generationSignatureHash[5], generationSignatureHash[4], generationSignatureHash[3], generationSignatureHash[2], generationSignatureHash[1], generationSignatureHash[0]});
lastBlocks.put(account, lastBlock);
hits.put(account, hit);
JSONObject response = new JSONObject();
response.put("response", "setBlockGenerationDeadline");
response.put("deadline", hit.divide(BigInteger.valueOf(Block.getBaseTarget()).multiply(BigInteger.valueOf(account.getEffectiveBalance()))).longValue() - (getEpochTime(System.currentTimeMillis()) - lastBlock.timestamp));
user.send(response);
}
int elapsedTime = getEpochTime(System.currentTimeMillis()) - lastBlock.timestamp;
if (elapsedTime > 0) {
BigInteger target = BigInteger.valueOf(Block.getBaseTarget()).multiply(BigInteger.valueOf(account.getEffectiveBalance())).multiply(BigInteger.valueOf(elapsedTime));
if (hits.get(account).compareTo(target) < 0) {
account.generateBlock(user.secretPhrase);
}
}
}
} catch (Exception e) { }
}
}, 0, 1, TimeUnit.SECONDS);
