Author

Topic: Bitcoin puzzle transaction ~32 BTC prize to who solves it - page 164. (Read 229908 times)

jr. member
Activity: 75
Merit: 5
Look closely, I am working with artistic binary, not with base58, Ripemd160, decimal, or hexadecimal. and just print output in any format, If you have any output result even in any format, please show us. 100% of people are trying randomly even in 130 also, and I am also trying randomly, but with some logic. You are a master of mathematics, so you can solve 130 directly even with your mobile. All the best!
[/quote]

I don't know if this will help you in any way:

the problem is I have almost 2 thousand of these which will be posted as a code below, in order to maintain orderliness and less consumption of space

Code:

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13zb1hQbYPS3S2jjfqmYoyaA8Jjn1opW4d - 46877035169548351519 - 20d45a6a762f86e2002a0241f4149a2c96b048f0 - 28A8CAF1F1C6C381F - KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3qZfsPaeVZnvEKViqd9xd
13zb1hQbYXYJXQKuRDHdUuxKL6edZRp95L - 53285710487348575445 - 20d45a6a76304a5cebd28c4ce4b363e9034a57e9 - 2E37CDF5E52B7FCD5 - KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3qZoH3bALtf7iDBnVUtDE
13zb1hQbYXpGzFnQqRHpp6MCFfwb28Af2T - 72896968735178121584 - 20d45a6a76305100bf4b15934a8b5cbfa421c6bc - 3F3A60ED7070C6170 - KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3qaBwqas7RnvrvGrbFQK4
13zb1hQbYYiNzeco5mRDJWJ84fyGex88p5 - 72943550970120977500 - 20d45a6a763066a95e37086ddbfb724619585ebb - 3F44B8D22C5A93C5C - KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3qaBzxieG9UEwhktryLzT
13zb1hQbYZQjVDN1sWfzK24RT5vqm5sLSC - 71934656248129423305 - 20d45a6a7630776f94f4490d49efb8fc111f2c7e - 3E64B3CBB459687C9 - KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3qaAqKejRGLtE3uA7KGXW
13zb1hQbYaS3V1B2rNVsfKwRNXZCSndaxt - 62240297718131037252 - 20d45a6a763090171bb2085804234d6cd930f5a1 - 35FC1F502EBC19444 - KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3qZydPKwoFUz8TxTuFwg3
13zb1hQbYeCgB67nYR3cw35dr1muSLn7hd - 67798801360980343580 - 20d45a6a7630eaf8faf86642758a4fa3232be824 - 3ACE5BA9FD680FB1C - KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3qa643TeuoeyoVaLQMhke
13zb1hQbYfCh4tLsFigCmhazz3epDuCbNQ - 48319096639085843099 - 20d45a6a76310316b604f954c8bbdda490518a7f - 29E8FEA63407B929B - KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3qZhY51Ts4Eg8JAFiaDAM
13zb1hQbYgwZkxQnjCRHojfBPmbKwNcDH8 - 72323466770253861848 - 20d45a6a76312d05410f3f2c035a368ed438f90e - 3EBB091D765BFD3D8 - KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3qaBHPXttYdEA91nSsfCB
13zb1hQbYi7eVzTRTMbhQXLW9Lf4tjK9y9 - 69223021477850718522 - 20d45a6a7631495233503d0a28b2cda6f8c5643f - 3C0A993465A87213A - KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3qa7hXWgFetfdV3mbkhjz
13zb1hQbYicmXEraYfreCSJJb2nPgPy1Y8 - 50739863439266470124 - 20d45a6a7631556d21157878f342c8884789d650 - 2C02834F7794ED8EC - KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3qZkLN7XEA4eXuDGToCFM
13zb1hQbYkE8CSJE9Dczmvvzmhm1CUdPmN - 44916764761681479414 - 20d45a6a76317c3bb1d3c4402f91b6356d3e8c5f - 26F5867924FCEC6F6 - KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3qZdby7CbVSJPg5QiNYZt
13zb1hQbYmXUp2kp1MnkCfm28Yccr1JDZJ - 49186179685162308609 - 20d45a6a76319b8eab500d387da1a1d19c453596 - 2AA9869D2F8A25401 - KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3qZiYCeKgWkgpm4GACVjy
13zb1hQbYnjxtCUX5nnowUK6p81Cy4RTNR - 40063177750128182863 - 20d45a6a7631b8db402cd786858d5cdb1fd3f9c4 - 22BFCFFE661B9464F - KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3qZXza2f2MZdRcVaxsm7Q
13zb1hQbYr65coaa35fwkmrDh1SiUa7U2U - 47556563278343707287 - 20d45a6a7632098c30e3686402166a0d082be821 - 293FADA5610101A97 - KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3qZgewutd5K1rpGSj9fx5
13zb1hQbYt7Dm4FycZoLJkp6KbZGH4Nszc - 53059098480127906699 - 20d45a6a76323a3dbacc7605f964f61d668faf7d - 2E057C8F2D27E138B - KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3qZo1rQw3fabbtbMnVitQ
13zb1hQbYta7n82gaH6kKBiZdXtEKet4Kz - 51379696827744687905 - 20d45a6a7632456bf85e5687ad15ad81f32e4177 - 2C9095A0B24FC9721 - KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3qZm5G6LjvzssU17Deiac
13zb1hQbYtqamAxgXWrvaivH1LR2hFbnyW - 52248453983132922421 - 20d45a6a76324bd9b585e3c0f4f794e020ac8f2a - 2D517CC12CFFB3235 - KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3qZn5WEmL3oJCR9jofCUs
13zb1hQbYwABKw7N2QkN2sBsapkiNb5QKm - 44302072124455547399 - 20d45a6a763283ccc9ba6f710d88eee18aa7901b - 266D093DFEFE87207 - KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3qZctktRSFm8kPC6B7s2W
13zb1hQbYyKFrt8MJqABBc9qYhjQqor4vf - 67626845178234534785 - 20d45a6a7632b7cb0759ce42c4b8c6a46204a7e2 - 3AA82D1632101FB81 - KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3qa5rWp4AWSeQ629A81T4
13zb1hQbYzjxDxHtxLizTcc4Y4JruUYPe7 - 44246694740411011399 - 20d45a6a7632da2b258158e4308d35933543b999 - 2660BD66FF757D147 - KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3qZcq3Z4GsW4XYrfzMu9j
13zb1hQbZ2m1fWDppGDU1vZrXD96gU6s7s - 41185244817163056292 - 20d45a6a76330ad40f0423d58207bc26473d864e - 23B8F61F3D28074A4 - KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3qZZHoAY9Y9bGszExd6zx
13zb1hQbZ7drTvxYRWwmswQWW4hgZwMjph - 42019911220101952898 - 20d45a6a76338066bb9a3ec519124f00fdc4163b - 24724B69FA7A0B582 - KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3qZaFkkQmqZUpxiEX3SXa
13zb1hQbZ7h14f2RR3E8he367D9DBe3ajX - 42340799662575025650 - 20d45a6a763381b5c164488fbb3b392970cfdad0 - 24B98BCF641C37DF2 - KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3qZadGWypcrEnCP4jX6UB
13zb1hQbZ7uFRvwiNetS4mWeiN1CQPN5d9 - 73298960546708798659 - 20d45a6a763386cd1977367af813a8872852b1f0 - 3F93A38433FF33CC3 - KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3qaCQniq2fg3BqiSD75WK
13zb1hQbZ8Q3gsemMLnkQitsGdJrPjQVi1 - 41108554716948110979 - 20d45a6a763392c599ed3914bdfa3b5c217a9527 - 23A7EECB66D669E83 - KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3qZZCexUaW44fFd714JEx
13zb1hQbZAoFwgfFDZMYnqpDshGZjJr6Dq - 47446912354920464392 - 20d45a6a7633cca3d326c7f9f020a8e17390d7d1 - 292754B66FC208008 - KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3qZgXbY7XLYDuDrp26UzB
13zb1hQbZAzTuretB5jaNU7ConrLPwEoPr - 46688318888855073721 - 20d45a6a7633d14c5a69331557f1c12fcd082300 - 287EE3AAA025DF3B9 - KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3qZfejm7SuigQwfWsgn68
13zb1hQbZByoUcmMqU1BbvTpV4uGZtBAC8 - 39970028619426507997 - 20d45a6a7633e921ed2ceed9ee482e0e5c6f8600 - 22AB21142531D2CDD - KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3qZXtKpZNbG3Tv94hUzgm
13zb1hQbZCPBSKqh1W5H1nJcR6XrCr1PQG - 56712421402939884764 - 20d45a6a7633f2d9c5af02e0d3207f4517adb0d3 - 3130AFECA6A7E04DC - KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3qZsEnHg7Wx9pfhx8uQVd
13zb1hQbZDED5RSGFTEwceLsPcSV1gmknC - 55623916971135547896 - 20d45a6a7634073b22575e019fa15535dab17c6f - 303EFD9C6F05B39F8 - KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3qZqyofEjKVs6ATaF6QyN
13zb1hQbZHz22BoPi6WomdnDqv9S7W4eWb - 60830966206306538975 - 20d45a6a763479e17eb2e70f300082c6475e311a - 34C330177E6B155DF - KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3qZwzuAn3JWb9UvvLd4L9
13zb1hQbZKJphfDfXNinY3a7c7jgBn9qEL - 71760461253069144487 - 20d45a6a763499ceb603a9bad2f958d507b154ce - 3E3E05F4E735E81A7 - KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3qaAdeJD7EiUs1W6aN9nd
13zb1hQbZKwipzYgbZxf6ojD6489Uvp7ND - 63135733581907222313 - 20d45a6a7634a9254db8f6b39c5633484ca42596 - 36C2F2F2F6F47DF29 - KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3qZzfRDGXP36kfd7MTgPh
13zb1hQbZNiYCx1iLvGmqNeFZUy8UF2KFQ - 59109423803581444657 - 20d45a6a7634ebfeb13fc7d054c498aa948ebe77 - 3344EDBC6327DB231 - KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3qZv1Uz6yGEnbCr65UUBY
13zb1hQbZPWNeHTyw3AaG5ryiKYjPxyAdg - 46316994679194156202 - 20d45a6a7634ff0c40fff2287dfc6fe357ee6c23 - 282C7054345067CAA - KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3qZfDqsfn6q9nRGAkb1Cg
13zb1hQbZPwbRxZQjysh6kw1GdMP7mgY6s - 51484651588548046457 - 20d45a6a7635098819aa599e708e55167515208b - 2CA7E39D7A8282E79 - KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3qZmCJCz3nuzxYW3ZoQLG
13zb1hQbZQxB2Uo9vStqyySebae1nWznZ4 - 62707459898691393621 - 20d45a6a763521e1d4c37892ef85cd8e24cd03e9 - 3663DA68A1C8D9855 - KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3qZzAhsuRrGmyN336Qre4
13zb1hQbZYKCT3ZseAEzMeknCrxHdRGN4B - 56318207850861952808 - 20d45a6a7635d363cf974abfabb40a0ad0c393a2 - 30D9277A7593DFF28 - KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3qZrnMPxRkBxgdj5rWYep
13zb1hQbZgqJpWZEKh5rKodYgG4tEAuiUm - 42146233785976033142 - 20d45a6a7636a0c8b26b880bdaa3be75271e4ce3 - 248E58053F9AB0F76 - KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3qZaQDxB6hqYfP92bj98w
13zb1hQbZhH3MqugYnYJHrJSuvxMhDPzq4 - 39901960523427979431 - 20d45a6a7636ab7b21d1a57d594103ddf086dcbc - 229C03DAFB895A0A7 - KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3qZXom92w4keNmMX7aden
13zb1hQbZkEAMBdGCHzhsoYyVpQc9idTVx - 37928688135156917422 - 20d45a6a7636f29cfc16e30973ae5ea6b4793a8c - 20E5DC4E77499E4AE - KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3qZVXU7E6qRdnfVsuDjvn
13zb1hQbZnEmeMRKk4dWoRvS3c3UjhupHM - 67915966895582247278 - 20d45a6a76372315eda44276e018e77c32962769 - 3AE85FC0EAC5E796E - KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3qa6Bu4DVuoZbytWGnmRs
13zb1hQbZtXa2N9tZDWWnrwv1ecyyaPViW - 37818162477213485699 - 20d45a6a7637baba38d216d75440a4158a510661 - 20CD51A6760510A83 - KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3qZVQ4LAjTkUfwa8ZLyWE
13zb1hQbZu5DpBkwxV8xVMQKiu172ZnXZD - 37332141779891591579 - 20d45a6a7637c7e26f1679739d23c9f59f2032ed - 20616692796F5199B - KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3qZUqUT1hobdzF69RsaFZ
13zb1hQbZv8cU8RZ7Jsih7jywZFmUjDfhg - 59503748966032306180 - 20d45a6a7637e167564113280fd1d1f5b06301b9 - 339C7C86B945F7004 - KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3qZvTvJzccvf78k8Cbxuf
13zb1hQbZvApRnT7VfASyyaitsiS6hQ8mS - 70197752828550488997 - 20d45a6a7637e2521c4a4b53dcc785bb5a04f359 - 3CE308446206CA3A5 - KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3qa8psjfDazNuCghxVMxQ
13zb1hQbZwHvxzBBNejGtsAn9EP3GcdnzY - 63014719132667385149 - 20d45a6a7637fd631b1858820308c1843888f919 - 36A81412F53A6953D - KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3qZzXJeesJ2Xi4hsvVqYi
13zb1hQbZwaBjkgF2pDKL8cj6vGGoYQ3kM - 69858139391242271699 - 20d45a6a76380424dac4e91b8e5082e06819a046 - 3C979F7A6ECB7FBD3 - KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3qa8S7A1MPgs9JKEgSQJt
13zb1hQbZx5pDaycRAJKCewQwoapXYhqhS - 59939320530308382581 - 20d45a6a76381075d4feb1f6b7760f99bf6da2d5 - 33FD33E733F4F3F75 - KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3qZvy82GBicciCVBUWQzy
13zb1hQbZxJoWv4Tg5BEp2Wh6jrHJ3izUQ - 38151524982449520153 - 20d45a6a763815dbf2060244293d14de1cb66192 - 2117571D60A583E19 - KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3qZVnQc36yxjhrUDV2PAf
13zb1hQbZzQTg82osBGLewsYb577Hk4MWk - 71636956086031639744 - 20d45a6a7638486e37de7cbf87b2aca95faeb7d4 - 3E2299802EA2C64C0 - KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3qaAVN3rkT1YBYJ9nq29X
13zb1hQba3haK5kdfNjuep2K8vggsX881g - 71692370163003147489 - 20d45a6a763897dfbbdbc937335fcc3e6513d945 - 3E2EE76D21F9DC4E1 - KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3qaAZ5XVtMsEJekK415ia
13zb1hQba4sqbb6QZwYQx5DNVm9UVNFjEe - 69023330083310371733 - 20d45a6a7638b44005ec24ed38bcb2655c0166af - 3BDE421026E3F8395 - KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3qa7U91uQci5qGdZTdp5G
13zb1hQba6j84GRShkeWwU1utueP1Y1nvj - 71238881664467444713 - 20d45a6a7638e0d8ab3a8cf0e7738513deca18c8 - 3DCA3596F1EABA3E9 - KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3qaA2g9PcgZ4vPLqVoCAf
13zb1hQba6yjaeZR74QhL5UWuVTmBBLmVk - 43560962407148933968 - 20d45a6a7638e6eba955cc0fb83a1607331539ba - 25C87A0837041D350 - KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3qZc356ZdF921RRbwTwkG
13zb1hQbaMSop4NgeJ6svfvsURwjWvRvmi - 50873275498753923907 - 20d45a6a763a43b5ee0d67822081babbea68342f - 2C2022E8727CF9B43 - KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3qZkVJtC9HWnC9WwrzJmA
 

the problem about trying to find a collision is very difficult...

I haven't seen anyone with the first 10 characters of puzzle 66 wallet address "13zb1hQbWV" maybe within this range, the first 10 character might be the solution to the puzzle itself

I have waited over 10 days straight on a 4090 going at 5 billion per second looking for the first 10 character "13zb1hQbWV" but all I always get is very close so the actual range has nothing to do with the characters of the wallet address or the characters of the rmd160 has there is not a single relationship between these

I even went as far as getting the closest difference between each rmd160 first 10 characters I got and I wote this code

Code:
import subprocess
import time
import random
import string
import signal
import sys
import os
import logging
import multiprocessing

# Define a function to save the current state (current_key) to a checkpoint file
def save_checkpoint(current_key, checkpoint_filename):
    with open(checkpoint_filename, 'w') as checkpoint_file:
        checkpoint_file.write(current_key)

# Define a function to load the current state (current_key) from a checkpoint file
def load_checkpoint(checkpoint_filename):
    if os.path.exists(checkpoint_filename):
        with open(checkpoint_filename, 'r') as checkpoint_file:
            return checkpoint_file.read()
    else:
        return None

def generate_next_key(current_key):
    # Convert the current_key to an integer, add 2385407605810, and convert back to hexadecimal
    next_key = hex(int(current_key, 16) + 2385407605810)[2:].zfill(18)
    return next_key

def key_search_worker(start_key, end_key):
    try:
        command = f"KeyHunt-Cuda.exe -g --gpux 2048,512 -m address --coin BTC --range {start_key}:{end_key} 13zb1hQbWVsc2S7ZTZnP2G4undNNpdh5so"
        subprocess.run(command, shell=True, check=True)
    except subprocess.CalledProcessError as e:
        logging.error(f"Error in subprocess: {e}")

def main():
    checkpoint_filename = "checkpoint.txt"  # Specify the checkpoint filename
    num_processes = 4  # Adjust as needed

    # Load the last saved checkpoint (if any)
    current_key = load_checkpoint(checkpoint_filename)
    if current_key is None:
        current_key = "2058E1E06903F1DCC"  # Specify your desired starting key here

    try:
        while True:
            processes = []
            for _ in range(num_processes):
                # Generate the next key and update current_key
                next_key = generate_next_key(current_key)

                # Split the key range for each process
                start_key = current_key
                end_key = next_key

                # Save the current state (current_key) to the checkpoint file at regular intervals
                if _ % 10 == 0:
                    save_checkpoint(current_key, checkpoint_filename)

                # Create a process to search for keys in the specified range
                process = multiprocessing.Process(target=key_search_worker, args=(start_key, end_key))
                processes.append(process)
                process.start()

                # Update current_key
                current_key = next_key

            # Wait for all processes to complete
            for process in processes:
                process.join()

    except KeyboardInterrupt:
        for process in processes:
            process.terminate()
            process.join()

        print("Script terminated by user.")
        try:
            input("Press Ctrl+C again to exit the script.")
        except KeyboardInterrupt:
            print("Exiting script.")
            sys.exit(0)

if __name__ == "__main__":
    logging.basicConfig(filename="key_search.log", level=logging.ERROR)
    main()

it adds the difference to the current key to get the next key and it scans it for the specified time before terminating the code and adding the difference again to the current key but no luck still

so its obvious the private key to puzzle 66 has nothing to do with the distance between the characters of the rmd160 or wallet addresses. it is what it is
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Activity: 49
Merit: 0

Look closely, I am working with artistic binary, not with base58, Ripemd160, decimal, or hexadecimal. and just print output in any format, If you have any output result even in any format, please show us. 100% of people are trying randomly even in 130 also, and I am also trying randomly, but with some logic. You are a master of mathematics, so you can solve 130 directly even with your mobile. All the best!

I don't know if this will help you in any way:

13zb1hQbWZ1a2xKWzTd4Wwm1JPUvMqG1f9  20000482560FB7F71  10 0000 0000 0000 0000 0100 1000 0010 0101 0110 0000 1111 1011 0111 1111 0111 0001
13zb1hQbWRtJwbYp2LoA2JVeBFnSgrf34F        20000508586CE7275  10 0000 0000 0000 0000 0101 0000 1000 0101 1000 0110 1100 1110 0111 0010 0111 0101
13zb1hQbWag5udkAQDnS4HJy8sb5o4uoov     200006E160DD67EE5  10 0000 0000 0000 0000 0110 1110 0001 0110 0000 1101 1101 0110 0111 1110 1110 0101
13zb1hQbWHZiXjDeN7iVDop52T3xYCF3G5      2000070B9014052ED  10 0000 0000 0000 0000 0111 0000 1011 1001 0000 0001 0100 0000 0101 0010 1110 1101
13zb1hQbW64hnLQnTFkQTU1Ed3tQoSqpFk     20000866E02263B6B  10 0000 0000 0000 0000 1000 0110 0110 1110 0000 0010 0010 0110 0011 1011 0110 1011
member
Activity: 93
Merit: 16
Are you trying to crack sha256 and hash160 simultaneously?
ecc has no relationship with these hashes, if your method, whatever it is, returns two results that partially agree, it is only a coincidence.
He will continue this outrage, he still thinks that there is a direct relationship between a certain range of keys and the received addresses, which partially coincide with the target one. He doesn't know anything.
member
Activity: 239
Merit: 53
New ideas will be criticized and then admired.
newbie
Activity: 25
Merit: 0
member
Activity: 499
Merit: 38
I have to admit that Open SSL is very good.  Cool
To have a good probability of finding, you need a good randomness of the search. Sounds logical  Roll Eyes. I have not studied probability theory. Previously, the program included the Mersenne Twister algorithm. The Mersenne Twister is a general-purpose pseudorandom number generator (PRNG) developed in 1997 by Makoto Matsumoto.
This algorithm is predictable, and external events are seconds of time and a hashed SEED from the command line.
OpenSSL is certainly better.


when Vanity Search is cleared of statistics, calculation of results per seconds, Timer ticking, you simply get a  10% more perfomance....The more simplified the better.
member
Activity: 275
Merit: 20
the right steps towerds the goal

As I mentioned before, I also use random numbers, just like others do. However, what you are doing in your 'random.cpp' involves seeding, twisting, doubling, and including 'rand.h,' which has already been created by someone else.

It uses many old and common methods for generating random numbers, which have been tried by many over the years. Unfortunately, there haven't been any positive results, and the only method that seems to work is brute force. Yet, you continue to use these methods instead of exploring something new. Just as some people are asking why I keep doing the same job repeatedly, I can also ask why you keep using the same old random methods repeatedly.

If someone attempts to innovate, you suggest they go to art school, taunting them in the process. I'm not here to teach anyone; I'm simply sharing my experiences with these so-called 'random' methods and my own random formula.
for your information.
When I was working on puzzle 64, I've come close to solving it using what you call 'cheap art' as random numbers. Right now, my 'cheap art' has brought me closer to possible keys for puzzle 66. And how am I able to differentiate between the two random methods? Because I have saved the analysis of the initial 8 hex (4 bytes) generated through both functions in my local database, and I have managed to obtain matches through my random method several times (3 or 4 bytes), whereas with the old random method, I have hardly obtained a match of (2 bytes). If puzzle 62 hasn't been solved yet, I've managed to solve it twice with my 'cheap art' through 14 zeros and 16 ones. My script skipped it 2 times because the range was already in the database, and I saved the skipped range also to study how randomness works. I'm not blindly running code like the so-called 'copy-paste' programmers.

Once I've achieved the 14:16 pattern and saved and merged my database, then I'll invert it and try more combinations. I also have ten more unique methods that I haven't shared yet. These methods are far better than the older random techniques that couldn't produce even three matching bytes of the private key hex in months, or even years.

As I mentioned earlier, I'm not here to teach anyone, just to share my experience whether it's the worst or good. These are common factors that cross everyone's minds to compare their results with something that exists, whether it's Ripemd160 or Base58. That's why I always share information related to these topics. That doesn't mean my calculation is totally dependent on these things. You may call it spam or anything else you like. The only difference is that I am using a different method to generate random numbers, which I prefer over the old methods, so please stop repeatedly giving me advice on this topic. I am well aware of non-linear or linear functions; please don't attempt to act overly intelligent. And I don't need advice from 'copy-paste' and renaming enthusiasts.

I have several people on ignore.
this is a good idea if my posts are irritating someone.

this master of mathematics has no clues what you are talking about.
This is the reason why I write long posts, so that they can penetrate people's minds without explaining much. But it's the sheer bad luck of some people that even after that, they can't understand properly. And people scold me, asking why I write such long posts... lol  Wink Wink. Here, I'm just reducing the possibilities from nearly 100% to 27%, you can try it yourself.

Code:
import math

def binomial_coefficient(n, k):
    return math.factorial(n) // (math.factorial(k) * math.factorial(n - k))

start = int('20000000', 16)
end = int('40000000', 16)

zeros = int(input("Enter the number of zeros (0-30): "))

if 0 <= zeros <= 30:
    total_possibilities = end - start + 1
    possibilities_with_zeros = binomial_coefficient(30, zeros)
    percentage_with_zeros = (possibilities_with_zeros / total_possibilities) * 100
    percentage_diff = 100 - percentage_with_zeros
    print(f"Total possibilities within the specified 30-bit range: {total_possibilities} (100%)")
    print(f"When applying {zeros} zeros within the range: {possibilities_with_zeros} ({percentage_with_zeros:.2f}%)")
    print(f"Difference between total possibilities and applying condition: {total_possibilities - possibilities_with_zeros} ({percentage_diff:.2f}%)")
else:
    print("Invalid input. Please enter a number between 0 and 30.")

Seriously, how much am I talking, that's why I try to explain it in the language of coding. My fingers are tired Undecided Undecided. Smarter people can kindly put me in their ignore list or create a new thread (I think there are already 2 more threads). You can go there, I won't be coming there. I'll just continue my nonsense here. Thank you very much, everyone👍
copper member
Activity: 1330
Merit: 899
🖤😏
You are a master of mathematics, so you can solve 130 directly even with your mobile.


Jokes aside.

Look closely
I want a working equation, this master of mathematics has no clues what you are talking about. You should forget about previously solved puzzles, it's not like the author designed the whole elliptic curve, hash functions and then applied your logic to create this puzzle with some sort of pattern to test our IQ level and gift us some candy.


Why are you looking in 66 bit space? You know there are 2^96 ( 79228162514264337593543950336 ) exactly identical bitcoin addresses just like #66 address?

If you are curious about finding collisions, start by searching in 256 bit, maybe you get lucky and find a private key/ address collision where different keys can open the same address.
Your artistic binary method ( whatever that even means ) is beyond my level of understanding.

Did you even know solving 130 give or take is as difficult as solving 66? So instead of going after 66, start working on public keys, I haven't seen anyone post something interesting about their discoveries while working on points.

I have posted a few proof of concept python scripts, it's the result of community's collective effort ( right, 🙃, just a few), since you are spending your time anyways, at least work with them and share your findings.
jr. member
Activity: 85
Merit: 2
I have several people on ignore.

So now have to figure what to do with those long quotes of the ignored. lol


The entire topic was filled with these useless calculations. This can be regarded as spam, because... you have many similar messages.

I already said that before but people  keep writing a lot non-senses, keep quoting entire long mesages just to write one single line.

https://bitcointalksearch.org/topic/m.62842432

Anyway...
hero member
Activity: 862
Merit: 662
The entire topic was filled with these useless calculations. This can be regarded as spam, because... you have many similar messages.

I already said that before but people  keep writing a lot non-senses, keep quoting entire long mesages just to write one single line.

https://bitcointalksearch.org/topic/m.62842432

Anyway...
member
Activity: 93
Merit: 16

Look closely, I am working with artistic binary, not with base58, Ripemd160, decimal, or hexadecimal. and just print output in any format, If you have any output result even in any format, please show us. 100% of people are trying randomly even in 130 also, and I am also trying randomly, but with some logic. You are a master of mathematics, so you can solve 130 directly even with your mobile. All the best!

Then you should go to an art school to teach  Grin Grin Grin
member
Activity: 93
Merit: 16
////
Do you know how any linear function differs from the sha256 and Ripemd160 functions? All your calculations make no sense, because... The output value of sha256 hash and Ripemd160 hash changes completely even if 1 byte of the input data changes. Points on a curve can be counted - these are linear calculations (addition and modulo division). And everything else that is obtained after hashing with the sha256 and Ripemd160 functions becomes non-linear data. Please clarify this!!!!!!!! The entire topic was filled with these useless calculations. This can be regarded as spam, because... you have many similar messages.
jr. member
Activity: 85
Merit: 2




@albert0bsd

Trying to understand...

Why would endomorphism not work with BSGS if I am searching the entire space?

Do you want the sort answer or a long answer?

I would try to explain it as simply as possible.

What is endomorphism?
According to wikipedia:

In mathematics, an endomorphism is a morphism from a mathematical object to itself.

In this case i see endomorphism as a math function that maps a public key to another public key

Examples of it ? Point negation function

...deleted...

Thanks for the explanation. I was only thinking of it in terms of it generating the extra addresses/points. I didn't think about the BSGS process. This makes sense.
member
Activity: 275
Merit: 20
the right steps towerds the goal


I can't understand your method, why are you looking for base58 addresses, can you at least explain this non existing mathematical relation? Base58 addresses distribution  can not be determined by permutation equation.
You know what you should do? You have to explain a mathematical logic behind your method which should be reproducible and   verifiable by everyone else.
Nobody knows, maybe hash 0 famous address with all 0 characters is somewhere in 66 or 67 bit range, right?  When there is no possible way  to accurately determine that, why do you keep doing it over and over and expect a different result?

Look closely, I am working with artistic binary, not with base58, Ripemd160, decimal, or hexadecimal. and just print output in any format, If you have any output result even in any format, please show us. 100% of people are trying randomly even in 130 also, and I am also trying randomly, but with some logic. You are a master of mathematics, so you can solve 130 directly even with your mobile. All the best!
hero member
Activity: 862
Merit: 662
@albert0bsd

Trying to understand...

Why would endomorphism not work with BSGS if I am searching the entire space?

Do you want the sort answer or a long answer?

I would try to explain it as simply as possible.

What is endomorphism?
According to wikipedia:

In mathematics, an endomorphism is a morphism from a mathematical object to itself.

In this case i see endomorphism as a math function that maps a public key to another public key

Examples of it ? Point negation function

Lets to said that you have a public key with some (X,Y) values, if you negate that Publickey you will get something like (X,Y2), The X value is the same value from the same point, if you negate this value again you will get the original (X,Y) values, do you the endomorphism here?

Code:
(X,Y) ->(X,Y2) -> (X,Y)

A math function that maps a value to another representation of itself.

In the case of of the Values of lambda and beta we have that:

Code:
Q * lambda = (x * beta mod p , y)

Q is a publickey and (x, y) are their independent values.
Q * lambda is a Scalar multiplication (It is some kind of expensive operation)
In the other hand x * beta is just a regular multiplication.

Code:
(x,y) -> (x * beta mod p , y) -> (x * beta^2 mod p , y) -> (x,y)


Now is it possible to apply this to BSGS? I've thinking a lot this and for BSGS the endomorphism is useless because, if you are working in a Baby table from 1 to N, the baby table for endomorphism  will be from
1*lambda , 2 * lambda , 3 * lambda , ... N * lambda.

and then you may need to add the x*beta to all your Giants steps (This will reduce the speed a little), But in any case, lets to said that you are going to hit the key with the regular BSGS process, that means that you are going to hit the key with the BSGS-endomorphism. So see it? it is useless if you are going to find the key with regular BSGS, why overcomplicate a process that actually is complicated?
copper member
Activity: 1330
Merit: 899
🖤😏


I can't understand your method, why are you looking for base58 addresses, can you at least explain this non existing mathematical relation? Base58 addresses distribution  can not be determined by permutation equation.
You know what you should do? You have to explain a mathematical logic behind your method which should be reproducible and   verifiable by everyone else.
Nobody knows, maybe hash 0 famous address with all 0 characters is somewhere in 66 or 67 bit range, right?  When there is no possible way  to accurately determine that, why do you keep doing it over and over and expect a different result?
member
Activity: 275
Merit: 20
the right steps towerds the goal

Should I have to create a pool with such stupidity?

No

Thank you for your suggestions. You are highly experienced, if you have ever used a method in your experience (without revealing the public key) that even slightly brings us closer to our goal, please do share it.

Edit-----------

Or any method to reach closer to pubkey

039f7bed2fb18144484a1db48d50c01e9ed80dd7a4166d7c1d2b7ca73c19d97c74  20d45a6a76753cb0a8fedc855ed3cee4705a1a3e
____________________________________________________________________20d45a6a762 535700ce9e0b216e31994335db8a5
                                                                    ^^^^^^^^^^ ^^  ^           ^   ^  ^


020b03dcc67a5279a4508319a498f529853de9c635343e6e7384e55244f73fbd12  20d45a6a764133470ef8e736e371fa347572bc35
____________________________________________________________________20d45a6a762 535700ce9e0b216e31994335db8a5
                                                                    ^^^^^^^^^^  ^   ^   ^          ^    ^  ^


0276fa074b58763dfba10124f49ee0a0e09856741a288bf9a45e6fdabc7479cd84  20d45a6a767f3f18ec9bced9cce1709114540295
____________________________________________________________________20d45a6a762 535700ce9e0b216e31994335db8a5
                                                                    ^^^^^^^^^^  ^    ^        ^   ^   ^    ^


033fe62b18c8bae2df06223b4e10cb75237a3a33650c496db4ed6d5968e7a0c8b1  20d45a6a7625d3b68c702a8b993379f0100758c9
____________________________________________________________________20d45a6a762 535700ce9e0b216e31994335db8a5
                                                                    ^^^^^^^^^^^^     ^         ^ ^       ^


033fe62b18c8bae2df06223b4e10cb75237a3a33650c496db4ed6d5968e7a0c8b1  20d45a6a7625d3b68c702a8b993379f0100758c9
____________________________________________________________________20d45a6a762 535700ce9e0b216e31994335db8a5
                                                                    ^^^^^^^^^^^^     ^         ^ ^       ^
hero member
Activity: 862
Merit: 662
your first analisys seems interesting but i think that those repeated bits in some specific puzzles are just a coincide.

Lastt Found Address : 13zb1hQbQVEsGkStRa5QNndvakyhr9ji6M  36DB505C509D330C1
Puzzl Sarch Address : 13zb1hQbWVsc2S7ZTZnP2G4undNNpdh5so.._________________
Prfix Match Address : ^^^^^^^^ ^
Charr Match Totalss : 9
Total Found Address : 458
Total scned rangess : 58410


Charr Match Totalss : 9 Huh??

Only the first 7 match, with out counting the first 1, i mean it is impossible  that the first character is not 1 for legacy address P2PKH


Lastt Found Address : 13zb1hQbBpwfx2dfsz96hZc3eyBAskknZD  3967C187FFBA0F1D1
Puzzl Sarch Address : 13zb1hQbWVsc2S7ZTZnP2G4undNNpdh5so.._________________
Prfix Match Address : ^^^^^^^^
Charr Match Totalss : 8
Total Found Address : 459
Total scned rangess : 58411

Again only 7 match

Lastt Found Address : 13zb1hQbBpwfx2dfsz96hZc3eyBAskknZD  3967C187FFBA0F1D1
Puzzl Sarch Address : 13zb1hQbWVsc2S7ZTZnP2G4undNNpdh5so.._________________
Prfix Match Address : ^^^^^^^^
Charr Match Totalss : 8
Total Found Address : 459
Total scned rangess : 58412

Only 7, the thing is that all the characters need to match

1FeexV6bAHo9rxCoRCbMbdGsVA13ca3Cc6  2B91CA5E6DE963B9F
1FeexV6bAHb8ybZjqQMjJrcCrHGW9sb6uF

Those M aren't even in the same position, those extra characters doesn't metter, it need to match all 160 bits..


Should I have to create a pool with such stupidity?

No
member
Activity: 275
Merit: 20
the right steps towerds the goal
puzzle: 30 frontHex: 3d94cd64 Binary: 111101100101001100110101100100        Zeros: 14        Ones: 16

puzzle: 34 frontHex: 34a65911 Binary: 110100101001100101100100010001        Zeros: 17        Ones: 13

puzzle: 38 frontHex: 22382fac Binary: 100010001110000010111110101100        Zeros: 16        Ones: 14

puzzle: 42 frontHex: 2a221c58 Binary: 101010001000100001110001011000        Zeros: 19        Ones: 11

puzzle: 46 frontHex: 2ec18388 Binary: 101110110000011000001110001000        Zeros: 18        Ones: 12

puzzle: 50 frontHex: 22bd43c2 Binary: 100010101111010100001111000010        Zeros: 16        Ones: 14

puzzle: 54 frontHex: 236fb6d5 Binary: 100011011011111011011011010101        Zeros: 11        Ones: 19

puzzle: 58 frontHex: 2c675b85 Binary: 101100011001110101101110000101        Zeros: 14        Ones: 16

puzzle: 62 frontHex: 363d541e Binary: 110110001111010101010000011110        Zeros: 14        Ones: 16


frontHex: 3aea4435     Zeros: 15 Ones: 15     Bin: 111010111010100100010000110101     Addr: 13zb1hQbWVLbiRYaoLhWuCDY7WcAw4dXF9
frontHex: 354d62e5     Zeros: 14 Ones: 16     Bin: 110101010011010110001011100101     Addr: 13zb1hQbWVnN3ag9GNS2vCraT8PQJDjVdr
frontHex: 345ccb1b     Zeros: 14 Ones: 16     Bin: 110100010111001100101100011011     Addr: 13zb1hQbWVi8cYnLyEus3LFucU535Bm52s
frontHex: 33dfe480     Zeros: 14 Ones: 16     Bin: 110011110111111110010010000000     Addr: 13zb1hQbWVBmBqFsBnFR49ZxK8A6RXeaMg

frontHex: 35e3dacf     Zeros: 10 Ones: 20     Bin: 110101111000111101101011001111     Addr: 13zb1hQbWVByHkiAWQr5wmdiSyeAzNBwEb    

 Bin: 11 1 0 1 0 1 1 1 0 1 0 1 0 0 1 0 0 0 1 0 0 0 0 1 1 0 1 0 1
 Bin: 11 0 1 0 1 0 1 0 0 1 1 0 1 0 1 1 0 0 0 1 0 1 1 1 0 0 1 0 1
 Bin: 11 0 1 0 0 0 1 0 1 1 1 0 0 1 1 0 0 1 0 1 1 0 0 0 1 1 0 1 1
 Bin: 11 0 0 1 1 1 1 0 1 1 1 1 1 1 1 1 0 0 1 0 0 1 0 0 0 0 0 0 0
 Bin: 11 0 1 0 1 1 1 1 0 0 0 1 1 1 1 0 1 1 0 1 0 1 1 0 0 1 1 1 1
 Bin: 11 X X X X X 1 X X X X X X X 1 X X X X X X X X X X X X X X


URange : 37cac165000000000:37cac165fffffffff
FntHex : 37cac165x
Binary : 110111110010101100000101100101 num_zeros : 14, num_ones : 16
Cnditn : 11xxxxx1xxxxxxx1xxxxxxxxxxxxxx

VanBitCrackenS v1.0
Keyspace start=37CAC165000000000
Keyspace   end=37CAC165FFFFFFFFF
Search: 15 prefixes (Lookup size 15) [Compressed]
Started at Tue Sep 26 18:06:24 2023
CPU threads used: 0
GPU: GPU #0 NVIDIA GeForce RTX 3060 Ti (38x128 cores) Grid(304x512)
1108.527 MK/s (GPU 1108.527 MK/s) (2^36.14) [00:01:07 Elapsed Time][0]
[EXIT] Reached end of keyspace.

Finish at Tue Sep 26 18:07:32 2023

Lastt Found Address : 13zb1hQbQVEsGkStRa5QNndvakyhr9ji6M  36DB505C509D330C1
Puzzl Sarch Address : 13zb1hQbWVsc2S7ZTZnP2G4undNNpdh5so.._________________
Prfix Match Address : ^^^^^^^^ ^
Charr Match Totalss : 9
Total Found Address : 458
Total scned rangess : 58410

URange : 3967c187000000000:3967c187fffffffff
FntHex : 3967c187x
Binary : 111001011001111100000110000111 num_zeros : 14, num_ones : 16
Cnditn : 11xxxxx1xxxxxxx1xxxxxxxxxxxxxx

VanBitCrackenS v1.0
Keyspace start=3967C187000000000
Keyspace   end=3967C187FFFFFFFFF
Search: 15 prefixes (Lookup size 15) [Compressed]
Started at Tue Sep 26 18:07:38 2023
CPU threads used: 0
GPU: GPU #0 NVIDIA GeForce RTX 3060 Ti (38x128 cores) Grid(304x512)
1118.864 MK/s (GPU 1118.864 MK/s) (2^36.25) [00:01:13 Elapsed Time][1]
[EXIT] Reached end of keyspace.

Finish at Tue Sep 26 18:08:52 2023

Lastt Found Address : 13zb1hQbBpwfx2dfsz96hZc3eyBAskknZD  3967C187FFBA0F1D1
Puzzl Sarch Address : 13zb1hQbWVsc2S7ZTZnP2G4undNNpdh5so.._________________
Prfix Match Address : ^^^^^^^^
Charr Match Totalss : 8
Total Found Address : 459
Total scned rangess : 58411

URange : 32f0e8ce000000000:32f0e8cefffffffff
FntHex : 32f0e8cex
Binary : 110010111100001110100011001110 num_zeros : 14, num_ones : 16
Cnditn : 11xxxxx1xxxxxxx1xxxxxxxxxxxxxx

VanBitCrackenS v1.0
Keyspace start=32F0E8CE000000000
Keyspace   end=32F0E8CEFFFFFFFFF
Search: 15 prefixes (Lookup size 15) [Compressed]
Started at Tue Sep 26 18:08:57 2023
CPU threads used: 0
GPU: GPU #0 NVIDIA GeForce RTX 3060 Ti (38x128 cores) Grid(304x512)
1119.154 MK/s (GPU 1119.154 MK/s) (2^36.25) [00:01:13 Elapsed Time][0]
[EXIT] Reached end of keyspace.

Finish at Tue Sep 26 18:10:12 2023

Lastt Found Address : 13zb1hQbBpwfx2dfsz96hZc3eyBAskknZD  3967C187FFBA0F1D1
Puzzl Sarch Address : 13zb1hQbWVsc2S7ZTZnP2G4undNNpdh5so.._________________
Prfix Match Address : ^^^^^^^^
Charr Match Totalss : 8
Total Found Address : 459
Total scned rangess : 58412


When applying these conditions, I reduce the ranges too much. Should I have to create a pool with such stupidity?

Something interesting I found.. 

1FeexV6bAHo9rxCoRCbMbdGsVA13ca3Cc6  2B91CA5E6DE963B9F
1FeexV6bAHb8ybZjqQMjJrcCrHGW9sb6uF
member
Activity: 93
Merit: 16
I have to admit that Open SSL is very good.  Cool
To have a good probability of finding, you need a good randomness of the search. Sounds logical  Roll Eyes. I have not studied probability theory. Previously, the program included the Mersenne Twister algorithm. The Mersenne Twister is a general-purpose pseudorandom number generator (PRNG) developed in 1997 by Makoto Matsumoto.
This algorithm is predictable, and external events are seconds of time and a hashed SEED from the command line.
OpenSSL is certainly better.
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