Topic: Bitcoin puzzle transaction ~32 BTC prize to who solves it - page 227. (Read 248765 times)

digaran

I want to help you if you tell me what to do. Do you have telegram? Where can you chat?

Thanks, it was 2/5 years ago though sitting long periods of time does hurt even now, a few days workout will build more muscle to support the spine.

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Anyways, it seems there are no interesting parties wanting 1 bitcoin doing some simple (yeah right) math calculations, easy peasy. 😉

Anyhow, so I was thinking about a brute force/key solving method, it could work and not work but mentioning it doesn't hurt.

First we pick a small k, something like 3, then we start by multiplying a range of random numbers by our original number, when we reach the end of our search range without any hit, we'd pick another base key and select another set of random numbers until we again reach the end of our search range, and since multiplying only takes a few seconds to perform, we could scan the entire range in a few minutes and start again with new settings, this would increase the chance of a successful hit by many orders of magnitude.

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Just today I realized that I have been performing what kangaroo and other tools are doing, by hand! Lol  when you have limited resources, your mind is the best asset to utilize.😉

No doubt. I had a massive blow out/bulging disc, and an annular tear in another disc. Left leg was numb for months. Couldn't get comfortable in any form or fashion or position. I finally went outside and rubbed a cup of dirt on my back...Now, I am back! lol.

Indeed, back pain is the worse. It still gives me issues from time to time.

Speedy recovery digaran!

Where did you get 8,192 chances from? Don't tell me, actually don't tell anyone. You know if I had the means I would have joined you right? When you think about me just visualize a laptop with 30 mk/s search capability!

If I haven't solved the key yet is due to my back, I can no longer sit behind the system to work, I have been at it for a month and I had half of one of my discs removed, so I'm feeling a bit numb in my leg as I type this.

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I have got to get back to my trampoline, though I wouldn't call it that, it is more like triangulation method, for now I call it GPS for a lack of a better word.

You see, what I have is actually 2 public keys, when I subtract the 125 public key from each one of them I get the same key, one is inverse though, so one of them is -N. The part it gets interesting, when I add those 2 keys together it gives me the 125 key * 2.  And to my surprise I also have the distances between both of them with the *2 of 125, and obviously the distance between both of them with 125 key as well. Since I can't work on it right now, it remains unsolved.  Moreover I can't seem to figure the equations of adding and subtracting which to which and which from which yet because one or both are  probably -N.

So if you manage to help me out on this, I will give you 1BTC whole bitcoin.

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I rather give the whole world if I had the whole world to avoid experiencing the pain in my leg and my back again, nothing is worth more than our health.😉

Let's be honest, there are only a handful of people/groups looking for 125 using Kangaroo or random BSGS (hoping to get lucky), and no, I do not include you because I doubt you are putting in the work; besides playing with numbers lol. Which is fine, to learn and try applying your trampoline math to the challenge/curve. I'm not knocking you.

To be more honest, I could give people a 1/8,192 chance of solving #125, and earning 5 BTC, and they would not take it. People are strange creatures. We have a me me me and only me kinda vibe. People think they will get lucky and solve without helping or doing a lot of work, but even with a 1/8,192 chance of solving, they would not take it.

1/8,192 chance....

The sentence above is a puzzle of it's own, it keeps me up at nights ever since it was posted. lol.
What I would like to know, what quiet and calm? My man, you are a billionaire and one of the greatest inventors of all time, you should only have quiet and calm plus young virgins crawling around your palace! lol^2.

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Ok now back to business, anybody here knows what happens to G when we multiply it by 1? I mean why is G multiplied by 1 is not G itself?

By the way fellow hunters, I have figured out that puzzle 125 is most likely between 65% and 85% of 125 bit range, according to my awful calculations, I am 90% certain it resides in 75% of 125 bit range area.  When it's solved we will know for sure, till then hang tight and keep looking hopelessly, not sure if we could even see it's private key though, unless the solver is a real gentle man unlike some people cough 120 solver cough.

If you modify the SECP256K1 curve, for Bitcoin you obtain:
1. Non -valid addresses.
2. Valid addresses but with invalid private keys.

Sorry to give you the bad news this way son! But you just posted the same keys with different encodings, they don't have the exact same hash.

You see, this key
Has only 1 uncompressed key which is : There are no valid key such as

Or

Whatever they are feeding you over at that site you linked, is not proper secp256k1, elliptic curve cryptography.

Though if you are fond of public keys with a lot of zeros, I can give you one.


Next time when you try to spread information, make it legit and verifiable. Posting some random invalid keys and insisting they are valid is not a way to go around these woods, you need to change your supplier I mean tool, what you are using is broken.

play a little with the application below and convince yourself

https://iancoleman.io/bitcoin-key-compression/

all keys are 100% valid

(for uncompressed keys remove the spaces after copy/paste from here)

Did you change the keys somehow? It seems most of them are invalid, I don't know where you got them, but you should put each public key inside a code bracket to better identify them.
To be exact, the number of compressed and uncompressed keys are exactly 50-50.
You don't happen to have any of their private keys do you? For a second I thought you just found hash collisions.🤣

From  
addr: c.   1MRxjnjFDhZfjtjgpxBNczsMGVEtYqfFyS    u.  1Jy6aHcRTWjiPN9DpjZztk2F8xY9iNsaj2
020000000000000000000000000000000000000000000000000000000000000001
040000000000000000000000000000000000000000000000000000000000000001483ada7726a3c 4655da4fbfc0e1108a8fd17b448a68554199c47d08ffb10d4b8
```````
```````all hex range of x
```````
```````
to
addr: c.  1LCQXAGayRCWdAGrh7NKWEcyQNfbbxPdtw    u.   1F18os1CipgxyUj9wBMY4yK1HEVUaub2Nr
02ffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffff
04ffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffff483ada7726a3c 4655da4fbfc0e1108a8fd17b448a68554199c47d08ffb10d4b8

there are addresses with public keys where the coordinate y is the same.

More interesting is the fact that, the public key 02ffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffff is the correspondence for the same addresses  1LCQXAGayRCWdAGrh7NKWEcyQNfbbxPdtw as 0200000000000000000000000000000000000000000000000000000001000003d0 and continuing like this, if we change the value of the y-coordinate of the public key, for each even/odd value it seems the compressed address is the same:
1LCQXAGayRCWdAGrh7NKWEcyQNfbbxPdtw
0400000000000000000000000000000000000000000000000000000001000003d00000000000000 000000000000000000000000000000000000000000000000002

1KmKgQHBMbequmyi9uP1yfa1vsNjdsjyEz
0400000000000000000000000000000000000000000000000000000001000003d00000000000000 000000000000000000000000000000000000000000000000003

1LCQXAGayRCWdAGrh7NKWEcyQNfbbxPdtw
0400000000000000000000000000000000000000000000000000000001000003d00000000000000 000000000000000000000000000000000000000000000000004

1KmKgQHBMbequmyi9uP1yfa1vsNjdsjyEz
0400000000000000000000000000000000000000000000000000000001000003d00000000000000 000000000000000000000000000000000000000000000000005
`````
`````an so on
1LCQXAGayRCWdAGrh7NKWEcyQNfbbxPdtw
0400000000000000000000000000000000000000000000000000000001000003d0fffffffffffff fffffffffffffffffffffffffffffffffffffffffffffffffff

I could conclude from here that any compressed public address exists as many times as there are for each uncompressed address and vice versa, and the mathematical space of the corresponding keys that generate them is much larger and can be treated as a three-dimensional space.

Albert0bsd, what do you mean you can't get exact speed with kangaroo? Do you mean in general or with Iceland's kangaroo? I do not know much about Iceland's version.
When I look at that info displayed, it doesn't seem right to me. Like a bad copy and paste job. If you look at the numbers:


First, there is no way it found 2^29.29 DPs in 6 seconds. Even if it was DP 1. And I am quite sure 2^29.29 would eat up more than 53MB of RAM.

But generally speaking, if you are using GPU Kangaroo by JLP or another GPU version, the speed shown, is accurate. My benchmarks are easy to follow. I have a display (so does JLPs) of total keys checked and number of DPs found. If you are running DP 25 and have completed 2^42 ops (GPU speed * number of cards = keys checked/operations) then you will normally have around 2^17 DPs. 2^42-2^25=2^17.

in 3 months maximum it will be discovered

Proof what you said of GTFO.

Iceland tools are 100% trusted.

About the speed of kangaroo from that tool it is a calculated speed more o less about the expected speed, remember kangaroo it is a probabilistic algorithm and it can't give you exact speed only a near speed based on some math.

Regards

Thanks for the response guys, I was just more curious than anything.

To add to it...
Yes, first you would have to generate 2^75 pubkeys, and then run the kangaroo program, 2^75 times, once for each pubkey generated.

Firstly it would take at least a year and a very large hard drive to generate that many keys. but if you did and somehow found the key on 75 then you  convert that key to decimal and multiply this by 1,125,899,906,842,624 and convert back to hex for the 125 key.

Yeah, most people don't know that Beating Satoshi is impossible without quantum devices

Going back to this... So you drop it 50 bit... Get your insane number of public keys. Theoretically if you then Kangaroo it and get the private key in the range of 75...What's the following process?