Bitcoin puzzle transaction ~32 BTC prize to who solves it - page 286.

WanderingPhilospher

full member

Activity: 1232

Merit: 242

Shooters Shoot...

Quote

I do not believe, this is a scam nothing is easy, a huge amount of money can hit our greed to carry out their scam, you need to think transparently because I it's definitely one of the scams or this is one of a number of unusual transactions possibly money laundering or some kind of insider trading. I recommend staying away from scammers and chances are when you join they will make you pay part of the fee and then evaporate with the money you joined.

This user was obviously in the sauce, drinking when posting this...reading is hard, real hard.

Please read all about puzzle/challenge before posting crazy talk.

PrivatePerson

member

Activity: 174

Merit: 12

Quote from: GubiMixa1292 on October 21, 2021, 05:22:47 PM

I do not believe, this is a scam nothing is easy, a huge amount of money can hit our greed to carry out their scam, you need to think transparently because I it's definitely one of the scams or this is one of a number of unusual transactions possibly money laundering or some kind of insider trading. I recommend staying away from scammers and chances are when you join they will make you pay part of the fee and then evaporate with the money you joined.

Code:

  .-'---`-.
,'          `.
|             \
|              \
\           _  \
,\  _    ,'-,/-)\
( * \ \,' ,' ,'-)
 `._,)     -',-')
   \/         ''/
    )        / /
   /       ,'-'
*scam scam scam*

GubiMixa1292

member

Activity: 139

Merit: 10

Quote from: Bulista on December 28, 2015, 11:12:47 AM

Hi guys,

In continuation to this thread: https://bitcointalksearch.org/topic/brute-force-on-bitcoin-addresses-video-of-the-action-1305887

While playing around with my bot, I found out this mysterious transaction:

https://blockchain.info/tx/08389f34c98c606322740c0be6a7125d9860bb8d5cb182c02f98461e5fa6cd15

those 32.896 BTC were sent to multiple addresses, all the private keys of those addresses seem to be generated by some kind of formula.

For example:

Address 2:

KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3qYjgd9M7rFU74sHUHy8S
1CUNEBjYrCn2y1SdiUMohaKUi4wpP326Lb
Biginteger PVK value: 3
Hex PVK value: 3

Address 3:

KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3qYjgd9M7rFU76rnZwVdz
19ZewH8Kk1PDbSNdJ97FP4EiCjTRaZMZQA
Biginteger PVK value: 7
Hex PVK value: 7

Address 4:

KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3qYjgd9M7rFU77MfhviY5
1EhqbyUMvvs7BfL8goY6qcPbD6YKfPqb7e
Biginteger PVK value: 8
Hex PVK value: 8

Address 5:

KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3qYjgd9M7rFU7Dq8Au4Pv
1E6NuFjCi27W5zoXg8TRdcSRq84zJeBW3k
Biginteger PVK value: 21
Hex PVK value: 15

Address 6:

KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3qYjgd9M7rFU7Tmu6qHxS
1PitScNLyp2HCygzadCh7FveTnfmpPbfp8
Biginteger PVK value: 49
Hex PVK value: 31

Address 7:

KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3qYjgd9M7rFU7hDgvu64y
1McVt1vMtCC7yn5b9wgX1833yCcLXzueeC
Biginteger PVK value: 76
Hex PVK value: 4C

Address 8:

KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3qYjgd9M7rFU8xvGK1zpm
1M92tSqNmQLYw33fuBvjmeadirh1ysMBxK
Biginteger PVK value: 224
Hex PVK value: E0

Address 9:

KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3qYjgd9M7rFUB3vfDKcxZ
1CQFwcjw1dwhtkVWBttNLDtqL7ivBonGPV
Biginteger PVK value: 467
Hex PVK value: 1d3

Address 10:

KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3qYjgd9M7rFUBTL67V6dE
1LeBZP5QCwwgXRtmVUvTVrraqPUokyLHqe
Biginteger PVK value: 514
Hex PVK value: 202

Address 11:

KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3qYjgd9M7rFUGxXgtm63M
1PgQVLmst3Z314JrQn5TNiys8Hc38TcXJu
Biginteger PVK value: 1155
Hex PVK value: 483

Address 12:

KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3qYjgd9M7rFUW5RtS2JN1
1DBaumZxUkM4qMQRt2LVWyFJq5kDtSZQot
Biginteger PVK value: 2683
Hex PVK value: a7b

Address 13:

KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3qYjgd9M7rFUspniiQZds
1Pie8JkxBT6MGPz9Nvi3fsPkr2D8q3GBc1
Biginteger PVK value: 5216
Hex PVK value: 1460

Address 14:

KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3qYjgd9M7rFVfZyiN5iEG
1ErZWg5cFCe4Vw5BzgfzB74VNLaXEiEkhk
Biginteger PVK value: 10544
Hex PVK value: 2930

and so on...

until the addresses 50 (1MEzite4ReNuWaL5Ds17ePKt2dCxWEofwk) it was already cracked by someone.

Any ideas what's the formula behind the generation of these addresses?

Address 2, pvk decimal value: 3
Address 3, pvk decimal value: 7
Address 4, pvk decimal value: 8
Address 5, pvk decimal value: 21
Address 6, pvk decimal value: 49
Address 7, pvk decimal value: 76
Address 8, pvk decimal value: 224
Address 9, pvk decimal value: 467
Address 10, pvk decimal value: 514
Address 11, pvk decimal value: 1155
Address 12, pvk decimal value: 2683
Address 13, pvk decimal value: 5216
Address 14, pvk decimal value: 10544
Address 15 and after, pvk decimal value: ?

The prize would be ~32 BTC

EDIT: If you find the solution feel free to leave a tip

1DPUhjHvd2K4ZkycVHEJiN6wba79j5V1u3

I do not believe, this is a scam nothing is easy, a huge amount of money can hit our greed to carry out their scam, you need to think transparently because I it's definitely one of the scams or this is one of a number of unusual transactions possibly money laundering or some kind of insider trading. I recommend staying away from scammers and chances are when you join they will make you pay part of the fee and then evaporate with the money you joined.

MoreForUs

newbie

Activity: 17

Merit: 0

DID YOU ALL GIVE UP ? SHOULD I TAKE IT ALL FOR MYSELF?…..

NotATether

legendary

Activity: 1568

Merit: 6660

bitcoincleanup.com / bitmixlist.org

Quote from: ?? on ??

I can send you a tip if you have a private key for any of these

These are the addresses for #161-256.

If you look carefully at https://www.blockchain.com/btc/tx/5d45587cfd1d5b0fb826805541da7d94c61fe432259e68ee26f4a04544384164 you will see that the owner has moved the balances in these addresses to #53-#160 respectively.

Some of these private keys have already been found, namely: 53 to 63, 65, 70, 75 ... up to 115 and zielar has listed them in his thread.

NotATether

legendary

Activity: 1568

Merit: 6660

bitcoincleanup.com / bitmixlist.org

Quote from: ?? on ??

DOES ANY ONE HAVE KEY FOR ANY OF THESE SOLVED ADDRESSES
~

Why would you want the empty private keys unless you wanted to analyze their distribution in the range (since the private keys are random numbers that are generated in a range)?

PrivatePerson

member

Activity: 174

Merit: 12

Quote from: yoyodapro on August 24, 2021, 05:03:31 PM

I use -k 3250 on my main rig but your results may vary

How much RAM do you have?

yoyodapro

jr. member

Activity: 50

Merit: 7

Quote from: PrivatePerson on August 06, 2021, 05:26:30 AM

Quote from: COBRAS on August 05, 2021, 05:14:57 PM

With 256 GB ram I get speed about 22000 Gkeys/sec

What value are you using for the -k parameter?

play around with it, it will tell you how much ram is needed. I use -k 3250 on my main rig but your results may vary

PrivatePerson

member

Activity: 174

Merit: 12

Quote from: COBRAS on August 05, 2021, 05:14:57 PM

With 256 GB ram I get speed about 22000 Gkeys/sec

What value are you using for the -k parameter?

COBRAS

member

Activity: 873

Merit: 22

$$P2P BTC BRUTE.JOIN NOW ! https://uclck.me/SQPJk

@Andzhig - great work ! Thank you very mach

Fastest CPU privkeykey finder is a KEYHUNT https://github.com/albertobsd/keyhunt - speed calculates in gigagheshe on simple CPU with 4 cores and 8 GB RAM. With 256 GB ram I get speed about 22000 Gkeys/sec, this is mach faster then JeanLucKangaroo

Great work like yours, mast have access to a great soft Grin

Continue your work please - very interesting reading.

Regards !

Andzhig

jr. member

Activity: 184

Merit: 3

collision test for pz 20

2^20 1048576, 20 1HsMJxNiV7TLxmoF6uJNkydxPFDog4NQum | 863317

(24!/12!/12!)/2^20 2,578884124755859375
1048576 2^20
2704156 step
2 collisions, finds only 1 for some reason

(28!/14!/14!)/2^20 38,25817108154296875
1048576 2^20
40116600 step
38 collisions, why is it 43...

step 565214 seed 0000011001110101101110001110 bit 11010010110001010101 dec 863317 1HsMJxNiV7TLxmoF6uJNkydxPFDog4NQum
step 1269043 seed 0000101111000101110001110011 bit 11010010110001010101 dec 863317 1HsMJxNiV7TLxmoF6uJNkydxPFDog4NQum
step 1816300 seed 0000111100111010110010100101 bit 11010010110001010101 dec 863317 1HsMJxNiV7TLxmoF6uJNkydxPFDog4NQum
step 2886941 seed 0001011011010100110001100111 bit 11010010110001010101 dec 863317 1HsMJxNiV7TLxmoF6uJNkydxPFDog4NQum
step 3376293 seed 0001100111100010001011111100 bit 11010010110001010101 dec 863317 1HsMJxNiV7TLxmoF6uJNkydxPFDog4NQum
step 4307993 seed 0001111100011000111000110110 bit 11010010110001010101 dec 863317 1HsMJxNiV7TLxmoF6uJNkydxPFDog4NQum
step 5007146 seed 0010010010001011010111001111 bit 11010010110001010101 dec 863317 1HsMJxNiV7TLxmoF6uJNkydxPFDog4NQum
step 5488783 seed 0010011101100101001111110000 bit 11010010110001010101 dec 863317 1HsMJxNiV7TLxmoF6uJNkydxPFDog4NQum
step 6365709 seed 0010110010111101010100101001 bit 11010010110001010101 dec 863317 1HsMJxNiV7TLxmoF6uJNkydxPFDog4NQum
step 7330410 seed 0011001010001111010100011101 bit 11010010110001010101 dec 863317 1HsMJxNiV7TLxmoF6uJNkydxPFDog4NQum
step 8876578 seed 0011101100101011000110011001 bit 11010010110001010101 dec 863317 1HsMJxNiV7TLxmoF6uJNkydxPFDog4NQum
step 8937380 seed 0011101110000010110101011100 bit 11010010110001010101 dec 863317 1HsMJxNiV7TLxmoF6uJNkydxPFDog4NQum
step 9402193 seed 0011111000110001011110011000 bit 11010010110001010101 dec 863317 1HsMJxNiV7TLxmoF6uJNkydxPFDog4NQum
step 9785819 seed 0100000110000011101011011111 bit 11010010110001010101 dec 863317 1HsMJxNiV7TLxmoF6uJNkydxPFDog4NQum
step 10747091 seed 0100011110110000101110110010 bit 11010010110001010101 dec 863317 1HsMJxNiV7TLxmoF6uJNkydxPFDog4NQum
step 11895627 seed 0100111010000100011101011101 bit 11010010110001010101 dec 863317 1HsMJxNiV7TLxmoF6uJNkydxPFDog4NQum
step 11905033 seed 0100111010010000011001111101 bit 11010010110001010101 dec 863317 1HsMJxNiV7TLxmoF6uJNkydxPFDog4NQum
step 12211211 seed 0101000010010111100111010101 bit 11010010110001010101 dec 863317 1HsMJxNiV7TLxmoF6uJNkydxPFDog4NQum
step 12277674 seed 0101000011111100111001000110 bit 11010010110001010101 dec 863317 1HsMJxNiV7TLxmoF6uJNkydxPFDog4NQum
step 14709359 seed 0101111011001011001111000000 bit 11010010110001010101 dec 863317 1HsMJxNiV7TLxmoF6uJNkydxPFDog4NQum
step 15764971 seed 0110010101111111101000100000 bit 11010010110001010101 dec 863317 1HsMJxNiV7TLxmoF6uJNkydxPFDog4NQum
step 15843680 seed 0110010111100110101001011000 bit 11010010110001010101 dec 863317 1HsMJxNiV7TLxmoF6uJNkydxPFDog4NQum
step 15900143 seed 0110011000111110010011000110 bit 11010010110001010101 dec 863317 1HsMJxNiV7TLxmoF6uJNkydxPFDog4NQum
step 17155504 seed 0110110101001000010110111010 bit 11010010110001010101 dec 863317 1HsMJxNiV7TLxmoF6uJNkydxPFDog4NQum
step 17858310 seed 0111000110101101110010010010 bit 11010010110001010101 dec 863317 1HsMJxNiV7TLxmoF6uJNkydxPFDog4NQum
step 21522266 seed 1000101000111001001110001111 bit 11010010110001010101 dec 863317 1HsMJxNiV7TLxmoF6uJNkydxPFDog4NQum
step 23500878 seed 1001010110110010100110000111 bit 11010010110001010101 dec 863317 1HsMJxNiV7TLxmoF6uJNkydxPFDog4NQum
step 23833593 seed 1001011110000011100111000011 bit 11010010110001010101 dec 863317 1HsMJxNiV7TLxmoF6uJNkydxPFDog4NQum
step 24985276 seed 1001111000011011000101111000 bit 11010010110001010101 dec 863317 1HsMJxNiV7TLxmoF6uJNkydxPFDog4NQum
step 25327445 seed 1010000010101101110011010011 bit 11010010110001010101 dec 863317 1HsMJxNiV7TLxmoF6uJNkydxPFDog4NQum
step 26246246 seed 1010010111101001010111000001 bit 11010010110001010101 dec 863317 1HsMJxNiV7TLxmoF6uJNkydxPFDog4NQum
step 26556823 seed 1010011110011010110001101000 bit 11010010110001010101 dec 863317 1HsMJxNiV7TLxmoF6uJNkydxPFDog4NQum
step 28067683 seed 1011000010101110001101110010 bit 11010010110001010101 dec 863317 1HsMJxNiV7TLxmoF6uJNkydxPFDog4NQum
step 28359337 seed 1011001001000000110011111101 bit 11010010110001010101 dec 863317 1HsMJxNiV7TLxmoF6uJNkydxPFDog4NQum
step 28899884 seed 1011010100111100010011110000 bit 11010010110001010101 dec 863317 1HsMJxNiV7TLxmoF6uJNkydxPFDog4NQum
step 32201625 seed 1100101000111000110100110110 bit 11010010110001010101 dec 863317 1HsMJxNiV7TLxmoF6uJNkydxPFDog4NQum
step 32409102 seed 1100101101001110011100110000 bit 11010010110001010101 dec 863317 1HsMJxNiV7TLxmoF6uJNkydxPFDog4NQum
step 33586060 seed 1101001001100011001100001111 bit 11010010110001010101 dec 863317 1HsMJxNiV7TLxmoF6uJNkydxPFDog4NQum
step 33958451 seed 1101010001111011000100100101 bit 11010010110001010101 dec 863317 1HsMJxNiV7TLxmoF6uJNkydxPFDog4NQum
step 36614769 seed 1110010101010100011111000100 bit 11010010110001010101 dec 863317 1HsMJxNiV7TLxmoF6uJNkydxPFDog4NQum
step 36700341 seed 1110010111010100010111000010 bit 11010010110001010101 dec 863317 1HsMJxNiV7TLxmoF6uJNkydxPFDog4NQum
step 36918609 seed 1110011100101011000010100110 bit 11010010110001010101 dec 863317 1HsMJxNiV7TLxmoF6uJNkydxPFDog4NQum
step 37574368 seed 1110101100111010100010010001 bit 11010010110001010101 dec 863317 1HsMJxNiV7TLxmoF6uJNkydxPFDog4NQum

Quote

import random
from bit import Key

list = ["1HsMJxNiV7TLxmoF6uJNkydxPFDog4NQum"] # pz 20 > dec 863317

def lexico_permute_string(s):
   a = sorted(s)
   n = len(a) - 1
   while True:
   yield ''.join(a)
   for j in range(n-1, -1, -1):
   if a[j] < a[j + 1]:
   break
   else:
   return
   v = a[j]
   for k in range(n, j, -1):
   if v < a[k]:
   break
   a[j], a[k] = a[k], a[j]
   a[j+1:] = a[j+1:][::-1]

a1="1"*14
a2="0"*14
a3=a1+a2 # seed str

s = a3 # seed str 000000000000000111111111111111
sv = lexico_permute_string(s)

count0 = 0

for line1 in sv:

   s = line1#[0:30]

   count0 += 1
   random.seed(s)

   Nn = "0","1"

   RRR = [] #func()

   for RR in range(20): # "bit" set
   DDD = random.choice(Nn)
   RRR.append(DDD)

   d = ''.join(RRR)
   b = int(d,2)
   if b >= 1:
   key = Key.from_int(b)
   addr = key.address
   if addr in list:
   print ("found...........","seed step from 000000000000111111111111 to 111111111111000000000000","step",count0,"seed",s,"bit",d,"dec",b,addr)
   #s1 = str(b)
   #s2 = addr
   #f=open("a.txt","a")
   #f.write(s1)
   #f.write(s2)
   #f.close()
   pass
   else:
   pass
   #print ("step",count0,"seed",s,"bit",d,"dec",b,addr) #print (X,sv,len(sv),dd,len(dd),b,addr)

print("pz end")
input() #"pause"

for 64 ...

(188!/94!/94!)/2^64 1235956206315626091331338051467874028
18446744073709551616 2^64
22799367824217315491046998779230288685596678611381812000
1235956206315626091331338051467874028 collisions

(168!/84!/84!)/2^64 1246690648845973918331482456337
18446744073709551616 2^64
22997383338348585032434609379579328145757058837400 168!/84!/84!
1246690648845973918331482456337 collisions

(148!/74!/74!)/2^64 1266470970702566355349691
18446744073709551616 2^64
23362265873332749085315221863910685052043000 148!/74!/74!
1266470970702566355349691 collisions

(128!/64!/64!)/2^64 1298394228608800905,709 collisions
18446744073709551616 2^64
23951146041928082866135587776380551750 128!/64!/64!
1298394228608800905 collisions

(100!/50!/50!)/2^64 5469330747,064212325444
18446744073709551616 2^64
100891344545564193334812497256 100!/50!/50!
5469330747 collisions

(80!/40!/40!)/2^64 5827,977463326783892683
18446744073709551616 2^64
107507208733336176461620 80!/40!/40!
5827 collisions

(70!/35!/35!)/2^64 6,081630306594410506193
18446744073709551616 2^64
112186277816662845432 70!/35!/35!
6 collisions

(68!/34!/34!)/2^64 1,542442469063799766063
18446744073709551616 2^64
28453041475240576740 68!/34!/34!
1 collisions

the best option? (128!/64!/64!)/2^64

because 1 (68!/34!/34!)/2^64 may not exist, how to search 6? (70!/35!/35!)/2^64

112186277816662845432/6 = 18697712969443807572 (~ 2^64)

take the first step randomly and add to it 5 times dec 2^64...

or looking for "mathematical expectation" yeah monkeys are writing a book

it is not clear why because 256 bits can be different

bit to character sampling ratio

1111 11111111 1111111111111111 11111111111111111111111111111111...

Quote

import random

def lexico_permute_string(s):
   a = sorted(s)
   n = len(a) - 1
   while True:
   yield ''.join(a)
   for j in range(n-1, -1, -1):
   if a[j] < a[j + 1]:
   break
   else:
   return
   v = a[j]
   for k in range(n, j, -1):
   if v < a[k]:
   break
   a[j], a[k] = a[k], a[j]
   a[j+1:] = a[j+1:][::-1]

a1="1"*300
a2="0"*300
a3=a1+a2

s = a3#"11100000000" #000000000000000111111111111111
sv = lexico_permute_string(s)

count0 = 0
count1 = 0
count2 = 0
count3 = 0
count4 = 0
for line1 in sv:

   s = line1#[0:30]

   count0 += 1
   random.seed(s)

   Nn = "0","1"

   RRR = [] #func()

   for RR in range(256): # len bit set
   DDD = random.choice(Nn)
   RRR.append(DDD)

   d = ''.join(RRR)

   v1 = d[0:4]
   v2 = d[0:8]
   v3 = d[0:16]
   v4 = d[0:32]
   if v1 == "1111":
   count1 += 1
   #print(count0,count1,v1,s)
   if v2 == "11111111":
   count2 += 1
   #print(count0,count1,count2,v1,v2,s)
   if v3 == "1111111111111111":
   count3 += 1
   print(count0,count1,count2,count3,v1,v2,v3,s)
   #print("")
   if v4 == "11111111111111111111111111111111":
   count4 += 1
   print(count0,count1,count2,count3,count4,v1,v2,v3,v4,s)
   #print("")

***

or take for each puzzle the same ratio of collisions to length (as far as possible), look at the graphs for the distribution of collisions and search in possible areas... although there is a freaking random and there is not much sense from this.

Andzhig

jr. member

Activity: 184

Merit: 3

Quote from: zahid888 on July 25, 2021, 04:21:39 AM

@Andzhig And if we increase one more character of address 16jY7qLJn & 'x' then most binaries are started from '111'

few examples -

16jY7qLJnxLQQRYPX5BLuCtcBs6tvXz8BE   1110000000100110101001101101010100100011010011001000100000110110000   7013536A91A6441B0
16jY7qLJnX9uchnyf26t3QJnsUf78Xdikb   1110010000101000111010000001111110010000001011001101111011100000   E428E81F902CDEE0
16jY7qLJnX9eX8j612s8fnbn6uzR48xjua   1110100000001101111010110011001110101001011001111010000010001111   E80DEB33A967A08F
16jY7qLJnx2EZZumnYFke3GutCrRnHKs1M   111010110100110101001101101010111010101000110011101011001010110000   3AD3536AEA8CEB2B0
16jY7qLJnx2ixrxCnTLSraerkgyB3YYAiT   1110110111111001110011010110000000110101011011011100110000011001   EDF9CD60356DCC19
16jY7qLJnxHBp3dqwV2kzYq1LucfZzgxsH   1110111010111001101010110011001101001101111100100111011100001101   EEB9AB334DF2770D
16jY7qLJnX2cZXJ78wV1ef42e7cLAZJ1Vn   1111111000101000011001011100011011011011111111101100001110000011   FE2865C6DBFEC383

Could this also be some logic?

it is difficult to say that experiments are needed, but soon there is none. otherwise it's too easy.

16jY7qLJnxb7CHZyqBP8qca9d51gAjyXQN base58 , 58 characters 123456789ABCDEFGHJKLMNPQRSTUVWXYZabcdefghijkmnopqrstuvwxyz "x" we know. 2 after "x" and 24 after

how many possible addresses after "x" 2×58×58×58×58×58×58×58×58×58×58×58×58×58×58×58×58×58×58×58×58×58×58×58×58 = 4200508241814704971052461011661183822856192 (2^141)

***

Quote

How many characters are in the private key in binary?

we have 64 bit address 2^64 , 64 characters 1 and 0 randomly located (which are not known to us)

***

collisions and with such spreads slip

__1111111111_1100000000_0_0_00', ',_, >', 6, '001111111111011000000001010100 1111111100000000
1_111_111111_11000000_0_0_0000', ',_, >', 6, '101110111111011000000101010000 0000000011111111
11_1111_111111_000000_00_0_000', ',_, >', 6, '110111101111110000000100101000 1111111111111111
1111_1_1111_1110000_000_0_0000', ',_, >', 6, '111101011110111000010001010000 0000000011111111
11111_111_111_1_0_0000_0000000', ',_, >', 6, '111110111011101101000010000000 1111111111111111
111111111_1_11_000000_0_0_0000', ',_, >', 6, '111111111010110000000101010000 0000000011111111

000000000_000___1111111111__11', ',_, >', 6, '000000000100011011111111110011 0000000000000000
00000000__000_0111_1111111_11_', ',_, >', 6, '000000001100010111011111110110 1111111100000000
0000000_000_0_0111111111__111_', ',_, >', 6, '000000010001010111111111001110 1111111100000000
00000_0_0000_00111111_111_111_', ',_, >', 6, '000001010000100111111011101110 0000000011111111
0000_000000000_111111_11111_11', ',_, >', 4, '000010000000001111111011111011 0000000000000000
0000_0000_0_0001_111_1111_1111', ',_, >', 6, '000010000101000101110111101111 0000000000000000
0_000000_00000_111111_11111__1', ',_, >', 6, '010000001000001111111011111001 1111111100000000
_00_0000000_00011_1111111_1_11', ',_, >', 6, '100100000001000110111111101011 1111111111111111

i.e. 3 there 3 here (and 2 1 times)

but the whole enumeration of their 4 parts is too long

111111111111000 all permut 455 000000000000111 all permut 455, (15x15 = 30 seed, 455x455 = 207025) 207025×207025×207025×207025 = 1836923935996687890625 step

but can this be repeated when seed 78 len (1 seed for 64).

39 x 39 - 78
000000000000000000000000000000000000111 all permut 9139 111111111111111111111111111111111111000 all permut 9139, 9139 x 9139 = 83521321

still need to see if instead of 16 to 8, take (8x8) whether the chance of random catching increases.

***

1 by 2 ran empy, by 3 runs...

000000000000000000000000000100000001010101111011111111111111111111111111111110 78 1101011100110011010001001001010010000011111101100110011111110010 64 15506813346626562034 14rydssuUnBn2bDeDRwjRxn546iuYq5s8n
000000000000000000000000000100000001010101111011111111111111111111111111111011 78 1110110010100000011011001101111010011011010110010100100010100111 64 17050747892569557159 13kzS77Upy2EqPtSybbGmoYzZMXtAGtkVm
000000000000000000000000000100000001010101111011111111111111111111111111110111 78 1011000001001110010110100111110101011101010011101101111100000101 64 12704191093341609733 1FEDNb3vX4pkfHboWWuodggQdRSW5jA3ey
000000000000000000000000000100000001010101111011111111111111111111111111101111 78 1010111101000001100001001110101111000001100011001011011100110110 64 12628520978222987062 152M84nqWb66tJpueESC2XaFUCPq9HcsW4
000000000000000000000000000100000001010101111011111111111111111111111111011111 78 1101011101001100001101011101101001101000011001100000101100011011 64 15513834028555176731 15gV7VfkWFg9LdLcaYE2iL7q1t923uM7Dc
000000000000000000000000000100000001010101111011111111111111111111111011111111 78 1111100011010101010100010001000001001000110110101000110100010101 64 17930326621829106965 1NMJUq3TfTzW3846bC9kijhF1r77K7UhWY
000000000000000000000000000100000001010101111011111111111111111111101111111111 78 1110111101110101001100010100110001010001111100100011111101100110 64 17254751751202029414 1NYCF4WV6aD1Mz9VmFs9jXTjb8CFgzV7G4
000000000000000000000000000100000001010101111011111111111111111110111111111111 78 1110111000101011001001001111111011101010110010101111000101100101 64 17161851482304868709 1BDBLPttExoSwJDw7LbNWAsZ1JKdkLwwmE
000000000000000000000000000100000001010101111011111111111111111101111111111111 78 1011000001001101110100111011000011000110110110100110010100111010 64 12704042880085943610 13uodKaP1yYG2qUGrdUFTLDnZoTPV3GDqY
000000000000000000000000000100000001010101111011111111111111111011111111111111 78 1011000110110111101001100111001001101000100000011111100000100111 64 12805887075761125415 1En1yWAp8bP8s5Wsi3LnRVx9tfN2ABtNV5
000000000000000000000000000100000001010101111011111111111111101111111111111111 78 1100010001000110101010110011011011101100110111011010111111100111 64 14143179932194156519 1BuXVR46gQXHbo1n4UpUajbpHsE3oYYfsM
000000000000000000000000000100000001010101111011111111111111011111111111111111 78 1001110011100000001100010100100011101111111010110100101101110100 64 11304089254032526196 1HAo6Xq4N4nsS2r3ESt7Gzxs68EK6sqKZM
000000000000000000000000000100000001010101111011111111111110111111111111111111 78 1100001110111000110010011000111001111101101110000101011111000100 64 14103243846942480324 1KVPGV3irrQK2fXy9xbB5k44GehXhAhmM9
000000000000000000000000000100000001010101111011111111111101111111111111111111 78 1001110111110111101110011001100100010011000111010000011001110110 64 11382770650304022134 1GB6gXhhUFhhebYEARknDXCFgk5XzXaaBb
000000000000000000000000000100000001010101111011111111101111111111111111111111 78 1110000101111010110101101100110100000000111110100010101001111000 64 16247534781665520248 1Gkuxy1DhJYzHxCxNrmYQxmGCHj8c4KWVt
000000000000000000000000000100000001010101111011111110111111111111111111111111 78 1100011011001110000111101000100001100011000011000110000101110101 64 14325421035838267765 1GuL9fLofPMNNeT7rqmUezpDAKKuBgvL1T
000000000000000000000000000100000001010101111011111011111111111111111111111111 78 1010001111101100100001011111000011001100000111001100001100110110 64 11811963191949050678 1Cq9nGaqmP8bUUBKBFQqkC5nQ1Q2tpuoNF
000000000000000000000000000100000001010101111011110111111111111111111111111111 78 1110100011101110101011100111101110101110000011111011101110000001 64 16784544707480894337 1FBSMs5GU6pkd5QSCXYecRqbxvAhpZuL5C
000000000000000000000000000100000001010101111011101111111111111111111111111111 78 1001111101001000000110000110010111100110000000100001101011000011 64 11477450476283370179 1CAPXky8N3AqJwgKnv1vN9McC112ZZdw8m
000000000000000000000000000100000001010101111010111111111111111111111111111111 78 1000011001100111100100010011111101011101011000111111000111110001 64 9684869225019339249 1LUHZkGEBqXVtaN5MuFnvUrdEHf5B928jY
000000000000000000000000000100000001010101111001111111111111111111111111111111 78 1011001110001111001110100001101110101100111100011100001000111000 64 12938624144998777400 1MJxoDoa9kYFn4pdKeAi7gA83ZoPqvic9x
000000000000000000000000000100000001010101110111111111111111111111111111111101 78 1011010110100010010011110000010010111011001100100110101011001011 64 13088110348831189707 1JXNK2J6trmBQRMHDKgB8K8FYe7XPaneHa
000000000000000000000000000100000001010101110111111111111111111111111111111011 78 1001100010001010100001100000001000101110101000101010011010110010 64 10991745184481584818 12RXgtZZpaKXs2fX6whvs2ojceDRRyDZwP
000000000000000000000000000100000001010101110111111111111111111111111111110111 78 1100011110010010111100000011101010111010110010100010101111011110 64 14380820695179996126 1D2pcWu62Y3SJfejsgHXEKtNsAtvZGNtWK
000000000000000000000000000100000001010101110111111111111111111111111111101111 78 1010000011000101010011101111000111001000101100101111000000001101 64 11584752416841723917 1DX6NzYW2grMLGCUft1LBbFxm39nqEA9Ae
000000000000000000000000000100000001010101110111111111111111111111111110111111 78 1011000101010010010001111101000100010010101011100010011100111010 64 12777354056090658618 1N3Ku5oR3C88xVgm6VVquNs7JfnSk2xvZk
000000000000000000000000000100000001010101110111111111111111111111111101111111 78 1000010011001011110100110010011010001001101100110111111100011100 64 9568973995751210780 1NwpUf69nR9CTuNcWgKFXY7EuewSqTAtTS
000000000000000000000000000100000001010101110111111111111111111111111011111111 78 1101001001100011101001100110111010001001011110001010101001111100 64 15160143764342221436 19wQikrohsLzKDnwX8F4Ag6NCTxQ2fEpGE
000000000000000000000000000100000001010101110111111111111111111110111111111111 78 1000001111100101011101100100100000001010100111001100000111101000 64 9504132640423068136 1GmLqntzgCukjzF7xTzfjXLN8oDunwChkk
000000000000000000000000000100000001010101110111111111111111111101111111111111 78 1011011100101001000011011101000011111001011100010000110011111110 64 13198095374175243518 18zhvaSdwVmcAhorEYtfpHTGG8wB8jdWKV
000000000000000000000000000100000001010101110111111111111111110111111111111111 78 1001101111000001000000110011011111011101111110100011100001000110 64 11223255284866234438 19mCEpHUanT1J7hDbdyMgqCZUHLWeSb5xU
000000000000000000000000000100000001010101110111111111111111101111111111111111 78 1111001000011010100011100111011110011101001000001110101000000101 64 17445412750961469957 18VcFdKicFFqjKAXWRqd8zGXi43S4Rq2NM
000000000000000000000000000100000001010101110111111111111111011111111111111111 78 1000111001111000000010111100000111001111010111010001000011011000 64 10265968277626622168 1cTZzdVCNg8NG4a9xoQXgkWD4muJkppGa
000000000000000000000000000100000001010101110111111111111110111111111111111111 78 1001001001011111111110100101000110110001011001100000001011001110 64 10547424081100538574 1PZgpSVPtZDen8bBAMSrJ5gxcqUyFAqsQ4
000000000000000000000000000100000001010101110111111110111111111111111111111111 78 1000000000110101101000110110111101111010110001010101111100110111 64 9238469909816893239 19osC5SyTMdPY18sbjLuYuT44HppxXT28k
000000000000000000000000000100000001010101110111011111111111111111111111111111 78 1001111100000011000110001000001101001100110001110000100001101011 64 11458028829168568427 1HqH8xuq3WqsJxTE7QAu6iBDsPENzMJt6H
000000000000000000000000000100000001010101110101111111111111111111111111111111 78 1111000111100111110011001111011100111011001010111100011111001011 64 17431126244982507467 1BUVWY4UkZ39ZSZmiwe9fAPTwvZ3n6osK7
000000000000000000000000000100000001010101110011111111111111111111111111111111 78 1111111110111001001101110011011100111010000011000000000011001001 64 18426820060699689161 1Eqc7UPgWRPJidsvt3EhKZ6jNWkfdMFKrN

Quote

from os import system
system("title "+__file__)
import random
from bit import Key

def Permute(string):
   if len(string) == 0:
   return ['']
   prevList = Permute(string[1:len(string)])
   nextList = []
   for i in range(0,len(prevList)):
   for j in range(0,len(string)):
   newString = prevList[0:j]+string[0]+prevList[j:len(string)-1]
   if newString not in nextList:
   nextList.append(newString)
   return nextList

def Permute2(string2):
   if len(string2) == 0:
   return ['']
   prevList = Permute(string2[1:len(string2)])
   nextList = []
   for i in range(0,len(prevList)):
   for j in range(0,len(string2)):
   newString = prevList[0:j]+string2[0]+prevList[j:len(string2)-1]
   if newString not in nextList:
   nextList.append(newString)
   return nextList

list = ["16jY7qLJnxb7CHZyqBP8qca9d51gAjyXQN"]

for X in range(0,1,1):

   random.seed() # seed initiation () random or (X)

   string = "000000000000000000000000000000000000111" # initiation seed len
   sv = Permute(string) #''.join(random.sample(s,len(s)))
   string2 ="111111111111111111111111111111111111000" # initiation seed len
   sv2 = Permute2(string2)
   for elem in sv:
   for elem1 in sv2:
   sv3 = elem+elem1


   random.seed(sv3) #string

   Nn = "0","1" #"0","1"
   RRR = []

   for RR in range(64): # pz bit range
   DDD = random.choice(Nn)
   RRR.append(DDD)

   d = ''.join(RRR)
   #print(d,len(d))


   b = int(d,2)
   if b >= 9223372036854775807:
   key = Key.from_int(b)
   addr = key.address
   if addr in list:
   print ("found!!!",b,addr)
   s1 = str(b)
   s2 = addr
   f=open("a.txt","a")
   f.write(s1)
   f.write(s2)
   f.close()
   pass
   else:
   #print (X,"seed mask len",len(string),string,",","64 bit pz",dd,",",b,addr)
   print(sv3,len(sv3),d,len(d),b,addr) #print (X,sv,len(sv),dd,len(dd),b,addr)

***

can be 32 more out of 46

11111111111111111111000
00000000000000000000111 23+23 (1771×1771 = 3136441)

11111111111111110000000000000000 x2 32

3136441×3136441 = 9837262146481 steps ,for a long time

and it is problematic to analyze in a few hours only 3 seeds found

   steps 32 bits seed
169382696 11111111111111110000000000000000 0110111111111111111110000000000000000100011010
244507506 11111111111111110000000000000000 1111000111111111111111100000000000000001100100
244854754 11111111111111110000000000000000 1111001001010111111111111111100000000000000000

***

crap may be if "111111111111000 all permut 455 000000000000111 all permut 455, (15x15 = 30 seed, 455x455 = 207025)" 207025 everyone crawls here from surplus (16 bit, from 000000000000000 to 1111111111111111) 65536 i.e. 455^2 > 2^16. and to get for 64 bits it is necessary to have more "000000000000000000000000000000000000111 all permut 9139 111111111111111111111111111111111111000 all permut 9139, 9139 x 9139 = 83521321" 9139^2 need such a number so that it is also more than a 64-bit puzzle. and these are huge numbers something around this 25000000000^2 = 625000000000000000000. but maybe it doesn't work that way.

***

all permutations are considered factorial

256!/128!/128! = 5768658823449206338089748357862286887740211701975162032608436567264518750790 2^251

30!/15!/15! = 155117520, all 4 by 4 permut 155117520^4 578953136014989894775911260160000 and they have 1000^4 provided that we all 4 pebble.

578953136014989894775911260160000
1000000000000

partially which also got here

"collisions and with such spreads slip"
__1111111111_1100000000_0_0_00', ',_, >', 6, '001111111111011000000001010100 1111111100000000
1_111_111111_11000000_0_0_0000', ',_, >', 6, '101110111111011000000101010000 0000000011111111
11_1111_111111_000000_00_0_000', ',_, >', 6, '110111101111110000000100101000 1111111111111111
1111_1_1111_1110000_000_0_0000', ',_, >', 6, '111101011110111000010001010000 0000000011111111
11111_111_111_1_0_0000_0000000', ',_, >', 6, '111110111011101101000010000000 1111111111111111
111111111_1_11_000000_0_0_0000', ',_, >', 6, '111111111010110000000101010000 0000000011111111

000000000_000___1111111111__11', ',_, >', 6, '000000000100011011111111110011 0000000000000000
00000000__000_0111_1111111_11_', ',_, >', 6, '000000001100010111011111110110 1111111100000000
0000000_000_0_0111111111__111_', ',_, >', 6, '000000010001010111111111001110 1111111100000000
00000_0_0000_00111111_111_111_', ',_, >', 6, '000001010000100111111011101110 0000000011111111
0000_000000000_111111_11111_11', ',_, >', 4, '000010000000001111111011111011 0000000000000000
0000_0000_0_0001_111_1111_1111', ',_, >', 6, '000010000101000101110111101111 0000000000000000
0_000000_00000_111111_11111__1', ',_, >', 6, '010000001000001111111011111001 1111111100000000
_00_0000000_00011_1111111_1_11', ',_, >', 6, '100100000001000110111111101011 1111111111111111

apparently because here "455x455 = 207025" < 65536 (2^16 all bit)

but if we take

84!/42!/42! 1678910486211891090247320 < 18446744073709551616 2^64 the puzzle fits here but will he end up in the desired area

42!/39!/3! = 11480, 11480x11480 (42+42= seed 84 > 64 bit) = 131790400 , 131790400 vs 18446744073709551616

option to increase the ratio to repeat the experience with 16 of 30

4000!/3997!/3!)^2 = 113607203534224000000 (207025 < 65536, 6 len vs 5 len) 21 len vs 20
or
(42!/28!/14!)^2 = 2794203818390077646400 (207025 < 65536, 6 len vs 5 len) 22 len vs 20

probably this is how it works... but maybe not)))

***

how many fits 4 out of 30

2^4 = 16 (from 0000 to 1111)

for each about 31000 seeds 30, and for all 16 approximately 16x31000 = 499114 (although if 30!/15!/15! = 155117520, 155117520 / 65536 = ~2366 should be for 16, x4 from 30, and 155117520/16 =9694845 for 4 x16 from 30)

if all 16 iterate over 1×2×3×4×56×7×8×9×10×11×12×13×14×15×16 = 39055874457600

a chance for good luck? 31000^16 = 727423121747185263828481000000000000000000000000000000000000000000000000

how to guess 16 parts in correct sequence from 31000^16 or 8 random to take the rest 8 to rearrange all combinations... with the same success, can simply duplicate everything from 0000 to 1111 and randomly choose))

blablabla
000000000000101111111111111001 0000
000000000000111111101011111011 0011
000000000001011101110111111110 1111
000000000001011101111110111101 0011
000000000001011111111011010111 0011
000000000001101001111111111101 0111
000000000001101011010111111111 1111
000000000001101111111111101100 1010
000000000001110011111011111011 0111
000000000001111100111011110111 0100
000000000001111111010111101110 0111
000000000001111111101111011001 1100
000000000010010111111101111110 0010
000000000010011101101111101111 1000
000000000010011111111011110011 0101
000000000010011111111100011111 0001
000000000010101110011111101111 1010
000000000010101110111001111111 1101
000000000010101111011101011111 0101
000000000010110110111110011111 1110
000000000010111100111111101101 1001
000000000010111111110100111101 1000
000000000011001011101110111111 1111
000000000011001011111111110110 0000
000000000011001110110111111011 0011
000000000011001110111110111101 0100
000000000011010011110101111111 0110
000000000011010111110111110110 0111
000000000011011010111001111111 0111
000000000011011010111110101111 1110
000000000011011101111011111100 1010
000000000011011101111110100111 0000
000000000011100011110111111101 1101
000000000011100101011011111111 1100
000000000011100110111111100111 0101
000000000011100111011101111011 0011
000000000011101001111111011110 0001
000000000011101010111101111101 1100
000000000011101011011101110111 1010
000000000011101101001111011111 0011
000000000011101101111111011100 0100
000000000011101110010111111011 1001
000000000011101110111011011110 0010
000000000011101110111101111100 0110
...
111111111100000000100111001000 1000
111111111100000001000000111010 1100
111111111100000001101000101000 1010
111111111100000001110000011000 1101
111111111100000010110010100000 1110
111111111100000100000100011100 0011
111111111100000100011000101000 1001
111111111100000100100100100001 0101
111111111100000101001000100010 0100
111111111100000101100100000001 1000
111111111100000110000100000110 1110
111111111100000110001100001000 1011
111111111100000110010100000001 0111
111111111100010000001100101000 0110
111111111100010011000000001001 1010
111111111100010011011000000000 1100
111111111100100001000001101000 0001
111111111100100010001000101000 1001
111111111100100110000100000100 0100
111111111100101000000100001100 1011
111111111100101000010010001000 0110
111111111100110000000100010100 1101
111111111101000001010000000110 1011
111111111101000010100100100000 0100
111111111101001000000000101100 1001
111111111101001000000010000011 1111
111111111101001000010010000001 1001
111111111101010000000010100100 1100
111111111110000000000100011100 0001
111111111110000000100001010100 0111
111111111110000001011010000000 0100
111111111110001000000110000001 1110
111111111110001010100010000000 0101
111111111110001100000000000011 0010
111111111110001110000000000100 1100
111111111110010000000000110001 1010
111111111110010000000010100100 1111
111111111110010000000100100001 1101
111111111110010011000000001000 0000
111111111111000000010001000010 0010
111111111111000001001000000010 1101
111111111111010010000010000000 1101

if not all 16 mix, then you need to guess 1 of the first 4 of 16 or just randomly beat all

in general, need to read Knuth's books, maybe there are some ideas...

and where "collisions" can be hidden

2^256 115792089237316195423570985008687907853269984665640564039457584007913129639936

280!/140!/140! 9254907226247087987824475869322170638984082742378874048534193150547106114131047 0440

300!/150!/150! 9375970277282745279319375443906408487923265570008135892047235271297517002183959 1675861424

600!300!/300! 600!/300!/300! 1351079419961942685144748779785045303972339454491934799259657217864741504080057 1696195048019827446981867333413136583724904390049076115159169530842704853694762 1976068789875968372656

65536!/32768!/32768!
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7732596737481277100634850062654607918225721859000158655352316249488157653643894 6606372028220197015316239583528121934587597328045069273933689966874011867257067 6733729331608151899989646255160166488546208960556973235897050352490671107448591 4440675800707191124789192326507330077249237733260082767078570128436108125237227 1443969420582666229855359231399763088537617648375701867559234890795965719388521 7163315348210402464215481905945670589293529242503320703787242251821853985899188 9512815680103932319763515980764846569542231100329444778593302003414523100058620 5963810587290960912971650716517907073396007736249504411615371691043857316871426 6483349410368906128887060764124797835607270563333647531743803884503128088200802 4412266579349646633089008260789631840097698442447700550

***

example, total permutations of 1>10 and 0>10 = 20 11111111110000000000 = 20!/10!/10! 184756
means for each of 4 (2^4) 184756/2^4 = 11547 collisions
184756
11547

we can take this number of all permutations and use them as the initiating seed and they are almost completely enough to sort out all the permutations.

this is a search option in a larger number smaller

numbers can of course be converted into strings (str) it will not change the essence.

from 11547 collisions for "0000" (from 2^4 bit) from count 20!/10!/10! = 184756 (from 0 to 184756)

it is interesting that even secondary seeds repeat themselves initiated by different numbers first seed.

   seed 2 seed 1 4 bit
('00000110101010111101', 10580, '0000')
('00000110101010111101', 28894, '0000')
('00000110101010111101', 59931, '0000')
('00000110101010111101', 148666, '0000')

('01101000111110010100', 29195, '0000')
('01101000111110010100', 41692, '0000')
('01101000111110010100', 141462, '0000')
('01101000111110010100', 176562, '0000')

('01101001011001011010', 50482, '0000')
('01101001011001011010', 57288, '0000')
('01101001011001011010', 177912, '0000')
('01101001011001011010', 178529, '0000')

('01110011001011001010', 35976, '0000')
('01110011001011001010', 47548, '0000')
('01110011001011001010', 58853, '0000')
('01110011001011001010', 113112, '0000')
('01110011001011001010', 139744, '0000')

***

or filter the initiating seed by 4 > "1"

('00000001001111110111', 111185, '0010')
('00000011010100111111', 111017, '0010')
('00000011100111011110', 116511, '0110')
('00000011110001111101', 112811, '0011')
('00000011111101100101', 111451, '0011')
('00000100101111011011', 101119, '1001')
('00000101001110111011', 118181, '0110')
('00000101101101101101', 130111, '0100')
('00000101111010111001', 118611, '0000')
('00000110001110111110', 111417, '1001')
...
('11111100010000010101', 111189, '0000')
('11111100010101000100', 119116, '1010')
('11111101001010100000', 111166, '0011')
('11111101101000000100', 111671, '0101')
('11111110000101000010', 118141, '1100')
('11111110001001010000', 118118, '0101')
('11111110010001000001', 171181, '0000')

~800 can calculate similar techniques for attack pz

***

there are how many collisions

180!/90!/90! = 91012248672832285155575331798825309656983959185522800

91012248672832285155575331798825309656983959185522800/ pz 64 2^64 = 4933783886693786561852355929668775 collisions

91012248672832285155575331798825309656983959185522800/pz 160 2^160 = 62273 collisions

600!/300!/300!

1351079419961942685144748779785045303972339454491934799259657217864741504080057 1696195048019827446981867333413136583724904390049076115159169530842704853694762 1976068789875968372656

9244460529167650795540731674161791846040585150874740675211703275797841931797666 8404488686921898322882212568056295459139633654182256 2^160 collisions
7324216211615967328305946861026949927023153844181547075253885258466971658764981 4215996027965475907402114296086782480287591076169589308698251700422304548067593 59 2^64 collisions
1166814960211057090384486027721779669646648766821734965205742389473249903857269 571929430822183654654146 2^256 collisions

how to catch them? for 1 pz 64 7324216211615967328305946861026949927023153844181547075253885258466971658764981 4215996027965475907402114296086782480287591076169589308698251700422304548067593 59 collisions from 600!/300!/300!

is the probability of generating a collision in this way identical to the probability of guessing 64 puzzles by random?

in this way it is easier to fork "Isaacdelly/Plutus" to search for everything at once than just 1 64 pz

because of working with strings, the larger the string, the slower it works

65536!/32768!/32768! barely creeps

20000!/!10000/10000! 6019 len num, 6017 > 2, 2 > 4, 6019!/6017!/2! = 18111171, 6685588 ran in total in a day

6685588 dec init seed > 2222222222222222222222222222222222222222222222222222222222222222222222222222222 2222222222222222222222222222222222222222222222222222222222222222222222222222222 2222222222222222222222222222222222222222222222222222222222222222222222222222222 2222222222222222222222222222222222222222222222222222222222222222222222222222222 2222222222222222222222222222222222222222222222222222222222222222222222222222222 2222222222222222222222222222222222222222222222222222222222222222222222222222222 2222222222222222222222222222222222222222222222222222222222222222222222222222222 2222222222222222222222222222222222222222222222222222222222222222222222222222222 2222222222222222222222222222222222222222222222222222222222222222222222222222222 2222222222222222222222222222222222222222222222222222222222222222222222222222222 2222222222222222222222222222222222222222222222222222222222222222222222222222222 2222222222222222222222222222222222222222222222222222222222222222222222222222222 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***
algorithm, due to "Narayana Pandita" for permutations, the algorithm is normal and can write to the file immediately without loading memory (little who wants to experiment)

PrivatePerson

member

Activity: 174

Merit: 12

Have you tried to use this link yourself or just wrote it like that?

indoarts

newbie

Activity: 12

Merit: 0

Quote from: PrivatePerson on July 27, 2021, 03:29:36 AM

How many characters are in the private key in binary?

https://www.rapidtables.com/ convert/number/ binary-to-hex.html

PrivatePerson

member

Activity: 174

Merit: 12

How many characters are in the private key in binary?

PrivatePerson

member

Activity: 174

Merit: 12

How long does it take you to generate the 16jY7qLJn address with this script? It takes me over an hour to complete 16jY7.

zahid888

member

Activity: 282

Merit: 20

the right steps towerds the goal

@Andzhig And if we increase one more character of address 16jY7qLJn & 'x' then most binaries are started from '111'

few examples -

16jY7qLJnxLQQRYPX5BLuCtcBs6tvXz8BE   1110000000100110101001101101010100100011010011001000100000110110000   7013536A91A6441B0
16jY7qLJnX9uchnyf26t3QJnsUf78Xdikb   1110010000101000111010000001111110010000001011001101111011100000   E428E81F902CDEE0
16jY7qLJnX9eX8j612s8fnbn6uzR48xjua   1110100000001101111010110011001110101001011001111010000010001111   E80DEB33A967A08F
16jY7qLJnx2EZZumnYFke3GutCrRnHKs1M   111010110100110101001101101010111010101000110011101011001010110000   3AD3536AEA8CEB2B0
16jY7qLJnx2ixrxCnTLSraerkgyB3YYAiT   1110110111111001110011010110000000110101011011011100110000011001   EDF9CD60356DCC19
16jY7qLJnxHBp3dqwV2kzYq1LucfZzgxsH   1110111010111001101010110011001101001101111100100111011100001101   EEB9AB334DF2770D
16jY7qLJnX2cZXJ78wV1ef42e7cLAZJ1Vn   1111111000101000011001011100011011011011111111101100001110000011   FE2865C6DBFEC383

Could this also be some logic?

Andzhig

jr. member

Activity: 184

Merit: 3

logic to find puzzle 64 and the rest Grin

wrote above (with examples) how 16 "bits" (4x = 64) are obtained from seed 30 lenght

if all 4x permutations seed 30 "111111111111111000000000000000" give 1000^4 possible successful collisions, we need to find a way to catch these successful collisions in fewer steps.

for example, we take the first 9 and last 9 of 30, that is we take 18, 12 remain in the middle.

from ~ 4500 i got 385 and 6 full matches

001011011 001110110 001011011001010100011001110110 1111111111111111
001011011 110101100 001011011011001011000110101100 0000000000000000
001011011 001101110 001011011101000001101001101110 0000000011111111
001011011 011100101 001011011110011000100011100101 1111111100000000

100011011 010101011 100011011010000111001010101011 1111111111111111
100011011 101001011 100011011011100001001101001011 0000000011111111
100011011 010001111 100011011100100010110010001111 0000000000000000
100011011 101001011 100011011110010001100101001011 1111111100000000

100100111 101100101 100100111000110110010101100101 0000000000000000
100100111 011110001 100100111010110000110011110001 1111111111111111
100100111 101101001 100100111010110101000101101001 1111111100000000
100100111 111001100 100100111011001110000111001100 0000000011111111

110100101 100011110 110100101010011100001100011110 0000000011111111
110100101 010011011 110100101010100001101010011011 1111111111111111
110100101 100001111 110100101011010100010100001111 1111111100000000
110100101 010101011 110100101101000011001010101011 0000000000000000

110111000 100110110 110111000001101101000100110110 1111111100000000
110111000 011010101 110111000110001000011011010101 1111111111111111
110111000 001001111 110111000110101001000001001111 0000000000000000
110111000 101110010 110111000111000000110101110010 0000000011111111

111010100 001110110 111010100010011010001001110110 0000000011111111
111010100 101100101 111010100100011000101101100101 1111111111111111
111010100 010110110 111010100101000001110010110110 0000000000000000
111010100 110111000 111010100101010110000110111000 1111111100000000

the output is reduced to 16 characters

18
1>5, 0>4 9-9 1>5, 0>4
18 all permut from 111110000-000011111 = 126

12
1>5, 0>7
12 all permut from 111110000000-000000011111 = 792^4 (4x) = 393460125696

(18 for every 9 every 9, 126 x 126 = 15876) x 393460125696 = 6246572955549696 steps

***

the output is reduced to 15 characters

from ~ 4500 i got 493 and 1 full matches

0011100110 1101001001 001110011010000110111101001001 0000000011111111
0011100110 1010010101 001110011010111100001010010101 1111111100000000
0011100110 1100011010 001110011011000101101100011010 1111111111111111
0011100110 1010110010 001110011011100001101010110010 0000000000000000

20
1>10, 0>10 10-10 1>10, 0>10
20 all permut from 1111100000-0000011111 = 252

10
10 all permut from 1111100000-0000011111 = 252^4 (4x) = 4032758016

(20 for every 10 every 10, 252 × 252 = 63504) × 4032758016 = 256096265048064 steps

if i calculate correctly it seems that way...

in the middle of 10 and a passage begins for each of 4

1111100000
1111100000
1111100000
0000011111 252

1111100000
1111100000
1111000001
0000011111 252

1111100000
1111100000
1110000011
0000011111 252

and for each 10 by 10 in the front and in the back

252 × 252 = 63504

i.e.

1111100000 252
1111100000 252
1111100000 252
0000011111 252 x (252 × 252 = 63504)

1111100000 252
1111100000 252
1111000001 252
0000011111 252 x (252 × 252 = 63504)

1111100000 252
1111100000 252
1110000011 252
0000011111 252 x (252 × 252 = 63504)

for example, here we have 18 fixed positions for each of 4

100010110100110010100110010111 1111111100000000
100000110100110011100110010111 0000000011111111
110010011100110000100110110011 1111111111111111
100110110100010000101100110111 0000000000000000
1_0__0_1_100_100__10_1_0_10_11 these 12 are rearranged for each of 4 111111000000 (all permut 924) (924 x 924 x 924 x 924 = 728933458176)

1_0__0_1_100_100__10_1_0_10_11 924
1_0__0_1_100_100__10_1_0_10_11 924
1_0__0_1_100_100__10_1_0_10_11 924
1_0__0_1_100_100__10_1_0_10_11 924

1_0__0_1_100_100__10_1_0_10_11 923
1_0__0_1_100_100__10_1_0_10_11 924
1_0__0_1_100_100__10_1_0_10_11 924
1_0__0_1_100_100__10_1_0_10_11 924

1_0__0_1_100_100__10_1_0_10_11 922
1_0__0_1_100_100__10_1_0_10_11 924
1_0__0_1_100_100__10_1_0_10_11 924
1_0__0_1_100_100__10_1_0_10_11 924

1_0__0_1_100_100__10_1_0_10_11 921
1_0__0_1_100_100__10_1_0_10_11 924
1_0__0_1_100_100__10_1_0_10_11 924
1_0__0_1_100_100__10_1_0_10_11 924

1_0__0_1_100_100__10_1_0_10_11 0
1_0__0_1_100_100__10_1_0_10_11 924
1_0__0_1_100_100__10_1_0_10_11 924
1_0__0_1_100_100__10_1_0_10_11 924

these 12 turned out to be 18 to be rearranged

1_0__0_1_100_100__10_1_0_11_10 924
1_0__0_1_100_100__10_1_0_11_10 924
1_0__0_1_100_100__10_1_0_11_10 924
1_0__0_1_100_100__10_1_0_11_10 924

1_0__0_1_100_100__10_1_1_11_00 924
1_0__0_1_100_100__10_1_1_11_00 924
1_0__0_1_100_100__10_1_1_11_00 924
1_0__0_1_100_100__10_1_1_11_00 924

1_0__0_1_100_101__11_1_1_00_00 924
1_0__0_1_100_101__11_1_1_00_00 924
1_0__0_1_100_101__11_1_1_00_00 924
1_0__0_1_100_101__11_1_1_00_00 924

1_0__0_1_100_100__10_1_0_10_11 924
1_0__0_1_100_100__10_1_0_10_11 924
1_0__0_1_100_100__10_1_0_10_11 924
1_0__0_1_100_100__10_1_0_10_11 924

here they are not fixed, but they are moved step by step and all combinations pass including the same (fixed 10 instead of 18) for each of 4

1111100000 252
1111100000 252
1111100000 252
0000011111 252 x (252 × 252 = 63504)

when step by step, he will stand for example in such a position

1100000111 252
1100000111 252
1100000111 252
1100000111 252

that is, there are only 10 of all permutations 252 (1111100000-0000011111) in the center in 30, there are 4 of them and all their permutations (252 x 252 x 252 x 252) 252^4 = 4032758016

and for each of these permutations at the beginning and end 10(252)-10(4032758016)-10(252), all variants of permutations (252 × 252 = 63504) × 4032758016 = 256096265048064 steps

some kind of devilry Grin

or there it is necessary to multiply at every step

1111100000 252
1111100000 252
1111100000 252
0000011111 252 x (252 × 252 = 63504)

252 x (252 × 252 = 63504) = 16003008
and already multiply this 4 times 16003008^4 = 65585296971568246764230148096 a piece of crap

***

more matches

011110110110000100110001010110 0000000011111111
110100110100100100111001011010 1111111111111111
110110110110000100110001011010 0000000000000000
110110110110100000110001101010 1111111100000000
_1_1_01101_0_00_0011_001____10 19-11 11111100000

000010101111010101011001010101 1111111100000000
000010111111000111001001010101 1111111111111111
000010111111000111100001010011 0000000011111111
000011101011000111001001011101 0000000000000000
00001_1_1_110_01_1___00101___1 19-11 11111000000

011001100011110111010000100101 1111111100000000
011101001011010110110000100011 0000000011111111
011101100011010110010000100111 0000000000000000
011101101011110000010000100111 1111111111111111
011_01_0_011_10____10000100__1 20-10 1111110000

001010110111010000101100001111 1111111111111111
001010110111010010101010101010 1111111100000000
001010110111110010101000001011 0000000011111111
001010110111111000101000100011 0000000000000000
001010110111_1_0_0101__0_0__1_ 21-9 111100000

***

when looking for the maximum number of matches, you get this observation

for example this area of collisions, only a few "bits" move

001010110111010000101100001111 1111111111111111
001010110111110010101000001011 0000000011111111
001110100110010010101010011011 1111111111111111
001110100111010010101100001011 1111111111111111
001110110111011010001000001011 1111111111111111
...
001010111000110110111000100011 0000000011111111
001110110000110100111010100011 1111111100000000
011110100000111100011010100011 0000000011111111
...
001010110111110010101000001011 0000000011111111
001110100111010010101100001011 1111111111111111
001110110111011010001000001011 1111111111111111
...
000111000101001000111101011011 0000000011111111
000111100001001001111001111010 1111111100000000
001111000101001000111001111010 1111111111111111
...
100100101110010101111010100100 0000000011111111
100100111110010100110011100100 0000000011111111
110101101110010101111000000100 1111111100000000
...
100110111001010011001110000110 0000000011111111
100111011101010011000100001110 1111111111111111
100111101001010011000110001110 0000000011111111
...
100011100011001100011101000111 1111111100000000
110001100010001100111011100101 1111111100000000
110010000011001100111001001111 1111111111111111
110011100010001100111001000111 1111111100000000
...
110001100111000010100101111010 1111111111111111
110010010011000110100111011010 1111111100000000
110011100001001010100111010011 1111111111111111
110011100011000010100111011010 0000000011111111

how can it be used? for example we generate (by permutation method) 4 random seeds (111111111111111000000000000000) and move them a little bit. It seems simple, but what kind of bits need to be moved and isn't it easier to move everything at once (and how many at a time does the random move).

Another way to use this to catch collisions is if we generate 64 bits from a 74-bit long seed. then we do the same and begin to move a few bits into a 74-length seed (or any length) collisions nearby (but it is not clear which bits to move).

PrivatePerson

member

Activity: 174

Merit: 12

I don’t understand your logic

But if you want to generate addresses, you need a faster program, since your script is very slow, only on one processor core.

Andzhig

jr. member

Activity: 184

Merit: 3

Quote from: PrivatePerson on July 24, 2021, 03:26:41 AM

Does it just generate addresses in the specified range with the first characters specified? So does VanitySearch?

yes, linear step.

Quote

import os
import hashlib
import random
import datetime
from bitcoin import *

def _print(string, index):
   if index == len(string):
   binstr = ''.join(string)
# resint = int(stringx,2)
   myhex = int(binstr,2)
   priv = myhex
   pub = privtopub(priv)
   pubkey1 = encode_pubkey(privtopub(priv), "bin_compressed")
   addr = pubtoaddr(pubkey1)
   n = addr
   if n.startswith ('16jY7'):
   file = open('linelowincgen64mask.txt','a+')
   print (addr, ";",hex(myhex), file=file)
   file.close()
   if n.startswith ('1'):
   print ( addr, ";",hex(myhex),binstr,int(binstr,2))
   return
   if string[index] == "_":
   string[index] = '0'
   _print(string, index + 1)
   string[index] = '1'
   _print(string, index + 1)
   string[index] = '_'
   else:
   _print(string, index + 1)

if __name__ == "__main__":
   print ("Start")
   string = "11_________________0____________________________________________"
   #11_________________0____________________________________________
   string = list(string)
   _print(string, 0)

need to be found using VanitySearch addresses starting with 16jY7qLJn and check if they start with 10... bits then this idea can be forgotten, if they all start with 11... then we can define what is below 13835058055282163712 there will be no key.

but judging by the rest of the addresses there and 11 and 10 will be at the beginning then can generate a bunch 16jY7qLJm and 16jY7qLJo and break through masks based on their bits.

16jY7qLJm 1110011001111011011011011101101110010000101101010110111000001101
16jY7qLJm 1011100101000100001110100100101011011110010001101100110101110110
16jY7qLJm 1101110000000000000001000011100000000110110100101110110110010100
16jY7qLJm 1110010001001101101000011010000011110101001011010111011101100111
16jY7qLJn 1101100110001100111001101110011110001011000110001000111011000011
16jY7qLJn 1100001100001110101011001111101101101010101011001010011110101011
16jY7qLJn 1110010001001101101000100001011110110100100000000001110101001100
16jY7qLJn 1101010101101100000001001110101110010010101001111101111100100111
16jY7qLJn 1111111000101000011001011100011011011011111111101100001110000011
16jY7qLJn 1111000111011111001010100100110100011001100001001000010010111011
16jY7qLJn 1111011101000101001010000010011011010011110111010110100010000011
16jY7qLJn 1101100000111111111011110101010000000110011010011000011110001000
16jY7qLJn 1100000100000000000001111110110111101100010111101001001011001111
16jY7qLJn 1100010010010110011000101110100011110111110100101101011010111011
16jY7qLJn 1101101001100110111001010001001011101000110101110001000000101000
16jY7qLJn 11_________________0____________________________________________
16jY7qLJo 1111011010011001100010011000010110001001110001110001001010101001
16jY7qLJo 1101111101100110100010110010100111011110101000001011010010010011
16jY7qLJo 1010001111001101010000100010111101001111010101000010111111110000
16jY7qLJo 1101111010100111001111010101110100010101001011101000010010111110

although even if we generate a billion 16jY7qLJm, billion 16jY7qLJo we can look not to generate the same bits for pz64, but this is how any others can be generated with the same goals. or look in dec format in which space it piles more (if the overall distribution is even) and look in those spaces where there are fewer 16jY7qLJn.

***

and when searching 16 by 16

"0000000000000000","0000000000000001","0000000000000010","0000000000000011",
"0000000000000100","0000000000000101","0000000000000110","0000000000000111",
"0000000000001000","0000000000001001","0000000000001010","0000000000001011",
"0000000000001100","0000000000001101","0000000000001110","0000000000001111"

i get 17687

000000000001111111110100111011 0000000000001010
000000000100011011111111110011 0000000000000000
000000000110100011111011101111 0000000000001001
000000000110111001111101110110 0000000000001001
000000000111110010101111101011 0000000000001001
000000001001001111101111100111 0000000000000100
000000001001101010110111101111 0000000000001001
000000001001110011111101111100 0000000000001101
000000001001111001111011111001 0000000000001100
000000001011010111100011101111 0000000000001000
000000001011011101101110011110 0000000000000011
000000001011100010011111111101 0000000000000110
000000001100110110101111100111 0000000000000111
000000001100111010111110100111 0000000000001110
000000001101010010111101110111 0000000000001111
000000001101101101111111110000 0000000000000011
000000001101111101101101010101 0000000000001111
000000001110011011111101000111 0000000000000011
000000001110110101101110111100 0000000000000110
000000001111011011011010110011 0000000000000010
000000001111011011111110101000 0000000000001011
000000001111100111101011000111 0000000000000111
000000010010011111111100110110 0000000000000101
000000010011011111100111001110 0000000000000101
000000010101000110011111111110 0000000000000001
000000010101111101011001111100 0000000000000111
000000010110011110111100011101 0000000000001111
000000010110111010101101110110 0000000000000011
000000010111001001110101111101 0000000000000010
000000010111001111101000101111 0000000000001100
000000010111011001111011101001 0000000000001111
000000010111011101110111000101 0000000000000000
000000010111011110110101101100 0000000000000101
000000010111110000011111110011 0000000000000011
000000011001100110110110111110 0000000000001000
000000011001101111100000111111 0000000000001110
000000011010100111001111110101 0000000000001100
000000011011010011101011111001 0000000000000000
000000011011011101101110110001 0000000000000000
000000011011100101111010011110 0000000000001000
000000011011100110001100111111 0000000000001011
000000011011100111011110110010 0000000000000011
000000011011101000011101111011 0000000000001100
000000011011110000110010111111 0000000000001000
000000011100111011111001010011 0000000000001111
000000011100111111011101010001 0000000000000110
000000011101001001011101101111 0000000000001111
000000011101001111001111011010 0000000000001110
000000011101011011101010101110 0000000000000110
000000011101100111010111100101 0000000000000111
...
111111100110000110001000100101 0000000000001010
111111100111001000000010110010 0000000000000001
111111100111001000100001000101 0000000000000101
111111101000000000110001110011 0000000000000101
111111101000001110101010000010 0000000000001101
111111101000010011000110100001 0000000000000010
111111101000100010001100010011 0000000000001001
111111101000100011011010010000 0000000000001101
111111101000101000100000110110 0000000000001100
111111101000101101010010000010 0000000000001100
111111101001000001000001011101 0000000000001011
111111101100000000001100111001 0000000000000100
111111101100011100101000000001 0000000000000100
111111101100101000101100100000 0000000000001100
111111101101000111000101000000 0000000000001100
111111101101100001001000100010 0000000000001101
111111101101100100100000010010 0000000000000001
111111101110101000010001100000 0000000000001000
111111110000000110010101000011 0000000000000100
111111110000010100010110101000 0000000000000000
111111110000100010010111000010 0000000000001011
111111110000101011100100000010 0000000000001000
111111110000110000100100101100 0000000000000111
111111110001000000001101000111 0000000000001100
111111110001011000000000101011 0000000000001000
111111110001011000011100000010 0000000000001010
111111110001100000010110100010 0000000000000110
111111110001101000001110000010 0000000000000101
111111110010010000000111100001 0000000000001001
111111110010010001000110100100 0000000000001110
111111110100010100001010001001 0000000000000110
111111111000000010010010101001 0000000000000010
111111111000100101100000010100 0000000000001100
111111111001001110001000001000 0000000000000101
111111111001101010000010000001 0000000000000101
111111111010000011000011000010 0000000000000010
111111111010000101010000100100 0000000000001011
111111111010001011000000010010 0000000000001101

for searching 256 bit keys we get whole 1000^16 1000000000000000000000000000000000000000000000000
and for example lost one million bitcoins

1000000 x 1000000000000000000000000000000000000000000000000 = 1000000000000000000000000000000000000000000000000000000 chances of catching something.

but here it is more difficult to sort out everything 16 by 16 (this is not necessary in principle), but also 18-12, it may not be.

can take the first 6 zeros, the remaining 15 ones, and mix 9 zeros

000000________________________

or if we imagine that the scheme works from 18-12
18 48620
12 924^16 282326431934901224620323472702091393242629144576
48620 x 282326431934901224620323472702091393242629144576 = 13726711120674897541040127242775683539456629009285120

1000^16 1000000000000000000000000000000000000000000000000
13726711120674897541040127242775683539456629009285120

or

1000000 x 1000000000000000000000000000000000000000000000000 = 1000000000000000000000000000000000000000000000000000000

1000000000000000000000000000000000000000000000000000000
13726711120674897541040127242775683539456629009285120

this shit is not achievable, spaces 2^150-2^170+

Topic: Bitcoin puzzle transaction ~32 BTC prize to who solves it - page 286. (Read 253799 times)