Topic: Bitcoin puzzle transaction ~32 BTC prize to who solves it - page 315. (Read 228764 times)

No, I can't.


Information:

https://sefiks.com/2018/02/28/attacking-elliptic-curve-discrete-logarithm-problem/
http://andrea.corbellini.name/2015/06/08/elliptic-curve-cryptography-breaking-security-and-a-comparison-with-rsa/


Code (not mine, slower than mine but good, with the first 51 public keys of the puzzle transaction) :

https://gist.github.com/jhoenicke/2e39b3c6c49b1d7b216b8626197e4b89

Can you share the code?

If you use just only a mobile cpu, what repository you use (searching the space) that also work in mobile?

I'm currently using one in github but only works in pc.

Ok, that's fine, becouse  I began to get nervous yesterday about  my own wallet security.

i think that this sentence is pretty clear:

You can get the private key from a public key only if you know already that the private key lies in a very limited range (in this case from 2^56 to 2^57).

That means: only in the puzzle transaction case (for the keys number 1, 2,  3, ...., 80 more or less, more than 80 bit is not a very limited range)

You mean that everybody can calculate the private key of wallets or what?

Read 5/6 posts from here: https://bitcointalksearch.org/topic/m.40086839

How did you get private key then If you don't know the person?

Ok, I understand

Knowing that the private key has a limited width, so maybe you do your search so to  match the transaction script ?

So this person is still unknown ?

Just to be clear, I didn't find the key. I got the key only after the address was swept by somebody else.

He is finding keys using some sort of smart way but still random. He probably figured out a nice way to narrow the search.
It took 60 days to find  15c9mPGLku1HuW9LRtBf4jcHVpBUt8txKz after 17aPYR1m6pVAacXg1PTDDU7XafvK1dxvhi
I am not sure if he is the one who got 1LzhS3k3e9Ub8i2W1V8xQFdB8n2MYCHPCa.
If his algorithm is linear, we will see the next one in 60 days or so.
I thing we should show a lot of respect to this MAN 
bravo !!!

You are kinda pissing me off man! You keep finding the keys and making it worth no ones time to make use of their GPU miners with the Bitcrack program.

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0000000000000000000000000000000000000000000000000000000000000003 1CUNEBjYrCn2y1SdiUMohaKUi4wpP326Lb
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00000000000000000000000000000000000000000000000000022bd43c2e9354 1MEzite4ReNuWaL5Ds17ePKt2dCxWEofwk
00000000000000000000000000000000000000000000000000075070a1a009d4 1NpnQyZ7x24ud82b7WiRNvPm6N8bqGQnaS
000000000000000000000000000000000000000000000000000efae164cb9e3c 15z9c9sVpu6fwNiK7dMAFgMYSK4GqsGZim
00000000000000000000000000000000000000000000000000180788e47e326c 15K1YKJMiJ4fpesTVUcByoz334rHmknxmT
00000000000000000000000000000000000000000000000000236fb6d5ad1f46 19LeLQDmSR8nxFa4v7UdX9SC41mdxP6Rx9
000000000000000000000000000000000000000000000000006abe1f9b67e114 1LzhS3k3e9Ub8i2W1V8xQFdB8n2MYCHPCa
000000000000000000000000000000000000000000000000009d18b63ac4ffdf 17aPYR1m6pVAacXg1PTDDU7XafvK1dxvhi
00000000000000000000000000000000000000000000000001eb25c90795d61c 15c9mPGLku1HuW9LRtBf4jcHVpBUt8txKz

or in binary

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0000000000000000000000000000000000000000000000000010100100110000 1ErZWg5cFCe4Vw5BzgfzB74VNLaXEiEkhk
0000000000000000000000000000000000000000000000000110100011110011 1QCbW9HWnwQWiQqVo5exhAnmfqKRrCRsvW
0000000000000000000000000000000000000000000000001100100100110110 1BDyrQ6WoF8VN3g9SAS1iKZcPzFfnDVieY
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0000000000000000000000000000000000000110101011000011100001110101 128z5d7nN7PkCuX5qoA4Ys6pmxUYnEy86k
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0000000000000000000000000001011101010111011101010110101010010011 14iXhn8bGajVWegZHJ18vJLHhntcpL4dex
0000000000000000000000000010001000111000001011111010110011010000 1HBtApAFA9B2YZw3G2YKSMCtb3dVnjuNe2
0000000000000000000000000100101101011111100000110000001111101001 122AJhKLEfkFBaGAd84pLp1kfE7xK3GdT8
0000000000000000000000001110100110101110010010010011001111010110 1EeAxcprB2PpCnr34VfZdFrkUWuxyiNEFv
0000000000000000000000010101001110000110100110101100110001011011 1L5sU9qvJeuwQUdt4y1eiLmquFxKjtHr3E
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0000000000000000000011100000001010110011010110100011010110001111 1CkR2uS7LmFwc3T2jV8C1BhWb5mQaoxedF
0000000000000000000100100010111111001010000101000011110000000101 1NtiLNGegHWE3Mp9g2JPkgx6wUg4TW7bbk
0000000000000000001011101100000110000011100010001101010101000100 1F3JRMWudBaj48EhwcHDdpeuy2jwACNxjP
0000000000000000011011001101011000010000101101010011110010111010 1Pd8VvT49sHKsmqrQiP61RsVwmXCZ6ay7Z
0000000000000000101011011110011011010111110011100011101110011011 1DFYhaB2J9q1LLZJWKTnscPWos9VBqDHzv
0000000000000001011101000001011101101011000000010101111101001101 12CiUhYVTTH33w3SPUBqcpMoqnApAV4WCF
0000000000000010001010111101010000111100001011101001001101010100 1MEzite4ReNuWaL5Ds17ePKt2dCxWEofwk
0000000000000111010100000111000010100001101000000000100111010100 1NpnQyZ7x24ud82b7WiRNvPm6N8bqGQnaS
0000000000001110111110101110000101100100110010111001111000111100 15z9c9sVpu6fwNiK7dMAFgMYSK4GqsGZim
0000000000011000000001111000100011100100011111100011001001101100 15K1YKJMiJ4fpesTVUcByoz334rHmknxmT
0000000000100011011011111011011011010101101011010001111101000110 19LeLQDmSR8nxFa4v7UdX9SC41mdxP6Rx9
0000000001101010101111100001111110011011011001111110000100010100 1LzhS3k3e9Ub8i2W1V8xQFdB8n2MYCHPCa
0000000010011101000110001011011000111010110001001111111111011111 17aPYR1m6pVAacXg1PTDDU7XafvK1dxvhi
0000000111101011001001011100100100000111100101011101011000011100 15c9mPGLku1HuW9LRtBf4jcHVpBUt8txKz


(to be checked )

Ok thanks a lot

They are listed in this thread, you just need to look for them. Cheers.

Hi

Really impressive.
Could you provide a list of all the  hex private keys of this puzzle that have been found so far?
from 1 to 57



Thanks.

this time he quickly found it turned out, got a taste. Arulbero thx.

Another formula (of success. just to be)

                     puzzle  : 128  =                                           = 128 :  2^                      2^ -
53    6763683971478124    52841281027172  |   70368744177664   9007199254740992      8954357973713820
54    9974455244496707    77925431597630  | 140737488355328  18014398509481984    17936473077884354    
55  30045390491869460   234729613217730  | 281474976710656  36028797018963968    35794067405746238  
56  44218742292676575   345458924161535  | 562949953421312  72057594037927936    71712135113766401
57 138245758910846492 1080044991490988  |1125899906842624 144115188075855872  143035143084364884
                                                                                          288230376151711744

288230376151711744 : 128 = 2251799813685248  
                        
                                                        :128:128:128:128:128  
      70368744177664     69955921669639    2048  2035  13
    140737488355328    140128695920971    4096  4078  18
    281474976710656    279641151607392    8192  8138  54  
    562949953421312    560251055576300   16384 16305 79
  1125899906842624   1117462055346600   32768 32522 246
2251799813685248                              65536

for example the previous puzzle number 57. 144115188075855872 - 1080044991490988 = 143035143084364884
144115188075855872 : 128 = 1125899906842624
143035143084364884 : 128 = 1117462055346600
1125899906842624 - 1117462055346600 * 128 * 128 = 138245758910857216 practically what we need

look at the bin of the second column

1111111001111111100001110111000110111000000111
11111110011 (2035)
11111110111001001000001001001001010100101001011
111111101110 (4078)
111111100101010100000111100000011001001001100000
1111111001010 (8138)
1111111011000101110011101001001110001010011101100
11111110110001 (16305)
11111110000101001101101000110110111110000110101000
111111100001010 (32522)

111111100000000000000000000000000000000000000000000
1111111000000000 (65024-65279)

first bytes 11111110... + always 35 random bytes (here the right side increases)

for the 58 puzzle will 256 options beginning with 1111111000000000 (65024) finishing up 1111111011111111 (65279)

take these 256 initial parts and add random 35 bits for each and from the received number we take about 15000-20000 with - 1 step, profit

***

by zeros here we got in 58 11110101 10010010 11100100 10000011 11001010 11101011 00001110 0 28-29 almost equally divided 000000000000000000000000000011111111111111111111111111111

***

and to the extent

56.940012835374135824
55.295507509568065689
54.737993190511333013
53.147159473916182226
52.586730675690989872
51.904965885818221825
50.870703748687580964
49.118497410306637905
48.539513532885657356
47.442128478217754077
46.766014580697737785
45.547076931749783679
44.184810076602017917
43.808441604030467369
42.752573892536879788
41.396887129359569265

2^57
10100110110100011011011111000011010100010101010110000
101100010111001110100100111000101001110101111111111010000
110010101010000011110000001100100100110000001111011111000
111011100100100000100100100101010010100101110000010110110
111100111111110000111011100011011100000011100110110100010
111110001000001010001111010011011001101000110000111000110
111111000101011111000111101011110010111111111011000101011
111111101110101000010101111000011110100010110110010101100
111111110100010111110100010010100111111101010000010110100

this is man 1AqEgLuT4V2XL2yQ3cCzjMtu1mXtJLVvww hacked:

1LzhS3k3e9Ub8i2W1V8xQFdB8n2MYCHPCa 2018-05-29
17aPYR1m6pVAacXg1PTDDU7XafvK1dxvhi  2018-09-08
15c9mPGLku1HuW9LRtBf4jcHVpBUt8txKz 2018-11-08 today

=$ 10,448

what hash 15c9mPGLku1HuW9LRtBf4jcHVpBUt8txKz.........

Ok, but anyway I don't understand "257 bit", this value is not correct at all. Or 512 bit and 256 bit, or 8+512 bit and 8+256 bit.



No, the address in the blockchain's blocks (and in the UTXO data set) are stored exactly this way: ripemd160(sha256('02' or '03' + 'x'), 160 bit, no checksum, no base58 encode.

Example:

private key = 01
address = 91B24BF9F5288532960AC687ABB035127B1D28A5  (step 3, address for the blockchain)
address = 1EHNa6Q4Jz2uvNExL497mE43ikXhwF6kZm (checksum + base58) (step 9, address for human people)

Check with http://gobittest.appspot.com/Address  or https://www.blockchain.com/it/btc/address/91B24BF9F5288532960AC687ABB035127B1D28A5

Now if we look at a tx that funds the address 91B24BF9F5288532960AC687ABB035127B1D28A5 /  1EHNa6Q4Jz2uvNExL497mE43ikXhwF6kZm :

https://www.blockchain.com/btc/tx/6797afc4d9b91fb9b283fedddec4e35b00d54063d73bb0d3e97f3537ed8fff3c?show_adv=true

output script: DUP HASH160 PUSHDATA(20)[91b24bf9f5288532960ac687abb035127b1d28a5] EQUALVERIFY CHECKSIG

The address in the "1EHNa6Q4Jz2uvNExL497mE43ikXhwF6kZm" format is only for human people.