Topic: Bitcoin puzzle transaction ~32 BTC prize to who solves it - page 313. (Read 240259 times)

In fact, the code in this puzzle, I think, is the 310 bitcoin private keys, and these private keys are scattered and hidden in the picture, like playing a puzzle game, to find them and put them together correctly! Sounds simple, but a little bit of cryptography knows how to work out the combination of private keys by manpower, and it is estimated that it will not be worked out by the day of entering the coffin. The last thing Lao Shi regrets in his life is that he didn't study hard at the beginning. If he could study hard at the beginning, he would develop towards cryptography experts or mathematicians. It's not a piece of cake to crack such puzzles. It's hard to knock on keyboards every day like now. Therefore, the folks who have become parents must educate their children to listen from an early age. Ha-ha.

I tried this (I am not sure if it does what I think it shoukd )

./clBitCrack -r 61 -d 1 -b 72 -t 256 -p 2048 --continue hup.txt -o res.txt 1AVJKwzs9AskraJLGHAZPiaZcrpDr1U6AB


And this is what I get in my continue file hup.txt

start=0000000000000000000000000000000000000000000000000000000000000001
next=00000000000000000000000000000000000000000000000000000004A4000001
end=FFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFEBAAEDCE6AF48A03BBFD25E8CD0364140
blocks=72
threads=256
points=2048
compression=compressed
device=1
elapsed=344463
stride=0000000000000000000000000000000000000000000000000000000000000001

I suppose that in this context, continue file just tell me how many cases I ran .. right?

Nice

Thanks! Fixed in current version.

Thanks! Fixed in current version.

OK thanks.
The  integer  read after  the  -r option seems to be a signed  byte, can't go beyond 127 (you get  a negative  range)

https://gist.github.com/jhoenicke/2e39b3c6c49b1d7b216b8626197e4b89

In practice, you will not compile an executable script for this task (where you also need to change #define GSTEP (1 << 25)) to #define GSTEP (1UL << 60)

In the original version of the script it looks like this:
For the current level:

2 ^ 60 * 2 * 8/1024/1024 = 17592186044416 MB (seventeen trillion five hundred ninety-two billion one hundred eighty-six million forty-four thousand four hundred sixteen megabytes) #Required RAM

So ... if you do not have this amount of RAM - you will not use this method.

Hi guys,

In continuation to this thread: https://bitcointalksearch.org/topic/brute-force-on-bitcoin-addresses-video-of-the-action-1305887

While playing around with my bot, I found out this mysterious transaction:

https://blockchain.info/tx/08389f34c98c606322740c0be6a7125d9860bb8d5cb182c02f98461e5fa6cd15

those 32.896 BTC were sent to multiple addresses, all the private keys of those addresses seem to be generated by some kind of formula.

For example:

Address 2:

KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3qYjgd9M7rFU74sHUHy8S
1CUNEBjYrCn2y1SdiUMohaKUi4wpP326Lb
Biginteger PVK value: 3
Hex PVK value: 3

Address 3:

KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3qYjgd9M7rFU76rnZwVdz
19ZewH8Kk1PDbSNdJ97FP4EiCjTRaZMZQA
Biginteger PVK value: 7
Hex PVK value: 7

Address 4:

KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3qYjgd9M7rFU77MfhviY5
1EhqbyUMvvs7BfL8goY6qcPbD6YKfPqb7e
Biginteger PVK value: 8
Hex PVK value: 8

Address 5:

KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3qYjgd9M7rFU7Dq8Au4Pv
1E6NuFjCi27W5zoXg8TRdcSRq84zJeBW3k
Biginteger PVK value: 21
Hex PVK value: 15

Address 6:

KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3qYjgd9M7rFU7Tmu6qHxS
1PitScNLyp2HCygzadCh7FveTnfmpPbfp8
Biginteger PVK value: 49
Hex PVK value: 31

Address 7:

KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3qYjgd9M7rFU7hDgvu64y
1McVt1vMtCC7yn5b9wgX1833yCcLXzueeC
Biginteger PVK value: 76
Hex PVK value: 4C

Address 8:

KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3qYjgd9M7rFU8xvGK1zpm
1M92tSqNmQLYw33fuBvjmeadirh1ysMBxK
Biginteger PVK value: 224
Hex PVK value: E0

Address 9:

KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3qYjgd9M7rFUB3vfDKcxZ
1CQFwcjw1dwhtkVWBttNLDtqL7ivBonGPV
Biginteger PVK value: 467
Hex PVK value: 1d3

Address 10:

KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3qYjgd9M7rFUBTL67V6dE
1LeBZP5QCwwgXRtmVUvTVrraqPUokyLHqe
Biginteger PVK value: 514
Hex PVK value: 202

Address 11:

KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3qYjgd9M7rFUGxXgtm63M
1PgQVLmst3Z314JrQn5TNiys8Hc38TcXJu
Biginteger PVK value: 1155
Hex PVK value: 483

Address 12:

KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3qYjgd9M7rFUW5RtS2JN1
1DBaumZxUkM4qMQRt2LVWyFJq5kDtSZQot
Biginteger PVK value: 2683
Hex PVK value: a7b

Address 13:

KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3qYjgd9M7rFUspniiQZds
1Pie8JkxBT6MGPz9Nvi3fsPkr2D8q3GBc1
Biginteger PVK value: 5216
Hex PVK value: 1460

Address 14:

KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3qYjgd9M7rFVfZyiN5iEG
1ErZWg5cFCe4Vw5BzgfzB74VNLaXEiEkhk
Biginteger PVK value: 10544
Hex PVK value: 2930

and so on...

until the addresses 50 (1MEzite4ReNuWaL5Ds17ePKt2dCxWEofwk) it was already cracked by someone.

Any ideas what's the formula behind the generation of these addresses?

Address 2, pvk decimal value: 3
Address 3, pvk decimal value: 7
Address 4, pvk decimal value: 8
Address 5, pvk decimal value: 21
Address 6, pvk decimal value: 49
Address 7, pvk decimal value: 76
Address 8, pvk decimal value: 224
Address 9, pvk decimal value: 467
Address 10, pvk decimal value: 514
Address 11, pvk decimal value: 1155
Address 12, pvk decimal value: 2683
Address 13, pvk decimal value: 5216
Address 14, pvk decimal value: 10544
Address 15 and after, pvk decimal value: ?

The prize would be ~32 BTC

EDIT: If you find the solution feel free to leave a tip 1DPUhjHvd2K4ZkycVHEJiN6wba79j5V1u3

Please explain more what " -r  " does exactly. And why 3 starting points?