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Topic: BitPistol - Are you smart enough to solve these puzzles? >>>TEST your brains <<< - page 3. (Read 6111 times)

full member
Activity: 129
Merit: 100
I done it

http://prnt.sc/c6qa00

Thanks Wink

Great job! Promo of 1 mBTC was credited to your in game account!
full member
Activity: 368
Merit: 212
Don't buy Bitcoin - Earn it
HCP
legendary
Activity: 2086
Merit: 4361
Seems to me like you'd want to go first... because at most, you get 3 attempts... and by going first there is always a chance you don't die on each one of your attempts, whereas by starting 2nd, you end up at 100% chance of death on your 3rd try... plus your odds are technically better for each one of your attempts if you are 1st...

1st attempt: Player A 1/6 die, Player B 2/6 die
2nd attempt: Player A 3/6 die, Player B 4/6 die
3rd attempt: Player A 5/6 die, Player B 6/6 die

Although, I'm not exactly sure that is a mathematically sound explanation... perhaps it is more of a "gut instinct" answer?? Huh
copper member
Activity: 2562
Merit: 2510
Spear the bees
Would it not be a pure 50/50 chance (ie. "fair") regardless of where you started?

There are an even number of chambers and 2 players, so each player will have 3 chambers that they could potentially use. Regardless of who goes first, each player has an equal number of chambers assigned to them, so after the spin, both players have an equal chance of having a bullet in one of their chambers.

And because you can't change which chambers you have (no spinning) the odds of getting a bullet overall don't change from 50/50.


That is correct answer! But we got a greater challenge for you:

This one is die hard. Imagine that you and your opponent start with 1 bullet loaded into the 6 slot. After each try you load one more bullet to the chamber, spin again and pass the pistol to your opponent.

QUESTION: Do you prefer to start as first, or shoot in second turn?

Going to try the thing I did last time. Tired so I'm probably wrong, rounded to first decimal.

R1: P1 has a 1/6 chance to die. (16.6%)
R2: 5/6 chance to happen, 2/6 chance to shoot, 10/36 -> P2 has a 5/18 chance to die. (27.7%)
R3: 5/9 chance to happen, 3/6 chance to shoot, 15/54 -> P1 has a 5/18 chance to die. (27.7%)
R4: 5/18 chance to happen, 4/6 chance to shoot, 20/108 -> P2 has a 5/27 chance to die. (18.5%)
R5: 5/54 chance to happen, 5/6 chance to shoot, 25/324 -> P1 has a 25/324 chance to die (7.7%)
R6: 5/324 chance to happen, 6/6 chance to shoot, 5/324 -> P2 has a 5/324 chance to die (1.5%)

Tallying up gives:

P1 has a ~52.2% chance of death
P2 has a ~47.8% chance of death



Probably wrong, maybe. Someone else can do this better than me.

Go second?
full member
Activity: 129
Merit: 100
Would it not be a pure 50/50 chance (ie. "fair") regardless of where you started?

There are an even number of chambers and 2 players, so each player will have 3 chambers that they could potentially use. Regardless of who goes first, each player has an equal number of chambers assigned to them, so after the spin, both players have an equal chance of having a bullet in one of their chambers.

And because you can't change which chambers you have (no spinning) the odds of getting a bullet overall don't change from 50/50.


That is correct answer! But we got a greater challenge for you:

This one is die hard. Imagine that you and your opponent start with 1 bullet loaded into the 6 slot. After each try you load one more bullet to the chamber, spin again and pass the pistol to your opponent.

QUESTION: Do you prefer to start as first, or shoot in second turn?
full member
Activity: 129
Merit: 100
Ladies (if there are some) and Gentlemen!

I would like to introduce to you brand new deadly Bitcoin game - BitPistol!

Load your gun >>> Shoot! >>> Win Bitcoins!

As game is about shooting from 6 bullet pistol we have a great puzzle for you to solve!


Imagine a 6 bullet revolver as it is in BitPistol, which is loaded with 2 bullets in a row:



Now imagine you are playing russian roulette with your opponent! He just made an empty shot and passes revolver to you!

QUESTION: Would you spin the cylinder to randomize your turn or trigger the pistol right away without spinning? We are waiting for correct answers!


I'm not sure it'll matter either way? The odds of hitting red are the same either way, am I right?

Well, I certainly wouldn't play this 'game' irl, I mean, who invented such an awful event? I have known of people who played this game and died from it...

I'd also like to know how one reacts after seeing their friend blow their brains out, because someone is going to die (or end up messed up in the head at the very least).



The correct answer to this puzzle you can read a few replies above, however odds are not the same if we are speaking about 2 bullet puzzle, it is worth shooting without spinning as you have 25% of probability to be shot. I believe also the equal chances is the solution to the second puzzle, where people are shooting each after other 1 bullet loaded revolver without spinning the chamber. I also must agree with you that this game itself is very thrilling when played in real live, i am sure the one will be shocked when he sees what you suggested
full member
Activity: 129
Merit: 100
Hint: The problem is in how you calculate odds

Ah. My bad.

You want to go second. I hadn't miscalculated necessarily, but it was in isolated cases. Here's the revised edition:

Round 1: P1 has a 1/6 chance of dying
Round 2: has a 5/6 chance of occurring, P2 has a 1/5 chance of dying, which equates to a 1/6 chance of dying.
Round 3: has a 4/6 chance of occurring, P1 has a 1/4 chance of dying, which equates to a 1/6 chance of dying.
Round 4, 5, and 6 follow the same format.

Looks like I screwed up!

And you want to be second, since though the odds are the same, P1 COULD shoot themselves on the first round.

Though if you average it out it doesn't really matter. Either works.

Alternate solution: go first and shoot your opponent.

And yet i can't agree with your solution. Probably there is some simplier way to solve it and maybe the correct answer was already mentioned in this thread ... Roll Eyes
full member
Activity: 129
Merit: 100
Answer i sent pm

I haven't got any messages with answer, only with bonus attenting, where i couldn't find 3 in a row as well
full member
Activity: 238
Merit: 100
Ladies (if there are some) and Gentlemen!

I would like to introduce to you brand new deadly Bitcoin game - BitPistol!

Load your gun >>> Shoot! >>> Win Bitcoins!

As game is about shooting from 6 bullet pistol we have a great puzzle for you to solve!


Imagine a 6 bullet revolver as it is in BitPistol, which is loaded with 2 bullets in a row:



Now imagine you are playing russian roulette with your opponent! He just made an empty shot and passes revolver to you!

QUESTION: Would you spin the cylinder to randomize your turn or trigger the pistol right away without spinning? We are waiting for correct answers!


I'm not sure it'll matter either way? The odds of hitting red are the same either way, am I right?

Well, I certainly wouldn't play this 'game' irl, I mean, who invented such an awful event? I have known of people who played this game and died from it...

I'd also like to know how one reacts after seeing their friend blow their brains out, because someone is going to die (or end up messed up in the head at the very least).

full member
Activity: 140
Merit: 100
HCP
legendary
Activity: 2086
Merit: 4361
Would it not be a pure 50/50 chance (ie. "fair") regardless of where you started?

There are an even number of chambers and 2 players, so each player will have 3 chambers that they could potentially use. Regardless of who goes first, each player has an equal number of chambers assigned to them, so after the spin, both players have an equal chance of having a bullet in one of their chambers.

And because you can't change which chambers you have (no spinning) the odds of getting a bullet overall don't change from 50/50.
legendary
Activity: 966
Merit: 1000
In holiday we trust
A 1 in 3 chance of losing those that make it provably fair or the opposite ?
copper member
Activity: 2562
Merit: 2510
Spear the bees
Hint: The problem is in how you calculate odds

Ah. My bad.

You want to go second. I hadn't miscalculated necessarily, but it was in isolated cases. Here's the revised edition:

Round 1: P1 has a 1/6 chance of dying
Round 2: has a 5/6 chance of occurring, P2 has a 1/5 chance of dying, which equates to a 1/6 chance of dying.
Round 3: has a 4/6 chance of occurring, P1 has a 1/4 chance of dying, which equates to a 1/6 chance of dying.
Round 4, 5, and 6 follow the same format.

Looks like I screwed up!

And you want to be second, since though the odds are the same, P1 COULD shoot themselves on the first round.

Though if you average it out it doesn't really matter. Either works.

Alternate solution: go first and shoot your opponent.
full member
Activity: 129
Merit: 100
You must consider, that if he misses his second shot, then the pistol will be in your hands again!

Ah, but it's a matter of probability.

You have a 1/6, then 1/4, then 1/2 chance to shoot yourself if you go first.

For your opponent, it's a 1/5, then 1/3, and then 100% chance of shooting themselves.

Round 1: You have an 83.333% chance of survival
Round 2: Your opponent has an 80% chance of survival.
Round 3: The chances of you surviving both round 1 and round 3 (on average) is 62.5% or 15/24
Round 4: The chances of them surviving both round 2 and 4 (on average) is 53.333% or 8/15
Round 5: The chances of you surviving all rounds 1, 3, and 5 is 31.25% or 5/16
Round 6: Your opponent loses, guaranteed.

You always have a better chance of survival going first.



I didn't put in the isolated case percentages because that's obvious. (And gambler's fallacy doesn't apply to this case, since future CAN be anticipated if you look at the rounds)

I can't agree with you. You have to pay more attention to this case. I will keep the secret a bit longer so others can participate too in solving the puzzle

Hint: The problem is in how you calculate odds
full member
Activity: 129
Merit: 100
You must consider, that if he misses his second shot, then the pistol will be in your hands again!

Ah, but it's a matter of probability.

You have a 1/6, then 1/4, then 1/2 chance to shoot yourself if you go first.

For your opponent, it's a 1/5, then 1/3, and then 100% chance of shooting themselves.

Round 1: You have an 83.333% chance of survival
Round 2: Your opponent has an 80% chance of survival.
Round 3: The chances of you surviving both round 1 and round 3 (on average) is 62.5% or 15/24
Round 4: The chances of them surviving both round 2 and 4 (on average) is 53.333% or 8/15
Round 5: The chances of you surviving all rounds 1, 3, and 5 is 31.25% or 5/16
Round 6: Your opponent loses, guaranteed.

You always have a better chance of survival going first.



I didn't put in the isolated case percentages because that's obvious. (And gambler's fallacy doesn't apply to this case, since future CAN be anticipated if you look at the rounds)

I can't agree with you. You have to pay more attention to this case. I will keep the secret a bit longer so others can participate too in solving the puzzle
copper member
Activity: 2562
Merit: 2510
Spear the bees
You must consider, that if he misses his second shot, then the pistol will be in your hands again!

Ah, but it's a matter of probability.

You have a 1/6, then 1/4, then 1/2 chance to shoot yourself if you go first.

For your opponent, it's a 1/5, then 1/3, and then 100% chance of shooting themselves.

Round 1: You have an 83.333% chance of survival
Round 2: Your opponent has an 80% chance of survival.
Round 3: The chances of you surviving both round 1 and round 3 (on average) is 62.5% or 15/24
Round 4: The chances of them surviving both round 2 and 4 (on average) is 53.333% or 8/15
Round 5: The chances of you surviving all rounds 1, 3, and 5 is 31.25% or 5/16
Round 6: Your opponent loses, guaranteed.

You always have a better chance of survival going first.



I didn't put in the isolated case percentages because that's obvious. (And gambler's fallacy doesn't apply to this case, since future CAN be anticipated if you look at the rounds)
full member
Activity: 129
Merit: 100
Quote

Ok, here is another challenge for you. Imagine that you and your opponent start with 1 bullet loaded into the 6 slot. Both you and him will have to shoot without spinning and after shot pass the pistol to another.

The question is do you prefer to start as first, or shoot in second turn?

Give me frist shoot...  Wink

Can you explain why would you like to shoot in the first turn?  Huh
full member
Activity: 129
Merit: 100

Great job! That is correct answer! Seems that we need to come with something more trickier next time! =)

Thanks! I love these type of mathematical and logics puzzles. They really challenge you and in this case also provide you a bit of insight in the odds for winning (or surviving Wink) this gambling game.

I hope you can come up with another challenging puzzle to put me up to a bit of extra thinking!




Ok, here is another challenge for you. Imagine that you and your opponent start with 1 bullet loaded into the 6 slot. Both you and him will have to shoot without spinning and after shot pass the pistol to another.

The question is do you prefer to start as first, or shoot in second turn?

Cool puzzle, these are always fun to try and solve!
I'd say that I would prefer to start first, as if I start, I'd have a 1 in 6 chance of taking the shot, while if I go second, I'd have a 1 in 5 chance of biting a bullet. 1 in 6 are better odds, so I'd like to start first.




You must consider, that if he misses his second shot, then the pistol will be in your hands again!

full member
Activity: 168
Merit: 100
keybase.io/pndgoo
Quote

Ok, here is another challenge for you. Imagine that you and your opponent start with 1 bullet loaded into the 6 slot. Both you and him will have to shoot without spinning and after shot pass the pistol to another.

The question is do you prefer to start as first, or shoot in second turn?

Give me frist shoot...  Wink
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