but this is what follows from the original example, i.e. losing the first half somehow facilitates losing the second half, i.e. losing all the halves, no matter how many there could be.
If you are going to keep on arguing against a point that I am not making and have never made, there is no point trying to help you understand. My statement does not in any way imply that flipping 5 heads somehow facilitates flipping 5 more heads, and if you still think it does despite me explaining this several times then that's an issue with your English skills, not my logic skills.
I am going to make 10 flips.
Each flip has a probability of 0.5 to be heads.
Before I start, I have a 0.5
10 (1 in 1024) probability of my next 10 flips being heads.
After I've made 1 flip, I have a 0.5
9 (1 in 512) probability of my next 9 flips being heads.
After I've made 2 flips, I have a 0.5
8 (1 in 256) probability of my next 8 flips being heads.
After I've made 3 flips, I have a 0.5
7 (1 in 128) probability of my next 7 flips being heads.
After I've made 4 flips, I have a 0.5
6 (1 in 64) probability of my next 6 flips being heads.
After I've made 5 flips, I have a 0.5
5 (1 in 32) probability of my next 5 flips being heads.
After I've made 6 flips, I have a 0.5
4 (1 in 16) probability of my next 4 flips being heads.
After I've made 7 flips, I have a 0.5
3 (1 in 8) probability of my next 3 flips being heads.
After I've made 8 flips, I have a 0.5
2 (1 in 4) probability of my next 2 flips being heads.
After I've made 9 flips, I have a 0.5
1 (1 in 2) probability of my last flip being heads.
Now, if all my flips do end up as heads, then as I progress along my run of heads from having made 0 flips to having made 10 flips, the probability of my reaching 10 heads in a row becomes more likely.
This is going to be my last post on the subject, since I am running out of ways and examples to explain this very basic concept.