At last you guys put new games here, I just wondering om how much multiplier that you can give out?
The technical limits for a minesweeper game with 25 fields are multipliers just over 5 million, which can happen with 12 or 13 mines (full field uncovered).
But I saw there is 24 mines button which is only one left to hit, how about that multiplier goes if in case someone hit it? Because you said that with 12 or 13 mines there is already a big payout like 5mill. I wondering about this payout as well. And how about this uncover payout do you mean if somehow I manage to hit it then the max payout should be only 4 btc as the ToS said?
Minesweeper works in a way where the maximum multiplier goes down again if you add more mines after 13.
For a game with 24 mines, you can only play one round, thus the multiplier would be (25/1) = 25x before the house edge.
Compare this to 13 mines, where you have (25/12)*(24/11)*(23/10)*(22/9)*(21/8)*(20/7)*(19/6)*(18/5)*(17/4)*(16/3)*(15/2)*(14/1) = 5,200,300x before the house edge,
and you see, that the maximum multiplier relies on both you having many mines and you having the ability to play many rounds.
This sweet-spot is hit with 12 mines / 13 rounds and 13 mines / 12 rounds, where the maximum technically possible multiplier is achieved. Adding more mines after that only decreases this limit.
If you closely read the How to Play information for minesweeper, you will find that the 4
BTC limit is enforced by a stop requirement.
"We only accept bets that have a profit smaller than 4 BTC (maximum win per bet), this means your game will not be allowed to uncover additional fields, if your pending win would go over this threshold."You won't be able to play until the technically possible max multiplier, as the game reaches a win state before that, once you cross the 4
BTC limit.
