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Topic: Does martingale really works? - page 78. (Read 123303 times)

sr. member
Activity: 259
Merit: 250
August 09, 2014, 04:53:45 PM
I made from 0.3 -> 5 BTC in 10 hours with martingale on PrimeDice.
It were so freakin crazy.. that "ride" raised my total wagered to 113 BTC.

Then I cashed out and lost it all back 3 weeks later..  

My highest bet were around 1.25 BTC.

Martingale is always a losing strategy in the long-run.. if you don't have unlimited money supply.

Unlimited supply of money wouldn't even help you since sites have maximum bets that you'll hit quickly using martingale.

Yea, but in "theory" martingale would work if you have a unlimited money supply. But not on PrimeDice Tongue
full member
Activity: 154
Merit: 100
Calling out scams, one HYIP at a time...
August 09, 2014, 04:46:58 PM
I made from 0.3 -> 5 BTC in 10 hours with martingale on PrimeDice.
It were so freakin crazy.. that "ride" raised my total wagered to 113 BTC.

Then I cashed out and lost it all back 3 weeks later..  

My highest bet were around 1.25 BTC.

Martingale is always a losing strategy in the long-run.. if you don't have unlimited money supply.

Unlimited supply of money wouldn't even help you since sites have maximum bets that you'll hit quickly using martingale.
sr. member
Activity: 259
Merit: 250
August 09, 2014, 04:37:02 PM
I made from 0.3 -> 5 BTC in 10 hours with martingale on PrimeDice.
It were so freakin crazy.. that "ride" raised my total wagered to 113 BTC.

Then I cashed out and lost it all back 3 weeks later..  

My highest bet were around 1.25 BTC.

Martingale is always a losing strategy in the long-run.. if you don't have unlimited money supply.
full member
Activity: 154
Merit: 100
Calling out scams, one HYIP at a time...
August 09, 2014, 04:33:49 PM
All bets have a negative expectation equal to the house edge, regardless of strategy.
sr. member
Activity: 406
Merit: 250
August 09, 2014, 03:09:52 PM
omaha poker says to leave house keys under the mat


and for the liver, you can keep it.
It's all or nothing!  Grin

Why not try playing Russian Roulette as well? Cool
Russian Roulette is best solution for Martingale and its give success already to many and some still looking for this  Cheesy
hero member
Activity: 1022
Merit: 500
August 09, 2014, 07:23:05 AM
omaha poker says to leave house keys under the mat


and for the liver, you can keep it.
It's all or nothing!  Grin

Why not try playing Russian Roulette as well? Cool

Some do : http://www.crimelibrary.com/blog/2012/12/26/five-people-who-played-russian-roulette-and-lost/index.html

You can get 10k-100k$ to play in once
legendary
Activity: 3514
Merit: 1280
English ⬄ Russian Translation Services
August 09, 2014, 05:43:13 AM
omaha poker says to leave house keys under the mat


and for the liver, you can keep it.
It's all or nothing!  Grin

Why not try playing Russian Roulette as well? Cool
legendary
Activity: 2044
Merit: 1005
July 03, 2014, 11:09:42 AM
I think we've proven that it doesn't work for dice games... but anyone do any math around modelling martingale around bitcoin trade setups or any other markets?

Not quite sure what you mean by "martingale around bitcoin trade setups".

Anyway, if a game has -ve EV and each bet is independent from the others, there is definitely no strategy can help you beat the house.
But not all games have -ve EV and are purely luck-based. Wink
You just answered your own question.

If you have been reading the thread I talk about the supposition that market=non independent bets.
hero member
Activity: 896
Merit: 1000
July 03, 2014, 07:09:43 AM
I think we've proven that it doesn't work for dice games... but anyone do any math around modelling martingale around bitcoin trade setups or any other markets?

Not quite sure what you mean by "martingale around bitcoin trade setups".

Anyway, if a game has -ve EV and each bet is independent from the others, there is definitely no strategy can help you beat the house.
But not all games have -ve EV and are purely luck-based. Wink

All game have -ve EV but you just cant feel it  Wink
hero member
Activity: 896
Merit: 1000
July 03, 2014, 03:19:48 AM
I think we've proven that it doesn't work for dice games... but anyone do any math around modelling martingale around bitcoin trade setups or any other markets?

Not quite sure what you mean by "martingale around bitcoin trade setups".

Anyway, if a game has -ve EV and each bet is independent from the others, there is definitely no strategy can help you beat the house.
But not all games have -ve EV and are purely luck-based. Wink
legendary
Activity: 2044
Merit: 1005
July 03, 2014, 01:10:29 AM
I think we've proven that it doesn't work for dice games... but anyone do any math around modelling martingale around bitcoin trade setups or any other markets?
hero member
Activity: 896
Merit: 1000
July 02, 2014, 11:01:42 PM
Your 2nd part, Martingale doesn't always have negative expectancy(I don't think).  If you were to play up to 20 hands, and you had enough to cover 20 losses.  The odds of you winning just 1 roll, you would have a positive expectancy...

If you're playing a game with a house edge then you always have a negative expected value. Anything else is silly.  Consider a game where the site gave the player the edge.  Could you think of any way of betting that would give you a negative expected value?

Yep, I could.  If you went all in every time you bet to infinity, you are going to lose eventually.  Thus, negative expected value.


Yes, even with a house edge you can have a positive expected value(math someone?)  Like in my example.  20 losses, or if you had 200 losses to cover, and you only wanted to win 1 base bet.  Your expected value should be darn close to the base bet no?  Any math people out there, Doog you have been good at this, I could be wrong as well just figured

Looks like you have a misunderstanding on "expected value".

Take your 20-hand martingale as an example.
P(20 consecutive losses) = 0.505^20 ~= 0.000116366%
P(win 1 base unit) = 1-0.505^20 ~= 99.999883633%
EV = P(win 1 base bet) * 1 - P(20 consecutive losses) * 2^20 = -0.22019120361 < 0

So, you have a very high chance to win 1 base unit, but you are still having a negative EV.
hero member
Activity: 896
Merit: 1000
July 02, 2014, 10:49:43 PM
You could define it as higher chance of winning, or as a higher EV play. 

Betting 100 with 99% chance to win 1 vs betting 1 with 49.5% chance to win 1.  Both have the same EV, but the first has a higher chance of winning, so is that better?

Both game has the same EV, but the former one has a house edge of 0.01% while the latter one has a house edge of 1%.
legendary
Activity: 2044
Merit: 1005
July 02, 2014, 10:11:08 PM
With infinite balance martingale is never going to break you but what system would? The key is to strike a balance between potential risk and reward and a favourable expectancy over the long haul. Anything else and you are going to learn the hard way.
legendary
Activity: 1456
Merit: 1081
I may write code in exchange for bitcoins.
July 02, 2014, 10:03:17 PM
legendary
Activity: 2044
Merit: 1005
July 02, 2014, 06:13:14 PM
You could define it as higher chance of winning, or as a higher EV play. 

Betting 100 with 99% chance to win 1 vs betting 1 with 49.5% chance to win 1.  Both have the same EV, but the first has a higher chance of winning, so is that better?

Correct but I think he showed that the expectancy was better with a 7 series martingale, very slightly. In the end it won't matter in this type of game.
legendary
Activity: 2940
Merit: 1333
July 02, 2014, 05:42:48 PM
Both have the same EV

How do you figure?
cp1
hero member
Activity: 616
Merit: 500
Stop using branwallets
July 02, 2014, 05:06:11 PM
You could define it as higher chance of winning, or as a higher EV play. 

Betting 100 with 99% chance to win 1 vs betting 1 with 49.5% chance to win 1.  Both have the same EV, but the first has a higher chance of winning, so is that better?
legendary
Activity: 2940
Merit: 1333
July 02, 2014, 04:51:20 PM
I think you need to define what you mean by "better".

If two things are identical except that one has a higher chance of winning than the other, I think it's pretty clear that the one with the higher chance of winning is "better".

It's hard to conceive of a definition whereby it isn't. Unless you think winning is bad, I guess.

Edit: are you thinking that for something to be better than something else it has to be good?

It is better to only lose the tip of a finger to an industrial accident than to lose a whole arm. Neither is good, but the less serious accident is "better" than the more serious accident.

Edit2: and so while I wouldn't recommend industrial accidents, I can say that if you're going to have one, try to have a minor one.  Because they are "better" than major ones.

Edit3: lol
cp1
hero member
Activity: 616
Merit: 500
Stop using branwallets
July 02, 2014, 03:48:11 PM
I think you need to define what you mean by "better".
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