For those of you who have not yet seen it:
https://youtu.be/LyVLq13WfsE
Topic: IOTA - page 313. (Read 1473405 times)
I signed up specifically out of interest in IOTA. Been involved in Bitcoin since 2011. Feel like this is the most disruptive token getting exposure right now. Can easily see it at #2 position by end of year. The technology is a game changer and their progress is excellent.
50:50 on that but yes I feel the same. Hope we are right here.
I think Bitcoin will loose traction and move Position 4-5 , ETH will stay No1 for some time and after that IOTA has a good chance.
I signed up specifically out of interest in IOTA. Been involved in Bitcoin since 2011. Feel like this is the most disruptive token getting exposure right now. Can easily see it at #2 position by end of year. The technology is a game changer and their progress is excellent.
https://amp.ibtimes.co.uk/iotas-tangle-meets-internet-things-requirements-better-any-blockchain-1626218
"It's not surprising that Internet of Things (IoT) transactional settlement and data transfer layer IOTA is a co-founding partner of IoT consortium the Trusted Internet of Things Alliance.
As well as other blockchain IoT specialists like Filament and Chronicled, the new consortium features heavyweight industry players such as Bosch and Cisco."
"It's not surprising that Internet of Things (IoT) transactional settlement and data transfer layer IOTA is a co-founding partner of IoT consortium the Trusted Internet of Things Alliance.
As well as other blockchain IoT specialists like Filament and Chronicled, the new consortium features heavyweight industry players such as Bosch and Cisco."
Can you answer this (quoting myself from another post):
Iota introduces an interesting new concept in the crypto scenario: the directed acyclic graph, or DAG. Basically it's an evolution of the usual blockchain, requiring no fees and without scaling issues.
Nevertheless, after having a quick look at the white paper I still don't understand how the nodes will keep working continuously. In the "tangle" there are no miners, the beloved greedy workers of the Bitcoin blockchain. Instead, here to perform a transaction, you should verify other transactions first. In the white paper (http://iotatoken.com/IOTA_Whitepaper.pdf) they say:
I'm not convinced by this statement. In fact, let's say that I'm a node and I don't want to be excluded by other nodes (and even on this I would like to understand what it means to be excluded. If you start again working hard can you be re-admitted? I could work only if I need to do transactions).
If my fellow nodes work x, I could work 0.99 x to not get excluded and minimize my work. But this reasoning can be applied to every node, since electricity has a cost, so everyone one will lower its effort, resulting in a system that perform poorly.
Iota introduces an interesting new concept in the crypto scenario: the directed acyclic graph, or DAG. Basically it's an evolution of the usual blockchain, requiring no fees and without scaling issues.
Nevertheless, after having a quick look at the white paper I still don't understand how the nodes will keep working continuously. In the "tangle" there are no miners, the beloved greedy workers of the Bitcoin blockchain. Instead, here to perform a transaction, you should verify other transactions first. In the white paper (http://iotatoken.com/IOTA_Whitepaper.pdf) they say:
Quote
what motivates the nodes to propagate transactions? In fact, in our setup the nodes do not have motivation
not to propagate. Every node calculates some statistics, one of which is how many
new transactions are received from a neighbor. If one particular node is “too lazy”, it
will be dropped by its neighbors. So, even if a node does not issue transactions (and
hence has no direct incentive to share new transactions that approve its own one), it
still has incentive to work hard.
not to propagate. Every node calculates some statistics, one of which is how many
new transactions are received from a neighbor. If one particular node is “too lazy”, it
will be dropped by its neighbors. So, even if a node does not issue transactions (and
hence has no direct incentive to share new transactions that approve its own one), it
still has incentive to work hard.
I'm not convinced by this statement. In fact, let's say that I'm a node and I don't want to be excluded by other nodes (and even on this I would like to understand what it means to be excluded. If you start again working hard can you be re-admitted? I could work only if I need to do transactions).
If my fellow nodes work x, I could work 0.99 x to not get excluded and minimize my work. But this reasoning can be applied to every node, since electricity has a cost, so everyone one will lower its effort, resulting in a system that perform poorly.
yes wondering this also what is the incentive basis for the nodes to operate? I guess if they want to use their iota for something then they must have a node.....will this lead to sort of a centralized holder of iota on behalf of people that can't be bothered running a node with sufficient up time
If I understood correctly the display is bugged on bitfinex?
We are not buying IOTA but MIOTA (M for Mega = 1 000 000) ?
We are not buying IOTA but MIOTA (M for Mega = 1 000 000) ?
I partly agree, maybe they could label it better, but:
Bitfinex Orderbook: "Amount (Mi)"
Bitfinex "About IOTA" link:
"To make more reasonable trading prices, all IOTA trading on Bitfinex is in units of Mi (MegaIota) - one million IOTA."
I don't see that (Mi) anywhere
https://ibb.co/f0ARF5
below your bottom red circle
Ooooh
Right xD, sorry
If I understood correctly the display is bugged on bitfinex?
We are not buying IOTA but MIOTA (M for Mega = 1 000 000) ?
We are not buying IOTA but MIOTA (M for Mega = 1 000 000) ?
I partly agree, maybe they could label it better, but:
Bitfinex Orderbook: "Amount (Mi)"
Bitfinex "About IOTA" link:
"To make more reasonable trading prices, all IOTA trading on Bitfinex is in units of Mi (MegaIota) - one million IOTA."
I don't see that (Mi) anywhere
https://ibb.co/f0ARF5
below your bottom red circle
If I understood correctly the display is bugged on bitfinex?
We are not buying IOTA but MIOTA (M for Mega = 1 000 000) ?
We are not buying IOTA but MIOTA (M for Mega = 1 000 000) ?
I partly agree, maybe they could label it better, but:
Bitfinex Orderbook: "Amount (Mi)"
Bitfinex "About IOTA" link:
"To make more reasonable trading prices, all IOTA trading on Bitfinex is in units of Mi (MegaIota) - one million IOTA."
I don't see that (Mi) anywhere
https://ibb.co/f0ARF5
If I understood correctly the display is bugged on bitfinex?
We are not buying IOTA but MIOTA (M for Mega = 1 000 000) ?
We are not buying IOTA but MIOTA (M for Mega = 1 000 000) ?
I partly agree, maybe they could label it better, but:
Bitfinex Orderbook: "Amount (Mi)"
Bitfinex "About IOTA" link:
"To make more reasonable trading prices, all IOTA trading on Bitfinex is in units of Mi (MegaIota) - one million IOTA."
$50B cap in the end of the year is possible with IOTA.
Much hard to say anything about that but in current scenario everything is possible how like these projects are growing this year now everyone is crazy about these. I hope so we will see much solid growth when it will get matured.
Can you answer this (quoting myself from another post):
Iota introduces an interesting new concept in the crypto scenario: the directed acyclic graph, or DAG. Basically it's an evolution of the usual blockchain, requiring no fees and without scaling issues.
Nevertheless, after having a quick look at the white paper I still don't understand how the nodes will keep working continuously. In the "tangle" there are no miners, the beloved greedy workers of the Bitcoin blockchain. Instead, here to perform a transaction, you should verify other transactions first. In the white paper (http://iotatoken.com/IOTA_Whitepaper.pdf) they say:
I'm not convinced by this statement. In fact, let's say that I'm a node and I don't want to be excluded by other nodes (and even on this I would like to understand what it means to be excluded. If you start again working hard can you be re-admitted? I could work only if I need to do transactions).
If my fellow nodes work x, I could work 0.99 x to not get excluded and minimize my work. But this reasoning can be applied to every node, since electricity has a cost, so everyone one will lower its effort, resulting in a system that perform poorly.
Iota introduces an interesting new concept in the crypto scenario: the directed acyclic graph, or DAG. Basically it's an evolution of the usual blockchain, requiring no fees and without scaling issues.
Nevertheless, after having a quick look at the white paper I still don't understand how the nodes will keep working continuously. In the "tangle" there are no miners, the beloved greedy workers of the Bitcoin blockchain. Instead, here to perform a transaction, you should verify other transactions first. In the white paper (http://iotatoken.com/IOTA_Whitepaper.pdf) they say:
Quote
what motivates the nodes to propagate transactions? In fact, in our setup the nodes do not have motivation
not to propagate. Every node calculates some statistics, one of which is how many
new transactions are received from a neighbor. If one particular node is “too lazy”, it
will be dropped by its neighbors. So, even if a node does not issue transactions (and
hence has no direct incentive to share new transactions that approve its own one), it
still has incentive to work hard.
not to propagate. Every node calculates some statistics, one of which is how many
new transactions are received from a neighbor. If one particular node is “too lazy”, it
will be dropped by its neighbors. So, even if a node does not issue transactions (and
hence has no direct incentive to share new transactions that approve its own one), it
still has incentive to work hard.
I'm not convinced by this statement. In fact, let's say that I'm a node and I don't want to be excluded by other nodes (and even on this I would like to understand what it means to be excluded. If you start again working hard can you be re-admitted? I could work only if I need to do transactions).
If my fellow nodes work x, I could work 0.99 x to not get excluded and minimize my work. But this reasoning can be applied to every node, since electricity has a cost, so everyone one will lower its effort, resulting in a system that perform poorly.
Am I seeing this correctly on Bitfinex 1 Gi ~= 0.22BTC? 
ok thanks but is still very high
Am I seeing this correctly on Bitfinex 1 Gi ~= 0.22BTC?
Yeah 
Have they reopened deposits yet?
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