Pages:
Author

Topic: [SOLVED] Skill Testing Math Question -- 0.08 BTC Reward (Read 1936 times)

legendary
Activity: 1120
Merit: 1038
i want to reclamation

From your question, you are looking for weight in grams.
in physics weight are united with Newton, not in grams. but in real world sometimes people call mass as weight.

   Quote from: lili song on July 24, 2015, 08:00:46 AM
                      Centripetal_force 1      =  centripetal_force 2
   84,000 g * (464 m/2)^2 / 6,371,000 m = mass * (463.2 m/s)^2 / 6,371,000 m

   mass = 84,290.4 g

and u claimed this answer as the winner. So the answer you are looking is mass not weight.

from this https://en.wikipedia.org/wiki/Weight is the description of weight physics
and this https://en.wikipedia.org/wiki/Mass is the description of mass in physics

if you are reading it carefully, in paragraph 2 of description of mass you will read  "An object on the Moon would weigh less than it would on Earth because of the lower gravity, but it would still have the same mass".
so whenever you are, whatever the velocity or radius of the planet
your mass will still same, but your weight will change.

and I want to straighten our concept about centripetal force.

from lili song answer centripetal force 1 = centripetal force 2.
This is completely wrong! As far as i know centripetal force change as the related variable change.
Sorry, lili, i did not mean to blame you.
this for the reference of the centripetal force description http://www.regentsprep.org/regents/physics/phys06/bcentrif/default.htm

So, the answer should still same mass(weight) 84,000 grams

As ndnhc pointed out, and as I already said in my answer, I gave it in mass equivalent.
What do I mean by mass equivalent?

The weight is 826.59 N, but it is the same weight of an object with mass of 84,289.46 grams on the surface of the earth.
OP asked for it in grams, so I gave it in mass equivalent.

Read my answer, it is different from lili's answer, but straightens out a lot of things he said, better explaining them.
He has a valid reason for being unable to explain it too, as English is not his first language either.
legendary
Activity: 1302
Merit: 1005
New Decentralized Nuclear Hobbit
btw, that is already accounted for here:

                     Centripetal_force 1      =  centripetal_force 2
84,000 g * (464 m/2)^2 / 6,371,000 m = mass * (463.2 m/s)^2 / 6,371,000 m

mass = 84,290.4 g


I just corrected that here: Grin

                     Centripetal_force 1      =  centripetal_force 2
84,000 g * (464 m/2)^2 / 6,371,000 m = mass * (463.2 m/s)^2 / 6,371,000 m

weight (in grams) = 84,290.4 g



The question clearly states:
Reduction Increase in weight = Change in centripetal force = m(V^2)/r - m(v^2)/r =  84(464^2 - 0.8^2)/6,371,000 = 2.83861407
legendary
Activity: 1148
Merit: 1006
Black Panther
i want to reclamation

From your question, you are looking for weight in grams.
in physics weight are united with Newton, not in grams. but in real world sometimes people call mass as weight.

   Quote from: lili song on July 24, 2015, 08:00:46 AM
                      Centripetal_force 1      =  centripetal_force 2
   84,000 g * (464 m/2)^2 / 6,371,000 m = mass * (463.2 m/s)^2 / 6,371,000 m

   mass = 84,290.4 g

and u claimed this answer as the winner. So the answer you are looking is mass not weight.

from this https://en.wikipedia.org/wiki/Weight is the description of weight physics
and this https://en.wikipedia.org/wiki/Mass is the description of mass in physics

if you are reading it carefully, in paragraph 2 of description of mass you will read  "An object on the Moon would weigh less than it would on Earth because of the lower gravity, but it would still have the same mass".
so whenever you are, whatever the velocity or radius of the planet
your mass will still same, but your weight will change.

and I want to straighten our concept about centripetal force.

from lili song answer centripetal force 1 = centripetal force 2.
This is completely wrong! As far as i know centripetal force change as the related variable change.
Sorry, lili, i did not mean to blame you.
this for the reference of the centripetal force description http://www.regentsprep.org/regents/physics/phys06/bcentrif/default.htm

So, the answer should still same mass(weight) 84,000 grams
legendary
Activity: 1120
Merit: 1038
'lili song' is the winner! (19jD5PfF5TqeF5xJWa5US2rM7GHVr5hdX) <-- 0.07 BTC

'jambola2' is the runner up. (1FRkoJDy8CwZ84RSeMs2tCEKBdVfHu32Ra) <-- 0.01 BTC

I decided not to be a cheap ass and reward the entire 0.08 BTC but, lili song's works sucks so jamola2 gets 0.01 BTC of her reward. Technically lili song posted while the reward was 0.01 BTC so consider yourself lucky.


Woah  Roll Eyes I can't believe it that I'm the winner
Thanks notbatman  Grin and thanks for jambola2 for clarification (since english is not my mother tongue, I can't argument just like you did. )

Yup, you owe me one for proving you right Wink

And notbatman, shoot me a PM the next time you're hosting this sort of stuff.
This was fun, and the free BTC for a few minutes of work was more fun Tongue
hero member
Activity: 980
Merit: 509
'lili song' is the winner! (19jD5PfF5TqeF5xJWa5US2rM7GHVr5hdX) <-- 0.07 BTC

'jambola2' is the runner up. (1FRkoJDy8CwZ84RSeMs2tCEKBdVfHu32Ra) <-- 0.01 BTC

I decided not to be a cheap ass and reward the entire 0.08 BTC but, lili song's works sucks so jamola2 gets 0.01 BTC of her reward. Technically lili song posted while the reward was 0.01 BTC so consider yourself lucky.


Woah  Roll Eyes I can't believe it that I'm the winner
Thanks notbatman  Grin and thanks for jambola2 for clarification (since english is not my mother tongue, I can't argument just like you did. )
vip
Activity: 1428
Merit: 1145
Don't think this proves that the Earth is a spinning globe, it doesn't. It does however prove that I'm somewhat of a massive fool for just assuming the centripetal force would be a large value.  Cry

NASA and the rest of the establishment are a den of vipers. Their eggheads have however defiantly crunched all the numbers. I won't make the same mistake twice. Math is the only science you can be 100% sure of the results and I'm going to find a hole in their global conspiracy.

The Earth is flat!

I was wonder why YouTube was suggesting me the likes of Saudi Cleric Was Right: USA Faked Moon Landing - Coriolis Effect Fraud lately. It's because I commented on this thread. Bad, notbatman!  Wink
legendary
Activity: 2212
Merit: 1038
Don't think this proves that the Earth is a spinning globe, it doesn't. It does however prove that I'm somewhat of a massive fool for just assuming the centripetal force would be a large value.  Cry

NASA and the rest of the establishment are a den of vipers. Their eggheads have however defiantly crunched all the numbers. I won't make the same mistake twice. Math is the only science you can be 100% sure of the results and I'm going to find a hole in their global conspiracy.

The Earth is flat!
legendary
Activity: 2212
Merit: 1038
legendary
Activity: 2212
Merit: 1038
'lili song' is the winner! (19jD5PfF5TqeF5xJWa5US2rM7GHVr5hdX) <-- 0.07 BTC

'jambola2' is the runner up. (1FRkoJDy8CwZ84RSeMs2tCEKBdVfHu32Ra) <-- 0.01 BTC

I decided not to be a cheap ass and reward the entire 0.08 BTC but, lili song's works sucks so jamola2 gets 0.01 BTC of her reward. Technically lili song posted while the reward was 0.01 BTC so consider yourself lucky.





full member
Activity: 182
Merit: 100
Lilisong answer answer is correct?
hero member
Activity: 616
Merit: 500
Based on following what would be the weight of an average person at the equator if the equatorial velocity was slowed to 0.8 m/s?

Earth's radius at the equator: 6,371,000 m
Earth's velocity at the equator: 464 m/s
Average weight of a person: 84,000 g
formula: centripetal_force = mass * velocity^2 / radius

Please provide the answer in grams and show your work!


It's 4567,85 g
newbie
Activity: 16
Merit: 0
its too hard  Cheesy

84000*464^2/6,371,000

2838.622 G
legendary
Activity: 2212
Merit: 1038
Reduction in weight = Change in centripetal force = m(V^2)/r - m(v^2)/r =  84(464^2 - 0.8^2)/6,371,000 = 2.83861407

However, since centripetal force is in Newtons, this is in Newtons.
Converting it to mass equivalent with the number you gave (1 newton = 101.971621 grams)

2.83861407 Newtons * 101.971621 Grams per newton = 289.458078111 Grams heavier

Wait what really? So less?

Let's look at the equation of centripetal force again.
Let's calculate the total centripetal force for any person

Mass in kg * (velocity)^2 / Radius
84 KG * 464 * 464  / 6,371,000
The thing you notice is that the radius is so large it makes the speed look extremely tiny.

Quote
So you're saying that the force on an average person from being whipped around at 464 meters per second is 290.4 grams?  Cheesy There's a ride at PlayLand called the Gravitron, you should ride it sometime!

Also, the only velocities that should be used here are 464 m/s and 0.8 m/s. Where on Earth did you get 463.2 m/s from?

Yes it is so low!
The author of that response made a mistake (464^2 - 0.8^2) =/= (463.2^2) , but was correct for the rest.

I'm not sure if you're playing a prank on the forums, but that's what happens when something is inversely proportional to the radius of something, and that radius is HUGE.

The fact that someone noted that this was consistent with NASA calculations regarding weight at the poles hints that your idea is wrong.

Leaving margin for error, I can say with certainty that the weight of the average person will be approximately 826.59 Newtons. (YES, Google it. The SI unit of weight is Newton, not mass)
Or, to use your extremely weird scale of stating weights in mass equivalent, 84,289.46 grams. Can't vouch for accuracy, may vary between 84,280 and 84,300 grams.

And here's my address: 1FRkoJDy8CwZ84RSeMs2tCEKBdVfHu32Ra

Best attempt yet... but, I need some time to go over it and some sleep. If I can't poke any holes in it I'll send the 0.08 BTC.

EDIT:

Reviewing the other posts it looks like 'lili song' (19jD5PfF5TqeF5xJWa5US2rM7GHVr5hdX) may have beaten you to it especially with your margin of error...

                     Centripetal_force 1      =  centripetal_force 2
84,000 g * (464 m/2)^2 / 6,371,000 m = mass * (463.2 m/s)^2 / 6,371,000 m

mass = 84,290.4 g


Oh, my precious Bitcoins, this isn't looking good for me. 'lili song' did however post while the reward was 0.01 BTC.

I'm still going over the numbers...
legendary
Activity: 1120
Merit: 1038
Reduction in weight = Change in centripetal force = m(V^2)/r - m(v^2)/r =  84(464^2 - 0.8^2)/6,371,000 = 2.83861407

However, since centripetal force is in Newtons, this is in Newtons.
Converting it to mass equivalent with the number you gave (1 newton = 101.971621 grams)

2.83861407 Newtons * 101.971621 Grams per newton = 289.458078111 Grams heavier

Wait what really? So less?

Let's look at the equation of centripetal force again.
Let's calculate the total centripetal force for any person

Mass in kg * (velocity)^2 / Radius
84 KG * 464 * 464  / 6,371,000
The thing you notice is that the radius is so large it makes the speed look extremely tiny.

Quote
So you're saying that the force on an average person from being whipped around at 464 meters per second is 290.4 grams?  Cheesy There's a ride at PlayLand called the Gravitron, you should ride it sometime!

Also, the only velocities that should be used here are 464 m/s and 0.8 m/s. Where on Earth did you get 463.2 m/s from?

Yes it is so low!
The author of that response made a mistake (464^2 - 0.8^2) =/= (463.2^2) , but was correct for the rest.

I'm not sure if you're playing a prank on the forums, but that's what happens when something is inversely proportional to the radius of something, and that radius is HUGE.

The fact that someone noted that this was consistent with NASA calculations regarding weight at the poles hints that your idea is wrong.

Leaving margin for error, I can say with certainty that the weight of the average person will be approximately 826.59 Newtons. (YES, Google it. The SI unit of weight is Newton, not mass)
Or, to use your extremely weird scale of stating weights in mass equivalent, 84,289.46 grams. Can't vouch for accuracy, may vary between 84,280 and 84,300 grams.

And here's my address: 1FRkoJDy8CwZ84RSeMs2tCEKBdVfHu32Ra
legendary
Activity: 2212
Merit: 1038
given:  if the equatorial velocity was slowed to 0.8 m/s?
Earth's radius at the equator: 6,371,000 m
Earth's velocity at the equator: 464 m/s
Average weight of a person: 84,000 g

formula: centripetal_force = mass * velocity^2 / radius

84,000 * (464-0.8/464)^2 / 6,371,000 = 2838.60141269 newtons
2838.60141269 *101.97 =  289452.186052 grams

this is my try Smiley
i think im missing something


a) The SI unit for mass is the kilogram.
b) You've only attempted to calculate part of the problem.
c) Other issues with the part you've attempted.
legendary
Activity: 3136
Merit: 1870
Metawin.com
given:  if the equatorial velocity was slowed to 0.8 m/s?
Earth's radius at the equator: 6,371,000 m
Earth's velocity at the equator: 464 m/s
Average weight of a person: 84,000 g

formula: centripetal_force = mass * velocity^2 / radius

84,000 * (464-0.8/464)^2 / 6,371,000 = 2838.60141269 newtons
2838.60141269 *101.97 =  289452.186052 grams

this is my try Smiley
i think im missing something
legendary
Activity: 2212
Merit: 1038
I've increased the reward to 0.08 BTC.
legendary
Activity: 2212
Merit: 1038
...
If you weighed 100 pounds at the north pole on a spring scale, at the equator you would weigh 99.65 pounds, or 5.5 ounces less.
we'll apply the calculation used to answer this skill testing question to the north pole as a test of its validity later...
Quote
84,000 * 9.79/0.00843823575 = 97456390.6916 grams. Grin

a) The SI unit for mass is the kilogram.
b) Where do you get '9.79' from?
c) Again, where do you get '0.00843823575' from?
d) How is the result of your calculation in grams and not newtons?
e) Many other issues.
legendary
Activity: 1302
Merit: 1005
New Decentralized Nuclear Hobbit
Based on following what would be the weight of an average person at the equator if the equatorial velocity was slowed to 0.8 m/s?

Earth's radius at the equator: 6,371,000 m
Earth's velocity at the equator: 464 m/s
Average weight of a person: 84,000 g
formula: centripetal_force = mass * velocity^2 / radius

Please provide the answer in grams and show your work!


84000 * 0.8^2/6,371,000 = 0.00843823575 grams.

Er.. wait.. something is wrong?

Edit: Re-attempt. I assume that weight and mass in both cases are equally proportional.
Honestly, I know nothing Physics. Grin


OH okay, so this centripedal force acts against gravity?
I see.

At the Equator.

Quote
If you weighed 100 pounds at the north pole on a spring scale, at the equator you would weigh 99.65 pounds, or 5.5 ounces less.

84,000 * 9.79/0.00843823575 = 97456390.6916 grams. Grin
vip
Activity: 1428
Merit: 1145
While I've provided the average weight of a person in grams and requested the answer in grams the SI unit for mass is the kilogram.

Also keep in mind the fact that mass is not the same as weight.

This is fucked up on so many levels! Does this now mean that I wasn't even close with my answer? If so, that really makes me out to look like a fool.  Cry
Pages:
Jump to: