[SOLVED] Skill Testing Math Question -- 0.08 BTC Reward - page 2.

ndnh

legendary

Activity: 1302

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New Decentralized Nuclear Hobbit

Quote from: notbatman on July 22, 2015, 11:23:47 AM

Based on following what would be the weight of an average person at the equator if the equatorial velocity was slowed to 0.8 m/s?

Earth's radius at the equator: 6,371,000 m
Earth's velocity at the equator: 464 m/s
Average weight of a person: 84,000 g
formula: centripetal_force = mass * velocity^2 / radius

Please provide the answer in grams and show your work!

84000 * 0.8^2/6,371,000 = 0.00843823575 grams.

Er.. wait.. something is wrong?

Edit: Re-attempt. I assume that weight and mass in both cases are equally proportional.
Honestly, I know nothing Physics. Grin

OH okay, so this centripedal force acts against gravity?
I see.

notbatman

legendary

Activity: 2212

Merit: 1038

While I've provided the average weight of a person in grams and requested the answer in grams the SI unit for mass is the kilogram.

Also keep in mind the fact that mass is not the same as weight.

BAGOBO

legendary

Activity: 1163

Merit: 1005

here's another attempt

r = 6,371,000 m
v = 464 m/s
m = 84,000 gr

cf = m* v^2 / r
= 84,000 gr * (464 m/s)^2 / 6,371,000 m
=2,838.62251 gr.m/s^2

if v = 0.8 m/s then
cf = m * v^2 / r

m = cf * r / v^2
= 2,838.62251 gr.m/s^2 * 6,371,000 m / (0.8 m/s)^2
= 28,257,600,000 gr

notbatman

legendary

Activity: 2212

Merit: 1038

Quote from: BAGOBO on July 23, 2015, 09:25:57 PM

So what are you looking for ?
The mass shift or looking for the exact mass ?

"...the weight..."

Quote

How about

0.8^2 / 464^2 * 84,000 = 0.2497026 gram

You're short a few kg.

notbatman

legendary

Activity: 2212

Merit: 1038

Quote from: Justin00 on July 23, 2015, 11:56:54 PM

pie squared - 2

let me know when you need my addy for reward.

Let this spin for a bit... Wink

notbatman

legendary

Activity: 2212

Merit: 1038

Quote from: lili song on July 24, 2015, 03:00:46 AM

Centripetal_force 1 = centripetal_force 2
84,000 g * (464 m/2)^2 / 6,371,000 m = mass * (463.2 m/s)^2 / 6,371,000 m

mass = 84,290.4 g

So you're saying that the force on an average person from being whipped around at 464 meters per second is 290.4 grams? Cheesy

There's a ride at PlayLand called the Gravitron, you should ride it sometime!

Also, the only velocities that should be used here are 464 m/s and 0.8 m/s. Where on Earth did you get 463.2 m/s from?

lili song

hero member

Activity: 980

Merit: 509

Centripetal_force 1 = centripetal_force 2
84,000 g * (464 m/2)^2 / 6,371,000 m = mass * (463.2 m/s)^2 / 6,371,000 m

mass = 84,290.4 g

Justin00

legendary

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★YoBit.Net★ 350+ Coins Exchange & Dice

pie squared - 2

let me know when you need my addy for reward.

googleindo

full member

Activity: 121

Merit: 100

this is going to be games and rounds section sir.
i dont like math sigh ....

BAGOBO

legendary

Activity: 1163

Merit: 1005

So what are you looking for ?
The mass shift or looking for the exact mass ?

How about

0.8^2 / 464^2 * 84,000 = 0.2497026 gram

GSLynn

newbie

Activity: 8

Merit: 0

ok so mass=x 84,000=x(464^2)/6,371,000 ----
x/101= 25,202
0.64 / 6371000 = 4077440
4077440 *25,202 = 102759642880g's or 102,759,642.880Kg

^^^ I think *** am i getting closer?

GSLynn

newbie

Activity: 8

Merit: 0

Quote from: notbatman on July 23, 2015, 02:09:38 PM

Using the information you've provided I've formatted your response to make it readable...

Quote from: JLynn171

0.8^2 = 0.64
0.64 / 6371000 = 4077440
4077440 * 84000 = 342504960000
342504960000 / 101.971621 = 3358826275.7929483145119366102849 grams

(velocity^2 / radius) * mass = 342,504,960,000 grams
342,504,960,000 / 101.971621 = 3,358,826,275.7929483145119366102849 newtons

So based on your response your answer is about 3,358,826,276 newtons or 342,504,960 kg, is that correct?

We're getting close but I don't think we've arrived at a BTC reward yet...

Problems I can see:

a) your giving results from your force formula in grams not newtons.
b) your mass is still incorporating a velocity of 464 m/s to get 84 kg.
c) many other issues.

lol ok i will break out pen and paper now i been trying do it in my head all day

notbatman

legendary

Activity: 2212

Merit: 1038

Tip: The SI unit of mass is the kilogram. Mass is not the same as weight.

notbatman

legendary

Activity: 2212

Merit: 1038

Using the information you've provided I've formatted your response to make it readable...

Quote from: JLynn171

0.8^2 = 0.64
0.64 / 6371000 = 4077440
4077440 * 84000 = 342504960000
342504960000 / 101.971621 = 3358826275.7929483145119366102849 grams

(velocity^2 / radius) * mass = 342,504,960,000 grams
342,504,960,000 / 101.971621 = 3,358,826,275.7929483145119366102849 newtons

So based on your response your answer is about 3,358,826,276 newtons or 342,504,960 kg, is that correct?

We're getting close but I don't think we've arrived at a BTC reward yet...

Problems I can see:

a) your giving results from your force formula in grams not newtons.
b) your mass is still incorporating a velocity of 464 m/s to get 84 kg.
c) many other issues.

JLynn171

sr. member

Activity: 406

Merit: 250

Quote from: notbatman on July 23, 2015, 11:44:36 AM

Quote from: sukamasoto on July 23, 2015, 10:33:38 AM

Let me try

( 464-0.8 )^2 / 464^2 * 84,000 = 83,710.5945303210463 gram

sent to here
1E1j2uMTLfXMDM6YZrWSnXPneRsVbht8k3
If my answer satisfy you Grin

The centripetal force that counters the gravitational force has been reduced to a fraction of what it normally is. How can they (the average person) possibly weigh 0.3 kg less?

Quote from: JLynn171 on July 23, 2015, 10:43:56 AM

0.64/ 6,371,000 =4077440
4077440x84,000=
?

You got a nice big number so you're going in the right direction but, where did you get '0.64' from?

342504960000gs/101.xxx=

3358826275.7929483145119366102849gs
0.8^2?= 0.64?

notbatman

legendary

Activity: 2212

Merit: 1038

Tip: the SI unit for force (in this case centripetal force) is the Newton. 1 newton = 101.971621 grams.

notbatman

legendary

Activity: 2212

Merit: 1038

Quote from: sukamasoto on July 23, 2015, 10:33:38 AM

Let me try

( 464-0.8 )^2 / 464^2 * 84,000 = 83,710.5945303210463 gram

sent to here
1E1j2uMTLfXMDM6YZrWSnXPneRsVbht8k3
If my answer satisfy you Grin

The centripetal force that counters the gravitational force has been reduced to a fraction of what it normally is. How can they (the average person) possibly weigh 0.3 kg less?

Quote from: JLynn171 on July 23, 2015, 10:43:56 AM

0.64/ 6,371,000 =4077440
4077440x84,000= 342504960000gs?

You got a nice big number so you're going in the right direction but, where did you get '0.64' from?

JLynn171

sr. member

Activity: 406

Merit: 250

0.64/ 6,371,000 =4077440
4077440x84,000= 342504960000gs?

sukamasoto

legendary

Activity: 1148

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Black Panther

Quote from: notbatman on July 22, 2015, 11:23:47 AM

Based on following what would be the weight of an average person at the equator if the equatorial velocity was slowed to 0.8 m/s?

Earth's radius at the equator: 6,371,000 m
Earth's velocity at the equator: 464 m/s
Average weight of a person: 84,000 g
formula: centripetal_force = mass * velocity^2 / radius

Please provide the answer in grams and show your work!

Let me try

( 464-0.8 )^2 / 464^2 * 84,000 = 83,710.5945303210463 gram

sent to here
1E1j2uMTLfXMDM6YZrWSnXPneRsVbht8k3
If my answer satisfy you Grin

notbatman

legendary

Activity: 2212

Merit: 1038

I've added a 0.01 BTC reward for the first correct answer.

Topic: [SOLVED] Skill Testing Math Question -- 0.08 BTC Reward - page 2. (Read 2026 times)