How about a 0.1 BTC reward, would that be enough to get a serious attempt at answering this question? That's almost $28 USD.
I think 0.02BTC would do.
Just a small rewards for attach people
Topic: [SOLVED] Skill Testing Math Question -- 0.08 BTC Reward - page 3. (Read 2024 times)
I think 0.02BTC would do.
Just a small rewards for attach people
How about a 0.1 BTC reward, would that be enough to get a serious attempt at answering this question? That's almost $28 USD.
Please provide the answer in grams and show your work!
144.82758612 gms
.8/464 = 0.00172413793
0.00172413793 X 84,000 = 144.82758612
The merry-go-round is slowed to a fraction of its regular speed, the centripetal force countering gravity is also reduced and the average person weighs less according to your answer?
I'm sorry but the average person is going to weigh more not less as the centripetal force is reduced.
Consider two magnets stuck together with one of them tied to a string. If you twirl the magnets fast enough the one held on will fly off once the centripetal force exceeds the magnetic force holding them together.
I do however appreciate your attempt at answering the question all-be-it a less than serious attempt.
Please provide the answer in grams and show your work!
144.82758612 gms
.8/464 = 0.00172413793
0.00172413793 X 84,000 = 144.82758612
I'm considering adding a reward, is 0.01 BTC enough?
Based on following what would be the weight of an average person at the equator if the equatorial velocity was slowed to 0.8 m/s?
Earth's radius at the equator: 6,371,000 m
Earth's velocity at the equator: 464 m/s
Average weight of a person: 84,000 g
formula: centripetal_force = mass * velocity^2 / radius
Earth's radius at the equator: 6,371,000 m
Earth's velocity at the equator: 464 m/s
Average weight of a person: 84,000 g
formula: centripetal_force = mass * velocity^2 / radius
0.8/464 X 84,000 = ____
Did I do that right?
Full Disclosure: I was the first one finishing the test and got a perfect 800 on the math section of the SAT back in 1978, but have probably forgotten more than half of what I've learnt back in the day. I taught myself calculus because it wasn't offered in my high school.
I purchased a Timex Sinclair 1000 from Radio Shack (circa 1983), read the manual and learnt how to program a clock via Basic. Upon the first read-through, I quickly realized that I could program a clock to run backwards. Without referencing the program further, I implemented the program and it worked as I envisioned it. I then realized how boring this computer programming bullshit was, so I abandoned all future efforts. And you guys thought I was an idiot.
Ironically, during the same basic timeframe on some other part of the world, some dude named Andreas Antonopoulos immersed himself with basically the same device. I wonder what ever happened to him.
Based on following what would be the weight of an average person at the equator if the equatorial velocity was slowed to 0.8 m/s?
Earth's radius at the equator: 6,371,000 m
Earth's velocity at the equator: 464 m/s
Average weight of a person: 84,000 g
formula: centripetal_force = mass * velocity^2 / radius
Please provide the answer in grams and show your work!
Earth's radius at the equator: 6,371,000 m
Earth's velocity at the equator: 464 m/s
Average weight of a person: 84,000 g
formula: centripetal_force = mass * velocity^2 / radius
Please provide the answer in grams and show your work!
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