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My favorite also is setting:
1, 1% of bankroll
2, Bet on x 1.02
3, If win, multiply wager x 1.02
4, Repeat 2-3, 35 times
If did not lose, you now have double of 1%. Use this on lowest payout until bust. Repeat again.
with the multipliers like that you are paying the highest HE "fee" so to say
the weight of it is way higher the lower your multiplier isits a legit wagering strategy though , one can easily get 100-200x his balance wagered
unfortunately , it is almost inevitable bust in the end , I prefer wagering strategies where you can have a chance to win
for example 50% chance flat bets , if you pick a lucky side , you could get even or even profit
Correct me if I'm wrong, but I think the house edge is always the same, and whether we win or not depends entirely on luck.
Let's examine what happens when we make 10,000 bets with the highest and lowest multipliers possible, and with 1.98x(50% win chance) on WinDice. Let's get rid of the luck factor by supposing that within 10,000 bets we'll have exactly 9,800 wins and 200 losses playing with 98% win chance; and we'll have 1 win and 9,999 losses playing with 0.01% win chance; and we'll have 5,000 wins and 5,000 losses playing with 50% win chance. Let's suppose, the bet amount equals to 100 sats.
98% win chanceWon: 9,800 x 1.0102 = 9,899.96 or roughly 9,900
Lost: 200 x 100 = 20,000
Profit = - 10,1000.01% win chanceWon: 9,900 x 100 - 100 = 990,000 - 100 = 989,900
Lost: 9,999 x 100 = 999,900
Profit = - 10,00050% win chanceWon: 5,000 x 98 = 490,000
Lost: 5,000 x 100 = 500,000
Profit = - 10,000To be honest, I didn't expect the 100 sats difference between 98% win chance and others here, but I can't see what went wrong with my calculations. So, if they are correct, then you are right, there is indeed a small difference, just 1%, but still it's there.