== Bitcoin challenge transaction: ~1000 BTC total bounty to solvers! ==UPDATED== - page 27.

Lolo54

member

Activity: 117

Merit: 32

Quote from: digaran on March 02, 2023, 06:57:52 PM

This message is for @satoshi aka the author of this challenge, "Live long in prosperity under the bluish violet dome".
Now could you create a new challenge with riddles and equations for us to seek and solve please? We're bored honestly and it could light up the mood in crypto-community ushering new methods and never ending possibilities. Though not something that someone could solve them all with one go, maybe make them in episode where each riddle's answer is just a small piece of the greater puzzle. ❤👏💯

even if he does not intervene with his nickname it seems that he has read and listened to you digaran making it even more attractive Grin

#66 and #67 should not last long because it becomes very interesting (profitable) to rent a strong computing power to reach them

pbies

full member

Activity: 297

Merit: 133

They begin with a "1":

Puzzle 65 is 21.439643985050658 times the puzzle 61.
Puzzle 61 is 10.313427000231762 times the puzzle 57.
Puzzle 57 is 20.439417260448156 times the puzzle 53.
Puzzle 53 is 16.532318326723157 times the puzzle 49.

Puzzle 65 times 10 is starting point 0x109236ec1238f81406.
Puzzle 65 times 20 is starting point 0x21246dd82471f0280c.

These are each 4th that are starting with "1".

Each other by 4th are also similar when multiplying.

mr. k0c

newbie

Activity: 12

Merit: 0

wtf?? someone just deposited a shit load of BTC into puzzles

JDScreesh

jr. member

Activity: 47

Merit: 13

WOW! Somebody (maybe the owner) increased the unsolved puzzles prizes again by x10 😱
Now the puzzle #66 prize is 6.6 BTC, #67 is 6.7 BTC... and so on .... puzzle # 160 prize is 16 BTC now
👍🏼🥳

WanderingPhilospher

full member

Activity: 1162

Merit: 237

Shooters Shoot...

Quote from: kalos15btc on April 08, 2023, 10:41:00 AM

Quote from: Lolo54 on April 08, 2023, 06:38:23 AM

13zb1hQbw fhhEryPWBrAioLY5tiFLr hs5o - 0x319AFC9E3FF391B01

take a good look at the end of the address it is in no way identical to the 66 which is h5so no hs5o Wink

13zb1hQbWVsc2S7ZTZnP2G4undNNpdh5so

it is only the first 7 characters which are identical but several utilities can allow you to find some in this range with even more characters just for example
13zb1hQbWLiYzxkb5Qeiwr9ZZRHycheQBV
KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3qZo5eQmmER3KXshr85jU
2E120C91F20C0B511
20d45a6a762458afee967c590479283af57e7c40

i know that, and thats what im talking about men Cheesy

, its located in the range of 200.. to 3fff..

if you find same 7 or 8 digits of the rmd160 that means its in that range bro, so, when i post the public key substracted from 125 to 110. i told you this is in the 110 bits because it start with the 4 same rmd160 of other wallet in 110, that means its in the same range of 110, like you said bro in 66 20d45a6a same start of wallet 66, and the range is 319afc.... so, do you understand what im talking ?

Yeah, that's not how it works...I can generate 2^20 unique addresses and roughly 64,000 will have matching first 4 characters of their rmd160 value.
Think of it this way; there are only 2^16 (or 16^4) combinations of the same 4 leading rmd160 characters; in all of the 2^160 combinations.

albert0bsd

hero member

Activity: 862

Merit: 662

Quote from: kalos15btc on April 08, 2023, 10:41:00 AM

i know that, and thats what im talking about men Cheesy

, its located in the range of 200.. to 3fff..

if you find same 7 or 8 digits of the rmd160 that means its in that range bro, so, when i post the public key substracted from 125 to 110. i told you this is in the 110 bits because it start with the 4 same rmd160 of other wallet in 110, that means its in the same range of 110, like you said bro in 66 20d45a6a same start of wallet 66, and the range is 319afc.... so, do you understand what im talking ?

I don't understand anything, the start string of the address don't have any relationship with the range

kalos15btc

jr. member

Activity: 50

Merit: 1

Quote from: Lolo54 on April 08, 2023, 06:38:23 AM

13zb1hQbw fhhEryPWBrAioLY5tiFLr hs5o - 0x319AFC9E3FF391B01

take a good look at the end of the address it is in no way identical to the 66 which is h5so no hs5o Wink

13zb1hQbWVsc2S7ZTZnP2G4undNNpdh5so

it is only the first 7 characters which are identical but several utilities can allow you to find some in this range with even more characters just for example
13zb1hQbWLiYzxkb5Qeiwr9ZZRHycheQBV
KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3qZo5eQmmER3KXshr85jU
2E120C91F20C0B511
20d45a6a762458afee967c590479283af57e7c40

i know that, and thats what im talking about men Cheesy

, its located in the range of 200.. to 3fff..

if you find same 7 or 8 digits of the rmd160 that means its in that range bro, so, when i post the public key substracted from 125 to 110. i told you this is in the 110 bits because it start with the 4 same rmd160 of other wallet in 110, that means its in the same range of 110, like you said bro in 66 20d45a6a same start of wallet 66, and the range is 319afc.... so, do you understand what im talking ?

Lolo54

member

Activity: 117

Merit: 32

13zb1hQbw fhhEryPWBrAioLY5tiFLr hs5o - 0x319AFC9E3FF391B01

take a good look at the end of the address it is in no way identical to the 66 which is h5so no hs5o Wink

13zb1hQbWVsc2S7ZTZnP2G4undNNpdh5so

it is only the first 7 characters which are identical but several utilities can allow you to find some in this range with even more characters just for example
13zb1hQbWLiYzxkb5Qeiwr9ZZRHycheQBV
KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3qZo5eQmmER3KXshr85jU
2E120C91F20C0B511
20d45a6a762458afee967c590479283af57e7c40

ProjectSe7en

jr. member

Activity: 59

Merit: 1

Quote from: unclevito on April 05, 2023, 01:20:38 PM

I can do 1 quintillion/sec 1,000,000,000,000,000,000 but the range of 110 alone is 649037107316853453566312041152512 or
six hundred forty nine nonillion ,
thirty seven octillion ,
one hundred seven septillion ,
three hundred sixteen sextillion ,
eight hundred fifty three quintillion ,
four hundred fifty three quadrillion ,
five hundred sixty six trillion ,
three hundred twelve billion ,
forty one million ,
one hundred fifty two thousand ,
five hundred twelve
so it would take me 649,037,107,316,853 seconds or 7,635,730,674 days 20,919,810 (a little over 20 million years, I better stop smoking) just to go all the way through 110 with my 1070 and a whole lot of luck. I will try with kangaroo with an old gt1030 which does about 370 Trillion/ sec and about as much electricity as an led bulb. have you scanned any of 110?

with wich programm? Huh

kalos15btc

jr. member

Activity: 50

Merit: 1

Quote from: unclevito on April 05, 2023, 01:20:38 PM

I can do 1 quintillion/sec 1,000,000,000,000,000,000 but the range of 110 alone is 649037107316853453566312041152512 or
six hundred forty nine nonillion ,
thirty seven octillion ,
one hundred seven septillion ,
three hundred sixteen sextillion ,
eight hundred fifty three quintillion ,
four hundred fifty three quadrillion ,
five hundred sixty six trillion ,
three hundred twelve billion ,
forty one million ,
one hundred fifty two thousand ,
five hundred twelve
so it would take me 649,037,107,316,853 seconds or 7,635,730,674 days 20,919,810 (a little over 20 million years, I better stop smoking) just to go all the way through 110 with my 1070 and a whole lot of luck. I will try with kangaroo with an old gt1030 which does about 370 Trillion/ sec and about as much electricity as an led bulb. have you scanned any of 110?

i have the same speed 7terrak per sec thats 7 quantillion per sec , thats why i told you my speed is slow im running bsgs on 8 core cpu, so i cant complete the entire range in 1 week or month, thats why i ask for help here.

Quote from: albert0bsd on April 05, 2023, 04:54:03 PM

Quote from: kalos15btc on April 05, 2023, 12:08:16 PM

... i found a substracted key his hash160 start with the same 4 lettres as a hash160 of an adress in the range 110 bit, so, am i close to find it ?
...

No you aren't any closer

i understand, thanks for your help, i was thinking like that because in this post
https://bitcointalksearch.org/user/dextronomous-306088

Quote from: dextronomous on October 01, 2022, 08:30:25 AM

Quote from: Jolly Jocker on September 30, 2022, 04:40:13 PM

Puzzle 66... ( 13zb1hQbWVsc2S7ZTZnP2G4undNNpdh5so )

That's a mockery ....! Sad

13zb1hQbwfhhEryPWBrAioLY5tiFLrhs5o - 0x319AFC9E3FF391B01

my guess. it should be above this one,
00000000000000000000000000000000000000000000000319AFC9E3FF391B01

KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3q > ZsnspiitMKGTKUxzXus

KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3q > (a) something

ripemd -- 20D45A6A76AEB187FB6E669463E929D7072AB330

13zb1hQbwfhhEryPWBrAioLY5tiFLrhs5o

they find same firsts caracteres hash160 of the puzzle 66 so logic its on that bit range 66
thats why when i found the same 4 hex of 110 bits of other 110 bit wallet i say that, im just asking the question and if in 2020 they cracked the 110 bit, if you have a good speed and you can search for the entire range in 1 hour you can try the public key, maybe im wrong but if its correct, you will earn smthing,

you can substract the bit 125 but you wont find a hash same as you have in a specific bit range start with same digits, its luck i think when i found it but maybe im not wrong ,, if we found hashes starts with same 4 digits in all bit ranges then im wrong, that information i dont have, i dont know how the hash160 works so, i just want you to help guys maybe there is smthing.

Quote from: WanderingPhilospher on April 05, 2023, 01:35:44 PM

Quote from: unclevito on April 05, 2023, 01:20:38 PM

I can do 1 quintillion/sec 1,000,000,000,000,000,000 but the range of 110 alone is 649037107316853453566312041152512 or
six hundred forty nine nonillion ,
thirty seven octillion ,
one hundred seven septillion ,
three hundred sixteen sextillion ,
eight hundred fifty three quintillion ,
four hundred fifty three quadrillion ,
five hundred sixty six trillion ,
three hundred twelve billion ,
forty one million ,
one hundred fifty two thousand ,
five hundred twelve
so it would take me 649,037,107,316,853 seconds or 7,635,730,674 days 20,919,810 (a little over 20 million years, I better stop smoking) just to go all the way through 110 with my 1070 and a whole lot of luck. I will try with kangaroo with an old gt1030 which does about 370 Trillion/ sec and about as much electricity as an led bulb. have you scanned any of 110?

I have. I have over 33GB of tame points (DP 25) in the 110 bit range lol. But I wouldn’t chase down a 4 character h160 that’s for sure lol.
Also, the “1 hour” entire range scan had me laughing 😂

i dont know 1 hour or 1 day, but if you want to have a test of that public key, thanks

albert0bsd

hero member

Activity: 862

Merit: 662

Quote from: kalos15btc on April 05, 2023, 12:08:16 PM

... i found a substracted key his hash160 start with the same 4 lettres as a hash160 of an adress in the range 110 bit, so, am i close to find it ?
...

No you aren't any closer

unclevito

jr. member

Activity: 76

Merit: 4

yea I could use iceland2k14 scalar program and make 16k keys and use albertobsd bsgs and load them all takes about 15 minutes to load and get 10 trillion/sec and do random on my 1070 but I am in Florida and the room is already too hot lol. my little 1030 is doing dp 10

WanderingPhilospher

full member

Activity: 1162

Merit: 237

Shooters Shoot...

Quote from: unclevito on April 05, 2023, 01:20:38 PM

I can do 1 quintillion/sec 1,000,000,000,000,000,000 but the range of 110 alone is 649037107316853453566312041152512 or
six hundred forty nine nonillion ,
thirty seven octillion ,
one hundred seven septillion ,
three hundred sixteen sextillion ,
eight hundred fifty three quintillion ,
four hundred fifty three quadrillion ,
five hundred sixty six trillion ,
three hundred twelve billion ,
forty one million ,
one hundred fifty two thousand ,
five hundred twelve
so it would take me 649,037,107,316,853 seconds or 7,635,730,674 days 20,919,810 (a little over 20 million years, I better stop smoking) just to go all the way through 110 with my 1070 and a whole lot of luck. I will try with kangaroo with an old gt1030 which does about 370 Trillion/ sec and about as much electricity as an led bulb. have you scanned any of 110?

I have. I have over 33GB of tame points (DP 25) in the 110 bit range lol. But I wouldn’t chase down a 4 character h160 that’s for sure lol.
Also, the “1 hour” entire range scan had me laughing 😂

unclevito

jr. member

Activity: 76

Merit: 4

I can do 1 quintillion/sec 1,000,000,000,000,000,000 but the range of 110 alone is 649037107316853453566312041152512 or
six hundred forty nine nonillion ,
thirty seven octillion ,
one hundred seven septillion ,
three hundred sixteen sextillion ,
eight hundred fifty three quintillion ,
four hundred fifty three quadrillion ,
five hundred sixty six trillion ,
three hundred twelve billion ,
forty one million ,
one hundred fifty two thousand ,
five hundred twelve
so it would take me 649,037,107,316,853 seconds or 7,635,730,674 days 20,919,810 (a little over 20 million years, I better stop smoking) just to go all the way through 110 with my 1070 and a whole lot of luck. I will try with kangaroo with an old gt1030 which does about 370 Trillion/ sec and about as much electricity as an led bulb. have you scanned any of 110?

WanderingPhilospher

full member

Activity: 1162

Merit: 237

Shooters Shoot...

Quote from: digaran on April 05, 2023, 12:52:48 PM

Quote from: kalos15btc on April 05, 2023, 12:08:16 PM

hi guys, im working on puzzle 125 for a long time, today, i have substracted the public key (im always test and substract by random) of 125 to a smaller range randomly i found a substracted key his hash160 start with the same 4 lettres as a hash160 of an adress in the range 110 bit, so, am i close to find it ? if i search this substracted public key in 110 bit range will i found it ? the probleme im runing 7TerraK per sec its slow, and if anyone can help we will split the reward of the puzzle 125,
02a0397a2b74177e0f101ab1cbe9d560ac384c01fd69d7e19593d1ab3155f9ad73
2000000000000000000000000000:3fffffffffffffffffffffffffff
if you have better speed search from 1f00000000000000000000000000:7fffffffffffffffffffffffffff from 109 to 111 bits,

if you have good speed and can finish this range in 1hour, you wont lose nothing, we will split the reward

thank you

How can you search for a 125 bit range public key in 109-111 bit range? And why would you care about the first 4 characters of a hash160 of another random address?
Please explain the magic here.😉

You can shrink a search range via subtraction of a known public key.

If you shrink #125 down to 110 bits, you will create 2^15 new public keys. One of those will be guaranteed to be in the 110 bit range.

I do not understand the initial post of finding the first 4 hash160 characters...IMO, that does not help nor narrow down the search to that one pubkey.

digaran

copper member

Activity: 1330

Merit: 899

🖤😏

Quote from: kalos15btc on April 05, 2023, 12:08:16 PM

hi guys, im working on puzzle 125 for a long time, today, i have substracted the public key (im always test and substract by random) of 125 to a smaller range randomly i found a substracted key his hash160 start with the same 4 lettres as a hash160 of an adress in the range 110 bit, so, am i close to find it ? if i search this substracted public key in 110 bit range will i found it ? the probleme im runing 7TerraK per sec its slow, and if anyone can help we will split the reward of the puzzle 125,
02a0397a2b74177e0f101ab1cbe9d560ac384c01fd69d7e19593d1ab3155f9ad73
2000000000000000000000000000:3fffffffffffffffffffffffffff
if you have better speed search from 1f00000000000000000000000000:7fffffffffffffffffffffffffff from 109 to 111 bits,

if you have good speed and can finish this range in 1hour, you wont lose nothing, we will split the reward

thank you

How can you search for a 125 bit range public key in 109-111 bit range? And why would you care about the first 4 characters of a hash160 of another random address?
Please explain the magic here.😉

kalos15btc

jr. member

Activity: 50

Merit: 1

hi guys, im working on puzzle 125 for a long time, today, i have substracted the public key (im always test and substract by random) of 125 to a smaller range randomly i found a substracted key his hash160 start with the same 4 lettres as a hash160 of an adress in the range 110 bit, so, am i close to find it ? if i search this substracted public key in 110 bit range will i found it ? the probleme im runing 7TerraK per sec its slow, and if anyone can help we will split the reward of the puzzle 125,
02a0397a2b74177e0f101ab1cbe9d560ac384c01fd69d7e19593d1ab3155f9ad73
2000000000000000000000000000:3fffffffffffffffffffffffffff
if you have better speed search from 1f00000000000000000000000000:7fffffffffffffffffffffffffff from 109 to 111 bits,

if you have good speed and can finish this range in 1hour, you wont lose nothing, we will split the reward

thank you

digaran

copper member

Activity: 1330

Merit: 899

🖤😏

Guys I'm telling you, Satoshi solved the puzzle, few days after I pointed him to this thread, he did it with his super GPU computer, and I bet he is busy with the next one #125. I just didn't expect him to take the loots alone, we were partners.🤣 at least let me loot the garbage coins. Lol.

noecp

newbie

Activity: 7

Merit: 5

Not a 32 times bigger but √32 like ~5.65. this not full space search, this birthday collision check.
You can compare 'expected operations' for
115 2^58.1
120 2^60.61
125 2^63.10
130 2^65.61
...

zielar

full member

Activity: 282

Merit: 114

Quote from: albert0bsd on March 07, 2023, 07:26:53 AM

Hi @zielar, nice to see you here

Quote from: zielar on March 05, 2023, 08:01:05 PM

2. Someone has a tool to find #125 soon

As we know the puzzle 125 is 32 times bigger than puzzle 120 but prize is only a 4% bigger, i doubt about that such "magic" tool exists. But we don't have way to know.

If that exists it should be a mathematical approach.

Nice to see you too :-)
Despite the passage of time and the fact that people who are more active in the subject know each other only from here - there is a smile on your face knowing that everything is fine with you :-)
It is also certain that no matter how much time passes - the solution of the next thresholds will certainly take place, whether it is due to the fact that the technology will develop further or because the value of assets, despite being only 4% more - will be much higher in terms of physical currency than today. Time will tell. I also believe that we will get to know the finder of solution 120 and how he did it, how much time he needed for it, or at least the private key to complete the list of keys of solved addresses. Greetings!

Topic: == Bitcoin challenge transaction: ~1000 BTC total bounty to solvers! ==UPDATED== - page 27. (Read 54326 times)