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Topic: == Bitcoin challenge transaction: ~1000 BTC total bounty to solvers! ==UPDATED== - page 28. (Read 54326 times)

hero member
Activity: 862
Merit: 662
Hi @zielar, nice to see you here

2. Someone has a tool to find #125 soon

As we know the puzzle 125 is 32 times bigger than puzzle 120 but prize is only a 4% bigger, i doubt about that such "magic" tool exists. But we don't have way to know.

If that exists it should be a mathematical approach.

I made some computations. Used Python 3. I was curious if the next puzzle can be ax+b=y.
d1, d2, d3 are corresponding private keys from puzzle. Needed to compute a and b.

We already know that puzzles a random and there is not math relationship between them
full member
Activity: 297
Merit: 133
I made some computations. Used Python 3. I was curious if the next puzzle can be ax+b=y.
d1, d2, d3 are corresponding private keys from puzzle. Needed to compute a and b.

First script for puzzle 66:

Code:
#!/usr/bin/env python3
import math

d1=0x0000000000000000000000000000000000000000000000007cce5efdaccf6808
d2=0x000000000000000000000000000000000000000000000000f7051f27b09112d4
d3=0x000000000000000000000000000000000000000000000001a838b13505b26867

asqr=(d2-(d2/d1))/d1
a=math.sqrt(asqr)
print("a =",a)
b=d2/(a*d1)
print("b =",b)
d4=a*d3+b
print("next =",hex(int(d4)))

Second script for puzzle 120:

Code:
#!/usr/bin/env python3
import math

d1=0x000000000000000000000000000000000000016f14fc2054cd87ee6396b33df3
d2=0x00000000000000000000000000000000000035c0d7234df7deb0f20cf7062444
d3=0x0000000000000000000000000000000000060f4d11574f5deee49961d9609ac6

asqr=(d2-(d2/d1))/d1
a=math.sqrt(asqr)
print("a =",a)
b=d2/(a*d1)
print("b =",b)
d4=a*d3+b
print("next =",hex(int(d4)))

The output is however strange, because a=b!

This means the next puzzle is multiplied and added to it the same value, I mean the multiplicator and later adding a number are the same.

First script gives:

Code:
a = 1.4068509690560507
b = 1.4068509690560507
next = 0x254d0fd348f800000

Second script gives:

Code:
a = 6.122671382779787
b = 6.122671382779785
next = 0x251a1b44dd0e160000000000000000

What can mean that just raising the value(s) of a and b can give next puzzle private key!
full member
Activity: 282
Merit: 114
It is a real shame that the solver of #120 still didn't give us the private key.
Dude, if you're out there, please find a way to communicate it

There are various reasons why we still don't have the key:
1. The finder wishes to remain anonymous
2. Someone has a tool to find #125 soon
3. The withdrawal was made by someone outside the forum
4. Someone has some other purpose in it, so as not to reveal themselves.

It is certainly puzzling that BCH and BTG have not been paid out from this wallet so far, while the payment was made to the address without any other transaction before, nor was it sent further - which also raises the suspicion that the finder could use some tool that worked for a long time -> found the right key and made the withdrawal, but the initiator himself still does not know that he found solution #120. A lot of unknowns, but I believe that eventually someone will somehow provide a solution, because the solution #120 without indicating the key to the public will simply be a blow to the whole history of these puzzles.
newbie
Activity: 12
Merit: 0
It is a real shame that the solver of #120 still didn't give us the private key.
Dude, if you're out there, please find a way to communicate it
hero member
Activity: 862
Merit: 662
This message is for @satoshi aka the author of this challenge, "Live long in prosperity under the bluish violet dome".

Now could you create a new challenge with riddles and equations for us to seek and solve please? We're bored honestly and it could light up the mood in crypto-community ushering new methods and never ending possibilities. Though not something that someone could solve them all with one go, maybe make them in episode where each riddle's answer is just a small piece of the greater puzzle. ❤👏💯


Do you expected a new Cicada 3301 ?

I really want some challenges like that, but diffucults please.
copper member
Activity: 1330
Merit: 899
🖤😏
+1 I am also interested but I think it's just playing with the ripemd160 hash
You think? Lol.

Could you at least share the process, maybe some code somewhere can help you automate it.

Convert each of them into hash160 and look at the last hex characters, change their values in an orderly fashion to be amazed by the beauty of order amongst the chaos.
Have you seen websites providing an online(totally unsafe) service where you could just insert your desired private key in hex format and see all the corresponding properties such as addresses, public/ private keys even for many coins etc? It would be great if we could build an algorithm specifically designed to do the same for addresses only, this way we wouldn't need to count from 1 up to 2^256, we'd only need to represent 2^160.8 (more or less) total number of addresses with hexadecimal values, so when you search for the address #0 you'd get
Code:
1111111111111111111114oLvT2
for #1 you'd get
Code:
11111111111111111111BZbvjr
and so on until you reach the end of the address range. This is just for entertainment and would have no use case for storing bitcoins because you don't know the private keys, you might only know the private keys which you had generated before, i.e, using a wallet etc.

If we could manage to do something like that, imagine the awe of the beholder! Being present at such a mesmerizing sight!

Just don't forget to include my address on the footer of the site for donations, make sure to name me as the cofounder . Lol.
And remember, no offensive words, no sacrilegious words, we wouldn't wanna upset the boss up stairs, so we should skip 4 to 8 percent of addresses.



This message is for @satoshi aka the author of this challenge, "Live long in prosperity under the bluish violet dome".

Now could you create a new challenge with riddles and equations for us to seek and solve please? We're bored honestly and it could light up the mood in crypto-community ushering new methods and never ending possibilities. Though not something that someone could solve them all with one go, maybe make them in episode where each riddle's answer is just a small piece of the greater puzzle. ❤👏💯
member
Activity: 117
Merit: 32
Congratulations to the person who found key #120.
I am impressed and I will be grateful if this person publicly discloses the private key and provides information on how he found the key, or provided this information in a private message if he wants to remain anonymous, and that I complete this information in the table in the main post on his behalf.
the same I am impressed because only those who ignore the difficulty do not express themselves while it remains a feat / an event !!
I just say congratulations to the one who succeeded but it would be nice if he at least gave the key!
you zielar  you said how you succeeded congratulations to you
newbie
Activity: 24
Merit: 4


Only if I knew how to automate this process!

Could you at least share the process, maybe some code somewhere can help you automate it.


+1 I am also interested but I think it's just playing with the ripemd160 hash
full member
Activity: 282
Merit: 114
Congratulations to the person who found key #120.
I am impressed and I will be grateful if this person publicly discloses the private key and provides information on how he found the key, or provided this information in a private message if he wants to remain anonymous, and that I complete this information in the table in the main post on his behalf.
sr. member
Activity: 345
Merit: 250


Only if I knew how to automate this process!

Could you at least share the process, maybe some code somewhere can help you automate it.
newbie
Activity: 24
Merit: 4
Can you share at least two private key from each list to be sure there is a process to begin with? Grin
With the speed which I am progressing, you'd need to wait 40,000 years before I can get a single private key for one of the addresses, and that would be the address for #66, given everybody know exactly where to look.🤣

This is so inspiring! Thank you!  Cheesy
copper member
Activity: 1330
Merit: 899
🖤😏
Can you share at least two private key from each list to be sure there is a process to begin with? Grin
With the speed which I am progressing, you'd need to wait 40,000 years before I can get a single private key for one of the addresses, and that would be the address for #66, given everybody know exactly where to look.🤣
newbie
Activity: 24
Merit: 4
WOW, guys look what I found, seek and you shall find;

Code:
13zb1hQbWVsc2S7ZTZnP2G4undNPCTfqJZ
13zb1hQbWVsc2S7ZTZnP2G4undNP7kEP7M
13zb1hQbWVsc2S7ZTZnP2G4undNNwgQut1
13zb1hQbWVsc2S7ZTZnP2G4undNNvZeouk
13zb1hQbWVsc2S7ZTZnP2G4undNNpdh5so
13zb1hQbWVsc2S7ZTZnP2G4undNNgMUm4n
13zb1hQbWVsc2S7ZTZnP2G4undNNViSuhK
13zb1hQbWVsc2S7ZTZnP2G4undNNTCnWQi
13zb1hQbWVsc2S7ZTZnP2G4undNNMNtEnp
13zb1hQbWVsc2S7ZTZnP2G4undNNEaaHF4
13zb1hQbWVsc2S7ZTZnP2G4undNPNuwE3h
13zb1hQbWVsc2S7ZTZnP2G4undNPQxu217
13zb1hQbWVsc2S7ZTZnP2G4undNPZxBxnH
13zb1hQbWVsc2S7ZTZnP2G4undNPf3VD6N
13zb1hQbWVsc2S7ZTZnP2G4undNPnJ2jFS
13zb1hQbWVsc2S7ZTZnP2G4undNPsJ7T9P
13zb1hQbWVsc2S7ZTZnP2G4undNPygXueW
13zb1hQbWVsc2S7ZTZnP2G4undNQ59XjMk
13zb1hQbWVsc2S7ZTZnP2G4undNQGH2W2c
13zb1hQbWVsc2S7ZTZnP2G4undNQPnwQJw

Code:
 1111111111111111111114oLvT2
11111111111111111111BZbvjr
11111111111111111111HeBAGj
11111111111111111111QekFQw
11111111111111111111UpYBrS
11111111111111111111g4hiWR
11111111111111111111jGyPM8
11111111111111111111o9FmEC
11111111111111111111ufYVpS
1111111111111111111127DiY8B
111111111111111111112BEH2ro
111111111111111111112KWC9yd
111111111111111111112MbYeKK
111111111111111111112WhxnQF
111111111111111111112czxoHN
111111111111111111112kmzDG2
111111111111111111112xT3273
1111111111111111111135LjaTk
111111111111111111113BCNaZA
111111111111111111113MEMrbm
111111111111111111113UauxVS
111111111111111111113Vsgn16
111111111111111111113h6eYvj
111111111111111111113iqSWm1
111111111111111111113twUjvB
111111111111111111114gFexwh
111111111111111111114mA2k9d
111111111111111111114ry6XwB
111111111111111111114ysyUW1
111111111111111111115719xWh
111111111111111111115GZoCZK
111111111111111111115Jk6jSN
111111111111111111115Vdmk4z
111111111111111111115bqgQLs
111111111111111111115hA977A
111111111111111111116WGuH8i
111111111111111111116ayzEtU
111111111111111111116iBpJVP
111111111111111111116p9wW39
111111111111111111116xyhaXw
111111111111111111116zvHYMP
1111111111111111111178p8Uvz
111111111111111111117HhpFr4
111111111111111111117MncoQu
111111111111111111117TDMMQQ
111111111111111111118GEJCAf

Only if I knew how to automate this process!

Can you share at least two private key from each list to be sure there is a process to begin with? Grin
copper member
Activity: 1330
Merit: 899
🖤😏
WOW, guys look what I found, seek and you shall find;

Code:
13zb1hQbWVsc2S7ZTZnP2G4undNPCTfqJZ
13zb1hQbWVsc2S7ZTZnP2G4undNP7kEP7M
13zb1hQbWVsc2S7ZTZnP2G4undNNwgQut1
13zb1hQbWVsc2S7ZTZnP2G4undNNvZeouk
13zb1hQbWVsc2S7ZTZnP2G4undNNpdh5so
13zb1hQbWVsc2S7ZTZnP2G4undNNgMUm4n
13zb1hQbWVsc2S7ZTZnP2G4undNNViSuhK
13zb1hQbWVsc2S7ZTZnP2G4undNNTCnWQi
13zb1hQbWVsc2S7ZTZnP2G4undNNMNtEnp
13zb1hQbWVsc2S7ZTZnP2G4undNNEaaHF4
13zb1hQbWVsc2S7ZTZnP2G4undNPNuwE3h
13zb1hQbWVsc2S7ZTZnP2G4undNPQxu217
13zb1hQbWVsc2S7ZTZnP2G4undNPZxBxnH
13zb1hQbWVsc2S7ZTZnP2G4undNPf3VD6N
13zb1hQbWVsc2S7ZTZnP2G4undNPnJ2jFS
13zb1hQbWVsc2S7ZTZnP2G4undNPsJ7T9P
13zb1hQbWVsc2S7ZTZnP2G4undNPygXueW
13zb1hQbWVsc2S7ZTZnP2G4undNQ59XjMk
13zb1hQbWVsc2S7ZTZnP2G4undNQGH2W2c
13zb1hQbWVsc2S7ZTZnP2G4undNQPnwQJw

Code:
 1111111111111111111114oLvT2
11111111111111111111BZbvjr
11111111111111111111HeBAGj
11111111111111111111QekFQw
11111111111111111111UpYBrS
11111111111111111111g4hiWR
11111111111111111111jGyPM8
11111111111111111111o9FmEC
11111111111111111111ufYVpS
1111111111111111111127DiY8B
111111111111111111112BEH2ro
111111111111111111112KWC9yd
111111111111111111112MbYeKK
111111111111111111112WhxnQF
111111111111111111112czxoHN
111111111111111111112kmzDG2
111111111111111111112xT3273
1111111111111111111135LjaTk
111111111111111111113BCNaZA
111111111111111111113MEMrbm
111111111111111111113UauxVS
111111111111111111113Vsgn16
111111111111111111113h6eYvj
111111111111111111113iqSWm1
111111111111111111113twUjvB
111111111111111111114gFexwh
111111111111111111114mA2k9d
111111111111111111114ry6XwB
111111111111111111114ysyUW1
111111111111111111115719xWh
111111111111111111115GZoCZK
111111111111111111115Jk6jSN
111111111111111111115Vdmk4z
111111111111111111115bqgQLs
111111111111111111115hA977A
111111111111111111116WGuH8i
111111111111111111116ayzEtU
111111111111111111116iBpJVP
111111111111111111116p9wW39
111111111111111111116xyhaXw
111111111111111111116zvHYMP
1111111111111111111178p8Uvz
111111111111111111117HhpFr4
111111111111111111117MncoQu
111111111111111111117TDMMQQ
111111111111111111118GEJCAf

Only if I knew how to automate this process!
jr. member
Activity: 47
Merit: 13
Hello there  Smiley

Congratulations to the solver of the Puzzle #120  Cheesy

I wonder which is the private key.
copper member
Activity: 1330
Merit: 899
🖤😏
Guys I just found the true identity of Satoshi, here take a look: https://en.m.wikipedia.org/wiki/Satoshi_Matsuoka

Go read his published articles from 2007, 2008 and 2009, it's all hinting at bitcoin. Maybe we could use his super computer to solve these puzzles? Lol.
No need to hide any more dear Satoshi, come out come out wherever you are. You never thought creating a challenge to test the strength of your implementation could actually result in a identity revelation did you? Now gimme my prize!🤣
newbie
Activity: 2
Merit: 0
And finaly the #115 was found. Congratulations Zielar and Jean_Luc_Pons  Smiley We are all wondering which was the privkey  Wink

Many thanks!
A valid private key that is solution #115 has already been placed in the main post table.
full member
Activity: 297
Merit: 133
I am adding my work:

Code:
+------------+-----------------+-----------------+-------------------+
| orig hex   | orig dec        | difference      | difference in hex |
+------------+-----------------+-----------------+-------------------+
| 1          | 1               |                 |                   |
+------------+-----------------+-----------------+-------------------+
| 3          | 3               | 2               | 2                 |
+------------+-----------------+-----------------+-------------------+
| 7          | 7               | 4               | 4                 |
+------------+-----------------+-----------------+-------------------+
| 8          | 8               | 1               | 1                 |
+------------+-----------------+-----------------+-------------------+
| 15         | 21              | 13              | D                 |
+------------+-----------------+-----------------+-------------------+
| 31         | 49              | 28              | 1C                |
+------------+-----------------+-----------------+-------------------+
| 4C         | 76              | 27              | 1B                |
+------------+-----------------+-----------------+-------------------+
| E0         | 224             | 148             | 94                |
+------------+-----------------+-----------------+-------------------+
| 1D3        | 467             | 243             | F3                |
+------------+-----------------+-----------------+-------------------+
| 202        | 514             | 47              | 2F                |
+------------+-----------------+-----------------+-------------------+
| 483        | 1 155           | 641             | 281               |
+------------+-----------------+-----------------+-------------------+
| A7B        | 2 683           | 1 528           | 5F8               |
+------------+-----------------+-----------------+-------------------+
| 1460       | 5 216           | 2 533           | 9E5               |
+------------+-----------------+-----------------+-------------------+
| 2930       | 10 544          | 5 328           | 14D0              |
+------------+-----------------+-----------------+-------------------+
| 68F3       | 26 867          | 16 323          | 3FC3              |
+------------+-----------------+-----------------+-------------------+
| C936       | 51 510          | 24 643          | 6043              |
+------------+-----------------+-----------------+-------------------+
| 1764F      | 95 823          | 44 313          | AD19              |
+------------+-----------------+-----------------+-------------------+
| 3080D      | 198 669         | 102 846         | 191BE             |
+------------+-----------------+-----------------+-------------------+
| 5749F      | 357 535         | 158 866         | 26C92             |
+------------+-----------------+-----------------+-------------------+
| D2C55      | 863 317         | 505 782         | 7B7B6             |
+------------+-----------------+-----------------+-------------------+
| 1BA534     | 1 811 764       | 948 447         | E78DF             |
+------------+-----------------+-----------------+-------------------+
| 2DE40F     | 3 007 503       | 1 195 739       | 123EDB            |
+------------+-----------------+-----------------+-------------------+
| 556E52     | 5 598 802       | 2 591 299       | 278A43            |
+------------+-----------------+-----------------+-------------------+
| DC2A04     | 14 428 676      | 8 829 874       | 86BBB2            |
+------------+-----------------+-----------------+-------------------+
| 1FA5EE5    | 33 185 509      | 18 756 833      | 11E34E1           |
+------------+-----------------+-----------------+-------------------+
| 340326E    | 54 538 862      | 21 353 353      | 145D389           |
+------------+-----------------+-----------------+-------------------+
| 6AC3875    | 111 949 941     | 57 411 079      | 36C0607           |
+------------+-----------------+-----------------+-------------------+
| D916CE8    | 227 634 408     | 115 684 467     | 6E53473           |
+------------+-----------------+-----------------+-------------------+
| 17E2551E   | 400 708 894     | 173 074 486     | A50E836           |
+------------+-----------------+-----------------+-------------------+
| 3D94CD64   | 1 033 162 084   | 632 453 190     | 25B27846          |
+------------+-----------------+-----------------+-------------------+
| 7D4FE747   | 2 102 388 551   | 1 069 226 467   | 3FBB19E3          |
+------------+-----------------+-----------------+-------------------+
| B862A62E   | 3 093 472 814   | 991 084 263     | 3B12BEE7          |
+------------+-----------------+-----------------+-------------------+
| 1A96CA8D8  | 7 137 437 912   | 4 043 965 098   | F10A02AA          |
+------------+-----------------+-----------------+-------------------+
| 34A65911D  | 14 133 072 157  | 6 995 634 245   | 1A0F8E845         |
+------------+-----------------+-----------------+-------------------+
| 4AED21170  | 20 112 871 792  | 5 979 799 635   | 1646C8053         |
+------------+-----------------+-----------------+-------------------+
| 9DE820A7C  | 42 387 769 980  | 22 274 898 188  | 52FAFF90C         |
+------------+-----------------+-----------------+-------------------+
| 1757756A93 | 100 251 560 595 | 57 863 790 615  | D78F36017         |
+------------+-----------------+-----------------+-------------------+
| 22382FACD0 | 146 971 536 592 | 46 719 975 997  | AE0BA423D         |
+------------+-----------------+-----------------+-------------------+
| 4B5F8303E9 | 323 724 968 937 | 176 753 432 345 | 2927535719        |
+------------+-----------------+-----------------+-------------------+

No more because Excel does not accept larger numbers.

Maybe someone will find the above table useful.

EDIT below:

I also had division of each next number by the previous one, but see no sense to add it to this table.

I suspect that this puzzle can be solved by something related to HD wallet with proper seed (words as first as possible from the english set for seeds) or binary data (some simple, as hex 0x00...0001) as master private key.
copper member
Activity: 1330
Merit: 899
🖤😏
Has anyone made a tool to correctly calculate the estimated time based on GPU computing power per puzzle? I could tell without any calculations that we are just scratching the surface using our systems, meaning it's not worth the time and effort, unless there was more bitcoins. Lol.

Easy way to calculate:

Take your speed in MKey/s. Divide range total by your MKey/s.

So if you have 30 MKey/s:

#66 has 36,893,488,147,419,103,232 total keys to check

36,893,488,147,419,103,232 / 30,000,000 (your total speed) = 1,229,782,938,247 seconds = 20,496,382,304 minutes = 341,606,371 hours = 14,233,598 days = 38,996 years to check all keys in #66 range.


And this is my cue to quit, lol. One could say, hope is a powerful motivation. That one is currently myself.
full member
Activity: 1162
Merit: 237
Shooters Shoot...
Has anyone made a tool to correctly calculate the estimated time based on GPU computing power per puzzle? I could tell without any calculations that we are just scratching the surface using our systems, meaning it's not worth the time and effort, unless there was more bitcoins. Lol.

Easy way to calculate:

Take your speed in MKey/s. Divide range total by your MKey/s.

So if you have 30 MKey/s:

#66 has 36,893,488,147,419,103,232 total keys to check

36,893,488,147,419,103,232 / 30,000,000 (your total speed) = 1,229,782,938,247 seconds = 20,496,382,304 minutes = 341,606,371 hours = 14,233,598 days = 38,996 years to check all keys in #66 range.

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