This may be wrong, but for my situation where there is a 12 character random sequence password (that I have wrote down) where any 2 characters could be missing, there aren't as many outcomes as I thought there would be I'm getting 66 outcomes. Although long winded it may be worth me trying to enter those manually. I'm not sure what that number goes up to if there are 3 though.
It is possible that I've made an error in the math, but I'm pretty sure there are:
1 possibility if no characters are missing.
12 possibilities if 1 character is missing.
66 possibilities if 2 characters are missing.
220 possibilities if 3 characters are missing.
Therefore, if you don't know if it's 0, 1, 2, or 3 characters that are missing, then there are a total of 299 possibilities to try?