Topic: Flat Earth - page 763. (Read 1095196 times)

PSo, it's all density, eh?

Here's a question for you then, and I'll even play by your rules:  In simulated anti-gravitational environments, such as when an airplane dips at a given speed and angle such that everything is floating around (actually, they're just in free-fall) in an air-filled chamber -- you know, just like the videos you almost surely believe NASA creates to fool us into believing that astronauts are in outer space -- how do you explain that everything in the plane is *floating*?  In other words, if both the air and all objects in the air-filled chamber are descending at the same speed relative to each other, why doesn't density separate the more-dense objects (like people) from the air in the chamber?

The problem for you is that hydrostatic pressure decreases in weightless (NOT sparce)  environments.  If it didn't, then in the descending airplane that causes all things inside it to free-fall, all of the objects that are more dense than the air would fall to the floor of the plane, even in free-fall conditions.

1) Mass + gravity --> weight --> hydrostatic pressure --> balloons rise, apples fall
2).Mass + no gravity --> weightlessness --> no hydrostatic pressure --> balloons and apples behave similarly
3) Density = mass/volume.  That's it.  Density is dependent upon mass, but is independent of weight which is integral to hydrostatic pressure.  We can see this from free-fall airplanes in which all objects are weightless in their environment; it doesn't matter how much mass or density the objects have, they all have no weight.  This gives us two scenarios to consider -- we see how objects behave in weightless environments (such as free-fall planes), and also in weighted environments (such as on Earth's surface).  Does density explain both scenarios? No. What does? Gravity.

By the way, the formula for weight is w=mg where m=mass and g=Freefall acceleration of gravity.  In a freefall airplane, g=0, so w=0.

It will stop rising when the density of the atmosphere reaches that of the helium in the balloon. We haven't even reached this mythical vacuum space you talk about before it stops that is if it hasn't already popped which is unlikely. Then you invoke the magical force of gravity but why? This unpoppable balloon has stopped rising due to the atmosphere it's displaced being the same density as the helium. Then you go on to mention the fantasy of interstellar space; this isn't even relevant. As for the apple it falls because it's denser than air and again you invoke the magical force of gravity for no reason.

You accuse me of intellectual dishonesty yet your statements here show that you're an outright intellectual fraud.

Balloons rise in the atmosphere due to hydrostatic pressure (i.e. lighter fluids rise when immersed in heavier ones), but a balloon in space doesn't rise.  Balloons released on Earth won't reach outer space because the force of lift will eventually reach equilibrium with the force of gravity.  Hydrostatic pressure applies to fluids, but the density of interstellar gasses is so low in space that they behave like individual particles (which is why balloons won't rise in space).  Apples are too dense and heavy to gain lift from hydrostatic pressure.  So, apples fall when dropped because of gravity, and because they aren't buoyant in the atmosphere like balloons are.  Balloons are subject to gravity, too, but this doesn't become as obvious until balloons reach an altitude at which the atmosphere is so thin that the lift generated from hydrostatic pressure is overcome by the force of gravity.  In a vacuum affected by a gravitational field, a helium balloon would actually fall; this is because gravity still affects it, but hydrostatic pressure doesn't.

I'll answer your question but first you have to explain why a helium balloon rises up into the sky when you let go of the string? Then you have to explain why the apple has to play by a different set of rules?