so...you're saying there's a chance?
That is a very simplified calculation, that doesn't take into consideration a lot of factors. The probability of what is happening is very very low.
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n= 50000
cutoff = 50
bets = sign(rand(n,2000)-.505);
outcomes = sum(bets,2);
sum(outcomes>cutoff)/n
sum(outcomes
intBets = cumsum(bets,2);
peak = max(intBets,[],2);
sum(peak>cutoff)/n
sum(peak
%%
figure(1);clf;set(gcf,'paperposition',[0 0 8 6])
hist(outcomes,50)
hold on
plot([cutoff cutoff],[0 5000],'r-')
ylabel('Number of outcomes')
xlabel('Profit (number of max bets above zero)')
title('Results of 2000 consecutive max bets, unlimited bankroll, (50,000 simulations)')
text(55,4000,['Chance of exeeding = ' num2str(sum(outcomes>cutoff)/n)])
print(gcf,'-depsc', 'MaxBets1')
figure(2);clf;set(gcf,'paperposition',[0 0 8 6])
hist(peak,50)
hold on
plot([cutoff cutoff],[0 6000],'r-')
ylabel('Number of outcomes')
xlabel('Peak profit (number of max bets above zero)')
title('Results of 2000 consecutive max bets, unlimited bankroll, (50,000 simulations)')
set(gca,'xlim',[0 max(peak)])
text(55,5000,['Chance of exeeding = ' num2str(sum(peak>cutoff)/n)])
print(gcf,'-depsc', 'MaxBets2')