@Counselor
Well, you have to know the range, were you assume the privatekey. So how do you determine that range?
How do you know to search in D1745D1745D1745D1745D1745D1745D06A31FA8E3252B1A53FDAAA73xxxxxxxxxxxxxxxx?
If we use 33 as divisor, than to determine beginning of each range you have to multiply numbers (1 .. 33) to inverse(33, secp256k1.p)
therefore you will get 33 possible ranges beginnings:
1 6c9b26c9b26c9b26c9b26c9b26c9b26c9b26c9b26c9b26c9b26c9b265d174433
2 d9364d9364d9364d9364d9364d9364d9364d9364d9364d9364d9364cba2e8866
3 45d1745d1745d1745d1745d1745d1745d1745d1745d1745d1745d1741745d06a
4 b26c9b26c9b26c9b26c9b26c9b26c9b26c9b26c9b26c9b26c9b26c9a745d149d
5 1f07c1f07c1f07c1f07c1f07c1f07c1f07c1f07c1f07c1f07c1f07c1d1745ca1
6 8ba2e8ba2e8ba2e8ba2e8ba2e8ba2e8ba2e8ba2e8ba2e8ba2e8ba2e82e8ba0d4
7 f83e0f83e0f83e0f83e0f83e0f83e0f83e0f83e0f83e0f83e0f83e0e8ba2e507
8 64d9364d9364d9364d9364d9364d9364d9364d9364d9364d9364d935e8ba2d0b
9 d1745d1745d1745d1745d1745d1745d1745d1745d1745d1745d1745c45d1713e
10 3e0f83e0f83e0f83e0f83e0f83e0f83e0f83e0f83e0f83e0f83e0f83a2e8b942
11 aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa9fffffd75
12 1745d1745d1745d1745d1745d1745d1745d1745d1745d1745d1745d15d174579
13 83e0f83e0f83e0f83e0f83e0f83e0f83e0f83e0f83e0f83e0f83e0f7ba2e89ac
14 f07c1f07c1f07c1f07c1f07c1f07c1f07c1f07c1f07c1f07c1f07c1e1745cddf
15 5d1745d1745d1745d1745d1745d1745d1745d1745d1745d1745d1745745d15e3
16 c9b26c9b26c9b26c9b26c9b26c9b26c9b26c9b26c9b26c9b26c9b26bd1745a16
17 364d9364d9364d9364d9364d9364d9364d9364d9364d9364d9364d932e8ba21a
18 a2e8ba2e8ba2e8ba2e8ba2e8ba2e8ba2e8ba2e8ba2e8ba2e8ba2e8b98ba2e64d
19 f83e0f83e0f83e0f83e0f83e0f83e0f83e0f83e0f83e0f83e0f83e0e8ba2e51
20 7c1f07c1f07c1f07c1f07c1f07c1f07c1f07c1f07c1f07c1f07c1f0745d17284
21 e8ba2e8ba2e8ba2e8ba2e8ba2e8ba2e8ba2e8ba2e8ba2e8ba2e8ba2da2e8b6b7
22 55555555555555555555555555555555555555555555555555555554fffffebb
23 c1f07c1f07c1f07c1f07c1f07c1f07c1f07c1f07c1f07c1f07c1f07b5d1742ee
24 2e8ba2e8ba2e8ba2e8ba2e8ba2e8ba2e8ba2e8ba2e8ba2e8ba2e8ba2ba2e8af2
25 9b26c9b26c9b26c9b26c9b26c9b26c9b26c9b26c9b26c9b26c9b26c91745cf25
26 7c1f07c1f07c1f07c1f07c1f07c1f07c1f07c1f07c1f07c1f07c1f0745d1729
27 745d1745d1745d1745d1745d1745d1745d1745d1745d1745d1745d16d1745b5c
28 e0f83e0f83e0f83e0f83e0f83e0f83e0f83e0f83e0f83e0f83e0f83d2e8b9f8f
29 4d9364d9364d9364d9364d9364d9364d9364d9364d9364d9364d93648ba2e793
30 ba2e8ba2e8ba2e8ba2e8ba2e8ba2e8ba2e8ba2e8ba2e8ba2e8ba2e8ae8ba2bc6
31 26c9b26c9b26c9b26c9b26c9b26c9b26c9b26c9b26c9b26c9b26c9b245d173ca
32 9364d9364d9364d9364d9364d9364d9364d9364d9364d9364d9364d8a2e8b7fd
33 1
Size of the resulting ranges will be 33 times smaller than original, so you can calculate end of each range.
In our case WP searched this range:
3 45d1745d1745d1745d1745d1745d1745d1745d1745d1745d1745d1741745d06a
To be honest, I don't know how and what exactly WP calculates, but that is main idea of such key reduction.