Guys, if brainless really succeeded in reducing the number of keys, then you would listen carefully, turn on your brain, think, try and analyze. And I see that Brainless is giving advice, and others already being shit on here for 2 pages, as if all of you have a script to reduce by 10 bits with one key.
Brainless gives interesting math from a side that many haven't even thought about. So less showing off and more focus to understand the algorithm itself. I don't think Brainless will give it in a ready-made form. Thank you for at least giving hints. Enjoy.
Topic: Pollard's kangaroo ECDLP solver - page 31. (Read 59389 times)
30240 came from astro
360 days in year
7 day in week
12 month in year
360 x 7 x 12 = 30240
Full ver
2520
360 x 7 = 2520
For complete numerology 30240 will work
2520 will make u stuck in some part of calc
360 days in year
7 day in week
12 month in year
360 x 7 x 12 = 30240
Full ver
2520
360 x 7 = 2520
For complete numerology 30240 will work
2520 will make u stuck in some part of calc
2 447 7572 564114
3 596 9536 752152
4 631 10096 1128228
6 894 14304 1504304
8 1192 15144 2256456
12 1262 20192 3008608
16 1788 28608 4512912
24 1893 30288 6017216
32 2384 40384 9025824
48 2524 60576 18051648
64 3576 94019
96 3786 121152
149 4768 188038
192 5048 282057
298 7152 376076
30288 what other guys call 30240 as i call this shit a 30288
WTF ?
dude you are going against your magic numbers , somebody please hand over me tomato ketchup i will assume it soda and drink it today
where the hell i left my .75 btc? sorry i forgot
so talk about idea guys
here is idea , brainless make a fire here and instead of drinking soda i throw all my soda to extinguish this shit but all in vein ~ now when i am out from all soda cans . my mind start working again and got a idea
why the hell i should not ask brainless to share a script which he is using to reduce the shit out of keys.
brainless : could you please be so kind and share your genius script so i can see what u did in this summer.
as i cant see a working logic here and i have to sale that script to a.a to buy a soda cans
here is idea , brainless make a fire here and instead of drinking soda i throw all my soda to extinguish this shit but all in vein ~ now when i am out from all soda cans . my mind start working again and got a idea
why the hell i should not ask brainless to share a script which he is using to reduce the shit out of keys.
brainless : could you please be so kind and share your genius script so i can see what u did in this summer.
as i cant see a working logic here and i have to sale that script to a.a to buy a soda cans
~
I don't want to upset you, but there are 365 days in a yearWhat a dumpster fire the last few pages of this thread have been.
30240 came from astro
360 days in year
7 day in week
12 month in year
360 x 7 x 12 = 30240
Full ver
2520
360 x 7 = 2520
For complete numerology 30240 will work
2520 will make u stuck in some part of calc
360 days in year
7 day in week
12 month in year
360 x 7 x 12 = 30240
Full ver
2520
360 x 7 = 2520
For complete numerology 30240 will work
2520 will make u stuck in some part of calc
I don't want to upset you, but there are 365 days in a year
30240 came from astro
360 days in year
7 day in week
12 month in year
360 x 7 x 12 = 30240
Full ver
2520
360 x 7 = 2520
For complete numerology 30240 will work
2520 will make u stuck in some part of calc
360 days in year
7 day in week
12 month in year
360 x 7 x 12 = 30240
Full ver
2520
360 x 7 = 2520
For complete numerology 30240 will work
2520 will make u stuck in some part of calc
come to papa
brainless.... are you kidding me? Come with some reasonable arguments and not with conjectures.
2520 will get you stuck, but 30240 will work. Old Babylonian Astronomers knew this.
Source(s): Dude trust me
2520 will get you stuck, but 30240 will work. Old Babylonian Astronomers knew this.
Source(s): Dude trust me
30240 came from astro
360 days in year
7 day in week
12 month in year
360 x 7 x 12 = 30240
Full ver
2520
360 x 7 = 2520
For complete numerology 30240 will work
2520 will make u stuck in some part of calc
360 days in year
7 day in week
12 month in year
360 x 7 x 12 = 30240
Full ver
2520
360 x 7 = 2520
For complete numerology 30240 will work
2520 will make u stuck in some part of calc
So no new knowledge 
@WP
I take a 255 bit pubkey, divide it by 33. Now I only have to search the 2^255/33 ~ 2^252 range to find the key. What a reduction.
@ssxb
Well but what is the new knowledge?
I take a 255 bit pubkey, divide it by 33. Now I only have to search the 2^255/33 ~ 2^252 range to find the key. What a reduction.
@ssxb
Well but what is the new knowledge?
Well but what is the new knowledge?
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8
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hope you get the point ~
congratulation to me today i learnt how to generate numbers in series from 1 to 32 with python. such a genius (wile-e-coyote)
now i am telling you guys dont follow me you can hardly program this. (My brainless theory)
watching wile e coyote vs bugs bunny
@WP
I take a 255 bit pubkey, divide it by 33. Now I only have to search the 2^255/33 ~ 2^252 range to find the key. What a reduction.
@ssxb
Well but what is the new knowledge?
I take a 255 bit pubkey, divide it by 33. Now I only have to search the 2^255/33 ~ 2^252 range to find the key. What a reduction.
@ssxb
Well but what is the new knowledge?
i am drinking soda right now and watching screen (no red wine as i am Muslim 
) 32 keys are in front of me telling me that we are relative to each other and no matter from where you will jump toward us we will be always on distance of 1 with each other. if you knows the private keys you will find these keys are lying but hell yaa man when you work blindly on public keys without knowing private keys you will know they are having relation on curve and on 1 key distance from each other. fck math is beautiful . curse you elliptic curve sorry glass slipped from my hand i need to clean the table 
) 32 keys are in front of me telling me that we are relative to each other and no matter from where you will jump toward us we will be always on distance of 1 with each other. if you knows the private keys you will find these keys are lying but hell yaa man when you work blindly on public keys without knowing private keys you will know they are having relation on curve and on 1 key distance from each other. fck math is beautiful . curse you elliptic curve sorry glass slipped from my hand i need to clean the table Giving you all one more tip , in total numerology, only 30240 is is dividable from 1 to 10, mean 5 even 5 odd, at same time, and no floating result
I don't know what you mean by "numerology", but 30240 is not the only such number (some people already told about it)if you multuply 30240 to any numbers, and result could also div by 1 to 10, and in result no floating point
If you multiply any X by any Y, that resulting number will be divisible without remainder by all factors of Y (and X). There is no secrets. That is basics. Fundamental theorem of arithmetic.I saw that you posted before I could post. I had already invested about 20 minutes for the post and was like: "Well, it is already said, but not from everyone" and so I posted it anyway.
Also the 33 division makes sense as the distance between each point will be the mod inverse of 33 or so. Its like cutting the whole N into ranges, as mentioned before. Only problem is, that you are only getting one in the lower bruteforcable range and then can jump from that one and can determine the other 32 private keys.
And yes, you just have to multiply the privatekey times your divisor and then mod N to get the right result.
Also the 33 division makes sense as the distance between each point will be the mod inverse of 33 or so. Its like cutting the whole N into ranges, as mentioned before. Only problem is, that you are only getting one in the lower bruteforcable range and then can jump from that one and can determine the other 32 private keys.
And yes, you just have to multiply the privatekey times your divisor and then mod N to get the right result.
that what i said before
What about 2520?
2520 = 2³ * 3² * 5 * 7
2520 / 10 = 252
2520 / 9 = 280
2520 / 8 = 315
2520 / 7 = 360
2520 / 6 = 420
2520 / 5 = 504
2520 / 4 = 630
2520 / 3 = 830
2520 / 2 = 1260
2520 / 1 = 2520
Only difference is, that dividing by 8 will get you a odd number. If you want that it is even when dividing by 8, then just double 2520. So 5040 is much smaller than 30240. So why is according to you only 30240 dividable from 1 to 10? If it is even relevant as 30240 is not a divisor of N-1.
References:
https://en.wikipedia.org/wiki/Highly_composite_number
https://mrob.com/pub/math/numbers-14.html#lc5040
Yeah I already asked about 2520; I did not see where he stated it had to be even or odd, just no float. It could be beneficial, I will have to run more tests tomorrow. But as of now, I can find any key in any range with any divisor. So I did learn something from all of this discussion. Example, if you took a 40 bit public key and divided it by 33, I could find every public key that is generated and ultimately each pub key found in any/every range will lead me back to private key of original pub key, with a click of a button.2520 = 2³ * 3² * 5 * 7
2520 / 10 = 252
2520 / 9 = 280
2520 / 8 = 315
2520 / 7 = 360
2520 / 6 = 420
2520 / 5 = 504
2520 / 4 = 630
2520 / 3 = 830
2520 / 2 = 1260
2520 / 1 = 2520
Only difference is, that dividing by 8 will get you a odd number. If you want that it is even when dividing by 8, then just double 2520. So 5040 is much smaller than 30240. So why is according to you only 30240 dividable from 1 to 10? If it is even relevant as 30240 is not a divisor of N-1.
References:
https://en.wikipedia.org/wiki/Highly_composite_number
https://mrob.com/pub/math/numbers-14.html#lc5040
I ran several tests with divisor of 33 and a few with a divisor of 192. Find one pubkey in any range and you have the private key of original pub key.
Find one pubkey in any range and you have the private key of original pub key
that what i said before
I saw that you posted before I could post. I had already invested about 20 minutes for the post and was like: "Well, it is already said, but not from everyone" and so I posted it anyway.
Also the 33 division makes sense as the distance between each point will be the mod inverse of 33 or so. Its like cutting the whole N into ranges, as mentioned before. Only problem is, that you are only getting one in the lower bruteforcable range and then can jump from that one and can determine the other 32 private keys.
And yes, you just have to multiply the privatekey times your divisor and then mod N to get the right result.
Also the 33 division makes sense as the distance between each point will be the mod inverse of 33 or so. Its like cutting the whole N into ranges, as mentioned before. Only problem is, that you are only getting one in the lower bruteforcable range and then can jump from that one and can determine the other 32 private keys.
And yes, you just have to multiply the privatekey times your divisor and then mod N to get the right result.
What about 2520?
2520 = 2³ * 3² * 5 * 7
2520 / 10 = 252
2520 / 9 = 280
2520 / 8 = 315
2520 / 7 = 360
2520 / 6 = 420
2520 / 5 = 504
2520 / 4 = 630
2520 / 3 = 830
2520 / 2 = 1260
2520 / 1 = 2520
Only difference is, that dividing by 8 will get you a odd number. If you want that it is even when dividing by 8, then just double 2520. So 5040 is much smaller than 30240. So why is according to you only 30240 dividable from 1 to 10? If it is even relevant as 30240 is not a divisor of N-1.
References:
https://en.wikipedia.org/wiki/Highly_composite_number
https://mrob.com/pub/math/numbers-14.html#lc5040
Yeah I already asked about 2520; I did not see where he stated it had to be even or odd, just no float. It could be beneficial, I will have to run more tests tomorrow. But as of now, I can find any key in any range with any divisor. So I did learn something from all of this discussion. Example, if you took a 40 bit public key and divided it by 33, I could find every public key that is generated and ultimately each pub key found in any/every range will lead me back to private key of original pub key, with a click of a button.2520 = 2³ * 3² * 5 * 7
2520 / 10 = 252
2520 / 9 = 280
2520 / 8 = 315
2520 / 7 = 360
2520 / 6 = 420
2520 / 5 = 504
2520 / 4 = 630
2520 / 3 = 830
2520 / 2 = 1260
2520 / 1 = 2520
Only difference is, that dividing by 8 will get you a odd number. If you want that it is even when dividing by 8, then just double 2520. So 5040 is much smaller than 30240. So why is according to you only 30240 dividable from 1 to 10? If it is even relevant as 30240 is not a divisor of N-1.
References:
https://en.wikipedia.org/wiki/Highly_composite_number
https://mrob.com/pub/math/numbers-14.html#lc5040
I ran several tests with divisor of 33 and a few with a divisor of 192. Find one pubkey in any range and you have the private key of original pub key.
What about 2520?
2520 = 2³ * 3² * 5 * 7
2520 / 10 = 252
2520 / 9 = 280
2520 / 8 = 315
2520 / 7 = 360
2520 / 6 = 420
2520 / 5 = 504
2520 / 4 = 630
2520 / 3 = 830
2520 / 2 = 1260
2520 / 1 = 2520
Only difference is, that dividing by 8 will get you a odd number. If you want that it is even when dividing by 8, then just double 2520. So 5040 is much smaller than 30240. So why is according to you only 30240 dividable from 1 to 10? If it is even relevant as 30240 is not a divisor of N-1.
References:
https://en.wikipedia.org/wiki/Highly_composite_number
https://mrob.com/pub/math/numbers-14.html#lc5040
2520 = 2³ * 3² * 5 * 7
2520 / 10 = 252
2520 / 9 = 280
2520 / 8 = 315
2520 / 7 = 360
2520 / 6 = 420
2520 / 5 = 504
2520 / 4 = 630
2520 / 3 = 830
2520 / 2 = 1260
2520 / 1 = 2520
Only difference is, that dividing by 8 will get you a odd number. If you want that it is even when dividing by 8, then just double 2520. So 5040 is much smaller than 30240. So why is according to you only 30240 dividable from 1 to 10? If it is even relevant as 30240 is not a divisor of N-1.
References:
https://en.wikipedia.org/wiki/Highly_composite_number
https://mrob.com/pub/math/numbers-14.html#lc5040
Giving you all one more tip , in total numerology, only 30240 is is dividable from 1 to 10, mean 5 even 5 odd, at same time, and no floating result
i gurantee, you never see 30240 secrets
30240.0000 10.0000 3024.0000
30240.0000 9.0000 3360.0000
30240.0000 8.0000 3780.0000
30240.0000 7.0000 4320.0000
30240.0000 6.0000 5040.0000
30240.0000 5.0000 6048.0000
30240.0000 4.0000 7560.0000
30240.0000 3.0000 10080.0000
30240.0000 2.0000 15120.0000
30240.0000 1.0000 30240.0000
if you multuply 30240 to any numbers, and result could also div by 1 to 10, and in result no floating point
30240 * 777 = 23496480.0000
23496480.0000 10.0000 2349648.0000
23496480.0000 9.0000 2610720.0000
23496480.0000 8.0000 2937060.0000
23496480.0000 7.0000 3356640.0000
23496480.0000 6.0000 3916080.0000
23496480.0000 5.0000 4699296.0000
23496480.0000 4.0000 5874120.0000
23496480.0000 3.0000 7832160.0000
23496480.0000 2.0000 11748240.0000
23496480.0000 1.0000 23496480.0000
hope like in my preivios post for magic numbers, you could not understand, same hope you will not understand secrets behind this only 1 magic numberology
Maybe I am misunderstanding you and what you mean, but any multiple of 2520 would have the same result... i gurantee, you never see 30240 secrets
30240.0000 10.0000 3024.0000
30240.0000 9.0000 3360.0000
30240.0000 8.0000 3780.0000
30240.0000 7.0000 4320.0000
30240.0000 6.0000 5040.0000
30240.0000 5.0000 6048.0000
30240.0000 4.0000 7560.0000
30240.0000 3.0000 10080.0000
30240.0000 2.0000 15120.0000
30240.0000 1.0000 30240.0000
if you multuply 30240 to any numbers, and result could also div by 1 to 10, and in result no floating point
30240 * 777 = 23496480.0000
23496480.0000 10.0000 2349648.0000
23496480.0000 9.0000 2610720.0000
23496480.0000 8.0000 2937060.0000
23496480.0000 7.0000 3356640.0000
23496480.0000 6.0000 3916080.0000
23496480.0000 5.0000 4699296.0000
23496480.0000 4.0000 5874120.0000
23496480.0000 3.0000 7832160.0000
23496480.0000 2.0000 11748240.0000
23496480.0000 1.0000 23496480.0000
hope like in my preivios post for magic numbers, you could not understand, same hope you will not understand secrets behind this only 1 magic numberology
Giving you all one more tip , in total numerology, only 30240 is is dividable from 1 to 10, mean 5 even 5 odd, at same time, and no floating result
i gurantee, you never see 30240 secrets
30240.0000 10.0000 3024.0000
30240.0000 9.0000 3360.0000
30240.0000 8.0000 3780.0000
30240.0000 7.0000 4320.0000
30240.0000 6.0000 5040.0000
30240.0000 5.0000 6048.0000
30240.0000 4.0000 7560.0000
30240.0000 3.0000 10080.0000
30240.0000 2.0000 15120.0000
30240.0000 1.0000 30240.0000
if you multuply 30240 to any numbers, and result could also div by 1 to 10, and in result no floating point
30240 * 777 = 23496480.0000
23496480.0000 10.0000 2349648.0000
23496480.0000 9.0000 2610720.0000
23496480.0000 8.0000 2937060.0000
23496480.0000 7.0000 3356640.0000
23496480.0000 6.0000 3916080.0000
23496480.0000 5.0000 4699296.0000
23496480.0000 4.0000 5874120.0000
23496480.0000 3.0000 7832160.0000
23496480.0000 2.0000 11748240.0000
23496480.0000 1.0000 23496480.0000
hope like in my preivios post for magic numbers, you could not understand, same hope you will not understand secrets behind this only 1 magic numberology
i gurantee, you never see 30240 secrets
30240.0000 10.0000 3024.0000
30240.0000 9.0000 3360.0000
30240.0000 8.0000 3780.0000
30240.0000 7.0000 4320.0000
30240.0000 6.0000 5040.0000
30240.0000 5.0000 6048.0000
30240.0000 4.0000 7560.0000
30240.0000 3.0000 10080.0000
30240.0000 2.0000 15120.0000
30240.0000 1.0000 30240.0000
if you multuply 30240 to any numbers, and result could also div by 1 to 10, and in result no floating point
30240 * 777 = 23496480.0000
23496480.0000 10.0000 2349648.0000
23496480.0000 9.0000 2610720.0000
23496480.0000 8.0000 2937060.0000
23496480.0000 7.0000 3356640.0000
23496480.0000 6.0000 3916080.0000
23496480.0000 5.0000 4699296.0000
23496480.0000 4.0000 5874120.0000
23496480.0000 3.0000 7832160.0000
23496480.0000 2.0000 11748240.0000
23496480.0000 1.0000 23496480.0000
hope like in my preivios post for magic numbers, you could not understand, same hope you will not understand secrets behind this only 1 magic numberology
Thanks for the number hint.
I hope to figure it out and solve this problem.
In the previous post, I thought the other way, that we need to find such a divisor and such a multiplier that would get the same division residuals. For example, below are the results of division and multiplication using these and other numbers:
Code:
2281607788513008375014137388606100914
2281607788513008375014137388605979764
2281607788513008375014137388605858614
2281607788513008375014137388605737464
2281607788513008375014137388605616314
2281607788513008375014137388605495164
2281607788513008375014137388605374014
2281607788513008375014137388605252864
2281607788513008375014137388605131714
2281607788513008375014137388605010564
2281607788513008375014137388604889414
2281607788513008375014137388604768264
2281607788513008375014137388604647114
2281607788513008375014137388604525964
2281607788513008375014137388604404814
don't look at the specific values of the numbers, this is for an example. All that matters is that they end in one digit and the second digit alternates. 2281607788513008375014137388605979764
2281607788513008375014137388605858614
2281607788513008375014137388605737464
2281607788513008375014137388605616314
2281607788513008375014137388605495164
2281607788513008375014137388605374014
2281607788513008375014137388605252864
2281607788513008375014137388605131714
2281607788513008375014137388605010564
2281607788513008375014137388604889414
2281607788513008375014137388604768264
2281607788513008375014137388604647114
2281607788513008375014137388604525964
2281607788513008375014137388604404814
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