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Topic: Pollard's kangaroo ECDLP solver - page 30. (Read 58537 times)

jr. member
Activity: 48
Merit: 11
September 29, 2021, 03:57:08 AM
Guys, if brainless really succeeded in reducing the number of keys, then you would listen carefully, turn on your brain, think, try and analyze. And I see that Brainless is giving advice, and others already being shit on here for 2 pages, as if all of you have a script to reduce by 10 bits with one key.
Brainless gives interesting math from a side that many haven't even thought about. So less showing off and more focus to understand the algorithm itself. I don't think Brainless will give it in a ready-made form. Thank you for at least giving hints. Enjoy.
jr. member
Activity: 81
Merit: 2
September 29, 2021, 03:09:46 AM
30240 came from astro
360 days in year
7 day in week
12 month in year
360 x 7 x 12 = 30240
Full ver
2520
360 x 7 = 2520
For complete numerology 30240 will work
2520 will make u stuck in some part of calc


2   447   7572   564114
3   596   9536   752152
4   631   10096   1128228
6   894   14304   1504304
8   1192   15144   2256456
12   1262   20192   3008608
16   1788   28608   4512912
24   1893   30288   6017216
32   2384   40384   9025824
48   2524   60576   18051648
64   3576   94019  
96   3786   121152  
149   4768   188038  
192   5048   282057  
298   7152   376076  

30288 what other guys call 30240 as i call this shit a 30288

WTF ?  Huh

dude you are going against your magic numbers , somebody please hand over me tomato ketchup i will assume it soda and drink it today

 where the hell i left my .75 btc? sorry i forgot  Grin
jr. member
Activity: 81
Merit: 2
September 29, 2021, 02:52:57 AM
so talk about idea guys

here is idea , brainless make a fire here and instead of drinking soda i throw all my soda to extinguish this shit but all in vein ~ now when i am out from all soda cans . my mind start working again and got a idea
why the hell i should not ask brainless to share a script which he is using to reduce the shit out of keys.

brainless : could you please be so kind and share your genius script so i can see what u did in this summer.

as i cant see a working logic here and i have to sale that script to a.a to buy a soda cans
legendary
Activity: 1568
Merit: 6660
bitcoincleanup.com / bitmixlist.org
September 29, 2021, 02:39:52 AM
~
I don't want to upset you, but there are 365 days in a year

What a dumpster fire the last few pages of this thread have been.  Sad
member
Activity: 110
Merit: 61
September 29, 2021, 02:36:30 AM
30240 came from astro
360 days in year
7 day in week
12 month in year
360 x 7 x 12 = 30240
Full ver
2520
360 x 7 = 2520
For complete numerology 30240 will work
2520 will make u stuck in some part of calc

I don't want to upset you, but there are 365 days in a year
jr. member
Activity: 81
Merit: 2
September 29, 2021, 02:31:08 AM
30240 came from astro
360 days in year
7 day in week
12 month in year
360 x 7 x 12 = 30240
Full ver
2520
360 x 7 = 2520
For complete numerology 30240 will work
2520 will make u stuck in some part of calc

come to papa  Kiss
a.a
member
Activity: 126
Merit: 36
September 29, 2021, 02:30:18 AM
brainless.... are you kidding me? Come with some reasonable arguments and not with conjectures.


2520 will get you stuck, but 30240 will work. Old Babylonian Astronomers knew this.

Source(s): Dude trust me
member
Activity: 330
Merit: 34
September 29, 2021, 02:26:34 AM
30240 came from astro
360 days in year
7 day in week
12 month in year
360 x 7 x 12 = 30240
Full ver
2520
360 x 7 = 2520
For complete numerology 30240 will work
2520 will make u stuck in some part of calc
a.a
member
Activity: 126
Merit: 36
September 29, 2021, 02:24:56 AM
So no new knowledge  Cool
jr. member
Activity: 81
Merit: 2
September 29, 2021, 02:20:39 AM
@WP
I take a 255 bit pubkey, divide it by 33. Now I only have to search the 2^255/33 ~ 2^252  range to find the key. What a reduction.

@ssxb

Well but what is the new knowledge?

Well but what is the new knowledge?

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hope you get the point ~
congratulation to me today i learnt how to generate numbers in series from 1 to 32 with python. such a genius (wile-e-coyote)

now i am telling you guys dont follow me you can hardly program this. (My brainless theory)

watching wile e coyote vs bugs bunny
a.a
member
Activity: 126
Merit: 36
September 29, 2021, 01:48:14 AM
@WP
I take a 255 bit pubkey, divide it by 33. Now I only have to search the 2^255/33 ~ 2^252  range to find the key. What a reduction.

@ssxb

Well but what is the new knowledge?
jr. member
Activity: 81
Merit: 2
September 29, 2021, 01:31:32 AM
i am drinking soda right now and watching screen (no red wine as i am Muslim Tongue) 32 keys are in front of me telling me that we are relative to each other and no matter from where you will jump toward us we will be always on distance of 1 with each other. if you knows the private keys you will find these keys are lying but hell yaa man when you work blindly on public keys without knowing private keys you will know they are having relation on curve and on 1 key distance from each other. fck math is beautiful . curse you elliptic curve sorry glass slipped from my hand i need to clean the table  Roll Eyes
member
Activity: 110
Merit: 61
September 29, 2021, 01:26:14 AM
Giving you all one more tip , in total numerology, only 30240 is is dividable from 1 to 10, mean 5 even 5 odd, at same time, and no floating result
I don't know what you mean by "numerology", but 30240 is not the only such number (some people already told about it)

if you multuply 30240 to any numbers, and result could also div by 1 to 10, and in result no floating point
If you multiply any X by any Y, that resulting number will be divisible without remainder by all factors of Y (and X). There is no secrets. That is basics. Fundamental theorem of arithmetic.
jr. member
Activity: 81
Merit: 2
September 29, 2021, 01:25:12 AM
I saw that you posted before I could post. I had already invested about 20 minutes for the post and was like: "Well, it is already said, but not from everyone" and so I posted it anyway.

Also the 33 division makes sense as the distance between each point will be the mod inverse of 33 or so. Its like cutting the whole N into ranges, as mentioned before. Only problem is, that you are only getting one in the lower bruteforcable range and then can jump from that one and can determine the other 32 private keys.

And yes, you just have to multiply the privatekey times your divisor and then mod N to get the right result.

that what i said before   Grin
jr. member
Activity: 81
Merit: 2
September 29, 2021, 01:22:09 AM
What about 2520?

2520 = 2³ * 3² * 5 * 7

2520 / 10 = 252
2520 / 9 = 280
2520 / 8 = 315
2520 / 7 = 360
2520 / 6 = 420
2520 / 5 = 504
2520 / 4 = 630
2520 / 3 = 830
2520  / 2 = 1260
2520 / 1 = 2520

Only difference is, that dividing by 8 will get you a odd number. If you want that it is even when dividing by 8, then just double 2520. So 5040 is much smaller than 30240. So why is according to you only 30240 dividable from 1 to 10? If it is even relevant as 30240 is not a divisor of N-1.

References:
https://en.wikipedia.org/wiki/Highly_composite_number
https://mrob.com/pub/math/numbers-14.html#lc5040

 


Yeah I already asked about 2520; I did not see where he stated it had to be even or odd, just no float. It could be beneficial, I will have to run more tests tomorrow. But as of now, I can find any key in any range with any divisor. So I did learn something from all of this discussion. Example, if you took a 40 bit public key and divided it by 33, I could find every public key that is generated and ultimately each pub key found in any/every range will lead me back to private key of original pub key, with a click of a button.

I ran several tests with divisor of 33 and a few with a divisor of 192. Find one pubkey in any range and you have the private key of original pub key.

Find one pubkey in any range and you have the private key of original pub key

that what i said before  Grin
a.a
member
Activity: 126
Merit: 36
September 29, 2021, 01:16:36 AM
I saw that you posted before I could post. I had already invested about 20 minutes for the post and was like: "Well, it is already said, but not from everyone" and so I posted it anyway.

Also the 33 division makes sense as the distance between each point will be the mod inverse of 33 or so. Its like cutting the whole N into ranges, as mentioned before. Only problem is, that you are only getting one in the lower bruteforcable range and then can jump from that one and can determine the other 32 private keys.

And yes, you just have to multiply the privatekey times your divisor and then mod N to get the right result.
full member
Activity: 1162
Merit: 237
Shooters Shoot...
September 29, 2021, 01:04:17 AM
What about 2520?

2520 = 2³ * 3² * 5 * 7

2520 / 10 = 252
2520 / 9 = 280
2520 / 8 = 315
2520 / 7 = 360
2520 / 6 = 420
2520 / 5 = 504
2520 / 4 = 630
2520 / 3 = 830
2520  / 2 = 1260
2520 / 1 = 2520

Only difference is, that dividing by 8 will get you a odd number. If you want that it is even when dividing by 8, then just double 2520. So 5040 is much smaller than 30240. So why is according to you only 30240 dividable from 1 to 10? If it is even relevant as 30240 is not a divisor of N-1.

References:
https://en.wikipedia.org/wiki/Highly_composite_number
https://mrob.com/pub/math/numbers-14.html#lc5040

 


Yeah I already asked about 2520; I did not see where he stated it had to be even or odd, just no float. It could be beneficial, I will have to run more tests tomorrow. But as of now, I can find any key in any range with any divisor. So I did learn something from all of this discussion. Example, if you took a 40 bit public key and divided it by 33, I could find every public key that is generated and ultimately each pub key found in any/every range will lead me back to private key of original pub key, with a click of a button.

I ran several tests with divisor of 33 and a few with a divisor of 192. Find one pubkey in any range and you have the private key of original pub key.
a.a
member
Activity: 126
Merit: 36
September 29, 2021, 12:58:07 AM
What about 2520?

2520 = 2³ * 3² * 5 * 7

2520 / 10 = 252
2520 / 9 = 280
2520 / 8 = 315
2520 / 7 = 360
2520 / 6 = 420
2520 / 5 = 504
2520 / 4 = 630
2520 / 3 = 830
2520  / 2 = 1260
2520 / 1 = 2520

Only difference is, that dividing by 8 will get you a odd number. If you want that it is even when dividing by 8, then just double 2520. So 5040 is much smaller than 30240. So why is according to you only 30240 dividable from 1 to 10? If it is even relevant as 30240 is not a divisor of N-1.

References:
https://en.wikipedia.org/wiki/Highly_composite_number
https://mrob.com/pub/math/numbers-14.html#lc5040

 

full member
Activity: 1162
Merit: 237
Shooters Shoot...
September 29, 2021, 12:41:12 AM
Giving you all one more tip , in total numerology, only 30240 is is dividable from 1 to 10, mean 5 even 5 odd, at same time, and no floating result
i gurantee, you never see 30240 secrets
30240.0000   10.0000   3024.0000
30240.0000   9.0000   3360.0000
30240.0000   8.0000   3780.0000
30240.0000   7.0000   4320.0000
30240.0000   6.0000   5040.0000
30240.0000   5.0000   6048.0000
30240.0000   4.0000   7560.0000
30240.0000   3.0000   10080.0000
30240.0000   2.0000   15120.0000
30240.0000   1.0000   30240.0000

if you multuply 30240 to any numbers, and result could also div by 1 to 10, and in result no floating point

30240 * 777 = 23496480.0000
23496480.0000   10.0000   2349648.0000
23496480.0000   9.0000   2610720.0000
23496480.0000   8.0000   2937060.0000
23496480.0000   7.0000   3356640.0000
23496480.0000   6.0000   3916080.0000
23496480.0000   5.0000   4699296.0000
23496480.0000   4.0000   5874120.0000
23496480.0000   3.0000   7832160.0000
23496480.0000   2.0000   11748240.0000
23496480.0000   1.0000   23496480.0000

hope like in my preivios post for magic numbers, you could not understand, same hope you will not understand secrets behind this only 1 magic numberology Smiley
 
Maybe I am misunderstanding you and what you mean, but any multiple of 2520 would have the same result...
jr. member
Activity: 48
Merit: 11
September 29, 2021, 12:15:27 AM
Giving you all one more tip , in total numerology, only 30240 is is dividable from 1 to 10, mean 5 even 5 odd, at same time, and no floating result
i gurantee, you never see 30240 secrets
30240.0000   10.0000   3024.0000
30240.0000   9.0000   3360.0000
30240.0000   8.0000   3780.0000
30240.0000   7.0000   4320.0000
30240.0000   6.0000   5040.0000
30240.0000   5.0000   6048.0000
30240.0000   4.0000   7560.0000
30240.0000   3.0000   10080.0000
30240.0000   2.0000   15120.0000
30240.0000   1.0000   30240.0000

if you multuply 30240 to any numbers, and result could also div by 1 to 10, and in result no floating point

30240 * 777 = 23496480.0000
23496480.0000   10.0000   2349648.0000
23496480.0000   9.0000   2610720.0000
23496480.0000   8.0000   2937060.0000
23496480.0000   7.0000   3356640.0000
23496480.0000   6.0000   3916080.0000
23496480.0000   5.0000   4699296.0000
23496480.0000   4.0000   5874120.0000
23496480.0000   3.0000   7832160.0000
23496480.0000   2.0000   11748240.0000
23496480.0000   1.0000   23496480.0000

hope like in my preivios post for magic numbers, you could not understand, same hope you will not understand secrets behind this only 1 magic numberology Smiley
 

Thanks for the number hint.
I hope to figure it out and solve this problem.

In the previous post, I thought the other way, that we need to find such a divisor and such a multiplier that would get the same division residuals. For example, below are the results of division and multiplication using these and other numbers:
Code:
2281607788513008375014137388606100914
 2281607788513008375014137388605979764
 2281607788513008375014137388605858614
 2281607788513008375014137388605737464
 2281607788513008375014137388605616314
 2281607788513008375014137388605495164
 2281607788513008375014137388605374014
 2281607788513008375014137388605252864
 2281607788513008375014137388605131714
 2281607788513008375014137388605010564
 2281607788513008375014137388604889414
 2281607788513008375014137388604768264
 2281607788513008375014137388604647114
 2281607788513008375014137388604525964
 2281607788513008375014137388604404814
don't look at the specific values of the numbers, this is for an example. All that matters is that they end in one digit and the second digit alternates.

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