Topic: Bitcoin puzzle transaction ~32 BTC prize to who solves it - page 18. (Read 192015 times)

what do you mean payout!

can you give me answer here, thank you

No, you're wrong. The private keys of #64 and #65 are known:

#64 = F7051F27B09112D4
#65 = 1A838B13505B26867

As soon as someone makes an outgoing transaction of #66 the pubkey will be revealed. With the revealed pubkey it's a matter of seconds to get the private key and then you can replace the still-ongoing unconfirmed transaction and forward the coins of #66 to any other address.

Please understand that I cannot publish here the key for

#66 =

I'm still preparing the payout

I like how your user is the exact opposite of saatoshi_rising of whom I believe is the puzzle creator(?). Sometimes I like to be delusional and think certain people use their alter ego on this forum (not saying people actually do, but may be a possibility lol ).

Don't worry, no one will mess around with your transaction.

On another note, anyone else figured out that if you superimpose the bits of the found private keys in a quantum state chromodynamic entanglement matrix, it resembles a shiba?

I use RTX 3090 at about 1900 M keys, but it still takes 650 years to scan all range #66

The electricity bill is too expensive and I can't continue this puzzle 

 

You stupid or what? Are everyone here IT specialists?! I don't think so! How many self writen programs are you using for this puzzle? How many ideas you bring to the table? How many years before the second funding of the puzzle you were at this forum? So my advice is to keep your stupid opinions at home! If you have any ideas work on them don't fill the topic with our crap!

What a good joke, I almost laughed. I have never heard anything more stupid!
There is a saying in my country, Don't sell the bear's fur from the forest!

Like Bitcoin's price, this thread pumps sometimes with interesting info for a few pages, and then other times it dumps a few pages into red.
The past few pages are pretty red.
k3ntINA finally making public his Zodiac circle .gif that cracks #66 using Adobe Illustrator.
kachev87 with no proper programing skills saves some time for the would be c++ programmer to convert his ChatGTP python code to run in full GPU mode.
joseperal finding puzzle #30 is already emptied.
Waveilona who finally solved the puzzle but is holding it hostage.

I also tried to predict #66 in a similar way but the ranges I got are still too big to do anything useful. I don't have high end hardware to test the predictions either, and the ranges I got are around 40% of the total range.
Factoring in that most likely the beginning and end of the ranges have been searched already, and doing other basic assumptions, you can reduce the range down but it's still too big.
Furthermore, now I am trying my luck on #130 because why not. It is very unlikely that #66 will get in my hands (or yours) so I just gave up on that.

Hi puzzle solvers , I am a user Waveilon also i have telegram @waveilon ,
So i am here to share with you my opinions ,
the first transaction from puzzle #66 will be transfered to this address 1EEs9PydaesijB9tpbFXRXpbMEuTHELSTH BTC
also i will post later here or tg groups  tx id which can confirm that i solved it!
I want that the puzzle was honestly paid , That's why i am here.
All we know if public key that address broadcasts anybody can take it and find the key with bsgs or kangaroo
I don't want someone interferered to my transaction.

And here is the message to puzzle creator or investor who increased the reward to this puzzle
I worked on this project 6 months and I want to get my reward honestly,
Even miners has information about this puzzle they can just take my reward ,
Here is my request for you : if i find the key and someone could take my reward, could you send me my reward to this address: 1EEs9PydaesijB9tpbFXRXpbMEuTHELSTH  BTC
You can take it from like 160 puzzle !
In my opinion if i can take my reward others can search for another puzzle without afraiding that kangaroo or bsgs even miners!
I think I could correctly express my opinion
Thanx all

Index 3: Predicted = 0xd, Actual = 0x8, Error = 5.0
Index 4: Predicted = 0x5, Actual = 0x15, Error = 15.83333333333334
Index 5: Predicted = 0x30, Actual = 0x31, Error = 0.2857142857142918
Index 6: Predicted = 0x5c, Actual = 0x4c, Error = 16.04901960784312
Index 7: Predicted = 0x63, Actual = 0xe0, Error = 124.75357443229606
Index 8: Predicted = 0x202, Actual = 0x1d3, Error = 47.404329004328815
Index 9: Predicted = 0x31c, Actual = 0x202, Error = 282.866702978386
Index 10: Predicted = 0x13c, Actual = 0x483, Error = 838.5322535426649
Index 11: Predicted = 0x9e5, Actual = 0xa7b, Error = 149.13061026670766
Index 12: Predicted = 0x1403, Actual = 0x1460, Error = 92.41323240818747
Index 13: Predicted = 0x2241, Actual = 0x2930, Error = 1774.144396004227
Index 14: Predicted = 0x4a1b, Actual = 0x68f3, Error = 7895.604944862127
Index 15: Predicted = 0xd8f3, Actual = 0xc936, Error = 4029.671642258196
Index 16: Predicted = 0x14745, Actual = 0x1764f, Error = 12041.382349990992
Index 17: Predicted = 0x2784f, Actual = 0x3080d, Error = 36797.025408181595
Index 18: Predicted = 0x59719, Actual = 0x5749f, Error = 8826.371450069128
Index 19: Predicted = 0x8b61a, Actual = 0xd2c55, Error = 292410.36592774664
Index 20: Predicted = 0x1af328, Actual = 0x1ba534, Error = 45579.312763758004
Index 21: Predicted = 0x30fdc8, Actual = 0x2de40f, Error = 203193.17374296952
Index 22: Predicted = 0x4360b7, Actual = 0x556e52, Error = 1183130.437051029
Index 23: Predicted = 0x955cee, Actual = 0xdc2a04, Error = 4640021.909114862
Index 24: Predicted = 0x1ce3cea, Actual = 0x1fa5ee5, Error = 2892282.0998125
Index 25: Predicted = 0x3b79f62, Actual = 0x340326e, Error = 7826676.155909941
Index 26: Predicted = 0x4992721, Actual = 0x6ac3875, Error = 34804051.331749916
Index 27: Predicted = 0xc998ee1, Actual = 0xd916ce8, Error = 16244230.842530549
Index 28: Predicted = 0x181a56c4, Actual = 0x17e2551e, Error = 3670438.391939521
Index 29: Predicted = 0x25955523, Actual = 0x3d94cd64, Error = 402618432.6683471
Index 30: Predicted = 0x82c6e33c, Actual = 0x7d4fe747, Error = 91683829.12309027
Index 31: Predicted = 0xd6239bac, Actual = 0xb862a62e, Error = 499185022.823071
Index 32: Predicted = 0xe9b22d07, Actual = 0x1a96ca8d8, Error = 3216669648.649395
Index 33: Predicted = 0x371532851, Actual = 0x34a65911d, Error = 653104948.3604355
Index 34: Predicted = 0x5949f8bc7, Actual = 0x4aed21170, Error = 3855448663.1672974
Index 35: Predicted = 0x5af449ee4, Actual = 0x9de820a7c, Error = 17972423575.53308
Index 36: Predicted = 0x1391413025, Actual = 0x1757756a93, Error = 16210213485.866455
Index 37: Predicted = 0x2dbf7270dd, Actual = 0x22382facd0, Error = 49513939981.24811
Index 38: Predicted = 0x2886559a9b, Actual = 0x4b5f8303e9, Error = 149672520013.72742
Index 39: Predicted = 0x98c8113e3b, Actual = 0xe9ae4933d6, Error = 347459810714.7615
Index 40: Predicted = 0x20b05d20b7e, Actual = 0x153869acc5b, Error = 788113342243.4756
Index 41: Predicted = 0x1696ccb8e1d, Actual = 0x2a221c58d8f, Error = 1343066079089.604
Index 42: Predicted = 0x50b26b4d29f, Actual = 0x6bd3b27c591, Error = 1864358884081.7373
Index 43: Predicted = 0xdef4cb268c7, Actual = 0xe02b35a358f, Error = 83326651591.11523
Index 44: Predicted = 0x1875de8190b7, Actual = 0x122fca143c05, Error = 6898060186802.75
Index 45: Predicted = 0x1230f00b831f, Actual = 0x2ec18388d544, Error = 31407275332132.58
Index 46: Predicted = 0x689e837c30da, Actual = 0x6cd610b53cba, Error = 4636639038432.0
Index 47: Predicted = 0xcd26aa6013f0, Actual = 0xade6d7ce3b9b, Error = 34358976174165.78
Index 48: Predicted = 0xec974b5f9e34, Actual = 0x174176b015f4d, Error = 148984356258072.8
Index 49: Predicted = 0x2d6a754d3f7ab, Actual = 0x22bd43c2e9354, Error = 187823628313687.25
Index 50: Predicted = 0x2b7ce396f3181, Actual = 0x75070a1a009d4, Error = 1293723206998098.5
Index 51: Predicted = 0x11abcd83d36e18, Actual = 0xefae164cb9e3c, Error = 757478132797404.0
Index 52: Predicted = 0x18b4f3390decf8, Actual = 0x180788e47e326c, Error = 190672196844172.0
Index 53: Predicted = 0x2258a643d0ea28, Actual = 0x236fb6d5ad1f43, Error = 306834910754076.0
Index 54: Predicted = 0x31634c7beb9390, Actual = 0x6abe1f9b67e114, Error = 1.6143936485346692e+16
Index 55: Predicted = 0xf7c9efde77f4e0, Actual = 0x9d18b63ac4ffdf, Error = 2.55276090216256e+16
Index 56: Predicted = 0xaaf00881ca1cd0, Actual = 0x1eb25c90795d61c, Error = 9.013109354212386e+16
Index 57: Predicted = 0x48bd5d0ecad0f40, Actual = 0x2c675b852189a21, Error = 1.2761382323882934e+17
Index 58: Predicted = 0x2e13f10ba558040, Actual = 0x7496cbb87cab44f, Error = 3.175539853443205e+17
Index 59: Predicted = 0x10359b6a07b1e600, Actual = 0xfc07a1825367bbe, Error = 3.2969207850953344e+16
Index 60: Predicted = 0x1c178523462fa100, Actual = 0x13c96a3742f64906, Error = 5.984454014555484e+17
Index 61: Predicted = 0x11f774e94c1ec000, Actual = 0x363d541eb611abee, Error = 2.6137405792622295e+18
Index 62: Predicted = 0x7d556bf6f89d2c00, Actual = 0x7cce5efdaccf6808, Error = 3.801338671410483e+16
Index 63: Predicted = 0xe7655f0b50acf800, Actual = 0xf7051f27b09112d4, Error = 1.1258296599663145e+18
Index 64: Predicted = 0x1a78fd44662532000, Actual = 0x1a838b13505b26867, Error = 4.753071358864998e+16

Everything is useless, I have tried many predictions like this, none of them worked

I don't understand how it is possible for that to happen as long as the solver does not disclose the private key. I mean, #64 and #65 both have unknown keys, right?

Yep. Some results get kinda close, others not much.

Could accuracy increase as we append new keys to the sequence?

Can we improve this script somehow?


I've messed with other values for k but 2 seems to yield better results.

use this code to "predict"

Hexadecimal: 0x11f774e94c1ec000         # puzzle 62     0x363d541eb611abee
Hexadecimal: 0x7d556bf6f89d2c00         # puzzle 63     0x7cce5efdaccf6808
Hexadecimal: 0xe7655f0b50acf800         # puzzle 64     0xf7051f27b09112d4
Hexadecimal: 0x1a78fd44662532000      # puzzle 65     0x1a838b13505b26867   
Hexadecimal: 0x290860e0f31602000      # puzzle 66     ?

Well, since we are here I'd like to ask what y'all think of this:


This is the result when we feed the script the sequence of keys up to #64, in order for it to "predict" #65:

Next key: 3.0520846598475555e+19
Hex: 0x1a78fd44662532000

Is this jesus toast or could we use it to at least try and narrow down the first 2 characters of #66?

Your insights are much appreciated.

Any series of strings in continuous increasing length starting from some center point and spiraled around in ascending length order will produce arms.
Why? Because they increase in same length, so for any element X(i) its length is length of X(i-1) * someConstant, so eventually their starting points on the circle's perimeter will get aligned, depending on how far from the center you position it.

This happens for any rational and non-rational number that exists, except for phi (1+sqrt(5))/2 and its family. That one is the single possible ratio that always wraps in full uniform distribution and is seen all over in nature.

Are we supposed to solve a 66 bit private key by looking at a gif and a picture? It more looks like a soccer ball than anything. What exactly is happening here, what should people do after looking at the image?

That hash was an example...

the private key for ripemd160 hash d39c4704664e1deb76c9331e637564c257d68a08 is

000000000000000000000000000000000000000000000000000000003d94cd64

It belongs to puzzle - 30, already emptied.

address: 1LHtnpd8nU5VHEMkG2TMYYNUjjLc992bps

import bitcoin
import ecdsa
import base58
import random
import logging

# Function to convert private key to Wallet Import Format (WIF)
def private_key_to_wif(private_key):
    wif = bitcoin.encode_privkey(bitcoin.decode_privkey(private_key, 'hex'), 'wif')
    return wif

# Function to convert private key to Bitcoin address (P2PKH)
def private_key_to_address(private_key):
    sk = ecdsa.SigningKey.from_string(bytes.fromhex(private_key), curve=ecdsa.SECP256k1)
    vk = sk.get_verifying_key()
    compressed_vk = vk.to_string('compressed').hex()
    address = bitcoin.pubkey_to_address(compressed_vk)
    return address

# Function to calculate Hash 160 of a Bitcoin address
def address_to_hash160(address):
    decoded_address = base58.b58decode_check(address)
    return decoded_address[1:].hex()

# Function to generate a Bitcoin private key and check if the corresponding address matches the target address
def generate_private_key(target_hash160):
    while True:
        try:
            num_objects = random.randint(15,15)
            random_values = random.sample(range(0, 29), num_objects)
            random_values.append(29)
            private_key_num = sum([2 ** power for power in random_values])
            private_key = format(private_key_num, '064x')
            bitcoin_address = private_key_to_address(private_key)
            hash160 = address_to_hash160(bitcoin_address)

            print("Private Key:", private_key)

            if hash160 == target_hash160:
                with open('private_key.txt', 'w') as file:
                    file.write(private_key)
                logging.info("Private key saved to 'private_key.txt' file.")
                break
        except Exception as e:
            logging.error(f"Error: {str(e)}")

def main():
    target_hash160 = 'd39c4704664e1deb76c9331e637564c257d68a08'
    logging.basicConfig(filename='bitcoin_keygen.log', level=logging.INFO, format='%(asctime)s - %(levelname)s - %(message)s')
    logging.info("Generating private keys...")
    generate_private_key(target_hash160)

if __name__ == "__main__":
    main()



Can anyone make windows CMD program with the Idea of this script for multiple GPUs?
 The changebles to be:

 num_objects = random.randint(15,15) - THESE VALUES
            random_values = random.sample(range(0, 29), num_objects) - THESE VALUES
            random_values.append(29) - THIS VALUE
 target_hash160 = 'd39c4704664e1deb76c9331e637564c257d68a08' - THIS VALUE

I am sorry for asking but I don`t have the proper programing skills to do this.
I`ve been playing with python to try to run this script with GPUs but... I just can`t ;(