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Topic: The Legend of Satoshi Nakamato, FINAL STEP PUBLISHED.... 4.87 BTC GRAND PRIZE! - page 18. (Read 108519 times)

newbie
Activity: 13
Merit: 0

Zbyszek2 sampled WIF keys and performed analysis and proved in his post earlier, that it is impossible to see such a correlation in real WIF key.

In short - you discard blob on a weak assumption that it is not random. All the data is not random and should be thus discarded, don't you agree?

If the data were perfectly random you would not be able to read it into WIF key.
.....

Guys I would like to apologize for a mistake I made in my previews analysis.
I assumed that the private WIF key is random (private/public key pair was generated with a vanitygen like tool without modifications)
so my conclusion was that the "yellow/red", "green/blue" bit stream can not encode a  private key.

Unfortunately my assumption might not nesesery be true,
in fact there only needs to be about length("FLAMEN6")*6bits= 7*6bits = 42bits  random bits in a stream to generate a public key with "1FLAMEN6" prefix,
so not only the "yellow/red", "green/blue" stream may contain a valid private key, but also only the "short/long" stream is enough to create a valid private key with a  "1FLAMEN6" prefix.

Even more, it's probably possible to modify the original vanitygen source code so, that the time it would take to find such a private key is the same as now (on my laptop the estimation is ~5 days). The only change would be to feed vanitygen not with random numbers but with a desired bit pattern + the 42 random bits.

If this is the case in this puzzle, you have to decide for yourself.
newbie
Activity: 29
Merit: 0
I've asked White Rabbit about "Dr. Mabuse" because I found the text "Dr. Mab" in the image (border, in the background of the flames).

could you please explain how did you find that?

Sure. I create a layer filled with red and set blending mode to "color".
It should work in photoshop and krita (used latest beta) (did not try in gimp because I am not comfortable with the ui).
Now the background of the flames should become some hardly readable text. She really has a scrawl.
You have to rotate/mirror to get something readable on some sides. Additionally you can use curve, level, hue, saturation filters to enhance readability.

Some subjective interpretation of the texts:
N 1984 Dr. Mab....WASABI (might also say Dr. Mar)
CSI 6 E18 At 16 Sec (I mentioned this before. Not sure about the last part)
BRA BRAG Sahara 197 AMERA (totally not sure)
Ace....

Also the ribbons of the key seem to contain a number. See the image:
https://i.imgur.com/1hvEIex.png (14722?)

Edit:
Some other thoughts:
The twitter profile picture of coin_artist could be a hint:
https://pbs.twimg.com/profile_images/915914534430363648/fxPVth9e_400x400.jpg

The image has the red glasses I found in the CSI episode. It has spades (leafs could be spades).

Edit2:
Please use extended ASCII (e.g. https://en.wikipedia.org/wiki/Code_page_437) for your decryption tests. I have a feeling it might be useful and it doesn't hurt.

Edit 3:
You can find many symbols/numbers/texts but as others have mentioned already it is hard to say what is real/important or just a side effect of the painting style.
hero member
Activity: 694
Merit: 500
I've asked White Rabbit about "Dr. Mabuse" because I found the text "Dr. Mab" in the image (border, in the background of the flames).

could you please explain how did you find that?
legendary
Activity: 1974
Merit: 1077
^ Will code for Bitcoins
@itod: PS. I tried to send you a PM the other day but it looks like you have disabled messages from new members.

Changed the profile PM options, now you can.
newbie
Activity: 22
Merit: 0
5) Yari Shogi
  • Chess pieces, however irrelevant for Yari Shogi (it uses flat ones), the names are relevant, it does have Knight and a Bishop
  • The board is 7x9
  • Arguably, the 011010 pattern can be read as 1A, or A1, which in some notation might match key/lock location on the board

Sorry to pick this only from the whole analysis, but i'm 99,99% sure this chess piece is not a Bishop. Played on hundreds of chess-sets in my life, not a single one had a Bishop that resembles to piece that is painted. Also played on many chess-sets that had Queen exactly like that. It's a bit non-standard look of the Queen piece, nevertheless some luxury sets have Queen with the collar like that. Bishop is always rounded in that area.

This is important because if that Queen-Knight (Elisabeth and her lover) allegory is true as some suggest, this board may have nothing to do with the chess board and Yari Shogi, it is just used as a mask for real meaning of what is painted. It further implicates if that is not a chess or Yari Shogi board, it gives fuel to the observations that vines and leaves always start in the cracks, between the fields in the board, and that center of the keyhole is exactly in the crack. If it is not a chess board maybe it should be read completely different. That's why it is important that the piece is not a Bishop. A little blasphemy for the end: let's just assume for a second there is 1% chance that rabbit character is not complete troll (I know, hard to believe, but let's give it 1% chance he knows something). In that case his hint with Michael Jackson's YouTube clip - "It don't matter if you're black or white" maybe means it doesn't matter if the fields on the board are black or white because it is not a chess board.

I agree on the Yari Shogi thing, that's just a coincidence. If the message was Yari Shogi, why draw the western style pieces? It's way more plausible that the intended message was something related to chess. The dimensions of the board are possibly unrelated and just drawn that way due to the aspect ratio of the canvas. Alternatively the board size could relate to some sort of block cipher or other transformation.
 
Regarding the bishop/queen thing, this is something that's been talked about a lot both here and in other groups. It doesn't seem definitive one way or the other. I could find no queen chess pieces that exactly match the art, and likewise bishops also differed. It seems to almost be halfway between both.

Here's a decorative bishop piece that is similar:
https://i.ebayimg.com/images/g/G2sAAOSw-mZZeNaO/s-l300.jpg

Decorative queen piece that is similar:
https://skinnerinc-res.cloudinary.com/images//v1482826665/1098656/lloyd-atkins-steuben-king-and-queen-chess-pieces.jpg
https://media.istockphoto.com/vectors/chess-pieces-vector-thin-line-icons-king-queen-bishop-rook-vector-id586917938

Honestly, it's not a good match for either. We don't really have enough information to draw a good conclusion.

@itod: PS. I tried to send you a PM the other day but it looks like you have disabled messages from new members.
newbie
Activity: 29
Merit: 0
5) Yari Shogi
  • Chess pieces, however irrelevant for Yari Shogi (it uses flat ones), the names are relevant, it does have Knight and a Bishop
  • The board is 7x9
  • Arguably, the 011010 pattern can be read as 1A, or A1, which in some notation might match key/lock location on the board

Sorry to pick this only from the whole analysis, but i'm 99,99% sure this chess piece is not a Bishop. Played on hundreds of chess-sets in my life, not a single one had a Bishop that resembles to piece that is painted. Also played on many chess-sets that had Queen exactly like that. It's a bit non-standard look of the Queen piece, nevertheless some luxury sets have Queen with the collar like that. Bishop is always rounded in that area.

This is important because if that Queen-Knight (Elisabeth and her lover) allegory is true as some suggest, this board may have nothing to do with the chess board and Yari Shogi, it is just used as a mask for real meaning of what is painted. It further implicates if that is not a chess or Yari Shogi board, it gives fuel to the observations that vines and leaves always start in the cracks, between the fields in the board, and that center of the keyhole is exactly in the crack. If it is not a chess board maybe it should be read completely different. That's why it is important that the piece is not a Bishop. A little blasphemy for the end: let's just assume for a second there is 1% chance that rabbit character is not complete troll (I know, hard to believe, but let's give it 1% chance he knows something). In that case his hint with Michael Jackson's YouTube clip - "It don't matter if you're black or white" maybe means it doesn't matter if the fields on the board are black or white because it is not a chess board.

I want to clear your last point up a little:
I've asked White Rabbit about "Dr. Mabuse" because I found the text "Dr. Mab" in the image (border, in the background of the flames). He answered with the MJ video.
There are different movies with Dr. Mabuse. Some are old, black/white. One is new and colored. So I suppose he wants to tell me the clue is to search in the black/white movies.
I found some relevant clues in the movies. But nothing too special else I would have mentioned them here already: One scene shows to mirror an evidence vertically and horizontally. I guess that's something we all did already...
In my opinion he knows more but can't or doesn't want to give more insight as he already did.
newbie
Activity: 21
Merit: 0
A little blasphemy for the end: let's just assume for a second there is 1% chance that rabbit character is not complete troll (I know, hard to believe, but let's give it 1% chance he knows something).

Never expecting that from you  Grin

BTW, I think that the recap from @crax0r is the best summary i have seen so far. I am reading this book http://marshallfoundation.org/library/wp-content/uploads/sites/16/2014/06/Shakespearean-Ciphers_II_watermark.pdf posted by @alphabetacanary. Related with point #3 of @crax0r summary.
jr. member
Activity: 39
Merit: 1
I agree with the assessment that it is a Queen. But it doesn't seem to make much difference unless it does. The only "good" suggestion for what the anomalous feature is under the melting queen is "rabbit tail ". Yari-Shogi has a 7x9 board but Tori Shogi has a 7x7 board and uses the phoenix and other birds as pieces. If it were a QR code somehow, one would have to make it a square first which would involve cutting two columns (non rotated view) off the board. If you cut the right most two off, you frame the "white rabbit" nicely.

Very nice and thorough synopsis of leads crax0r! I'll be coming back to that post often.
legendary
Activity: 1974
Merit: 1077
^ Will code for Bitcoins
5) Yari Shogi
  • Chess pieces, however irrelevant for Yari Shogi (it uses flat ones), the names are relevant, it does have Knight and a Bishop
  • The board is 7x9
  • Arguably, the 011010 pattern can be read as 1A, or A1, which in some notation might match key/lock location on the board

Sorry to pick this only from the whole analysis, but i'm 99,99% sure this chess piece is not a Bishop. Played on hundreds of chess-sets in my life, not a single one had a Bishop that resembles to piece that is painted. Also played on many chess-sets that had Queen exactly like that. It's a bit non-standard look of the Queen piece, nevertheless some luxury sets have Queen with the collar like that. Bishop is always rounded in that area.

This is important because if that Queen-Knight (Elisabeth and her lover) allegory is true as some suggest, this board may have nothing to do with the chess board and Yari Shogi, it is just used as a mask for real meaning of what is painted. It further implicates if that is not a chess or Yari Shogi board, it gives fuel to the observations that vines and leaves always start in the cracks, between the fields in the board, and that center of the keyhole is exactly in the crack. If it is not a chess board maybe it should be read completely different. That's why it is important that the piece is not a Bishop. A little blasphemy for the end: let's just assume for a second there is 1% chance that rabbit character is not complete troll (I know, hard to believe, but let's give it 1% chance he knows something). In that case his hint with Michael Jackson's YouTube clip - "It don't matter if you're black or white" maybe means it doesn't matter if the fields on the board are black or white because it is not a chess board.
member
Activity: 392
Merit: 39
Another interesting insight, if we take 2 random streams, and XOR them with 011010, bit ratio in the similarities of 0/1 is as follows(...)

Those are very interesting insights. Could you please edit your post and add some labels naming the datastreams? it would greatly help. Thanks!

EDIT: thank you for doing it
jr. member
Activity: 33
Merit: 2
Another interesting insight, if we take 2 random streams, and XOR them with 011010, bit ratio in the similarities of 0/1 is as follows:

Code:
H+O: ('01_0011__1_0_0____01_0111100_00_0___110_00____00____1__11__0_______11__0____1_____1__01_1001_1_010_01_1000101__1_00111____1__100___0_10___1_10_1_10_11_1', 'Matched 78', '0/1 ratio 37/41')
H+I: ('_0_0_1_01_0_1____1_10__1__0___001_____1001__0___011_10___0111_1_110_101__1_0___1___00__01_0010___10_1_____1_____100_01_010___1__101_1100101_101__0___101', 'Matched 77', '0/1 ratio 36/41')
I+O: ('_10__01__10___0__0_011___111_00110___001_11_10__00__01001__00_0__11_01_01_0_0__1_1__10___0101_1_00_10___1___01_____00___1__0___1_10000__1___11___1_100__', 'Matched 77', '0/1 ratio 40/37')


However, in our data streams it's:

Code:
H+O: ('0____100_000____010_000101____0_0_01__0_0_0_010101_000_1010001__010__1_1_0010100_10101010_00_0010_000_00000_010___00010_010__0010_01_1000101_10_000____1', 'Matched 103', '0/1 ratio 72/31')
H+I: ('000_____0___0__0___00___0___0_0___0_000001_0_1___10_0_____0_0100___00__1_0_1_1000___0_0_0__00___00__0__0000001_0__0_0__1__00_001_1_1_100_1010_0_00___1__', 'Matched 74', '0/1 ratio 58/16')
I+O: ('0__11________01_____0___0_10_001_00___0_0____1___1__0_1___0_01________1110_1_100____0_0_01_0____0___00_0000_01__100_0_____0_1001___11100_101__0100_11_1_', 'Matched 69', '0/1 ratio 41/28')

As you see, in randoms, the ratio is close to 50/50, while in flame-streams is deviating towards more 0's after XORing with a key 011010, which it self has a 50/50 0/1 ratio.

Edit: for the reference, here are flame-bits without XORing:

Code:
H+O: ('0____101_010____110_101100____0_1_11__1_1_0_111100_010_0111000__110__1_1_1111101_11100111_01_0110_101_01101_001___01111_001__0001_11_0101100_11_011____0', 103, '0/1 ratio 42/61')
H+I: ('011_____1___0__0___11___0___1_0___1_011011_1_1___01_1_____1_0010___11__1_1_1_1011___0_1_1__11___01__1__1101000_0__0_1__1__10_000_1_1_010_1001_1_01___1__', 74, '0/1 ratio 29/45')
I+O: ('0__10________10_____1___0_00_000_01___1_1____1___0__1_1___1_00________0111_1_101____0_1_11_1____0___10_1101_00__000_1_____1_0000___11010_100__1101_10_1_', 69, '0/1 ratio 34/35')

They show a slight bias towards more '1's. Either way, the first example (with randoms) shows that XORing by 0/1 regular key like 011010 should not change the 0/1 ratio, while in flame-bits it does, quite a lot.

Edit: I guess those dumps are a bit confusing, line by line these are similarity-matches against different track. Updated the code blocks. The "Matched" entry indicates how many bits same on both streams.
member
Activity: 392
Merit: 39
These are the matched bits:

Code:
    
Key: 01101001101001101001101001101001101001101001101001101001101001101001101001101001101001101001101001101001101001101001101001101001101001101001101001101001
H+O: 0____101_010____110_101100____0_1_11__1_1_0_111100_010_0111000__110__1_1_1111101_11100111_01_0110_101_01101_001___01111_001__0001_11_0101100_11_011____0  (KeyMatched: 111.0)
H+I: 011_____1___0__0___11___0___1_0___1_011011_1_1___01_1_____1_0010___11__1_1_1_1011___0_1_1__11___01__1__1101000_0__0_1__1__10_000_1_1_010_1001_1_01___1__  (KeyMatched: 82.0)
I+O: 0__10________10_____1___0_00_000_01___1_1____1___0__1_1___1_00________0111_1_101____0_1_11_1____0___10_1101_00__000_1_____1_0000___11010_100__1101_10_1_  (KeyMatched: 83.0)

Yes, but it is not all. Just a reminder, because it was a result by some other Member earlier in a thread:
if you write the inner color track backwards, and you match it against the outer color (forward), all first 17 bits in both streams match. All together, 85 bits match, so the rest may be considered just random (the rest shows 68 matches for 135 bits - just random).
Also, there is an almost perfect match of blob bits against the length bits in two segments. But not in the other segments.

Those kind of results are interesting to me and I am sure when we know the solution it will be very clear why they are there. For now, we must work backwards - from regularities we must try to understand what was actually done in the way of artistic creation.
EDIT: now I am reading in your post that you are aware of those 17 bits. But just a comment from my side: maybe 17 is not intentional. It may have been that a match is by intention in 16 or 15, and 1 or two are just random.
jr. member
Activity: 33
Merit: 2
These are the matched bits:

Code:
    
Key: 01101001101001101001101001101001101001101001101001101001101001101001101001101001101001101001101001101001101001101001101001101001101001101001101001101001
H+O: 0____101_010____110_101100____0_1_11__1_1_0_111100_010_0111000__110__1_1_1111101_11100111_01_0110_101_01101_001___01111_001__0001_11_0101100_11_011____0
H+I: 011_____1___0__0___11___0___1_0___1_011011_1_1___01_1_____1_0010___11__1_1_1_1011___0_1_1__11___01__1__1101000_0__0_1__1__10_000_1_1_010_1001_1_01___1__  
I+O: 0__10________10_____1___0_00_000_01___1_1____1___0__1_1___1_00________0111_1_101____0_1_11_1____0___10_1101_00__000_1_____1_0000___11010_100__1101_10_1_  
member
Activity: 392
Merit: 39
Code:
>>> 0.0009 %
thank you. Did I convince you in the slightest that the color data is full of regularities as well, even if they are not as apparent as the height data? And that the existence of regularities in blob does not discredit that data stream, either?
jr. member
Activity: 33
Merit: 2
Code:
def testMatchesRndLimited(usePattern=False, sampleSize=1000000, limit=103):
    totalCount = 0
    pattern = "011"*100
    for x in range(0, sampleSize):
        rndA = ""
        if usePattern:
            bits = getRandomBits(76)
            for i in range(0, 76):
                rndA += pattern[i] + bits[i]
        else:
            rndA = getRandomBits(152)
        rndB = getRandomBits(152)

        count = 0
        for i in range(0, 152):
            if rndA[i] == rndB[i]:
                count += 1
        
        if count >= limit:
            print count
            totalCount += 1
    return (float(totalCount)/float(sampleSize))*100

print testMatchesRndLimited(False), "%"
>>> 0.0009 %

Edit: Bigger "sampleSize" shows 0.00068% chance. This is VERY unusual I agree. This might indicate the Outer-flame-bits are the highest bits in the Bacon26 char-bits (5), where we can find anomalous deviance towards more 0's than 1's (because Bacon26 encodes 26 chars using 5 bits, while 5 bits encode values up to 32, hence values 27-32 will never be encoded and those use mostly 1's). With this in mind, more NULLs in plain stream would indicate more bits would "leak" from the XOR 011010 key to the underlying data, hence Outer and Heights might share more bits cause underlying data in both had more NULLs.
member
Activity: 392
Merit: 39
If you define "red and long" as an irregularity, and then there are more longs than shorts, and there are 76/76 red/yellow, then red&long will show irregularity.
No Smiley
I am saying that if red and yellow arrive randomly, and you match it against the mixed fixed&random pattern of long and short, then (if red and short arrive randomly - remember) you will have the random number of matches. By "match" I consider matching red with long and yellow with short (red=long=1, yellow=short=0). But you have 103 matches out of 152. It is not random, or rather: not probable if randomity is assumed

Okay I see what you mean, yes, if we combine the chances of both red==long==1 and yellow==short==0, then of course at random it should be 50%/50%, so close to 76/152.

Here is a quick&lame function in python that tests it out:
Code:
def testMatchesRnd(usePattern=False, sampleSize=10000):
    totalCount = 0
    pattern = "011"*100
    for x in range(0, sampleSize):
        rndA = ""
        if usePattern:
            bits = getRandomBits(76)
            for i in range(0, 76):
                rndA += pattern[i] + bits[i]
        else:
            rndA = getRandomBits(152)
        rndB = getRandomBits(152)
        for i in range(0, 152):
            if rndA[i] == rndB[i]:
                totalCount += 1
    return (float(totalCount)/float(sampleSize))

def testMatchesFlames(trackA, trackB):
    totalCount = 0
    dataA = dataBuilder("abcdEFGH", trackA)
    dataB = dataBuilder("abcdEFGH", trackB)
    for i in range(0, 152):
        if dataA[i] == dataB[i]:
            totalCount += 1
    return (float(totalCount))

print testMatchesRnd(False), testMatchesRnd(True)
print testMatchesFlames(0, 1), testMatchesFlames(0, 2), testMatchesFlames(1, 2) #0=Heights,1=Outer,2=Inner

>> 76.0035  75.9582
>> 103.0  74.0  69.0



thanks I cannot currently run any simulations as I have no access to my R computer at the moment, but would you be so kind and check what are the chances of getting 103 or more matches by random? I would assume, quite low. Or I'll do it in the evening and post

jr. member
Activity: 33
Merit: 2
If you define "red and long" as an irregularity, and then there are more longs than shorts, and there are 76/76 red/yellow, then red&long will show irregularity.
No Smiley
I am saying that if red and yellow arrive randomly, and you match it against the mixed fixed&random pattern of long and short, then (if red and short arrive randomly - remember) you will have the random number of matches. By "match" I consider matching red with long and yellow with short (red=long=1, yellow=short=0). But you have 103 matches out of 152. It is not random, or rather: not probable if randomity is assumed

Okay I see what you mean, yes, if we combine the chances of both red==long==1 and yellow==short==0, then of course at random it should be 50%/50%, so close to 76/152.

Here is a quick&lame function in python that tests it out:
Code:
def testMatchesRnd(usePattern=False, sampleSize=10000):
    totalCount = 0
    pattern = "011"*100
    for x in range(0, sampleSize):
        rndA = ""
        if usePattern:
            bits = getRandomBits(76)
            for i in range(0, 76):
                rndA += pattern[i] + bits[i]
        else:
            rndA = getRandomBits(152)
        rndB = getRandomBits(152)
        for i in range(0, 152):
            if rndA[i] == rndB[i]:
                totalCount += 1
    return (float(totalCount)/float(sampleSize))

def testMatchesFlames(trackA, trackB):
    totalCount = 0
    dataA = dataBuilder("abcdEFGH", trackA)
    dataB = dataBuilder("abcdEFGH", trackB)
    for i in range(0, 152):
        if dataA[i] == dataB[i]:
            totalCount += 1
    return (float(totalCount))

print testMatchesRnd(False), testMatchesRnd(True)
print testMatchesFlames(0, 1), testMatchesFlames(0, 2), testMatchesFlames(1, 2) #0=Heights,1=Outer,2=Inner

>> 76.0035  75.9582
>> 103.0  74.0  69.0

member
Activity: 196
Merit: 23
Large scale, green crypto mining ICO
(...)
3) Bacon26 encoded string #1
(...)

It has been rumoured  on the forum many times it may be bacon cyphre. It seems to have been indicated by Coin Artist, allegedly in a tweet, that it is bacon. Does anyone have any source of that information, or a link to that tweet of hers? For now, it seems more like a rumour to me.
member
Activity: 392
Merit: 39

It may well be. But I am thinking it is there as an artifact of some other thing they did with the data. So it is not there with a purpose to show us the way to read the data, but rather it is there as the result of some other thing and we exploit it (thanks to alphabetcanary) to get the order on data. In the same way, we may find a way to exploit other regularities.


It's what I noted in one of the posts above, that if "1flamen6" is a clue, and some encoding only needs 5 bits (like Bacon26) but they used 6 bits, then 6th bit will always be NULL, hence after XOR'ing with 011010, 011 pattern will prevail all throughout the stream of 152 flames. They XOR'ed this or multiplexed it with 011. Either way, it was intentional cause "no brute-force needed" rule would otherwise be broken (we wouldn't know the reading order).


That I am not getting. Can you please explain? It seems to me that if we allow every 6th bit be 0 and the rest 5 bits are (more or less) random, and you xor them all against a 6 bit word 011010 in a loop, then only 6th bits are consistently impacted and fixed, and the rest of more or less random bits remain more or less random. The pattern 0x1x1x, however, is very consistent and it involves every 2nd bit, not every 6th.
EDIT: on second thought, you are absolutely right and I was wrong. I am getting it now Smiley . No further explanation is necessary. You are simply using colors as the remainder 4 bits.
EDIT2: But if you factor in blob, that is invalidated, again Smiley
 
member
Activity: 392
Merit: 39
If you define "red and long" as an irregularity, and then there are more longs than shorts, and there are 76/76 red/yellow, then red&long will show irregularity.
No Smiley
I am saying that if red and yellow arrive randomly, and you match it against the mixed fixed&random pattern of long and short, then (if red and yellow arrive randomly - remember) you will have the random number of matches. By "match" I consider matching red with long and yellow with short (red=long=1, yellow=short=0). But you have 103 matches out of 152. It is not random, or rather: not probable if randomity is assumed
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